Time I have in the following format<?= $post['created_at'] ?> Output: 2018-08-03 11:44:59
How can coordination work like the following example : ago 2 month !
I guess it 's less a matter of code igniter, butt rather a date time php thing. You can get it with the DateTime class of php.
$now = new \DateTime();
$then = new \DateTime('2018-08-03 11:44:59');
$difference = $nof->diff($then, true);
Now you hace the difference between now and then in a DateInterval object. With this you can easily display the difference in the format you want.
echo $difference->days . ' ago'; // n days ago
If you want to get exactly the number of weeks which run by, you have to do some math.
echo floor($now->diff($then, true)->days / 7);
Same works for every format you want.
That 's it.
Related
Im trying to get the difference between 2 differente dates in minutes, but is not outputting correctly.
Ex:
$then = "2017-01-23 18:21:24";
//Convert it into a timestamp.
$then = strtotime($then);
//Get the current timestamp.
$now = time();
//Calculate the difference.
$difference = $now - $then;
//Convert seconds into minutes.
$minutes = floor($difference / 60);
echo $minutes;
Is outputting 611 minutes, and is wrong since from "2017-01-23 18:21:24" to "2017-01-24 12:36:24" it past much more than 611 minutes. Is my code incorrect?
Try to set your default timezone
date_default_timezone_set('Europe/Copenhagen');
Ofc change Europe/Copenhagen for the one that suits your needs.
If you are using or able to use PHP 5.3.x or later, you can use its DateTime object functionality:
$date_a = new DateTime('2010-10-20 08:10:00');
$date_b = new DateTime('2008-12-13 10:42:00');
$interval = date_diff($date_a,$date_b);
echo $interval->format('%h:%i:%s');
You can play with the format in a variety of ways, and once you have dates in DateTime objects, you can take advantage of a lot of different functionality, for example comparison via normal operators. See the manual for more: http://us3.php.net/manual/en/datetime.diff.php
I've checked your code it works perfectly So if have any doubt see your result
But you got wrong, so to ignore this set your timezone.
I need to create a PHP script that pulls the timestamps of various stuff from a database (logs, messages, logins, etc) and removes them if they are older than X amount of days. I am poor at doing work with time and am a bit stumped on the best way to do this.
I realize I could separate the day/month/year in the string using explode() and compare these with a bunch of If statements, but would like to use a more efficient method. Something like the following would be the correct way to do this correct?
$dt = "2011-03-19 10:05:44";
//if $dt is older than 90 days
if((time()-(60*24*90)) > strtotime($dt))
{
}
Subtract (minutes*hours*days) from time() or are the numbers wrong?
You can use DateTime class for this. Example:
$dt = "2011-03-19 10:05:44";
$date = new DateTime($dt);
$now = new DateTime();
$diff = $now->diff($date);
if($diff->days > 90) {
echo 'its greater than 90 days';
}
I want to add an x number of week days (e.g. 48 weekday hours) to the current timestamp. I am trying to do this using the following
echo (strtotime('2 weekdays');
However, this doesn't seem to take me an exact 48 hours ahead in time. For example, inputting the current server time of Tuesday 18/03/2014 10:47 returns Thursday 20/03/2014 00:00. using the following function:
echo (strtotime('2 weekdays')-mktime())/86400;
It can tell that it's returning only 1.3 weekdays from now.
Why is it doing this? Are there any existing functions which allow an exact amount of weekday hours?
Given you want to preserve the weekdays functionality and not loose the hours, minutes and seconds, you could do this:
$now = new DateTime();
$hms = new DateInterval(
'PT'.$now->format('H').'H'.
$now->format('i').'M'.
$now->format('s').'S'.
);
$date = new DateTime('2 weekdays');
$date->add($hms);//add hours here again
The reason why weekday doesn't add the hours is because, if you add 1 weekday at any point in time on a monday, the next weekday has to be tuesday.
The hour simply does not matter. Say your date is 2014-01-02 12:12:12, and you want the next weekday, that day starts at 2014-01-03 00:00:00, so that's what you get.
My last solution works though, and here's how: I use the $now instance of DateTime, and its format method to construct a DateInterval format string, to be passed to the constructor. An interval format is quite easy: it starts with P, for period, then a digit and a char to indicate what that digit represents: 1Y for 1 Year, and 2D for 2 Days.
