Basically my task is,through the mandatory use of _GET,I'm supposed to make a code that fetches a specific php file when someone types in something like ..php?page=airlines and I dunno if I'm just lacking information or what but this isn't working router.php:
<?php
$nav =array("home"=>"C:\xampp\htdocs\project\home.php",
"flight"=>"C:xampp\htdocs\project\flight-detail.php",
"order"=>"C:xampp\htdocs\project\order-flight.php,",
"testimonial"=>"C:xampp\htdocs\project\add-testimonial.php");
if ( isset($nav[$_GET['page']]) )
{
echo header('Location: ' . $nav[$_GET['page']]);
}
if i understood your question, there are many ways to reach your goal.
I write an example that no change very your code:
<?php
$myPath="C:\xampp\htdocs\project\";
$nav =array("home"=>"home.php",
"flight"=>"flight-detail.php",
"order"=>"order-flight.php,",
"testimonial"=>"add-testimonial.php");
if ( isset($_GET['page']) and !empty($_GET['page']))
{
$myFile=nav[$_GET['page']];//i assume that in page there are only array keys value
echo header('Location: ' . myPath.$myFile);//i.e. I suppose in page there is home output is: "C:\xampp\htdocs\project\home.php"; file
}
else
{
echo 'error: page not found!';
}
An other "easy" solution is to create in first page the link where the user can choose the page:
<a href="C:\xampp\htdocs\project\home.php">HOME<a>
<a href="C:\xampp\htdocs\project\flight-detail.php">FLIGHT DETAIL<a>
....
Hope this helps
Related
Currently when i showing my username(through session) and logout function , both of them is in different lines
Image: http://prntscr.com/nc2v1b ( This is output )
What i want : https://prnt.sc/nc2w23
Username is on the right side of "Logout"
First of all, remove this part style='float:right;'
Using float:right will move the text right.
Second, need some spacing here:
echo $_SESSION["username"]." "; // you can use `|` to separation
echo '<span>Logout</span></li>';
Float right will push everything to the right (last item being the one the the most on the right).
Your code seem to work if you need to have everything on one line though.
<?php
session_start(); // Right at the top of your script
?>
<li class='active'>
<?php
if($_SESSION['logged']==true)
{
echo '<span>Logout</span>' . $_SESSION["username"];
}
else
{
echo '<span>Login/Register</span>';
}
echo '</li>';
?>
I'm a front-end developer who is somewhat familiar with but rarely uses PHP. I'm working on a personal project where I'm mostly just using includes to link PHP files together. Here is my overall basic page structure:
<?php include('header.php'); ?>
<?php include('pagetitle.php'); ?>
Page content goes here.
<?php include('footer.php'); ?>
On pagetitle.php, I have an <h1>,<h2> and background image relating to which page you're on.
My question is, how do I use conditional statements to put all the page titles/subheadings on pagetitle.php and have them switch depending on what page you're on? So for example, I want
<div id="about">
<h1>About</h1>
<h2>About page subheading</h2>
</div>
to show up on about.php, and
<div id="contact">
<h1>Contact Me</h1>
<h2>Contact page subheading</h2>
</div>
to show up on contact.php, etc. etc. ...but only using pagetitle.php on those pages.
The site isn't huge. It would have no more than 10 pages. Also, I do realize I can just use that page title segment on the respective page, but if possible, I want to try this out.
Thanks!
I would do something like this (not tested, but should work with few, if any, changes.)
(Everyone says that, right? :D):
<?php
/*
create a map that contains the information for each page.
the name of each page maps to an array containing the
(div id, heading 1, & subheading for that page).
*/
$pageinfo = array(
"about.php" => array ("about", "About", "About Page Subheading"),
"contact.php" => array ("contact", "Contact Me", "Contact Page Subheading"),
);
function printinfo($pagename) {
/*
This function will print the info for the current page.
*/
global $pageinfo;
$pagename = basename($pagename);
#make sure we have info for this page
if (!array_key_exists($pagename, $pageinfo) {
echo "<p><b>You did not supply info for page $pagename</b></p>";
return;
}
#we do have info ... continue
$info = $pageinfo[$pagename];
#let's print the div (with its custom id),
echo "<div id='" . $info[0] . "'>\n";
#print the headings
echo "<h1>" . $info[1] . "</h1>\n";
echo "<h2>" . $info[2] . "</h2>\n";
#close the div
echo "</div>\n";
}
?>
Then in each page where you wanted your div, you would place this code:
printinfo($_SERVER['PHP_SELF']);
Other:
This way is more flexible than the other ways, at the sacrifice of no conditional statements. (You specifically requested a solution that had conditional statements; however, in the interest of flexibility & maintainability, this example does not use switch statements or if statements.)
