I have an account on Gator.
I am trying to run a php script as follows
;$command = escapeshellcmd('./simple.py 2>&1');
$output = shell_exec($command);
echo $output
I would like to get as output anything that the python script prints to screen, but the output is empty no matter what I try (I use standard print in python
Use my method as a reference.
I have this two files
run.php
mkdir.py
Here, I've created a html page which contains GO button. Whenever you press this button a new folder will be created in directory whose path you have mentioned.
run.php
<html>
<body>
<head>
<title>
run
</title>
</head>
<form method="post">
<input type="submit" value="GO" name="GO">
</form>
</body>
</html>
<?php
if(isset($_POST['GO']))
{
shell_exec("python /var/www/html/lab/mkdir.py");
echo"success";
}
?>
mkdir.py
#!/usr/bin/env python
import os
os.makedirs("thisfolder");
$command = escapeshellcmd('./simple.py 2>&1');
escapeshellcmd is a form of surrender, it's php stupidity, it gets used as a DWIM band-aid when the programmer has lost control of the command-line.
It's breaking your stderr redirection.
Use escapeshellarg where you need to escape shell stuff.
$command = escapeshellarg('./simple.py') . ' ' . '2>&1';
Related
I'm setting up a Apache 2, PHP 7, Python 3.6.3 on my Raspberry pi (Ubuntu)
I want execute Python script using PHP.
I've tried execute below code, but it does not work.
This is my body tag.
con_LED.php:
<body>
<form method="post">
<button name="LightON" value="on">LightON</button>
</form>
<form method="post">
<button name="LightOFF" value="off">LightOFF</button>
</form>
<p></p>
<?php
if (isset($_POST["LightON"])) {
exec("python3 /var/www/html/LEDON.py", $output, $var);
print_r($output."<br>");
print_r($var);
}
if (isset($_POST["LightOFF"])) {
exec("python3 /var/www/html/LEDOFF.py");
print_r($output);
print_r($var);
}
?>
</body>
I did some some troubleshooting.
To check, I replace my code to:
exec("ls -al", $output, $var)
Which works.
I also made:
a.py:
with open("t1.txt","a") as f:
f.write("Heelo\n")
And executed:
exec("python3 /var/www/html/a.py", $output, $var);
This also works (meaning I can see t1.txt file on my server).
My project is using con_LED.php code to turn the LED on and off.
But my code isn't working.
Of course, I also tried this code directly on shell, which is working.
Does anyone know what my problem is?
I'm new to php and html (internet languages in general) and I would like to execute a python script that takes a picture from my php page.
I did some research, edited some code (according to my understanding) and came up with this, but it doens't do anything.
<!DOCTYPE html>
<html>
<head>
<title>Test</title>
</head>
<body>
<form action="" method="post">
<button type="submit" name="sub" value="call">Click</button>
</form>
</body>
</html>
<?php
if(isset($_POST['sub']))
{
exec('sudo python take_picture.py');
echo "Picture captured";
}
?>
I managed to execute the python script from a html page invoking a simple php script separately, but when it takes the picture it sends me to a new page (blank page with the text displayed) which I don't want. Here are the codes:
HTML button:
<form action="take_picture.php" method="post">
<button>Click</button>
</form>
PHP script:
<?php
exec('sudo python take_picture.py');
?>
What I need is to simply press the "click" button and take the picture without sending me to anywhere else.
Could you please guys aid me to achieve what I need and explain with apples what I was doing wrong or what I missed.
Thank you in advance!
You can make an :
<?php
$command = escapeshellcmd('/usr/custom/test.py');
$output = shell_exec($command);
echo $output;
?>
More information on this Stack Overflow Question.
