I am trying to order in while from higger count of clicks to the lower and I am a bit of lost so I decided to ask the qustion here.
My code :
$stmt = $db->query("SELECT DISTINCT `country` FROM `entries` ORDER by `id` ASC");
if ($stmt->rowCount() > 0) {
while ($row = $stmt->fetch()) {
$clicks = $db->query("SELECT `id` FROM `entries` WHERE `country` LIKE '{$row['country']}'")->rowCount();
$conversations = $db->query("SELECT `id` FROM `conversations` WHERE `country` LIKE '{$row['country']}' AND `link_id` = '{$id}'")->rowCount();
}
I want the foreach give me results from highest count of $clicks to the lowest.
Any ideas what can I do ?
You can do this query entirely in SQL with something like this (depending on SQL dialect):
$countries = $db->query("SELECT `country`, count(1) AS clicks FROM `entries` GROUP BY `country` ORDER BY clicks DESC");
foreach ($countries as $country) {
echo "${country['country']} has ${country['clicks']} clicks. ";
}
put number of clicks in an array as below :
$clicks[] = $db->query("SELECT `id` FROM `entries` WHERE `country` LIKE '{$row['country']}'")->rowCount();
then you can simply sort the array by rsort php function as below :
echo rsort($clicks);
Related
Im making a filter where you can select colors and select newest. It would filter them, but the order by doesn't work for some reason.
I tried it this way. It outputs the colors that match the database table, but it doesn't sort them by date.
$color_arr = ["red", "blue", "white"];
foreach($color_arr as $color) {
$data = $conn->query("SELECT * FROM `prod_items` WHERE item_color LIKE '%$color%' ORDER BY `item_date` DESC");
while ($row = $data->fetch()) {
print_r($row);
}
}
You can order by multiple fields, below is the MYSQL query:
SELECT * FROM `prod_items` WHERE item_color LIKE '%$color%' ORDER BY `item_date` DESC, `price` DESC"
This will first sort by item_date and then by price.
Don't run sql query inside loop.
$sql = array('0'); // Stop errors when $color_arr is empty
$color_arr = ["red", "blue", "white"];
foreach($color_arr as $color){
$sql[] = 'item_color LIKE "%'.$color.'%"';
}
$sql1 = implode(" OR ", $sql). " ORDER BY `item_date` DESC";
$sql = "SELECT * FROM `test` WHERE $sql1";
$data = $conn->query($sql);
while ($row = $data->fetch_array()) {
print_r($row);
}
I have a really simple question, but unfortunately I can't figure it out myself. I have a list of 12 players which all have an (unique)ID, rating, attribute1 and attribute4. I ONLY want the row of the player with the highest rating followed by attribute1 and then attribute4. So it will first have to sort on rating, if there are 2 with rating 84, SQL will check for attribute1 etc. This is my code.
$sql = "SELECT * FROM `players_db` WHERE `id` = $player[0] OR `id` = $player[1] OR `id` = $player[2] OR `id` = $player[3] OR `id` = $player[4] OR `id` = $player[5] OR `id` = $player[6] OR `id` = $player[7] OR `id` = $player[8] OR `id` = $player[9] OR `id` = $player[10] OR `id` = $player[11] ORDER BY `rating` DESC , `attribute1` DESC, `attribute4` DESC";
$result = $conn->query($sql);
while ($row = mysqli_fetch_assoc($result)) {
echo $row['rating'];
echo '<br>';
}
I can't figure it out how to go further, as I already tryed
SELECT MAX('rating') FROM players_db WHERE ...
But then it only gets the rating of the highest player, so how can I get the whole row of the player with the highest rating followed by attribute1 and attribute4?
I hope someone can help me out! Thanks!
This query will give the record corresponding to the player with the highest rating. In the event of a tie, attribute1 and attribute4 will be used to break the tie, in that order.
SELECT *
FROM players_db
ORDER BY rating DESC, attribute1 DESC, attribute4 DESC
LIMIT 1
Use LIMIT , So that first it will sort the records by rating, then it will select the first row from top AS used LIMIT 1:
$sql = "SELECT * FROM `players_db` WHERE `id` = $player[0] OR `id` = $player[1] OR `id` = $player[2] OR `id` = $player[3] OR `id` = $player[4] OR `id` = $player[5] OR `id` = $player[6] OR `id` = $player[7] OR `id` = $player[8] OR `id` = $player[9] OR `id` = $player[10] OR `id` = $player[11] ORDER BY `rating` DESC , `attribute1` DESC, `attribute4` DESC LIMIT 1";
$result = $conn->query($sql);
while ($row = mysqli_fetch_assoc($result)) {
echo $row['rating'];
echo '<br>';
}
I want order my activityComboHtml alphabetically. Any help would be appreciated.
