Here is an example array I want to split:
(1428,217,1428)
How do I split it in 2 array like this?
(1428,1428)
(217)
I have tried following way but it's only return 1428 array.
$counts = array_count_values($array);
$filtered = array_filter($array, function ($value) use ($counts) {
return $counts[$value] > 1;
});
One way to solve this for your example data is to sort the array and use array_shift to get the first element of the array and store that in an array.
$a = [1428,217,1428];
sort($a);
$b = [array_shift($a)];
print_r($a);
print_r($b);
Result
Array
(
[0] => 1428
[1] => 1428
)
Array
(
[0] => 217
)
You can try this.
$array = array(1428,217,1428);
$array1 = array_slice($array, 0, 2);
$array2 = array_slice($array, 2, 3);
print_r($array1);
print_r($array2);
And the output will like this:-
Array
(
[0] => 1428
[1] => 217
)
Array
(
[0] => 1428
)
In your case it will only return 1428 since array_count_values returns an array with values as keys and their frequency as array value therefore $counts will be equal to array('1428' => 2, '217' => 1);
If I understood your question well you should do something like this:
$array1 = [1428, 217, 1428];
$result = [];
foreach($array1 as $value){
$result[$value][] = $value;
}
This will not create an array for each different value but will create a new element for each unique value in $result. The final value of $result will be array('1428' => [1428, 1428], '217' => [217]) . Which can be easily manipulated as if they were 2 different arrays.
Let me know if this works for you, if not I will try to update my answer according to your specification.
Related
I have an existing array in this following structure,
Array
(
[0] => 1
[1] => 3
)
And, I want to convert in the following structure:
Array
(
[0] => Array
(
[class_id] => 1
)
[1] => Array
(
[class_id] => 3
)
)
Any suggestions, please let me know.
Thanks in advance!
Use a map to iterate over the array items and return a new array for each one of them.
<?php
function map($n) {
return [
'class_id' => $n
];
}
$a = array(1, 3);
$b = array_map("map", $a);
print_r($b);
?>
U just need to foreach this like this:
$data = [1, 3];
$result = [];
foreach ($data as $item) {
$result[] = ["class_id" => $item];
}
Seems that is exactly u need )
One liner:
array_walk($data, function(&$n){ $n = ['class_id'=>$n]; })
Keep in mind that we:
Pass the array as a reference to array_walk.
Then we pass each element as a reference to modify its content.
Also, array_walk keeps your index intact.
I have two array. I want to remove if 2nd array exists in 1st array. For example
array1 = array ("apple","banana","papaya","watermelon","avocado");
array2 = array ("apple","avocado");
I want the output should be
Array ( [1] => banana [2] => papaya [3] => watermelon)
Here are some code that I'd tried.
foreach($array2 as $key){
$keyToDelete = array_search($key, $array1);
unset($array1[$keyToDelete]);
}
print_r($array1);
but the output is
Array ( [1] => banana [2] => papaya [3] => watermelon [4] =>avocado )
It only remove first element.
i also tried to do something like this
$result = array_diff($array1,$array2);
print_r($result);
but the output is it print all element in array1
Noted: I want the result need to be outside foreach loop
array_diff should be work.
<?php
$array1 = array ("apple","banana","papaya","watermelon","avocado");
$array2 = array ("apple","avocado");
$array_diff = array_diff($array1, $array2);
print_r($array_diff);
?>
DEMO
output will be.
Array ( [1] => banana [2] => papaya [3] => watermelon)
You can also try below solution. result will be same.. using in_array Check if first array value not in the second tester that value in the new array 'final_result' for results.
in_array support (PHP 4, PHP 5, PHP 7)
$array1 = array ("apple","banana","papaya","watermelon","avocado");
$array2 = array ("apple","avocado");
$final_result = array();
foreach($array1 as $value){
if(!in_array($value, $array2)){
$final_result[] = $value;
}
}
print_r($final_result);
?>
DEMO
With the help of array_filter() we can do it easily. It filters elements of an array using a callback function.
array_filter() iterates over each value in the input array passing them to the callback function. If the callback function returns true, the current value from input is returned into the result array. Array keys are preserved.