However, we're only interested in hours, minutes and seconds. Actual time, which is indicated using a T in the interval format string, hence we start the string with PT (Period Time).
Using the format specifiers H, i and s, we construct an interval format that in the case of 12:12:12 looks like this:
$hms = new DateInterval(
'PT12H12M12S'
);
Then, it's a simple matter of calling the DateTime::add method to add the hours, minutes and seconds to our date + weekdays:
$weekdays = new DateTime('6 weekdays');
$weekdays->add($hms);
echo $weekdays->format('Y-m-d H:i:s'), PHP_EOL;
And you're there.
Alternatively, you could just use the basic same trick to compute the actual day-difference between your initial date, and that date + x weekdays, and then add that diff to your initial date. It's the same basic principle, but instead of having to create a format like PTXHXMXS, a simple PXD will do.
Working example here
I'd urge you to use the DateInterface classes, as it is more flexible, allows for type-hinting to be used and makes dealing with dates just a whole lot easier for all of us. Besides, it's not too different from your current code:
$today = new DateTime;
$tomorrow = new DateTime('tomorrow');
$dayAfter = new DateTime('2 days');
In fact, it's a lot easier if you want to do frequent date manipulations on a single date:
$date = new DateTime();//or DateTime::createFromFormat('Y-m-d H:i:s', $dateString);
$diff = new DateInterval('P2D');//2 days
$date->add($diff);
echo $date->format('Y-m-d H:i:s'), PHP_EOL, 'is the date + 2 days', PHP_EOL;
$date->sub($diff);
echo $date->format('Y-m-d H:i:s'), PHP_EOL, 'was the original date, now restored';
Easy, once you've spent some time browsing through the docs
I think I have found a solution. It's primitive but after some quick testing it seems to work.
The function calculates the time passed since midnight of the current day, and adds it onto the date returned by strtotime. Since this could fall into a weekend day, I've checked and added an extra day or two accordingly.
function weekDays($days) {
$tstamp = (strtotime($days.' weekdays') + (time() - strtotime("today")));
if(date('D',$tstamp) == 'Sat') {
$tstamp = $tstamp + 86400*2;
}
elseif(date('D',$tstamp) == 'Sun') {
$tstamp = $tstamp + 86400;
}
return $tstamp;
}
Function strtotime('2 weekdays') seems to add 2 weekdays to the current date without the time.
If you want to add 48 hours why not adding 2*24*60*60 to mktime()?
echo(date('Y-m-d', mktime()+2*24*60*60));
The currently accepted solution works, but it will fail when you want to add weekdays to a timestamp that is not now. Here's a simpler snippet that will work for any given point in time:
$start = new DateTime('2021-09-29 15:12:10');
$start->add(date_interval_create_from_date_string('+ 3 weekdays'));
echo $start->format('Y-m-d H:i:s'); // 2021-10-04 15:12:10
Note that this will also work for a negative amount of weekdays:
$start = new DateTime('2021-09-29 15:12:10');
$start->add(date_interval_create_from_date_string('- 3 weekdays'));
echo $start->format('Y-m-d H:i:s'); // 2021-09-24 15:12:10
I've been trying at this for a bit and can't get the damn code to work.. This is my first post, I've gone through a few, tried a million different ways.. I just want to get the difference in hours, then I'm set, I'll get the rest figured out..
Right now, it's giving me unusual answers (say there's a 2 hour difference, it'll give me 14 as an answer) Pardon my coding, I haven't done this in years and have no real formal training. I'll be as thorough as possible in my comments, and thanks a LOT. Any links appreciated. I have tried a LOT. Using PHP 5.3.something, and am pulling off a Wordpress 3.7.1 database.
Thanks in advance for the help for a beginner. I want to display "Updated x hours ago". Once I have the darned thing displaying the correct result, I'll figure the rest out.
//This is the current date, putting it into strtotime so everything is in the same format. It displays accurately.
$currentDate = date("Y-m-d");
$currentTime = date("H:i:s");
$currentDateHour = date("H", strtotime($currentDate . $currentTime));
// This is the date I'm pulling from the database, it only displays
// when in strtotime for some reason. It displays accurately to what is in the mySQL DB
$upDate = date("Y-m-d H", strtotime($row2[post_date]));
// Some variables to make life easier for later if statements if I ever get that far. Displays accurately.
