Modify and add to MySQL result - php

Question

How can I add a custom key value pair to the existing SQL result?
<?php
require_once "dbaccess.php";
$json = array();
$access = new DatabaseAccess();
$sql = $access->Connect();
$stmt = $sql->prepare("select * from people");
$stmt->execute();
$result = $stmt->fetchAll(PDO::FETCH_ASSOC);
foreach($result as $key => $value){
$json[$key] = $value;
};
echo json_encode($json, JSON_UNESCAPED_SLASHES);
?>
The current JSON result is :
[
{
"id": "1",
"first_name": "James",
"last_name": "Haze"
},
{
"id": "2",
"first_name": "Neo",
"last_name": "Anderson"
}
]
How can I add to the current elements "country": "Australia" without modifying MySQL database? I want the result to look like this:
[
{
"id": "1",
"first_name": "James",
"last_name": "Haze",
"Country": "Australia"
},
{
"id": "2",
"first_name": "Neo",
"last_name": "Anderson",
"Country": "Australia"
}
]
Is it possible?

Answer 1

You can just select the additional "columns" you want in your SQL:
$stmt = $sql->prepare("select
id
, first_name
, last_name
, 'Australia' as Country
from people");
As an aside, you shouldn't use * in your select queries - that makes them behave weird when you add new column names and hides errors when you rename a column.
If you want to select a variable value, you can do that by interpolating it into your SQL directly:
$stmt = $sql->prepare("select
id
, first_name
, last_name
, '$country_name' as Country
from people");
Even though it is not necessary for country names, it is still a good practice to use (named) SQL placeholders, so you really should be doing it as:
$stmt = $sql->prepare("select
id
, first_name
, last_name
, :country as Country
from people");
$stmt->execute([':country' => $country_name]);
(This is mostly when reusing this code elsewhere, as I'm unaware of valid country names that contain single quotes)

Answer 2

you could add the values you need directly in select
$stmt = $sql->prepare("select id
, firt_name
, last_name
, 'Australia' AS country
from people");