Because there are no conditional statements, there is less code to maintain. Granted, you have to setup the array with the information, but if you decided to change the <h2> to an <h3>, you would have to make the change at only one location, etc.
On your pagetitle.php you could do something like this
<?php
$scriptname = basename($_SERVER["PHP_SELF"]);
if ($scriptname == "about.php") {
echo "<h1>About Page</h1>";
}else if($scriptname == "contact.php"){
echo "<h1>Contact Us</h1>";
}
?>
You have to get the string after the domain name so you can use $_SERVER['REQUEST_URI']
$page = $_SERVER['REQUEST_URI'];
if ($page == "about.php") {
echo "<h1>About</h1>"."<br />";
echo "<h2>About page subheading</h2>"."<br />";
}else if($page == "contact.php"){
echo "<h1>Contact Me</h1>"."<br />";
echo "<h2>Contact page subheading</h2>"."<br />";
}
$page = $_SERVER['REQUEST_URI'];
switch($page){
case 'about.php':
echo "<h1>About</h1>";
echo "<h2>About page subheading</h2>";
break;
case 'contact.php':
echo "<h1>Contact Me</h1>";
echo "<h2>Contact page subheading</h2>";
break;
default:
echo "Invalid Request";
}
I have a page with a menu on for logged in users
i am including this page on all the other pages in my site but i don't want users that are NOT logged in to be able to click the links
How can I disable all the links on that page if a PHP variable = 'no'
i know i can use
if($php_var == 'no') {
//do something here
}
but I'm not sure how to disable the links?
Is there any way using CSS or Javascript to disable links?
try this
if($php_var == "no")
{
echo 'Your Text For Link';
}
else
{
echo 'Your Text For Link';
}
user javascript:void(0); for no redirection. this will maintain your css for link like others but when you click it won't redirect.
If i understood everything correctly, the answer is quite simple. Why dont you just replace the links with plain strings?
if($php_var === "no") {
echo "This is the text of your link.";
} else
{
echo "This is the text of your link.";
}
But as already mentioned, completely hiding the links is better, as usual users gets confused by such things.
this will remove all href from a tags. If php var is no. Put this code after all a tags else won't work
<?php
if($php_var === "no"){
echo '<script>var x=document.getElementsByTagName("a");for (i=0;i<x.length;i++){x[i].removeAttribute("href");}</script>';
}
?>
You would need to do the processing pre-output, PHP will not dynamically disable the href of an already created DOM element.
If you are producing the output of the links via PHP, you could do something like:
echo 'Link';
Otherwise, you could create an AJAX call to the PHP script, and if it returns 'no', iterate through your pages links and disable the links via JavaScript.
<a href='<?php echo ($php_var == "no") ? "javascript:void(0)" : "link.php" ?>'>
Hello user
</a>
you could do this:
// define if you want to make links work
$linking = true;
Then your link:
<a <?php if($linking == true) { ?> href="..." <?php } ?>>Link</a>
If links are not shown, I'd also add some CSS:
.link_that_is_no_link {
text-decoration: none;
cursor: default
}
How do you check if the user is logged in or not? Do you use sessions? The same way you check for the user if he is logged in you can decide to show items or not.
You can do both:
if(isset($_SESSION['id'])){
echo 'LINK';
}else{
echo 'LINK';
}
that will keep showing the link but will lead nowhere if the user is not logged in.
Or you can do :
if(isset($_SESSION['id'])){
echo 'LINK';
}else{
//do nothing here or put a link to the login page
}
that will show the link only if you are logged in.
I prefer the second option since I think that no users will like to see a link without being able to open it.
Note that code in this answer is just a guess of your real code
You can use PHP if-else condition and write HTML like this:
<a href="" onclick="return false;">
Still learning php as I go so this might just be something I haven't gotten to yet but it's the next roadblock in building my personal site. I have a basic understanding of includes such as linking:
<a href="art.php?id=image id&name=This is my title&menu=side-menu-portfolio">
to pull my includes but I've come to a small problem in that my generic art-gallery page needs to switch between a 'portfolio' header and an 'artwork' header. So I figured I could either build "art-gallery.php" AND "port-gallery.php" and go back and relink everything or just make it so that when you call the link like the above code I just specify which header goes with it. Unfortunately this would also require going back and changing every link. But I noticed that I did state:
...&menu=side-menu-portfolio...
and the pages are already calling side-menu-artwork or side-menu-portfolio so if I could just call in menu and cast aside the 'side-menu-" portion then it would just use artwork or portfolio and call the right header. Unfortunately this is where my limited knowledge of php and syntax come in. I have tried to produce the following code based on my php and js understanding:
<?php include("headlines/headline-" . $_GET[menu - "side-menu-" ] . ".php"); ?>
but I don't know if my syntax is just wrong or if what I'm trying to do is impossible to begin with. Note that when I try this I get
Function Include error of "Warning: include(headlines/headline-.php)"
so it looks like everything else is reading correctly, I just don't know if or how I can extract the word I want from the rest of the menu name.
