How can I get the Financial Year date range in PHP like below when I pass year and return date range of every year start and end.
Like Eg.
Input Array = [2017,2018]
Financial Start Month = 04
Output Array =
[
'2017' => [
'start' => '2016-04-01',
'end' => '2017-03-31'
],
'2018' => [
'start' => '2017-04-01',
'end' => '2018-03-31'
]
]
My Effort:-
$year_arr = [2017,2018];
$fn_month = 04;
$date_range_arr = [];
foreach ($year_arr as $key => $value) {
$fn_start_date_year = ($value - 1);
$fn_start_date_month = $fn_month;
$fn_start_date_day = '01';
$fn_start_date_string = $fn_start_date_year.'-'.$fn_start_date_month.'-'.$fn_start_date_day;
$start_date = date('Y-m-d',strtotime($fn_start_date_string));
$fn_end_date_year = ($value);
$fn_end_date_month = (fn_month == 1)?12:(fn_month-1);
$fn_end_date_day = date('t',strtotime($fn_end_date_year.'-'.$fn_end_date_month.'-01'));
$fn_start_date_string = $fn_end_date_year.'-'.$fn_end_date_month.'-'.$fn_end_date_day;
$end_date = date('Y-m-d',strtotime($fn_start_date_string));
$date_range_arr[$value] = [
'start_date' => $start_date,
'end_date' => $end_date
];
}
Above is my effort. It is working perfectly but needs a more robust code.
A good way to manipulate dates in PHP is using the DateTime class. Here's an example of how to get the results you want using it. By using the modify method, we can avoid worries about complications like leap years (see the result for 2016 below).
$year_arr = [2016,2017,2018];
$fn_month = 03;
foreach ($year_arr as $year) {
$end_date = new DateTime($year . '-' . $fn_month . '-01');
$start_date = clone $end_date;
$start_date->modify('-1 year');
$end_date->modify('-1 day');
$date_range_arr[$year] = array('start_date' => $start_date->format('Y-m-d'),
'end_date' => $end_date->format('Y-m-d'));
}
print_r($date_range_arr);
Output:
Array (
[2016] => Array (
[start_date] => 2015-03-01
[end_date] => 2016-02-29
)
[2017] => Array (
[start_date] => 2016-03-01
[end_date] => 2017-02-28
)
[2018] => Array (
[start_date] => 2017-03-01
[end_date] => 2018-02-28
)
)
Demo on 3v4l.org
Maybe this is what you need?
I use strtotime to parse the date strings.
$year_arr = [2017,2018];
$fn_month = 04;
$date_range_arr = [];
foreach($year_arr as $year){
$date_range_arr[$year] =['start' => date("Y-m-d", strtotime($year-1 . "-" .$fn_month . "-01")),
'end' => date("Y-m-d", strtotime($year . "-" .$fn_month . "-01 - 1 day"))];
}
var_dump($date_range_arr);
Output:
array(2) {
[2017]=>
array(2) {
["start"]=>
string(10) "2016-04-01"
["end"]=>
string(10) "2017-03-31"
}
[2018]=>
array(2) {
["start"]=>
string(10) "2017-04-01"
["end"]=>
string(10) "2018-03-31"
}
}
https://3v4l.org/nMUHt
Try this snippet,
function pr($a)
{
echo "<pre>";
print_r($a);
echo "</pre>";
}
$year_arr = [2017, 2018];
$fn_month = 4;
$date_range_arr = [];
foreach ($year_arr as $key => $value) {
$fn_month = str_pad(intval($fn_month),2, 0, STR_PAD_LEFT);
$date = "".($value-1)."-$fn_month-01"; // first day of month
$date_range_arr[$value] = [
'start_date' => $date,
'end_date' => date("Y-m-t", strtotime($date.' 11 months')), // last month minus and last date of month
];
}
pr($date_range_arr);
die;
str_pad - Pad a string to a certain length with another string
Here is working demo.
Related
I have a date range and I need it to group by month but I want to keep starting day and ending day. So far I have this:
$interval['from'] = '2017-01-02 00:00:00';
$interval['to'] = '2017-02-06 23:59:59';
$start = Carbon::createFromFormat('Y-m-d H:i:s', $interval['from'])->startOfMonth();
$end = Carbon::createFromFormat('Y-m-d H:i:s', $interval['to'])->startOfMonth()->addMonth();
$separate = CarbonInterval::month();
$period = new \DatePeriod($start, $separate, $end);
foreach ($period as $dt) {
dump($dt);
}
But as result I'm getting:
Carbon\Carbon(3) {
date => "2017-01-01 00:00:00.000000" (26)
timezone_type => 3
timezone => "Europe/Prague" (13)
}
Carbon\Carbon(3) {
date => "2017-02-01 00:00:00.000000" (26)
timezone_type => 3
timezone => "Europe/Prague" (13)
}
It is grouped by month but I need to get whole month period, I mean from
2017-01-02 00:00:00 to 2017-01-31 23:59:59
2017-02-01 00:00:00 to 2017-02-06 23:59:59.
