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I have these for loop to determine consecutive number. What I achieve so far is to print the output in string.
$arr = [1,2,3,6,11,5,4,8,9,3];
for($start=0; $start<=count($arr); $start++){
for($end=$start+1; $end<=count($arr); $end++){
$total = $arr[$end] - $arr[$start];
if($total == 1){
echo 'Number is '.$arr[$start].','.$arr[$end].'<br/>';
} else {
echo '';
}
$arr[$start++];
}
}
My goal is to add the output into array.
I tried to use multidimensional array but no output display.
$arr = [1,2,3,6,11,5,4,8,9,3];
$arr3 = [];
for($start=0; $start<=count($arr); $start++){
for($end=$start+1; $end<=count($arr); $end++){
$total = $arr[$end] - $arr[$start];
if($total == 1){
$arr2 = array();
$arr2[] = $arr[$start].','.$arr[$end].'';
$arr3[] = $arr2;
} else {
}
$arr[$start++];
}
}
echo '<pre>';
print_r($arr3);
echo '</pre>';
exit;
Appreciate if someone can help me. Thanks.
you can simply use array functions, if sorting is important to you as #nice_dev said, you must sort your array before.
$arr = [1,2,3,6,11,5,4,8,9,3];
$cons = [] ;
while (array_key_last($arr) != key($arr)) {
if ((current($arr)+1) == next($arr)) {
prev($arr);
$cons[] = current($arr) . ',' . next($arr);
}
}
print_r($cons);
the output will be :
Array
(
[0] => 1,2
[1] => 2,3
[2] => 8,9
)
You can better sort() the input array first. This way, collecting all consecutive elements would get much simpler. If value at any index isn't +1 of the previous one, we add the $temp in our $results array and start a new $temp from this index.
Snippet:
<?php
$arr = [1,2,3,6,11,5,4,8,9,3];
$result = [];
sort($arr);
$temp = [];
for($i = 0; $i < count($arr); ++$i){
if($i > 0 && $arr[ $i ] !== $arr[$i - 1] + 1){
$result[] = implode(",", $temp);
$temp = [];
}
$temp[] = $arr[$i];
if($i === count($arr) - 1) $result[] = implode(",", $temp);
}
print_r($result);
Online Demo
I have 2 arrays as follows:
$arr = array('one.jpg', 'two.jpg', 'three.jpg');
$arr1 = array('', 'five.jpg', '');
Now I want to make these two arrays to one array with following value:
$newArray = array('one.jpg', 'five.jpg', 'three.jpg');
How can I do this using PHP?
Use array_filter to remove the empty values.
Use array_replace to replace the values from the first array with the remaining values of the 2nd array.
$arr1=array_filter($arr1);
var_dump(array_replace($arr,$arr1));
Assuming you want to overwrite entries in the first array only with truthy values from the second:
$newArray = array_map(function ($a, $b) { return $b ?: $a; }, $arr, $arr1);
You can iterate through array and check value for second array :
$arr = array('one.jpg', 'two.jpg', 'three.jpg');
$arr1 = array('', 'five.jpg', '');
$newArray =array();
foreach ($arr as $key => $value) {
if(isset($arr1[$key]) && $arr1[$key] != "")
$newArray[$key] = $arr1[$key];
else
$newArray[$key] = $value;
}
var_dump($newArray);
Simple solution using a for loop, not sure whether there is a more elegant one:
$arr = array('one.jpg', 'two.jpg', 'three.jpg');
$arr1 = array('', 'five.jpg', '');
$newArray = array();
$size = count($arr);
for($i = 0; $i < $size; ++$i) {
if(!empty($arr1[$i])){
$newArray[$i] = $arr1[$i];
} else {
$newArray[$i] = $arr[$i];
}
}
I have this array:
$array = array(a, b, c, d, e, f, g);
I want to split it in two arrays depending if the index is even or odd, like this:
$odd = array(a, c, e, g);
$even = array(b, d, f);
Thanks in advance!
