There are a lot of free tools out there to convert from UTM to Lat/Long. Fine enough, but I need to go the other way; from WGS-84 to lat/long-format.
But it's more complicated than that; 'couse I need the result to be in UTM-33 (nordic) zone.
This might sound like a bad idea; why would I like to "force" the zone to 33N, when the geographical point might be laying in another zone ...
Well; the thing is that I already have a database with UTM33-coordinates of every address in Norway.
Those of you that are familiar with UTM # Northern Europe, knows that Norway spans across several zones; from 31 to 36.
(Okay, maybe we only spans from 32 to 36, cause of the strange width of zone 32V, but thats another discussion).
So, back to my problem: all my addresses are already given in UTM-33 format (with negative values when out of range). How can i proceed to get my Lat/Long into UTM-33?
I need a solution in PHP, and after a lot of debugging with "gPoint", I found out it just won't work ...
(gPoint is great to convert from/to UTM, but it will always return the UTM x/y-pair in the "correct" zone block. I don't want that! I need to always get results in zone 33, regardless of what is actual correct..)
I finally found a solution though Proj4 (thanx SlightlyCuban)!
// Conversion from WGS84 to UTM33
$proj4 = new Proj4php();
$projWGS84 = new Proj4phpProj('EPSG:4326');
$projUTM33N = new Proj4phpProj('EPSG:2078');
$result = $proj4->transform($projWGS84, $projUTM33N, new proj4phpPoint($long, $lat));
It is impossible to guess correct format for transformation, and I was struggling for a while ... then I discovered a really handy webpage: http://spatialreference.org. Here I found the definition I needed (EPSG:2078 = "+proj=utm +zone=33 +ellps=intl +units=m +no_defs")
The PHP-implementation of Proj4 needs hard-coded definitions; you cannot pass by a definition ad-hoc. EPSG:2078 was originally missing from Proj4php. Yay; lucky me!
I would therefor recommend to test Proj4 via Node.js and proj4js (see my little demo at http://pastebin.com/1BP8cWpj).
To succeed, I had to fork the Proj4PHP-library, and add a definition file for EPSG:2078 ...
In a project I am building I would like to use markdown as follows
*text* = <em>text</em>
**text** = <strong>text</strong>
***text*** = <strong><em>text</em><strong>
As those are the only three markdown formats I require, I would like to remain lightweight and avoid importing the entire PHP markdown library as that would introduce features I do not require and create issues.
So I have been trying to build some simple regex replaces. Using preg_replace I run:
'/(\*\*\*)(.*?)\1/' to '<strong><em>\2</em></strong>'
'/(\*\*)(.*?)\1/' to '<strong>\2</strong>'
'/(\*)(.*?)\1/' to '<em>\2</em>',
And this works great! em, bold, and the combo all work fine...
But if the user makes a mistake or enters to many stars, everything breaks.
i.e.
****hello**** = <strong><em><em>hello</em></strong></em>
*****hello***** = <strong><em><strong>hello</em></strong></strong>
******hello****** = <strong><em></em></strong>hello<strong><em></em></strong>
etc
When ideally it would create
****hello**** = *<strong><em>hello</em></strong>*
*****hello***** = **<strong><em>hello</em></strong>**
******hello****** = ***<strong><em>hello</em></strong>***
etc
Ignoring the un-required stars (so it would become clear to the user they made a mistake, and more importantly, the rendered HTML remains valid).
I presume there must be some way to modify my regex to do this but I cannot for the life of my work it out, even after a whole day trying!
I would also be happy with the result of
******hello****** = <strong><em>hello</em></strong>
So please, can anybody help me?
Also please consider uneven stars. In this case the below scenario would be ideal.
***hello* = **<em>hello</em>
And the time when a star should be part of the body and not detected, such as if a user inputs:
'terms and conditions may apply*'
or
'I give the film 5* out of 10'
Many many thanks
Try different capturing pattern (match anything except * one or more times),
'/(\*\*\*)([^*]+)\1/'
I have tried several regexes and still some valid postal codes sometimes get rejected.
Searching the internet, Wikipedia and SO, I could only find regex validation solutions.
Is there a validation method which does not use regex? In any language, I guess it would be easy to port.
I supose the easiest would be to compare against a postal code database, yet that would need to be maintained and updated periodically from a reliable source.
Edit: To help future visitors and keep you from posting any more regexes, here's a regex which I have tested (as of 2013-04-24) to work for all postal codes in Code Point (see #Mikkel Løkke's answer):
//PHP PCRE (it was on Wikipedia, it isn't there anymore; I might have modified it, don't remember).