Should be, Assumed your included file name is headline-side-menu-portfolio.php
<?php
$filename = str_replace("side-menu-", "", $_GET['menu']); // headline-portfolio
include("headlines/headline-" . $filename . ".php"); // headline-portfolio.php
?>
Something like this :
<?php include("headlines/headline-" . $_GET["menu"].".php"); ?>
<!--gives include("headlines/headline-side-menu-portfolio.php")-->
where
$_GET["menu"] = 'side-menu-portfolio'
Try this:
<?php include("headlines/headline-" . $_GET['menu'] . ".php"); ?>
Your code is wrong.
Instead of
<?php include("headlines/headline-" . $_GET[menu - "side-menu-" ] . ".php"); ?>
try
<?php include("headlines/headline-" . $_GET['menu'] . ".php"); ?>
You should check if the file exists before you try including it.
if (file_exists($filesrc)) { ... }
Better yet don't let the user change the menu through a $_GET variable. Instead link to a specific page or pass a variable then decide what menu to get. Like
switch ($_GET['menu']) {
case 'side-menu':
include("headlines/headline-side-menu.php");
break;
}
Just use
$_GET['menu']
, the "side-menu-" part is already in the content of your variable passed as param.
You propably want to do an if .... else so to include one header or another based on the $_GET variable menu.
So something like this will do this:
if($_GET['menu'] == 'side-menu-portfolio') {
include 'headliens/side-menu-portfolio.php';
} elseif($_GET['menu'] == 'side-menu-other') {
include 'headliens/side-menu-other.php';
}
okay....your are almost there....just quotes missing from include syntax...it should be
include("headlines/headline-.php"); /* notice the quotes*/
so it should be
<?php include("headlines/headline-" .$_GET['menu'].".php"); ?>
where $_GET['menu'] should be in the url, like:
art.php?id=image id&name=This-is-my-title&menu=side-menu-portfolio
so what's happening her ??
Upon execution of the line :
<?php include("headlines/headline-" .$_GET['menu'].".php"); ?>
$_GET is fetched from the url and replaced in the header tag, so now the header tag becomes :
<?php include("headlines/headline-"."side-menu-portfolio".".php"); ?> => <?php include("headlines/headline-side-menu-portfolio.php"); ?>
Also. may i suggest that for :
<a href="art.php?id=image id&name=This is my title&menu=side-menu-portfolio">
don't use space in the url, either replace it by - or _
I have a page with two links (text link & banner link),
that should lead to the same redirect page
(on my domain).
The redirect would be to a link that shall include a variable,
that indicates which of the two link was clicked.
e.g.:
<?php
header("Location: http://external-domain.com/?ref=[value]");
die();
?>
wheareas the "value" should be "text" / "banner" or something similar.
How can I do this?
I'm not a web programmer at all so I don't have much technical knowledge,
I guess one possible solution (which I would rather avoid) would be to give a separate id for the text link and for the banner, e.g.:
text link:
http://mydomain.com/redirect.php?id=text
banner link:
http://mydomain.com/redirect.php?id=banner
whereas redirect.php would contain:
<?php
$source = $_GET['id']
?>
<?php
header("Location: http://external-domain.com/?ref=<?php print $source; ?>");
die();
?>
But that would mean that I have to use a different id for these internal links;
I would rather find a way to use the same exact internal links (maybe for example, have each link in a "div" or a "class" and get the div/class name somehow, and have them appear as the [value].
*EDIT:
Let me emphasize again: I'm looking for a way to do this without having to use any "?id=[something]" at the end of the text link or the banner link.
Thanks!
If you're already outputting the banner/text do this for the banner
<img src="imageHere.png">
And this for the text
text here
Then catch the id get values with
<?php
$id = $_GET['id'];
if ($id == 'banner'){
echo 'The clicked link was a banner';
}
else{
echo 'The clicked link was text';
}
<?php
$source = $_GET['id']
?>
<?php
header("Location: http://external-domain.com/?ref=<?php print $source; ?>");
die();
?>
should be
<?php
$source = $_GET['id'];
header("Location: http://external-domain.com/?ref=".$source);
die();
?>
Basic concatenation.