php issue with date_diff - php

Question

I'm trying to figure out the number of months between two dates, the dates hypothetically lets say are between 2018-08-27 and 2018-10-10. What i want is a function based on those dates to return a difference of 3 months, 08,09,10. I have the following function, but it only seems to output 1 month;
public function getGraphMonthsCount(){
$now = '2018-08-27';
$then = '2018-10-10';
$newNow = new DateTime($now);
$newThen = new DateTime($then);
$result = $newNow->diff($newThen)->m;
return $result;
}
this return a value of 1.
this is what the diff function outputs without the ->m param
object(DateInterval)#157 (15) {
["y"]=>
int(0)
["m"]=>
int(1)
["d"]=>
int(13)
["h"]=>
int(0)
["i"]=>
int(0)
["s"]=>
int(0)
["weekday"]=>
int(0)
["weekday_behavior"]=>
int(0)
["first_last_day_of"]=>
int(0)
["invert"]=>
int(0)
["days"]=>
int(44)
["special_type"]=>
int(0)
["special_amount"]=>
int(0)
["have_weekday_relative"]=>
int(0)
["have_special_relative"]=>
int(0)
}
I don't know why it's providing only 13 'd' and 1 'm', but if you look further into the obj you can see it does have the correct amount of 'days'
Is there a better way of doing this?

Answer 1

What i want is a function based on those dates to return a difference of 3 months
You can try something like this:
$newNow = new DateTime($now);
$newNow = $newNow->modify('first day of this month');
$newThen = new DateTime($then);
$newThen = $newThen->modify('first day of next month');
$result = $newNow->diff($newThen)->m;
Test results:
$now = '2018-08-27';
$then = '2018-10-10';
// 3
$now = '2018-08-10';
$then = '2018-08-27';
// 1