Output:
$array = [
0 => [
'from' => '2017-01-02 00:00:00',
'to' => '2017-01-31 23:59:59'
],
1 => [
'from' => '2017-02-01 00:00:00',
'to' => '2017-02-06 23:59:59'
]
];
What is the easiest way to achive it?
Edit: Here is a little bit modified Carbon version of accepted answer, maybe somebody will need it:
$interval['from'] = '2017-01-02 00:00:00';
$interval['to'] = '2017-04-08 23:59:59';
$interval_from = Carbon::createFromFormat('Y-m-d H:i:s', $interval['from']);
$interval_to = Carbon::createFromFormat('Y-m-d H:i:s', $interval['to']);
$result = [];
foreach (range($interval_from->month, $interval_to->month) as $x) {
$to = $interval_from->copy()->endOfMonth();
if ($x == $interval_to->month) {
$result[] = ["from" => $interval_from, "to" => $interval_to];
} else {
$result[] = ["from" => $interval_from, "to" => $to];
}
$interval_from = $to->copy()->addSecond();
}
PHP code demo
Try this solution you can change from one month to another month(not year) and then check. Lengthy solution but hopefully works correctly, putting explaination.
<?php
ini_set('display_errors', 1);
$from=$interval['from'] = '2017-01-02 00:00:00';
$interval['to'] = '2017-03-07 23:59:59';
$month1=date("m", strtotime($interval['from']));
$month2=date("m", strtotime($interval['to']));
$result=array();
foreach(range($month1, $month2) as $x)
{
$dateTimeObj= new DateTime($from);
$dayDifference=($dateTimeObj->format('d')-1);
$dateTimeObj= new DateTime($from);
$dateTimeObj->add(new DateInterval("P1M"));
$dateTimeObj->sub(new DateInterval("P".$dayDifference."DT1S"));
$to= $dateTimeObj->format("Y-m-d H:i:s");
if($x==$month2)
{
$dateTimeObj= new DateTime($interval['to']);
$noOfDays=$dateTimeObj->format("d");
$dateTimeObj->sub(new DateInterval("P".($noOfDays-1)."D"));
$from=$dateTimeObj->format("Y-m-d H:i:s");
$result[]=array("from"=>$from,"to"=>$interval['to']);
}
else
{
$result[]=array("from"=>$from,"to"=>$to);
}
//adding 1 second to $to for next time to be treated as $from
$dateTimeObj= new DateTime($to);
$dateTimeObj->add(new DateInterval("PT1S"));
$from= $dateTimeObj->format("Y-m-d H:i:s");
}
print_r($result);
I have a script that queries an API and finds records within the last day.
I'd like to then loop through these results and solely get those within the last hour.
Can someone explain how I do this?
This is my array of daily results:
array(2) {
[0]=>
array(36) {
["CallRef"]=> string(10) "1234567891"
["CallStartTime"]=> string(8) "08:18:30"
}
[1]=>
array(36) {
["CallRef"]=> string(10) "1234567892"
["CallStartTime"]=> string(8) "14:04:20"
}
}
It's 14:40 here in the UK so my script should just grab the 2nd item from the array.
How about this?
$apiElements = [
['CallRef' => '1234567891', 'CallStartTime' => '08:18:30'],
['CallRef' => '1234567892', 'CallStartTime' => '14:04:20'],
];
$currentFormatted = (new DateTime())->format('H');
$startOfHour = DateTime::createFromFormat('H:i:s', $currentFormatted . ':00:00');
$endOfHour = DateTime::createFromFormat('H:i:s', $currentFormatted . ':59:59');
$callsInHour = array_filter($apiElements, function($element) use ($startOfHour, $endOfHour) {
$dt = DateTime::createFromFormat('H:i:s', $element['CallStartTime']);
return $dt >= $startOfHour && $dt <= $endOfHour;
});
Totally untested, but give it a try.
Next time, please post what code you tried...
