Explode and Set if condition php - php

Question

Array ( [0] => 1 [1] => 2 )
I'm trying to set an if condition based on user permission, the idea is to show menu based on given values, if it is 1, one menu will be displayed and 2 second menu will be displayed, if its both then all values will be displayed. So far for single values i have gotten it right but how to do it for array of values
This is my code
<?php
$userid = $this->phpsession->get("user_id");
$userrole = $this->phpsession->get("user_type");
$query = $this->db->select("role_empid,role_permissions")->from('hw_role')->where('role_empid', $userid)->get()->result();
$data = $query[0]->role_permissions;
if($data == 1){
?>
<li>Add Enquiry</li>
<li>Enquiry List</li>
<?php }else if($data == 2){ ?>
<li>Request For Proposal</li>
<?php } ?>
</ul>

Answer 1

if role_permission contain json object that first convert it into the array like
$data = $query[0]->role_permissions;
$data=json_decode($data);
otherwise direct check the condition for
$data = $query[0]->role_permissions;
if(in_array(1,$data) && in_array(2,$data))
{
}
else if(in_array(1,$data))
{
}
else if(in_array(2,$data))
{
}

Answer 2

If $query[0]->role_permissions is an array that has distinct value, then you can try :
<ul>
<?php for($i = 0; $i<count($data);$i++) {
if($data[$i] == 1){ ?>
<li>Add Enquiry</li>
<li>Enquiry List</li>
<?php }
if($data[$i] == 2){ ?>
<li>Request For Proposal</li>
<?php }} ?>
</ul>

Answer 3

Try This
<?php
if(in_array(1,$data)){
?>
<li>Add Enquiry</li>
<li>Enquiry List</li>
<?php }
if(in_array(2,$data)){
?>
<li>Request For Proposal</li>
<?php } ?>