static function GetInnerContent()
{
$activityComboHtml=Page::getActivityTitles();
$ageComboHtml=Page::getAgeComboHtml();
$displayBanner="";
$bannerUrl=Page::fetchAllOrganizaitonBanners();
$staticBanner= HelpingDBMethods::getStaticBanner();
if($bannerUrl=="-1")
{
$displayBanner="style='display:none'";
}
return
Here is the static function
static function getActivityTitles(){
$html="";
$Query="Select uniqueId, name from tbl_activity_type_general where NOT(uniqueId = '12')";
$result= mysql_query($Query);
if($result)
{
while($row= mysql_fetch_assoc($result))
{
$html=$html."<option id='".$row['uniqueId']."' value='".$row['uniqueId']."'>".$row['name']."</option>";
}
}
Change your SQL query to
SELECT `uniqueId`, `name`
FROM `tbl_activity_type_general`
WHERE NOT( `uniqueId` = '12' )
ORDER BY `name` ASC
So, the statement becomes:
$Query="SELECT `uniqueId`, `name` FROM `tbl_activity_type_general` WHERE NOT( `uniqueId` = '12' ) ORDER BY `name` ASC";
I'm trying to use the result of one query as part of a WHERE in a second query. I'm not sure how to best approach this, any assistance is greatly appreciated:
First Query:
$result = mysql_query("SELECT `keyword` FROM `history` ORDER BY `last_update` ASC LIMIT 1 ");
while($row = mysql_fetch_array($result))
$keyword = $row['keyword'];
Second Query
$result = mysql_query("SELECT `id` FROM `data_store` WHERE `keyword`= [result from my first query] ORDER BY `id` DESC LIMIT 1");
while($row = mysql_fetch_array($result))
$id = $row['id'];
For clarification, keyword.data_store relates to keyword.history
Use subquery
$result = mysql_query("
SELECT `id`
FROM `data_store`
WHERE `keyword` = (SELECT `keyword`
FROM `history`
ORDER BY `last_update` ASC
LIMIT 1)
ORDER BY `id` DESC");
while($row = mysql_fetch_array($result))
$id = $row['id'];
(Stripped out PHP aspects because it is irrelevant)
SELECT `id` FROM `data_store` WHERE
`keyword` IN (
SELECT `keyword` FROM `history` ORDER BY `last_update` ASC LIMIT 1
)
ORDER BY `id` DESC LIMIT 1
$result = mysql_query("SELECT `id`
FROM `data_store`
WHERE `keyword` = (
SELECT `keyword`
FROM `history`
ORDER BY `last_update` ASC
LIMIT 1 )
ORDER BY `id` DESC LIMIT 1");
$activeQuery = mysql_query("SELECT count(`status`) AS `active` FROM `assignments` WHERE `user` = $user_id AND `status` = 0");
$active = mysql_fetch_assoc($activeQuery);
$failedQuery = mysql_query("SELECT count(`status`) AS `failed` FROM `assignments` WHERE `user` = $user_id AND `status` = 1");
$failed = mysql_fetch_assoc($failedQuery);
$completedQuery = mysql_query("SELECT count(`status`) AS `completed` FROM `assignments` WHERE `user` = $user_id AND `status` = 2");
$completed = mysql_fetch_assoc($completedQuery);
There has to be a better way to do that, right? I don't know how much I need to elaborate as you can see what I'm trying to do, but is there any way to do all of that in one query? I need to be able to output the active, failed, and completed assignments, preferably in one query.
You can try something like this query
SELECT Status , COUNT(*) StatusCount
FROM assignments
WHERE Status IN (0, 1, 2)
AND User = $user_id
GROUP BY Status
Try this
$activeQuery = SELECT status, count(status) as "status count" FROM `assignments` WHERE `user` = $user_id GROUP BY `status`
edit: added group by
Instead of doing them individually you could use the following single SQL statement
SELECT count(*), `status`
FROM `assignments`
WHERE `user` = $user_id
AND `status` in (0,1,2)
GROUP BY `status`
ORDER BY `status`
The loop around the result set to extract the results.
SELECT
(SELECT COUNT(*) FROM `assignments` WHERE `user` = $user_id AND `status` = 0) AS active,
(SELECT COUNT(*) FROM `assignments` WHERE `user` = $user_id AND `status` = 1) AS failed,
(SELECT COUNT(*) FROM `assignments` WHERE `user` = $user_id AND `status` = 2) AS completed,
FROM `assignments`
GROUP BY active, failed, completed
Haven't checked the markup, but this is near or near enough.
Use the GROUP BY to get it in one query, but on separate rows.
$query = mysql_query("SELECT `status`, count(*) AS `num` FROM `assignments` WHERE `user` = $user_id AND `status` in (0,1,2) GROUP BY `status` ORDER BY `status` ASC");
$active_count = 0;
$failed_count = 0;
$completed_count = 0;
while ($array = mysql_fetch_assoc($query))
{
if ($array['status'] == 0)
$active_count = $array['num'];
else if ($array['status'] == 1)
$failed_count = $array['num'];
else if ($array['status'] == 2)
$completed_count = $array['num'];
}
When I have the option, I'm in the habit of using prepared statement(s) to help protect against sql-injection protection and for efficiency (requires using mysqli).
But if this is not an option, then
SELECT
CASE `status`
WHEN 0 THEN `active`
WHEN 1 THEN `failed`
WHEN 2 THEN `completed`
ELSE `unknown`
END
AS `statuslabel`,
COUNT(status)
AS `statuscount`
FROM `assignments`
WHERE `user` = $escaped_user_id
GROUP BY `statuslabel`
ORDER BY `statuslabel`
Note the use of the $escaped_user_id, which would be created beforehand:
$escaped_user_id = mysql_real_escape_string($user_id);