$strPostalCode=preg_replace("/[\s]/", "", $strPostalCode);
$bValid=preg_match("/^(GIR 0AA)|(((A[BL]|B[ABDHLNRSTX]?|C[ABFHMORTVW]|D[ADEGHLNTY]|E[HNX]?|F[KY]|G[LUY]?|H[ADGPRSUX]|I[GMPV]|JE|K[ATWY]|L[ADELNSU]?|M[EKL]?|N[EGNPRW]?|O[LX]|P[AEHLOR]|R[GHM]|S[AEGKLMNOPRSTY]?|T[ADFNQRSW]|UB|W[ADFNRSV]|YO|ZE)[1-9]?[0-9]|((E|N|NW|SE|SW|W)1|EC[1-4]|WC[12])[A-HJKMNPR-Y]|(SW|W)([2-9]|[1-9][0-9])|EC[1-9][0-9])[0-9][ABD-HJLNP-UW-Z]{2})$/i", $strPostalCode);
I'm writing this answer based on the wiki page.
When checking on the validation part, it seems that there are 6 type of formats (A = letter and 9 = digit):
AA9A 9AA AA9A9AA AA9A9AA
A9A 9AA Removing space A9A9AA order it AA999AA
A9 9AA ------------------> A99AA -------------> AA99AA
A99 9AA A999AA A9A9AA
AA9 9AA AA99AA A999AA
AA99 9AA AA999AA A99AA
As we can see, the length may vary from 5 to 7 and we have to take in account some special cases if we want to.
So the function we are coding has to do the following:
Remove spaces and convert to uppercase (or lower case).
Check if the input is an exception, if it is it should return valid
Check if the input's length is 4 < length < 8.
Check if it's a valid postcode.
The last part is tricky, but we will split it in 3 sections by length for some overview:
Length = 7: AA9A9AA and AA999AA
Length = 6: AA99AA, A9A9AA and A999AA
Length = 5: A99AA
For this we will be using a switch(). From now on it's just a matter of checking character by character if it's a letter or a number on the right place.
So let's take a look at our PHP implementation:
function check_uk_postcode($string){
// Start config
$valid_return_value = 'valid';
$invalid_return_value = 'invalid';
$exceptions = array('BS981TL', 'BX11LT', 'BX21LB', 'BX32BB', 'BX55AT', 'CF101BH', 'CF991NA', 'DE993GG', 'DH981BT', 'DH991NS', 'E161XL', 'E202AQ', 'E202BB', 'E202ST', 'E203BS', 'E203EL', 'E203ET', 'E203HB', 'E203HY', 'E981SN', 'E981ST', 'E981TT', 'EC2N2DB', 'EC4Y0HQ', 'EH991SP', 'G581SB', 'GIR0AA', 'IV212LR', 'L304GB', 'LS981FD', 'N19GU', 'N811ER', 'NG801EH', 'NG801LH', 'NG801RH', 'NG801TH', 'SE18UJ', 'SN381NW', 'SW1A0AA', 'SW1A0PW', 'SW1A1AA', 'SW1A2AA', 'SW1P3EU', 'SW1W0DT', 'TW89GS', 'W1A1AA', 'W1D4FA', 'W1N4DJ');
// Add Overseas territories ?
array_push($exceptions, 'AI-2640', 'ASCN1ZZ', 'STHL1ZZ', 'TDCU1ZZ', 'BBND1ZZ', 'BIQQ1ZZ', 'FIQQ1ZZ', 'GX111AA', 'PCRN1ZZ', 'SIQQ1ZZ', 'TKCA1ZZ');
// End config
$string = strtoupper(preg_replace('/\s/', '', $string)); // Remove the spaces and convert to uppercase.
$exceptions = array_flip($exceptions);
if(isset($exceptions[$string])){return $valid_return_value;} // Check for valid exception
$length = strlen($string);
if($length < 5 || $length > 7){return $invalid_return_value;} // Check for invalid length
$letters = array_flip(range('A', 'Z')); // An array of letters as keys
$numbers = array_flip(range(0, 9)); // An array of numbers as keys
switch($length){
case 7:
if(!isset($letters[$string[0]], $letters[$string[1]], $numbers[$string[2]], $numbers[$string[4]], $letters[$string[5]], $letters[$string[6]])){break;}
if(isset($letters[$string[3]]) || isset($numbers[$string[3]])){
return $valid_return_value;
}
break;
case 6:
if(!isset($letters[$string[0]], $numbers[$string[3]], $letters[$string[4]], $letters[$string[5]])){break;}
if(isset($letters[$string[1]], $numbers[$string[2]]) || isset($numbers[$string[1]], $letters[$string[2]]) || isset($numbers[$string[1]], $numbers[$string[2]])){
return $valid_return_value;
}
break;
case 5:
if(isset($letters[$string[0]], $numbers[$string[1]], $numbers[$string[2]], $letters[$string[3]], $letters[$string[4]])){
return $valid_return_value;
}
break;
}
return $invalid_return_value;
}
Note that I've not added British Forces Post Office and non-geographic codes.
Usage:
echo check_uk_postcode('AE3A 6AR').'<br>'; // valid
echo check_uk_postcode('Z9 9BA').'<br>'; // valid
echo check_uk_postcode('AE3A6AR').'<br>'; // valid
echo check_uk_postcode('EE34 6FR').'<br>'; // valid
echo check_uk_postcode('A23A 7AR').'<br>'; // invalid
echo check_uk_postcode('A23A 7AR').'<br>'; // invalid
echo check_uk_postcode('WA3334E').'<br>'; // invalid
echo check_uk_postcode('A2 AAR').'<br>'; // invalid
As supplied by the UK government.
