I need help with form validation. Specifically for Australian phone numbers. I can only do basic validation using the preg_match() method but I'm stuck with this.
Must start with +614, (04) or 04; then any grouping of 8 more digits
and single spaces is permitted.
That's the validation criteria, any help is appreciated.
if (!preg_match("/^[0-9 ]*$/",$name)) {
$numberErr = "Number format is invalid"
}
that's all I can do I don't know how to add conditions for the start of the number (start with +614, (04) or 04.
Edit: Also need help with credit card validation, validation criteria is:
Any grouping of 12 - 19 numbers and single spaces are permitted.
if(!preg_match('/[0-9]{12}(?:[0-9]{3})?$/', $card)) {
$cardErr = "Invalid card number";
}
I can't find anything that teaches preg_match() method parameters so I honestly don't even know what the above code is doing.
Sorry for my noobness ;)
I am using anchors (^ and $) so that the start and the end of the string are identified. The leading characters are in the first non-capturing group with pipes that represent "OR". The second non-capturing group, contains the "space-tolerant" 8-digit substring.
Let me know if you have any fringe cases that are not handled properly.
Code: (Demo)
$aussie_mobiles = ['+614 1234 5678', '02 11112222', '(04)98765432', '0413572468', '+614 1 2 3 4 5 6 7 8'];
foreach ($aussie_mobiles as $mob) {
echo "$mob: ";
if (preg_match('~^(?:\+614|\(04\)|04)(?: *\d){8}$~', $mob)) {
echo "pass\n";
} else {
echo "fail\n";
}
}
Output:
+614 1234 5678: pass
02 11112222: fail
(04)98765432: pass
0413572468: pass
+614 1 2 3 4 5 6 7 8: pass
Related
I want to limit the number of "b" between 1 and 6, for which I'm using the following code:
<?php
$str="Big black books being kept in a black bag of a beautiful babe";
$pattern="/(b){1,6}/";
if(!preg_match($pattern,$str,$matches))
{
echo "Please use six bs";
}else
{/*do nothing*/}
print_r($matches);
?>
But It's not working. What am I doing wrong?
Through regex alone..
$str="Big black books being kept in a black bag of a beautiful babe";
$pattern="/^([^b]*b){1,6}[^b]*$/";
if(!preg_match($pattern,$str,$matches))
{
echo "Please use upto six bs";
}else
{/*do nothing*/}
print_r($matches);
and note that this must except atleast one single b. If you want to match also the line which don't have any single b then use /^([^b]*b){0,6}[^b]*$/
Add case-insensitive modifier i if you want to count also for capital B's.
Explanation:
^ start of the line.
([^b]*b){1,6} It matches (zero or more non-b characters and a b)(from 1 to 6 times). So this ensures that there must be character b exists min of 1 time and a max of 6 times.
[^b]* Matches any char but not of b, zero or more times. This ensures that there are no more further b exists.
$ End of the line boundary..
Try using match count.
<?php
$str="Big black books being kept in a black bag of a beautiful babe";
preg_match_all("/(b)/i",$str,$matches);
if(isset($matches[1]) && count($matches[1]) > 6 )
{
echo "Please use six bs";
}else
{/*do nothing*/}
print_r($matches);
?>
I think you want to count the number of Bs in the whole string while your regular expression counts them only in rows. i.e. "bbb" or just "b" would return a match.
Try using substr_count to achieve what I think you want. Here's an example.
<?php
$str = "Big black books being kept in a black bag of a beautiful babe";
if(substr_count($str, "b") > 6)
echo "Six is the limit...";
else
echo "Doing nothing...";
?>
But of course, it won't really help if you want to see the found matches.
I want to display an error message if the number doesn't match any number with hyphen, plus sign, space or brackets. No numbers either.
For example:
(012) 123 4567
(012)-123-4567
012-345-6789
123 123 1234
+12 23 213 3456
The above examples all work with this expression:
if (!preg_match("/^[0-9\-]|[\+0-9]|[0-9\s]|[0-9()]*$/", $_POST['tel'])) {
$telErr = "Invalid contact number";
}
But it allows letters, which I do not want.
Example:
+00000000a
The above example is accepted by the expression I have.
Please can someone help me with this.
I first cleanup the string a bit (that avoids useless matches):
$input = preg_replace('/[^0-9+\(\)-]/', '', $_POST['tel']);
I than match an american number +1 (xxx) xxx-xxxx;
if(preg_match('/^(\+1|001)?\(?([0-9]{3})\)?([ .-]?)([0-9]{3})([ .-]?)([0-9]{4})/',$input))
$result = "match: USA";
else $result = "no match";
this allows for quite some input configurations - only your last number would not match (if I'd not do the cleanup first, not because of the international code which is matched, but because of the split in the area-code) all the others go also without cleanup.
