Generating 5 digit alphanumeric code with predifined characters in sequence - php

Question

I would like to generate a membership number consisting of alphanumeric characters, removing i o and l to save confusion when typing. to be done in php (also using Laravel 5.7 if that matters - but i feel this is a php question)
If simply using 0-9 the membership number would start at 00001 for the 1st one and the 11th person would have 00011. I would like to use alphanumeric characters from 0-9 + a-z (removing said letters)
0-9 (total 10 characters), abcdefghjkmnpqrstuvwxyz (total 23 characters) - this giving a total of 33 characters in each count cycle (0-10+a-Z). instead of just 10 (0-10)
So the first membership number would still be 00001 where as the 12th would now be 0000a, 14th 0000c and 34th would be 0001a.
To summarize i need a way of defining the characters for counting in a way that can be generated based on the id of a user.
I hope I have explained this well enough.

Answer 1

Assuming that these are the only characters you want to use:
0123456789abcdefghjkmnpqrstuvwxyz
You can use base_convert() and strtr() to translate specific characters of the result to the characters you want.
function mybase33($number) {
return str_pad(strtr(base_convert($number, 10, 33), [
'i' => 'j',
'j' => 'k',
'k' => 'm',
'l' => 'n',
'm' => 'p',
'n' => 'q',
'o' => 'r',
'p' => 's',
'q' => 't',
'r' => 'u',
's' => 'v',
't' => 'w',
'u' => 'x',
'v' => 'y',
'w' => 'z',
]), 5, '0', STR_PAD_LEFT);
}
echo "9 is ".mybase33(9)."\n";
echo "10 is ".mybase33(10)."\n";
echo "12 is ".mybase33(12)."\n";
echo "14 is ".mybase33(14)."\n";
echo "32 is ".mybase33(32)."\n";
echo "33 is ".mybase33(33)."\n";
echo "34 is ".mybase33(34)."\n";
Output:
9 is 00009
10 is 0000a
12 is 0000c
14 is 0000e
32 is 0000z
33 is 00010
34 is 00011
https://3v4l.org/8YtaR
Explanation
The output of base_convert() uses these characters:
0123456789abcdefghijklmnopqrstuvw
The strtr() translates specific characters of that output to:
0123456789abcdefghjkmnpqrstuvwxyz