(GIR 0AA)|((([A-Z-[QVX]][0-9][0-9]?)|(([A-Z-[QVX]][A-Z-[IJZ]][0-9][0-9]?)|(([A-Z-[QVX]][0-9][A-HJKSTUW])|([A-Z-[QVX]][A-Z-[IJZ]][0-9][ABEHMNPRVWXY])))) [0-9][A-Z-[CIKMOV]]{2})
I've built London only postcode based apps using the postcodes I got from HERE. But to be honest, even with London postcodes only, you need a lot more storage than necessary. Sure, the idea is trivial.
Store the postcodes, take the user input or whatever, and see if you get a match. But you are complicating the solution far more than you think. I HAD to use actual postcodes to achieve what I wanted, but for simple validation purposes, as hard as "maintaining" a regex is, storing tens of thousands or hundreds of thousands(if not more) and validating more or less in real-time is a far more difficult task.
If a mini distributed service sounds like a more efficient solution than a regex, go for it, but I'm sure it isn't. Unless you need geo-spatial querying of your own data against UK postcodes or things like that, I doubt DB storage is a feasible solution. Just my 2 cents.
Update
According to this index, there are 1,758,417 postcodes in the UK. I can tell you I am using a few Mongo clusters (Amazon EC2 High Memory Instances) to provide reliable London only services(indexing only London postcodes), and it's quite a pricy thing, even with basic storage.
Admittedly, the app is performing medium complexity geo-spatial queries, but the storage requirements alone are very expensive and demanding.
Bottom line, just stick to regex and be done with it in two minutes.
Im looking at the Postcodes in United Kingdom link in wikipedia right now.
http://en.wikipedia.org/wiki/Postcodes_in_the_United_Kingdom
The Validation section lists six formats with a combination of letters and numbers. Then there's more information in the notes below that. The first thing that I would try is a BNF type grammar with a tool like GoldParserBuilder. You could describe the basic formats in a more readable format, with efficient parser and lexer automatically generated. In the past, I've successfully used such tools to avoid writing huge, ugly regexes.
From that point, the program has a properly formatted zip code of a known type. At this point, the specific numbers or letters might violate something. Each type of zip code can have a function programmed to look for violations of that specific type. The final product will consist of an automatically generated parser that passes unvalidated, but structured/identified, zip codes to a dedicated validation function. You can then refactor or optimize from there.
(You can also use the grammar itself to enforce or disallow certain literals and combinations. Whatever is more readable or comprehensible for you. Different people gravitate toward different ends of these things.)
Here's a page highlighting advantages of GOLD Parsing System.You can use any you like: I just promote this one b/c it's good at its job and has steadily improved over many years.
http://www.goldparser.org/about/why-use-gold.htm
I would think the RegEX, while long-winded would probably be the best solution if all you want to do is validate if something could be a valid UK post code.
If you need absolute data, consider using Ordnance Survey OpenData initiative "Code-Point® Open" dataset, which is a CSV of lots of data points in Great Britain (so not Northern Ireland I'm guessing) one of which is postcode. Be aware that the file is 20MB, so you may have to convert it to a more manageable format.
Regexes are hard to debug, hard to port from one regex flavor to another (silent "errors"), and hard to update.
That is true for most regexes, but why don't you just split it up into multiple parts? You can easily split it into six parts for the six different general rules and maybe even more if you take all of the special cases into account.
Creating a well-commented method of 20 lines with simple regexes is easy to debug (one simple regex per line) and also easy to update. The porting problem is the same, but on the other hand you do not need to use some fancy grammar lib.
Are third party services an option?
http://www.postcodeanywhere.co.uk/address-validation/
GeoNames Database:
http://www.geonames.org/postal-codes/
+1 for the "why care" comments. I have had to use the 'official' regex in various projects and while I have never attempted to break it down, it works and it does the job. I've used it with Java and PHP code without any need to convert it between regex formats.
Is there a reason why you would have to debug it or break it down?
Incidentally, the regex rule used to be found on wikipedia, but it appears to have gone.
Edit: As for the space/no-space debate, the postcode should be valid with or without the space. As the last part of the postcode (after the space) is ALWAYS three digits, it is possible to insert the space manually, which will then allow you to run it through the regex rule.
Take the list of valid postcodes and check if the one entered is in it.
Let's say I want to display the following text to the user:
"John's car"
I'm using gettext to output it:
sprintf(_("%s's car"), $firstName)
The obvious problem is that, if the first name of the user ends in an S, we'll get something like this:
"James's car" (should be "James' car")
How do I solve that problem, especially considering that other languages might pose a similar challenge (different genitives depending on word ending or similar)?
Simply put: write a function with an explicit if to get the genitive form for a name, and print that instead. I'd provide an example but you haven't indicated what language we're talking about!