Here we have used use($array2) clause to access the external variable inside callback function. $array2 is needed to filter out $array1.
$array1 = array("apple","banana","papaya","watermelon","avocado");
$array2 = array("apple","avocado");
$array1 = array_filter($array1, function($item) use($array2) { return !in_array($item, $array2); });
print '<pre>';
print_r($array1);
Demo
The fastest way to do this is to create a set(associative array) of elements in $array2 and iterate over $array1 and check if element in $array1 exists in our set or not using isset(). We take advantage of the method/algorithm technique called hashing.
<?php
$array1 = array ("apple","banana","papaya","watermelon","avocado");
$array2 = array ("apple","avocado");
$set = [];
foreach($array2 as $element){
$set[$element] = true;
}
$result = [];
foreach($array1 as $element){
if(!isset($set[$element])){
$result[] = $element;
}
}
print_r($result);
Demo: https://3v4l.org/PcS45
I have a little problem. Here is the code:
$arr = explode(',', $odluka);
$arr2 = array($arr[0], $arr[1], $arr[2], $arr[3], $arr[4], $arr[5], $arr[6], $arr[7], $arr[8], $arr[9]);
while ($arrk = current($arr2)) {
if ($arrk == '1') {
$ark = key($arr2);
//print_r($ark);
//echo $arr2[$ark];
$arop = explode(',', $utroseno);
$aropk = array($arop[0], $arop[1], $arop[2], $arop[3], $arop[4], $arop[5], $arop[6], $arop[7], $arop[8], $arop[9]);
$array = array($aropk[$ark]);
print_r($array);
}
next($arr2);
}
Output of $array is
Array ( [0] => 1 ) Array ( [0] => 5 ) Array ( [0] => 10 ) Array ( [0] => 4 ) Array ( [0] => 4 ) Array ( [0] => 1 ) Array ( [0] => 1 )
How can I merge this values and sum them. I want sum of 1+5+10+4+4+1+1. Thanks!
declare a variable to store sum
iterate over array
-> add value to sum
Here is a simple example how to deal with your output array:
$data = [
[1], [5], [10], [4]
];
$sum = array_sum(array_map(function($elem) { return $elem[0]; }, $data));
var_dump($sum);
You don't need to assign them to another array and loop..you can just sum everything after explode. You just need one line of code for that:
array_sum(explode(',', $odluka));
Then you'll get the sum of all the numbers
Not need using any array and loop.You are using only "array_sum ()" php building function.Like
<?php
$foo[] = "12";
$foo[] = 10;
$foo[] = "bar";
$foo[] = "summer";
echo array_sum ($foo); //same as echo "22";
?>
For more information Read Php Manual link
Use this function
array_sum ($arr);
I am using the Flot jQuery plugin to create a graph on how many visitors there have been per platform. I would like to create a 4th line with total visitors, calculated by previously retrieved data.
I need to combine several multi-dimensional Indexed arrays, but not simply merging them recursively. I.E:
$arr1 = [[2016/05/04,2],[2016/05/03,4],[2016/05/02,6]];
$arr2 = [[2016/05/04,1],[2016/05/03,3],[2016/05/02,2]];
$arr3 = [[2016/05/04,6],[2016/05/03,7],[2016/05/02,8]];
The output should be:
$arrTotal = [[2016/05/04,9],[2016/05/03,14],[2016/05/02,16]];
How do I accomplish this in a (fairly) simple way?
First of all, you cannot declare your dates the way you did:
$arr1 = [[2016/05/04,2],[2016/05/03,4],[2016/05/02,6]];
Because it's going to take 2016, divide it by 5 then divide it by 4. You need to put them into quotes.