This expression'll accept +5number, 5number
"'^(([\+]([\d]{2,}))([0-9\.\-\/\s]{5,})|([0-9\.\-\/\s]{5,}))*$'"
Better regular expression is:
"/^[\+0-9\-\(\)\s]*$/"
It seems to me that what you want to express is in the ballpark of:
\+{0,1}\({0,1}[0-9]{0,3}\){0,1}[ -]{0,1}[0-9]{0,4}[ -]{0,1}[0-9]{0,4}[ -]{0,1}[0-9]{0,4}
that can be reduced to:
(\+?\(?[0-9]{2,3}\)?)([ -]?[0-9]{2,4}){3}
This can be read this way:
\+? //matches existence of +
\(? //matches existence of (
[0-9]{2,3} //matches 2 to 3 numbers
\)? //matches existence of )
([ -]?[0-9]{2,4}){3} //matches a space or a dash with 2 to 4 numbers, 3 times.
This will give you a maximum of 3 + 4 * 3 = 15 numbers without spaces for the phone variable.
But the best way in my opinion is to trim the input and then count it's length.
In RegEx there's always a perfect matching answer, but it doesn't always means it's a good idea to use it. It can be too complicated to maintain or too hard to understand.
SPAIN - ES
preg_match("/^(\+34|0034|34)?[6|7|9][0-9]{8}$/", $phone);
PORTUGAL - PT
preg_match("/^(\+351|00351|351)?[2|9][0-9]{8}$/", $phone);
ANDORRA - AD
preg_match("/^(\+376|00376|376)?[0-9]{6}$/", $phone);
GIBRALTAR - GI
preg_match("/^(\+350|00350|350)?[0-9]{8}$/", $phone);
--
It will be wonderfull have all the country list
I want to have a validation in php for price which can be 100 or 100.45
The 2 decimal places will be optional.
Now the validation should allow only digits.
So far i managed to achieve it
if (!preg_match('/^[0-9]+(\.[0-9]{1,2})?/', "100"))
{
echo "Invalid";
}
else
{
echo "Valid";
}
but the issue here is that it is showing valid even if i enter 100a.00 or 100a or 100.a00
Please help me in fixing it so that only digits are allowed i.e 100 or 100.00 format
Try this:
if (!preg_match('/^[0-9]+(\.[0-9]{1,2})?$/', "100"))
The $ denotes the "end of a string": http://www.php.net/manual/en/regexp.reference.meta.php
Lacks a $ in your regex.
Presently, the first 3 characters in '100a...' match your regex.
preg_match('/^[0-9]+(\.[0-9]{1,2})?$/', "100")
should do the trick.
I'm trying validate UK Mobile Phone Numbers, that are in the format:
075xxxxxxxx 077xxxxxxxx 078xxxxxxxx and 079xxxxxxxx
Each number must either start with the above 3 numbers and be 11 digits in length.
I've looked around and found several regex's such as:
RegEx1
RegEx2
But nothing I'm struggling to match my exact needs.
Has anyone got an example that would work with the numbers I'm trying to validate?
use this regex 07[5789]\d{8}
if you want to set dashes correct regex like this one 07[5789]\d{3}-\d{3}-\d{2}
07[57-9]\d{8}
07 -> exact match
[57-9] -> matches 5, 7, 8 and 9
\d{8} -> 8 digits more
Try this:
<?php
$telno = "07712345678";
preg_match("^07[5789]{1}[0-9]{8}^",$telno,$matches);
if(count($matches) > 0 && $matches[0] == $telno){
echo "valid tel no.";
}else{
echo "invalid no.";
}
?>
I purchased a contact form. Great little thing but I need to convert the validation for the phone number to allow for UK number formats - in other words, to allow for spaces.
Right now it validates without spaces and has a minimum length of 8 characters:
if(is_numeric($phone))
{
if(!$phone || strlen($phone) < 8)
{
$error .= "Please enter your phone number without spaces.<br />";
}
}
else
{
$error .= "Please enter numeric characters in the phone number field.<br />";
}
Phone numbers are typically horrible for regex patterns, which is what you will need.
This pattern for example:
$pattern = "/^(\+44\s?7\d{3}|\(?07\d{3}\)?)\s?\d{3}\s?\d{3}$/";
$match = preg_match($pattern,$input);
if ($match != false) {
// We have a valid phone number
} else {
// We have an invalid phone number
}
That pattern will match with +44 included or not e.g.
all these will match:
07222 555555
(07222) 555555
+44 7222 555 555
These won't
7222 555555
+44 07222 555555
(+447222) 555555
There are a load of sites that offer tutorials / cheat sheets etc. for regular expressions try some of these:
http://regexlib.com/Default.aspx
as well as a very good stack overflow post:
A comprehensive regex for phone number validation
So you just want to allow spaces?
Then you could use str_replace() to ignore spaces, right at the beginning:
$phone = str_replace(' ', '', $phone);
The is_numeric function that you're using isn't really even a suitable choice for American phone numbers. For example it accepts hexadecimal numbers like 0xABCDEF, which it should reject.
For simple text matching like this, regular expressions are often the easiest solution. A regular expression specifies a pattern of text. PHP has functions to let you search for or replace regular expression matches in text.
