I currently have a script that runs every 5 minutes and selects the data from a table on server 1 and an identical table on server2. This is a workaround for replication, essentially, since we don't have that option currently.
The script is successful but I've realized that it misses records sometimes, for whatever reason. The current script selects all records from the destination table, stores the max primary key, selects all data from the source table and then inserts anything with a greater Primary key into the dest. table.
I'd like to modify the script slightly and instead of using max id, just say "if a row has an primary key that doesn't exist in the destination table, insert that row there."
Again these are cloned tables so the structure is the same and they both use AI Primary Keys.
Here's the current working script:
$latest_result = $conn2->query("SELECT MAX(`SESSIONID`) FROM
`ambition`.`session`");
$latest_row = $latest_result->fetch_row();
$latest_session_id = $latest_row[0];
//Select All rows from the source phone database
$source_data = mysqli_query($conn, "SELECT * FROM
`cdrdb`.`session` WHERE `SESSIONID` > $latest_session_id");
// Loop on the results
while($source = $source_data->fetch_assoc()) {
// Check if row exists in destination phone database
$row_exists = $conn2->query("SELECT SESSIONID FROM
ambition.session WHERE SESSIONID = '".$source['SESSIONID']."' ") or
die(mysqli_error($conn2));
//if query returns false, rows don't exist with that new ID.
if ($row_exists->num_rows == 0){
//Insert new rows into ambition.session
$stmt = $conn2->prepare("INSERT INTO ambition.session (SESSIONID,
SESSIONTYPE,CALLINGPARTYNO,FINALLYCALLEDPARTYNO,
DIALPLANNAME,TERMINATIONREASONCODE //etc. There are a lot of columns so I
ommitted the others
Is there a way I can slightly modify this to just insert what doesn't exist rather than relying on the MAX ID?
Or is there something here that would be a culprit as to why it's missing records?
You could use INSERT INTO SELECT and check if value is already in target:
INSERT INTO trg_table (cols)
SELECT cols
FROM src_table s
WHERE NOT EXISTS (SELECT 1 FROM trg_table t WHERE t.id = s.id);
i have a table customer_stock_entries.. i want to insert the item if the item and supplier is not available and i want to update the item if item and supplier is available
Example in my table i have stock_supplier_name and quantity. What i want to do is that if the stock supplier name entry is new then insert it into the table and if the entry is already there then delete the previous value in column 'quantity' and insert the new value.
i am stuck with this. Please help me out
I have tried something like this.
for ($i = 0; $i < count($stock_name); $i++) {
$count = $db->countOf("customer_stock", "name='$stock_name[$i]'");
if ($count == 0) {
$db->query("insert into customer_stock(name,quantity) values('$stock_name[$i]',$quty[$i])");
echo "<br><font color=green size=+1 >New Stock Entry Inserted !</font>";
$db->query("insert into stock_details(stock_id,stock_name,stock_quatity,supplier_id,company_price,selling_price) values('$autoid','$stock_name[$i]',0,'$supplier','$cost[$i]','$sell[$i]')");
$db->query("INSERT INTO customer_stock_entries(stock_id,stock_name, stock_supplier_name, quantity, company_price, selling_price, opening_stock, closing_stock, date, username, type, total, payment, balance, mode, description, due, subtotal,count1,billnumber) VALUES ( '$autoid1','$stock_name[$i]','$supplier','$quty[$i]','$cost[$i]','$sell[$i]',0,'$quty[$i]','$date','$username','entry','$total[$i]','$payment','$balance','$mode','$description','$due','$subtotal',$i+1,'$bill_no')");
} else if ($count == 1) {
$amount = $db->queryUniqueValue("SELECT quantity FROM customer_stock WHERE name='$stock_name[$i]'");
$amount1 = $amount + $quty[$i];
$db->execute("UPDATE customer_stock SET quantity='$amount' WHERE name='$stock_name[$i]'");
$db->query("INSERT INTO customer_stock_entries(stock_id,stock_name,stock_supplier_name,quantity,company_price,selling_price,opening_stock,closing_stock,date,username,type,total,payment,balance,mode,description,due,subtotal,count1,billnumber) VALUES ('$autoid1','$stock_name[$i]','$supplier','$quty[$i]','$cost[$i]','$sell[$i]','$amount','$amount1','$date','$username','entry','$total[$i]','$payment','$balance','$mode','$description','$due','$subtotal',$i+1,'$bill_no')");
Thanks
Typical solution to this problem involve following typical steps:
Check if the record for the stock supplier exists by using a select query and if it exists, update the quantity attribute.