$arr1 = [['2016/05/04',2],['2016/05/03',4],['2016/05/02',6]];
But to create an associative array, you should do it this way:
$arr1 = array('2016/05/04' => 2, '2016/05/03' => 4, '2016/05/02' => 6);
$arr2 = array('2016/05/04' => 1, '2016/05/03' => 3, '2016/05/02' => 2);
$arr3 = array('2016/05/04' => 6, '2016/05/03' => 7, '2016/05/02' => 8);
Now all you want to do, is loop through each array and sum them up.
$merge = array();
function mergeArray(Array &$merge, Array $array){
// Loop through each key and value
foreach($array as $key => $value)
// Make sure the value is numeric
if(is_numeric($value)){
if(!isset($merge[$key]))
$merge[$key] = $value;
else
$merge[$key] += $value;
}
}
mergeArray($merge, $arr1);
mergeArray($merge, $arr2);
mergeArray($merge, $arr3);
And now if you dump the $merge:
array(3) {
["2016/05/04"]=>
int(9)
["2016/05/03"]=>
int(14)
["2016/05/02"]=>
int(16)
}
Build a method that will sum the values by respecting the keys of existing values.
$arr1 = array('2016/05/04'=>2,'2016/05/03'=>4,'2016/05/02'=>6);
$arr2 = array('2016/05/04'=>1,'2016/05/03'=>3,'2016/05/02'=>2);
$arr3 = array('2016/05/04'=>2,'2016/05/03'=>7,'2016/05/02'=>8);
function array_sum(&$new_arr,$arr) {
foreach ($arr as $date_key => $num_value) {
// initialize date in new array with 0, if not done previously
if (! isset($new_arr[$date_key])) { $new_arr[$date_key] = 0; }
// add number for indexed element of array
$new_arr[$date_key] += $num_value;
}
}
$new_arr = array();
array_sum($new_array,$arr1);
array_sum($new_array,$arr2);
array_sum($new_array,$arr3);
You are trying to sum up every second value from each nested array relatively to their position in the parent array.There's a short and simple solution using array_map, array_sum and array_column functions:
$groupped = array_map(null, $arr1,$arr2,$arr3);
$result = array_map(function($v){
return [$v[0][0], array_sum(array_column($v, 1))];
}, $groupped);
print_r($result);
The output:
Array
(
[0] => Array
(
[0] => 2016/05/04
[1] => 9
)
[1] => Array
(
[0] => 2016/05/03
[1] => 14
)
[2] => Array
(
[0] => 2016/05/02
[1] => 16
)
)
I have the array:
$total =array();
Array (
[0] => Array
(
[0] => 1
[1] => 3
)
[1] => Array
(
[0] => 6
[1] => 7
[2] => 8
)
[2] => Array
(
[0] => 9
[1] => 10
)
)
I need to dynamically change each array into an indexed array for a Cartesian function.
Here is how I need the code to look for the function to work correctly:
$count = cartesian(
Array(1,3),
Array(6,7,8),
Array(9,10)
);
Any help would be greatly appreciated! I have tried flattening, looping, using array_values, using just the array itself and I keep falling short.
Thanks
Nick
function cartesian() {
$_ = func_get_args();
if(count($_) == 0)
return array(array());
$a = array_shift($_);
$c = call_user_func_array(__FUNCTION__, $_);
$r = array();
foreach($a as $v)
foreach($c as $p)
$r[] = array_merge(array($v), $p);
return $r;
}
$count = call_user_func('cartesian', array($total));
print_r($count);
Your arrays already look exactly the way you want them to. array(1,3) is the same as array(0 => 1, 1 => 3) and both are an array with the value 1 at key 0 and 3 at key 1. Exactly what the debug output shows you.
It seems you just need to pass them as separate arguments to the function. E.g.:
cartesian($total[0], $total[1], $total[2])
For dynamic lengths of arrays, do:
call_user_func_array('cartesian', $total)
I believe that your $total array is multi-dimensional array with numeric indexed. So yo can try like this
$count = cartesian($total[0], $total[1], $total[2]);