Theres multiple ways to do this. You can get a Unix timestmap from a hour ago: strtotime('-1 hour'). You can explode the time on every : in the time and take the 2nd result from the explode result.
foreach ($array as $value){
$exploded=explode(":",$value['CallStartTime']);
if(date('H')-1>$exploded[1]){
//This means it's an hour ago.
}
}
Replace $allResults and try this:
date_default_timezone_set('UTC');
$hourAgo = strtotime(date('H:i:s')) - 3600;
foreach ($allResults as $result){
if(strtotime($result["CallStartTime"]) > $hourAgo){
var_dump($result);
}
}
More flexible solution:
First you need a function to convert time to seconds
function convertTimeToSeconds($hhmmss)
{
//correct format if needed
list($hours, $minutes, $seconds) = explode(':', $hhmmss);
return $hours * 3600 + $minutes * 60 + $seconds;
}
And then you just can use array_filter function
$now = date('H:i:s');
$nowSeconds = convertTimeToSeconds($now);
$filterFunction = function ($value) use ($nowSeconds) {
return ($nowSeconds - convertTimeToSeconds($value['CallStartTime'])) < 3600; //3600 seconds = hour
};
$filteredList = array_filter($array, $filterFunction);
All together https://3v4l.org/icAmp
I suppose you have this array
Array
(
[0] => Array
(
[CallRef] => 1234567892
[CallStartTime] => 21:04:20
)
[1] => Array
(
[CallRef] => 1234567892
[CallStartTime] => 09:08:08
)
[2] => Array
(
[CallRef] => 1234567892
[CallStartTime] => 08:11:08
)
[3] => Array
(
[CallRef] => 1234567892
[CallStartTime] => 20:59:08
)
)
And so i tried this
<?php
$arr = array(
"0" => array (
"CallRef" => 1234567892,
"CallStartTime" => "21:04:20"
),
"1" => array (
"CallRef" => 1234567892,
"CallStartTime" => "09:08:08"
),
"2" => array (
"CallRef" => 1234567892,
"CallStartTime" => "08:11:08"
),
"3" => array (
"CallRef" => 1234567892,
"CallStartTime" => "20:59:08"
)
);
//echo "<pre>";print_r($arr);die;
date_default_timezone_set('Asia/kolkata');//set your timezone
$currentTime = date('H:i:s');//getting current time
$lastHourTime = date('H:i:s', strtotime('-1 hour'));//getting last hour time
$result = array();
foreach ($arr as $singlearr){
if(strtotime($singlearr['CallStartTime']) >= strtotime($lastHourTime) && strtotime($singlearr['CallStartTime']) <= strtotime($currentTime)){
$result[] = $singlearr;
}else{
}
}
echo "<pre>";print_r($result);die;//this gives me last hour records only
Check Demo When you check demo All records which have time > last hour will return otherwise it will return empty array
May be it can help!
I am trying to Write Program for Calculating Next 20 dates After Specifying Start date, then from 20 dates i have Exclude Weekends & Holidays(Array holidays('2016-12-13',2016-12-24)) And Result Array which includes only Working Days Excluding Saturday & Sunday, from this Result Array after Passing Holiday array(Eg:- holidays('2016-12-13',2016-12-24))), it must be Excluded from result array. i:e;
I want Expected Output Below mentioned
.