If the the record doesn't exist, then insert the record in the table.
Sample Code as requested:
IF EXISTS(SELECT * FROM Users WHERE UserId = #UserId)
BEGIN
UPDATE TC_Users SET Salary = 25000 WHERE UserId = #UserId
END
ELSE
BEGIN
INSERT INTO TC_Users(UserId, Salary) VALUES(#UserId, 25000)
END
Hope this helps you.
Hare are some information's regarding your problem:
Primary Keys (To Avoid Duplication Of Data) :
Always use primary keys in your Database Table Structure i.e consider one column as primary key in order for it to be unique so that duplicate value won't be able to be inserted in your records.
Example : For instance I have a table with following columns as id,username,password,name .Now in order for to avoid duplication of data i.e that I don't want people to register with same username which means that username column value should be unique so instead I mark my username column as Primary Key.So now the new upcoming members won't be able to register with the same username which is already available in database i.e someone already registered using that username.Instead they will be needed to register with unique username.
Solution :
While here is code for to update your quantity value if supplier is already present in the database and if not so then insert the new record..!
$supplier_name = $_POST['supplier];
$query = mysqli_query($mysqli,"SELECT * FROM table");
$results = mysqli_fetch_array($query);
for ($i=0;$i<=count($results);$i++) {
//IF supplier is available in database
if ($results[$i]['supplier'] == $supplier_name) {
$query = mysqli_query($mysqli,"UPDATE table SET quantity=$quanity_new_value WHERE supplier=$supplier_name");
} else {
// If supplier is not available in database so it will insert new record
$query = mysqli_query($mysqli,"INSERT INTO table (supplier, quanity, email) VALUES ($supplier_name, $quantity, $email)");
}
}
I have the following two tables
Table player:
player_id (int)(primary)
player_name (varchar)
player_report_count (int)
Table report:
report_id (int)(primary)
player_id
report_description
report_location
Firstly I ask the user for the player_name and insert it into the player database. From here the player is given an id.
Then I tried to grab the value of the players report count and increment the current value by one (which isn't working).
This is followed by grabbing the playerId from the player table and then inserting into the corresponding column from the report table (also does not work).
When I insert some values into the database, the names, description and report are added to the database however the playerID remains at 0 for all entries and the player_report_count remains at a consistent 0.
What is the correct way to make these two features function? And also is there a more efficient way of doing this?
<?php
$records = array();
if(!empty($_POST)){
if(isset($_POST['player_name'],
$_POST['report_description'],
$_POST['report_location'])){
$player_name = trim($_POST['player_name']);
$report_description = trim($_POST['report_description']);
$report_location = trim($_POST['report_location']);
if(!empty($player_name) && !empty($report_description) && !empty($report_location)){
$insertPlayer = $db->prepare("
INSERT INTO player (player_name)
VALUES (?)
");
$insertPlayer->bind_param('s', $player_name);
$reportCount = $db->query("
UPDATE player
SET player_report_count = player_report_count + 1
WHERE
player_name = $player_name
");
$getPlayerId = $db->query("
SELECT player_id
FROM player
WHERE player_name = $player_name
");
$insertReport = $db->prepare("
INSERT INTO report (player_id, report_description, report_location)
VALUES (?, ?, ?)
");
$insertReport->bind_param('iss', $getPlayerId, $report_description, $report_location);
if($insertPlayer->execute()
&& $insertReport->execute()
){
header('Location: insert.php');
die();
}
}
}
Main issue here is you are getting player details before inserting it. $getPlayerId will return empty result always.
Please follow the order as follows.
Insert player details in to player table and get payerid with mysql_insert_id. After binding you need to execute to insert details to the table.
Then bind and execute insert report .
Then update the player table by incrementing report count with playerid which you got in step 1.
Note : use transactions when inserting multiple table. This will help you to rollback if any insert fails.
