How to Update one form data to different tables in Laravel? - php

Question

I am working with Laravel 5.6 and MySQL. in My app I have some data edit form and its updated values saving with 3 different tables. called vehicles, cars and upload My edit form url as following,
http://localhost:8000/myads/1/edit
number (1) is vehicle table id number, like this,
id name owner
1 toyota dane
2 BMW peter
3 Benz samantha
4 volvo Alex
and car table is like this,
id fuel vehicle_id
1 P 1
2 D 3
3 E 2
I need update cars table data with regarding to vehicle_id , My VehicleController vehicle table data update function is like this
public function update(Request $request, $id)
{
$vehicle = Vehicle::find($id);
$vehicle->name = $request->input('name');
$vehicle->owner = $request->input('owner');
$vehicle->save();
}
now I need update cars table fuel values with same form optional values input. how can I do this in the Controller?
My fuel selection input is like this,
<div class="form-group">
<label for="exampleFormControlSelect1">Fuel</label>
<select class="form-control" id="fuel" name="fuel">
#foreach($vehicles->cars as $car)
<option value="{!! $car->fuel !!}">{!! $car->fuel !!}</option>
#endforeach
<option value="P">Petrol</option>
<option value="D">Diesel</option>
<option value="H">Hybrid</option>
<option value="E">Electric</option>
</select>
</div>
relationship among Vehicle and Car Models are
Vehicle Model
public function cars()
{
return $this->hasMany(Car::class);
}
Car Model
public function vehicle()
{
return $this->belongsTo(Vehicle::class);
}
How can do it?

Answer 1

Use a hidden Input field (load car id to the input using $car->id ) in form and name it as 'car_id'.
In the same update function,
$carId = $request->input('car_id');
$car= Car::find($carId);
//Update details here
$car->save();
Note : when you are working with multiple table, do not forget to use DB Transaction.

Answer 2

got success with following codes,
$vehicle->cars()->where('vehicle_id', $id)->update(['fuel' => $request->input('fuel')]);