<?php
$Date=array('2016-12-01');
echo "\n <br />Start Date:-" . $Date[0] . "";
/*Code For Generating Next 20 Dates Starts*/
//$start = strtotime($s_row['schedule_start_date']);
$start = strtotime('2016-12-01');
$dates=array();
for($i = 0; $i<20; $i++)
{
array_push($dates,date('Y-m-d', strtotime("+$i day", $start)));
}
echo "\n <br /> Array Of next 20 Days/dates of Given:-";
print_r($dates);
$start=array();
$start=$dates; /*Code For Generating Next 20 Dates Ends*/
$result=array();
$start = strtotime(array_values($Date)[0]);
//$end = strtotime(array_values($Date)[30]);
$result = array();
$begin = new DateTime( '2016-12-01' );
$end = new DateTime( '' );
//$end = $end->modify( '+1 day' );
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
foreach($daterange as $date)
{
//echo $date->format("Y-m-d") . "<br>";
if (date('N', $start) <= 5) /* 'N' number days 1 (mon) to 7 (sun) */
/*5 weekday */
{
$current = date('Y-m-d', $start); //m/d/Y
$result[$current] = '';
}
$start += 86400;
//echo "Days Without Sat Sun".$result[date($date->format("Y-m-d"))];
//echo "Days Without Sat Sun".$result2[date($current->format("Y-m-d"))];
}
echo " \n <br /> Dates Without Weekends LIKE (Excluding Saturday & Sunday):-";
print_r($result);
/*For Holiday*/
$FinalArray = array();
$holidays = array(
'2016-12-13',
'2016-12-24',
);
echo " \n <br /> Given Holiday Dates Are:-";
print_r($holidays);
$a1 = $result;
$a2 = $holidays;
$array = array_diff(array_merge($a1,$a2),array_intersect($a1,$a2));
echo "\n <br /> Output:-";
print_r($array);
?>
it Gives Output as :- Array ( [2016-12-01] => [2016-12-02] => [2016-12-05] => [2016-12-06] => [2016-12-07] => [2016-12-08] => [2016-12-09] => [2016-12-12] => [2016-12-13] => [2016-12-14] => [2016-12-15] => [2016-12-16] => [2016-12-19] => [2016-12-20] => [2016-12-21] => [2016-12-22] => [2016-12-23] => [0] => 2016-12-13 [1] => 2016-12-24 )
> But I Want Expected Output:-
Array ( [2016-12-01] => [2016-12-02] => [2016-12-05] => [2016-12-06] => [2016-12-07] => [2016-12-08] => [2016-12-09] => [2016-12-12] => [2016-12-14] => [2016-12-15] => [2016-12-16] => [2016-12-19] => [2016-12-20] => [2016-12-21] => [2016-12-22] => [2016-12-23]
You Can Notice That 2016-12-13 is Not There in Above Expected Output as in '2016-12-13', 2016-12-24 is passed as Holiday via holiday array ($holidays = array( '2016-12-13', '2016-12-24', );) i:e; if i pass any date through holidays array it should not be included in result Array(). i:e 2016-12-13 is Available in Result array as well as holiday array So While while printing Final OUTPUT:- 13th date(2016-12-13) Should not be Included in final Output. Anybody Solve this will be Appreciated Thanks in Advance.
When I have to remove duplicates from a array the function that I keep going back to is
array array_unique ( array $array [, int $sort_flags = SORT_STRING ] )
you can find the documentation Here
<?php
$input = array("a" => "green", "red", "b" => "green", "blue", "red");
$result = array_unique($input);
print_r($result);
?>
the output
Array
(
[a] => green
[0] => red
[1] => blue
)
I hope that this was able to help
I prefer to calculate all dates just in one pass. (You may skip filling $dates and $dates_mon_fri arrays if they doesn't used in output also.) There is yet another approach to avoid array_diff() and array_unique() functions. I've used an array_flip() to exchange keys with values in $holdidays array to use fast array_key_exists() function.
<?php
$start = strtotime('2016-12-01');
$holidays = [
'2016-12-13',
'2016-12-24',
];
$dates = [];
$dates_mon_fri = [];
$dates_working = [];
$flip_holidays = array_flip($holidays);
for ($i = 0; $i < 20; $i++) {
$timestamp = strtotime("+$i day", $start);
$date = date('Y-m-d', $timestamp);
$dates[] = $date;
$mon_fri = false;
if (date('N', $timestamp) <= 5) {
$dates_mon_fri[] = $date;
$mon_fri = true;
}
if ($mon_fri && !array_key_exists($date, $flip_holidays)) {
$dates_working[] = $date;
}
}
var_dump($dates);
var_dump($dates_mon_fri);
var_dump($dates_working);
You can avoid using explicit looping:
$begin = new DateTimeImmutable('2016-12-01');
$end = $begin->modify('+20 days');
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval, $end);
$allDates = iterator_to_array($daterange);
$datesExcludingWeekends = array_filter($allDates, function ($date) {
return (int) $date->format("N") < 6;
});
$datesExcludingWeekends = array_map(
'date_format',
$datesExcludingWeekends,
array_fill(1, count($datesExcludingWeekends), 'Y-m-d')
);
$holidays = [
'2016-12-13',
'2016-12-24',
];
$datesExcludingWeekendsIncludingHolidays = array_flip(array_merge(
$datesExcludingWeekends,
array_diff($holidays, $datesExcludingWeekends)
));
Here is working demo.
Also, take a look at the Carbon library. If you need some exhaustive working with dates this library can really ease your life.
What is the most efficient way to get an array of months, from a specified date, up until the present day, grouped by year.
