SQL how to get all images to show for respective units - php

Question

My question is how to get multiple images to display next to their respective units information. I am able to print out all the images below but unable to get each listing to print out its respective images. originally i was trying to do it as a single query but it was only printing out the same image multiple times so i tried to do two seperate queries but it did not work, how can i fix it?
// Define the query but only for info:
$querystats = 'SELECT 8052monticello.UNIT, 8052monticello.SIZE, 8052monticello.id, 8052monticello.PRICE';
$querystats.= ' FROM 8052monticello';
if ($r = mysqli_query($connection, $querystats)) { // Run the query.
// Retrieve and print every record:
while ($row = mysqli_fetch_assoc($r)) {
if ($row['PRICE']){
// echo "<img src='images/".$row['image_name']."' width='100'>";
print "<p><h3>{$row['UNIT']} Unit #</h3>
{$row['SIZE']} Sq Feet<br>
{$row['PRICE']} Monthly rent<br>
Edit
Delete
</p><hr>\n";
}
}
}
//get the images
$queryimage = 'SELECT photos.image_name, photos.fk_unit, 8052monticello.UNIT';
$queryimage.= ' FROM photos, 8052monticello';
$queryimage.= ' WHERE photos.fk_unit= 8052monticello.unit';
if ($r = mysqli_query($connection, $queryimage)) { // Run the query.
// Retrieve and print every record:
while ($row = mysqli_fetch_assoc($r)) {
if ($row['image_name']){
echo "<img src='images/".$row['image_name']."' width='100'>";
}
}
}

Answer 1

You can use a JOIN in your query to join both the monticello and photos table:
$query = '
SELECT
m.UNIT, m.SIZE, m.id, m.PRICE,
p.image_name
FROM 8052monticello m
INNER JOIN photos p ON p.fk_unit = m.unit';
Now you have access to $row['image_name'] in your loop.
while ($row = mysqli_fetch_assoc($r)) {
if ($row['PRICE']){
print "<img src=\"images/{$row['image_name']}\" width='100'>
<p><h3>{$row['UNIT']} Unit #</h3>
{$row['SIZE']} Sq Feet<br>
{$row['PRICE']} Monthly rent<br>
Edit
Delete
</p><hr>\n";
}
}
Updated: For each row, images are fetched from the database.
$query = "SELECT
m.UNIT, m.SIZE, m.id, m.PRICE
FROM 8052monticello m ";
$res = mysqli_query($connection, $query);
if (!$res){
// throw error here
}
$query2 = "SELECT p.image_name
FROM photos p
WHERE p.fk_unit = '%s' ";
while ($row = mysqli_fetch_assoc($res)) {
$res2 = mysqli_query($connection, sprintf($query2, $row["UNIT"]));
while($img = mysqli_fetch_assoc($res2)) {
echo "<img src=\"images/{$img['image_name']}\" width='100'>";
}
print "<p><h3>{$row['UNIT']} Unit #</h3>
{$row['SIZE']} Sq Feet<br>
{$row['PRICE']} Monthly rent<br>
Edit
Delete
</p><hr>\n";
}