If you define a phone number as a string of at least 7 characters containing only digits and spaces, the corresponding regular expression would be /^[0-9 ]{7,}$/. The text inside the brackets represents a set of characters, the {7,} indicates that we're looking for at least 7 of these characters in a row, and the ^ and $ indicate that our match should start at the beginning of the string and end at the end of the string. The PHP documentation has a section explaining regular expressions in greater detail.
You would use the preg_match function to
ensure the phone number matched:
if (preg_match('/^[0-9 ]{7,}$/', $phone)) {
This matches all UK formats with a wide variety of punctuation:
^\(?(?:(?:0(?:0|11)\)?[\s-]?\(?|\+)44\)?[\s-]?\(?(?:0\)?[\s-]?\(?)?|0)(?:\d{5}\)?[\s-]?\d{4,5}|\d{4}\)?[\s-]?(?:\d{5}|\d{3}[\s-]?\d{3})|\d{3}\)?[\s-]?\d{3}[\s-]?\d{3,4}|\d{2}\)?[\s-]?\d{4}[\s-]?\d{4}|8(?:00[\s-]?11[\s-]?11|45[\s-]?46[\s-]?4\d))(?:(?:[\s-]?(?:x|ext\.?\s?|\#)\d+)?)$
Extract the various parts using this pattern
^\(?(?:(?:0(?:0|11)\)?[\s-]?\(?|\+)(44)\)?[\s-]?\(?(?:0\)?[\s-]?\(?)?|0)([1-9]\d{1,4}\)?[\s\d-]+)(?:((?:x|ext\.?\s?|\#)\d+)?)$
The country code is in $1 (and is null for national format). The NSN is in $2. The optional extension is in $3.
Remove all non-digits from $2 for further processing. The next step is to make sure the NSN is in a valid range and is a valid length (either 9 or 10 digits, depending on the range).
The list of patterns is too long to reproduce here but is available at:
http://aa-asterisk.org.uk/index.php/Regular_Expressions_for_Validating_and_Formatting_GB_Telephone_Numbers
You could parse the input to an integer, then validate for the correct number of digits;
$mobileNumber = intval($mobileNumber);
if (preg_match('/(^\d{12}$)|(^\d{10}$)/',$mobileNumber)==TRUE) {
//number has the right number of digits for a UK mobile number
} else {
//number does not have the right number of digits
}
Explained;
$mobileNumber = intval($mobileNumber);
This removes all non numerical characters from the string, and leading zero (eg spaces, brackets, plus signs, decimals etc);
*if (preg_match('/(^\d{12}$)|(^\d{10}$)/',$mobileNumber)==TRUE) {*
This regular expression then checks that the string contains either 12 or 10 digits which would cover 447712345678 (12 digits) or 7791234567 (10 digits). It is matched in two sub clauses (^\d{12}$) or (^\d{10}$) the carat (^) and dollar ($) represent to match everything from the very beginning (^) and to the very end ($) of the string. the \d represents any digit, and the following {12} means match the previous statement that number of times.
This does not mean that the number is valid, you could use an API like twillio to do additional validation of the numebr https://www.twilio.com/help/faq/sms/does-twilio-check-to-see-if-phone-numbers-can-receive-sms
For example;
$mobileNumber = '+447791234567';
$mobileNumber = intval($mobileNumber); //$mobileNumber is now 447791234567
if (preg_match('/(^\d{12}$)|(^\d{10}$)/',$mobileNumber)==TRUE) {
//$mobileNumber matches (^\d{12}$) and is valid
}
You could also add a check to ensure that number starts with either '07' or '447', required for UK mobiles, like this;
function isValidMobile($aNumber){
$aNumber = intval($aNumber);
return preg_match('/(^\d{12}$)|(^\d{10}$)/', $aNumber) && preg_match('/(^7)|(^447)/', $aNumber);
}
the intval removes leading zero,so the regular expression checks for a leadin 7 or 447.
I have found a solution with javascript according to the standards mentioned [here][1].**its not regex.**if you are using this solution there are three things to take care
validation can be used inside the UK
space cant be added. you need to type in your number without spaces
number has to begin with zero
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Document</title>
</head>
<body>
<script >
var name=window.prompt("Enter cell number");
var sixformat=["013397","013398","013873","015242","015394","015395","015396","016973","016974","017683","017684","017687","019467","019755","019756"];
var twoformat=["01","02","03","05","07","08","09"];
sixdi=name.substring(0,6);
twodi=name.substring(0,2);
document.write("phone number:",name,"<br>");
document.write("phone-number length:",name.length);
if(sixformat.includes(sixdi)&&name.length==11)
{
document.write("<br><h1>valid</h1>");
}
else if(sixdi=="016977"&&name.length==10)
{
document.write("<br><h1>valid<h1>");
}
else if(twoformat.includes(twodi)&&(name.length==11))//011########
{
document.write("<br><h1>valid</h1>");
}
else if(twodi=="01"&&(name.length==10))
{
document.write("<br><h1>valid</h1>");
}
else if(name.substring(0,4)=="0800"&&(name.length==10))
{
document.write("<br><h1>Valid</h1></br>");
}
else
{
document.write("<h1>invalid</h1>");
}
</script>
</body>
</html>