MySQL Query will return result object. Refer it from here https://stackoverflow.com/a/13791544/3045153
I hope it will help you
If you need to catch the ID of the last insterted player, This is the function you need if you're using PDO or if it's a custom Mysql Class, you need the return value of mysql_insert_id() (or mysqli_insert_id()) and then directly use it in the next INSERT INTO statement
Im creating a website for booking activities. I have 3 centres. The customer is cant book the same activity twice neither in a different centre. Im using a table in mysql which i store the infos provided by the costumers. Is there any way to filter or to check in my php code if a customer has already booked the same activity more than one time and echo an error msg?
my table(and the info im asking) contains these columns:
ID(Primary)
FirstName
LastName
Email
ContactNumber
ClassName
Week
Intensity
CentreName
$values = $_POST;
foreach ($values as &$value) {
$value = mysql_real_escape_string($value);
}
$sql1="INSERT INTO loan (loan_id)
VALUES ('$values[loan_id]')";
$result = mysql_query($sql1);
if (!$result) {
die('Invalid query: ' . mysql_error());
}
When you create the table add the unique attribute to the fields you want to prevent, something like this
CREATE TABLE Persons
(
P_Id INT NOT NULL AUTO_INCREMENT,
LastName VARCHAR(255) NOT NULL,
FirstName VARCHAR(255),
Address VARCHAR(255),
City VARCHAR(255),
UNIQUE (P_Id)
)
If you already have created the table just edit it like this
ALTER TABLE Persons
ADD UNIQUE (P_Id)
Hope this helps you; If you do not have a unique id i believe this will suit you best on what you need; Note that this is not the full code; You need to add some to other information to fit in your question;
// Checks if the value already exist on the database
$query = SELECT EXISTS(SELECT column_name FROM table_name WHERE
condition LIMIT 1)
// If condition is not met it will proceed with save
if (mysql_num_rows(!$query) > 0) {
echo "Activity Booked";
} else { // If condition is met it will echo an error message
echo "Unable to booked activity"; }
You need to create a unique (composite) index on the column(s) that you wish to be unique. You can disregard your PK when making your unique index. In your case your sql would look something like:
Alter table yourtablename
add unique index idx_unq(`LastName`, `FirstName`, `Email`, `ContactNumber` `ClassName`, `Week`, `Intensity`, `CentreName`);
Then do an INSERT IGNORE INTO instead of an INSERT INTO.
This post may also help you.
"INSERT INTO .. ON DUPLICATE KEY UPDATE" Only inserts new entries rather than replace?
In order to see if record already exist in table you must first "test" to see if that exact record exist in your table. This is to be done before the 'Insert IGNORE Into' in your logic. Using the variables your code would look something like this:
$testcount = "Select count(`LastName`, `FirstName`, `Email`, `ContactNumber` `ClassName`, `Week`, `Intensity`, `CentreName`)
from yourtablename
where
(LastName = '$LastName' AND FirstName= '$FirstName' AND Email= '$EMAIL' AND ContactNumber= '$ContactNumber' AND ClassName= '$ClassName' AND Week= '$Week' Intensity = '$Intensity' AND CentreName = '$CentreName' )";
This query will give you back (assuming there are no duplicates already in the table) a 0 or a 1 and store it in your $testcount variable. This can then be used to either determine based on the value to insert the record into the table or print a message to end user informing them that it already exist.
I am not sure how you want to structure the php code but the psuedocode would look something like:
If $testcount = 1 then do your insert.
else if $testcount = 0 then echo your message.
I'm pulling data from a calendar feed and each event in the calendar has a unique $EventID string. I'm using PHP.
I have a SQL database with an Event_ID column. These IDs are strings. I need to be able to compare my $EventID against the Event_ID column and put in in the database if it's not there.
I have a primary key set up to auto increment in the database, and I was thinking I can set up a loop to increment through those and compare each to the $EventID, but I'm wondering if there is a better way-maybe a PHP function I don't know about?
I've got a whole lot of code, but basically I've got:
<?php
$EventID = $event->id; //This is the event ID
mysql_query("INSERT INTO myTable
(Event_ID, Date_added, Date_edited)
VALUES
('$EventID', '$dateAdded', '$lastEdited')");
?>
So how do I set up a conditional to check all the Event_IDs that are already in the database against the $EventID?
$query = "SELECT * FROM `myTable` WHERE `Event_ID`='$EventID' ";
$result = mysql_query($query);
if (!mysql_num_rows($result))
// INSERT QUERY
Check if the Event ID is present, If not insert it
You could just skip the "Select" query and do an "INSERT IGNORE" instead:
mysql_query("INSERT IGNORE INTO myTable
(Event_ID, Date_added, Date_edited)
VALUES
('$EventID', '$dateAdded', '$lastEdited')");
this will leave existing Event_id's, and just add new records if required.