Eg getMonths("August 2012") would output
array(
array("Year"=>"2013", "months" = array(
"February", "January")
),
array("Year"=>"2012", "months" = array(
"December", "November","October", "September", "August")
)
)
So far I've got:
$start = strtotime('2012-08-01');
$end = time();
$month = $start;
$months[] = date('F', $start);
while($month <= $end) {
$month = strtotime("+1 month", $month);
$months[] = date('F', $month);
}
This is outputting the correct months, but not grouping them into years.
Thanks
You can try
function getMonths($month,$count = 1) {
$now = new DateTime();
$start = DateTime::createFromFormat("F Y", $month);
$list = array();
$interval = new DateInterval(sprintf("P%dM",$count));
while ( $start <= $now ) {
$list[$start->format("Y")][] = $start->format("F");
$start->add($interval);
}
return $list;
}
print_r(getMonths("August 2012"));
Output
Array
(
[2012] => Array
(
[0] => August
[1] => September
[2] => October
[3] => November
[4] => December
)
[2013] => Array
(
[0] => January
[1] => February
)
)
Since the answer posted here did not work for me (also tried online sandbox to be sure) i wrote a method that works with the very most versions of PHP:
function getMonths($monat, $year) {
$list = array();
for(;$monat <= 12;$monat++) {
if($year == date("Y") && $monat == date("m")) { // exit on current month+year
break;
}
if(!isset($list[ $year ])) {
$list[ $year ] = array();
}
$list[ $year ][ str_pad($monat, 2, '0', STR_PAD_LEFT) ] = date("F", strtotime('01.' . $monat . '.' . $year));
if($monat == 12) {
$monat = 0;
$year++;
}
}
return $list;
}
I just wondered if anybody can point me in the right direction: I'm looking to make a script whereby the logo on my site changes depending on the date; so for instance a haloween style one soon.
I started off by having 2 arrays, 1 of start dates and 1 of end dates(not sure even if this is the best way!):
<?php
$start_dates = array('01/01' => 'New Years',
'14/02' => 'Valentine Day',
'16/02/2010' => 'Pancake Day',
'17/03' => 'St Patricks Day',
'01/04' => 'April Fools',
'02/04/2010' => 'Easter',
'23/04' => 'St Georges Day',
'11/06/2010' => 'World Cup',
'31/10' => 'Halloween',
'05/11' => 'Guy Fawkes',
'11/11' => 'Armistice Day',
'16/10' => 'Today',
'15/12' => 'Christmas');
$end_dates = array( '08/01' => 'New Years',
'15/02' => 'Valentine Day',
'17/02/2010' => 'Pancake Day',
'18/03' => 'St Patricks Day',
'02/04' => 'April Fools',
'06/04/2010' => 'Easter',
'24/04' => 'St Georges Day',
'12/07/2010' => 'World Cup',
'01/11' => 'Halloween',
'06/11' => 'Guy Fawkes',
'12/11' => 'Armistice Day',
'17/10' => 'Today',
'01/01' => 'Christmas');
?>
Easy so far...the problemis that I need a way of working out if todays date falls between the start date and end date, then changing the image file name.
Its a long shot but I hope someone would be kind enough to help.
Thanks,
B.
like this
$events = array(
'New Year' => '01/01 01/08',
'Pancake Day' => '16/02/2010 17/02/2010',
//etc
);
echo find_event($events, '16/02');
where find_event() is
function mdy2time($date) {
$e = explode('/', $date);
if(count($e) < 3)
$e[] = '2010';
return strtotime("$e[1]-$e[0]-$e[2]");
}
function find_event($events, $date = null) {
$date = is_null($date) ? time() : mdy2time($date);
foreach($events as $name => $range) {
list($start, $end) = explode(' ', $range);
if($date >= mdy2time($start) && $date <= mdy2time($end))
return $name;
}
return null;
}
you should use an array more like this:
$dates = array();
$dates[] = array(
'name' => 'New Years'
'start' = '01/14',
'end' => '01/20',
'style' => 'haloween',
);
$dates[] = array(
//...
);
then you can get the style as follows:
$style='default';
// date as number e.g. 130 (january 30th)
$currDate = date('md',time()) * 1;
foreach ($dates AS $k => $v) {
$tmp = explode("/",$v['start'];
$start = ($tmp[1].$tmp[0])*1;
$tmp = explode("/",$v['end'];
$stop = ($tmp[1].$tmp[0])*1;
if ($start <= $currDate && $currDate < $stop) {
$style=$v['style'];
break;
}
}
echo 'style: '.$style;
Didn't check the code yet, so feel free to correct me if iam wrong.