Print JSON Content in PHP - php

Question

I'd like to print this json
i can print the first part with the actions
PHP:
$print= json_decode($output_data);
foreach($print->actions as $mydata)
{
echo $mydata->ID.'<br><br>';
}
JSON:
{
"actions": [
{
"ID":"Search",
"name":"Select"
}
],
"content": {
"TEST": "false",
"nickname": "brad"
}
}
but i cant print the content part to show the TEST and nickname content.
Can you please help me ?
Thanks

Answer 1

In the assumption you Json format is like this:
{
"actions" : [{
"ID" : "Search",
"name" : "Select"
}
],
"content" : {
"TEST" : "false",
"nickmane" : "brad"
}
}
You can do it like in next example:
$print= json_decode($output_data);
// Print all actions IDs:
foreach($print->actions as $mydata)
{
echo $mydata->ID . '<br><br>';
}
// Print TEST.
echo "TEST: " . $print->content->TEST . " Nickname: " . $print->content->nickname;
Also, if you need to dump all the JSON, try this:
$print = json_decode($output_data);
print_r($print);
Or this:
$print = json_decode($output_data);
$output = print_r($print, true);
echo $output;
You can read more about print_r() and other ways to dump variables here: http://php.net/manual/es/function.print-r.php

Answer 2

You can do it quite simply like this:
$print= json_decode($output_data);
echo $print->content->TEST;
echo "<br/>";
echo $print->content->nickmane;
The difference from the "actions" is that "actions" is an array whereas "content" is an object, so you don't need a loop.
Click here to run a demo of this code

Answer 3

Your JSON is not a valid format. I appears your JSON should be the following to do what you want:
{
"actions" : [{
"ID" : "Search",
"name" : "Select"
}
],
"content" : {
"TEST" : "false",
"nickmane" : "brad"
}
}