Want to get just two object in json - php

Question

I am trying to make a code verifier with the following code. I've looked at the answers in StackOverflow but couldn't get the right result.
The code is working fine but I want to echo just two value.
validate.php page code is here:
if(isset($apKey) && isset($code)) {
$en = new En();
$Key = $apKey;
$Codes = $code;
if($Key == null || $Codes == null) {
echo json_encode(['data' => 'No Key or code found, Please try again']);
exit;
}
$response = $en->validate($Key,$Codes);
$result = json_decode($response);
$elements = json_encode(['data' => $result]);
echo $elements;
exit;
}
echo json_encode(['data' => 'No Key or code found, Please try again']);
exit;
Now I am trying to check this validate page results using this code:
$siteurl = urlencode($_SERVER['SERVER_NAME']);
$arrContextOptions = array(
"ssl" => array(
"verify_peer" => false,
"verify_peer_name" => false
)
);
$file = file_get_contents('http://www.validates.com/validate.php?code=' . $check , false, stream_context_create($arrContextOptions));
$checks = json_decode($file, true);
$elements = $checks['data'];
echo print_r($elements);
So the results something like this:
Array
(
[buyer] => abcd
)
So what I want to do. I want to echo just buyer and error message after this code: $checks = json_decode($file, true);
The error result is here:
{"data":{"error":404,"description":"No sale belonging to the current user found with that code"}}
Like for example:
if(buyer){echo 'true';}
if(error message){echo 'error';}

Answer 1

I guess you can check with array_key_exists if there is error. You can do something like this:
$checks = json_decode($file, true);
$data = $checks['data'];
if (array_key_exists("error", $data))
echo $data["description"];
else
echo $data["buyer"];