Running a Python script from PHP
I am building an HTML document that is meant to run locally. On it is a button that I would like to have run a Python script when clicked. I'm trying to use a PHP-generated button. There's no input or output that I want to associate with the button; I just want it to run the script, which produces charts as image files that the rest of the page uses. I have tried a couple different ways to do it, including putting the PHP part in the HTML document, before the HTML:
<?php
if (isset($_POST['update']))
{
exec('python myScript.py');
}
>
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<form name="update" method="post" >
<button name = "update" type="submit"> Update charts </button>
</form>
</body>
I've also tried making the PHP code its own .php document in the same directory and calling it from the HTML code as so:
<form action = "updateCharts.php" method="post">
<input type="submit" name="update" />
</form>
where updateCharts.php is:
<?php
system('cd C:\My\Script\Path');
system('python MyScript.py');
?>
I've also tried substituting "system" with "exec" but to no avail. In the first part, I click the button and nothing happens. In the second, I click the button and I am taken to the text of the PHP document. In neither case does my Python script run!
Does anyone see what I'm missing? I'm admittedly a novice with php so it may be something glaring. Thanks for the help!
What this:
$command = escapeshellcmd('python /My/Script/Path/myscript.py');
// or
// $command = escapeshellcmd('/My/Script/Path/test.py');
// But you have to make your script executable doing: chmod +x myscript.py
$output = shell_exec($command);
echo $output;
This can not work.
<?php
system('cd C:\My\Script\Path');
system('python MyScript.py');
?>
You can not have a "session" over multiple system calls. Every system call has its own shell environment.
At least on Linux systems you can cascade commands by semicolons. If you need a work directory to be set before script execution, you could either do
system('cd C:\My\Script\Path ; MyScript.py');
or
chdir('C:\My\Script\Path');
system('MyScript.py');
However, script execution from PHP can be blocked, or apache might not have appropriate file permissions to the script, or, or, or.
You need to check log files and also post what actually is output.
I am trying to integrate matlab with php. So i need to use php to call a matlab function. I am passing file path as argument to the matlab function using exec(). I tried lot of things but couldn't make it work. This is my simple code of php to call function phpcreatefile() in matlab.
<html>
<body>
<form action="" method="post">
Enter a filename <input type="text" name="filepath"><br />
<input type="submit" /><br />
</form>
</body>
</html>
<?php
if(isset($_POST['filepath'])) {
$filename = $_POST['filepath'];
$inputDir = "C:\\matlab_2015\\bin";
$outputDir = "C:\\xampp\\htdocs\\software";
//echo $outputDir;
$command = "matlab -sd ".$inputDir." -r phpcreatefile('".$outputDir."\\".$filename."')";
exec($command);
echo "The following command was run: ".$command."<br/>";
echo $filename." was created in ".$outputDir."<br/>";
}
?>
P.S : I have already switched the safe mode to off by making safe_mode_exec_dir=Off in php.ini and restarted the xampp.
I tried the command in cmd manually and it works properly.
I have some basic knowledge of HTML/PHP. The situation I am facing is frustrating. What I want to accomplish is to create a simple search box on a web page, when the user puts in input and clicks submit then my shell script is executed and then presented on a php page. I have been successful in getting other commands to run when I click submit to make sure the PHP exec shell command is working.
I will see the output on the web page. Just not my script. My script uses an argument to pass and works thru command line. Below is the details of my script, HTML, and PHP page. Also, I'm using a FreeBSD 10 box.
My Script
Command Line -
$ csearch "argument"
#!/bin/sh
grep -ir -B 1 -A 4 "$*" /usr/local/var/rancid/CiscoDevices/configs
My HTML page
<html>
<body>
<form method="POST" action="csearch.php">
<input type="text" name="searchText">
<input type="submit" value="Search">
</form>
</body>
</html>
My PHP page
<?php
$searchText=$_POST['$searchText'];
?>
<html>
<?php
$output = shell_exec('/usr/local/bin/csearch $searchText');
echo "<pre>$output</pre>";
?>
</html>
Any help is greatly appreciated.
shell_exec('/usr/local/bin/csearch $searchText'); This isn't what you expect it to be:
<?php
$searchText = 'foobar';
$cmd = '/usr/local/bin/csearch $searchText';
echo $cmd;
?>
outputs:
/usr/local/bin/csearch $searchText
Change the string to use double quotes and $searchText will actually be what you want to it be:
$output = shell_exec("/usr/local/bin/csearch $searchText");
More info on the use of quotes in PHP.
As #uri2x hints in a comment:
$searchText=$_POST['$searchText']; should be changed to $searchText=$_POST['searchText']; for a similar reason.