$upDatehour = date("H", strtotime($row2[post_date]));
// trying simple subtraction
$hour = $currentDateHour - upDatehour;
// this is where the result is incorrect, what is wrong here? Any method I've tried gives me the same result, with or without strotime.. it's gotta be something simple, always is!
print strtotime($hour);
You can drastically simplify your code. I'd recommend refactoring it to use DateTime and specifically DateTime::diff().
$now = new DateTime();
$post = new DateTime($row2['post_date']);
$interval = $now->diff($post);
echo "Updated " . $interval->h . " hours ago";
Working example: http://3v4l.org/23AL6
Note that this will only show up to 24 hours difference. If you want to show all hours even for a difference of more than 24 hours, you'll need to figure in the days. Something like this:
$hours = $interval->h + ($interval->format("%a") * 24);
echo "Updated $hours hours ago";
Working example: http://3v4l.org/ilItU
If you are just trying to get the number of hours between two arbitrary times, the easiest way would be to get the difference in seconds of the two times, and then divide by 3600 to determine the number of hours between the two dates.
Here is a basic example:
<?php
$row2['post_date'] = '2013-12-02 07:45:38'; // date from database
$now = time(); // get current timestamp in seconds
$upDate = strtotime($row2['post_date']); // convert date string to timestamp
$diff = $now - $upDate; // subtract difference between the two times
$hours = floor($diff / 3600); // get the number of hours passed between the 2 times
echo $hours; // display result
Also, Wordpress has a built in function that may end up doing what your ultimate goal is, see wordpress function human_time_diff().
Example:
<?php echo human_time_diff( get_the_time('U'), current_time('timestamp') ) . ' ago';
Result:
2 days ago.
Example how to get difference between dates in hours:
$diff = date_diff(date_create(), date_create($row2['post_date']));
$hours = $diff->days * 24 + $diff->h;
If you wish to format output number with leading zeros, you can use sprintf() or str_pad() function. Example of sprintf() use for HH:mm format:
echo sprintf('%02d:%02d', $hours, $diff->i);
demo
I have a year (2002) and I'm trying to get it into the following format:
2002-00-00T00:00:00
I tried various iterations, the last of which was this:
$testdate = DateTime::createFromFormat(DateTime::ISO8601, date("c"))
echo date_format($testdate, '2002');
But, even if I come close, it always seems to add +00:00 to the end of it...
The 'c' format in PHP always appends the timezone offset. You can't avoid that. But you can build the date yourself from components:
date('Y-m-d\TH:i:s', $testdate);
Best way is to use constants (PHP 5 >= 5.5.0, PHP 7)
date(DATE_ISO8601, $timeToChange);
Docs:
http://php.net/manual/en/class.datetimeinterface.php#datetime.constants.types
The problem many times occurs with the milliseconds and final microseconds that many times are in 4 or 8 finals. To convert the DATE to ISO 8601 "date(DATE_ISO8601)" these are one of the solutions that works for me:
// In this form it leaves the date as it is without taking the current date as a reference
$dt = new DateTime();
echo $dt->format('Y-m-d\TH:i:s.').substr($dt->format('u'),0,3).'Z';
// return-> 2020-05-14T13:35:55.191Z
// In this form it takes the reference of the current date
echo date('Y-m-d\TH:i:s'.substr((string)microtime(), 1, 4).'\Z');
return-> 2020-05-14T13:35:55.191Z
// Various examples:
$date_in = '2020-05-25 22:12 03.056';
$dt = new DateTime($date_in);
echo $dt->format('Y-m-d\TH:i:s.').substr($dt->format('u'),0,3).'Z';
// return-> 2020-05-25T22:12:03.056Z
//In this form it takes the reference of the current date
echo date('Y-m-d\TH:i:s'.substr((string)microtime(), 1, 4).'\Z',strtotime($date_in));
// return-> 2020-05-25T14:22:05.188Z
Previous published: https://stackoverflow.com/a/61796705/5898408
date('Y-m-d\TH:i:s\Z', time() - date('Z'));