Multiple CSV File Creation in PHP - php

Question

I have a code below
<?php
/* Error display */
error_reporting(E_ALL);
ini_set('display_errors', 1);
ini_set('memory_limit', '512M');
/* Requires */
require 'conn.php';
/* Parameters (DIM) */
$param_customer = $_POST['param_customer'];
$param_user = $_POST['param_user'];
/* Others */
$param_email = $_POST['email'];
$file_dump_area = "../general_sync/";
/* Array */
$jsonData = array();
$arr_result = array();
/******************************** Download customer *********************************/
$cur_filename = $file_dump_area . removeCharEmail($param_email) . "_" . $param_customer . ".csv";
$cur_file = fopen($cur_filename, "w");
$cur_sql = "CALL android_getCustomer('" .$param_email. "')";
$cur_result = mysqli_query($con,$cur_sql);
if ($cur_file && $cur_result) {
while ($row = $cur_result->fetch_array(MYSQLI_NUM)) {
fputcsv($cur_file, array_values($row));
}
array_push($arr_result, array('done_process' => "done_cus"));
}
fclose($cur_file);
/******************************** Download user *********************************/
$cur_filename = $file_dump_area . removeCharEmail($param_email) . "_" . $param_customer . "1.csv";
$cur_file = fopen($cur_filename, "w");
$cur_sql = "CALL android_getCustomer('" .$param_email. "')";
$cur_result = mysqli_query($con,$cur_sql);
if ($cur_file && $cur_result) {
while ($row = $cur_result->fetch_array(MYSQLI_NUM)) {
fputcsv($cur_file, array_values($row));
}
array_push($arr_result, array('done_process' => "done_user"));
}
fclose($cur_file);
$jsonData = array("received"=>$arr_result);
echo json_encode($jsonData,JSON_PRETTY_PRINT);
function removeCharEmail($val) {
$new_val1 = str_replace(".", "", $val);
$new_val2 = str_replace("#", "", $new_val1);
return $new_val2;
}
?>
The target output of that code is to create 2 csv which is it does but the problem is the 2nd csv has no data although the query shows some it does not write. I tried to copy the 1st line of codes. it does create the file but it didnt write
Whats the problem?
Updated with help of Mr. Barmar
i got this error Commands out of sync; you can't run this command now

Answer 1

The stored procedure is apparently returning two result sets. You need to fetch the next result set before you can start another query. Add:
$cur_result->close();
$con->next_result();
After each loop that fetches the results. See https://stackoverflow.com/a/14561639/1491895 for more details.