One solution, using anonymous functions and array_walk:
$odd = array();
$even = array();
$both = array(&$even, &$odd);
array_walk($array, function($v, $k) use ($both) { $both[$k % 2][] = $v; });
This separates the items in just one pass over the array, but it's a bit on the "cleverish" side. It's not really any better than the classic, more verbose
$odd = array();
$even = array();
foreach ($array as $k => $v) {
if ($k % 2 == 0) {
$even[] = $v;
}
else {
$odd[] = $v;
}
}
Use array_filter (PHP >= 5.6):
$odd = array_filter($array, function ($input) {return $input & 1;}, ARRAY_FILTER_USE_KEY);
$even = array_filter($array, function ($input) {return !($input & 1);}, ARRAY_FILTER_USE_KEY);
I am not sure if this is the most elegant way, but it should work a charm:
$odd=array();
$even=array();
$count=1;
foreach($array as $val)
{
if($count%2==1)
{
$odd[]=$val;
}
else
{
$even[]=$val;
}
$count++;
}
As an almost-one-liner, I think this will be my favourite:
$even = $odd = array();
foreach( $array as $k => $v ) $k % 2 ? $odd[] = $v : $even[] = $v;
Or for a tiny little more? speed:
$even = $odd = array();
foreach( $array as $k => $v ) ( $k & 1 ) === 0 ? $even[] = $v : $odd[] = $v;
A bit more verbose variant:
$both = array( array(), array() );
// or, if $array has at least two elements:
$both = array();
foreach( $array as $k => $v ) $both[ $k % 2 ][] = $v;
list( $even, $odd ) = $both;
With array_chunk:
$even = $odd = array();
foreach( array_chunk( $array, 2 ) as $chunk ){
list( $even[], $odd[] ) = isset( $chunk[1]) ? $chunk : $chunk + array( null, null );
// or, to force even and odd arrays to have the same count:
list( $even[], $odd[] ) = $chunk + array( null, null );
}
If $array is guaranteed to have even number of elements:
$even = $odd = array();
foreach( array_chunk( $array, 2 ) as $chunk )
list( $even[], $odd[] ) = $chunk;
PHP 5.5.0+ with array_column:
$chunks = array_chunk( $array, 2 );
$even = array_column( $chunks, 0 );
$odd = array_column( $chunks, 1 );
Something similar for older PHP versions.
The keys will be 0,2,4,… and 1,3,5,…. If you don't like this, apply an array_values too:
$even = array_intersect_key( $array, array_flip( range( 0, count( $array ), 2 )));
$odd = array_intersect_key( $array, array_flip( range( 1, count( $array ), 2 )));
or
$even = array_intersect_key( $array, array_fill_keys( range( 0, count( $array ), 2 ), null ));
$odd = array_intersect_key( $array, array_fill_keys( range( 1, count( $array ), 2 ), null ));
One more functional solution with array_chunk and array_map. The last line removes empty item from the 2nd array, when size of a source array is odd
list($odd, $even) = array_map(null, ...array_chunk($ar,2));
if(count($ar) % 2) array_pop($even);
Just loop though them and check if the key is even or odd:
$odd = array();
$even = array();
foreach( $array as $key => $value ) {
if( 0 === $key%2) { //Even
$even[] = $value;
}
else {
$odd[] = $value;
}
}
One
$odd = $even = array();
for ($i = 0, $l = count($array ); $i < $l;) { // Notice how we increment $i each time we use it below, by two in total
$even[] = $array[$i++];
if($i < $l)
{
$odd[] = $array[$i++];
}
}
Two
$odd = $even = array();
foreach (array_chunk($array , 2) as $chunk) {
$even[] = $chunk[0];
if(!empty( $chunk[1]))
{
$odd[] = $chunk[1];
}
}
Based on #Jon's second variant, I made this following for use with PHP Smarty v3 template engine. This is for displaying news/blog with both one or two columns template model.
After the MySql query I'll do the following code :
if(sizeof($results) > 0) {
$data = array();
foreach($results as $k => $res) {
if($k % 2 == 0) {
$res["class"] = "even";
$data["all"][] = $data["even"][] = $res;
}
else {
$res["class"] = "odd";
$data["all"][] = $data["odd"][] = $res;
}
}
}
I obtain an array of 3 sub-arrays (including odd/even class) with Smarty syntax of use :
all items {foreach $data.all as $article}...{/foreach}
odd items only {foreach $data.odd as $article}...{/foreach}
even items only {foreach $data.even as $article}...{/foreach}
Hope it helps some people...
$odd = [];
$even = [];
while (count($arr)) {
$odd[] = array_shift($arr);
$even[] = array_shift($arr);
}
<?php
$array1 = array(0,1,2,3,4,5,6,7,8,9);
$oddarray = array();
$evenarray = array();
$count = 1;
echo "Original: ";
foreach ($array1 as $value)
{
echo "$value";
}
echo "<br> Even: ";
foreach ($array1 as $print)
{
if ($count%2==1)
{
$evenarray = $print;
echo "$print";
}
$count++;
}
echo "<br> Odd: ";
foreach ($array1 as $print2) {
if ($count%2!=1)
{
$oddarray[] = $print2;
echo "$print2";
}
$count++;
}
?>
Output:
Original: 0123456789
Even: 02468
Odd: 13579
array one: 1,3,5,7
array two: 2,4,6,8
the array i want would be 1,2,3,4,5,6,7,8
I'm just using numbers as examples. If it was just numbers i could merge and sort but they will be words. So maybe something like
array one: bob,a,awesome
array two: is,really,dude
should read: bob is a really awesome dude
Not really sure how to do this. Does PHP have something like this built in?
You could write yourself a function like this:
function array_merge_alternating($array1, $array2) {
if(count($array1) != count($array2)) {
return false; // Arrays must be the same length
}
$mergedArray = array();
while(count($array1) > 0) {
$mergedArray[] = array_shift($array1);
$mergedArray[] = array_shift($array2);
}
return $mergedArray;
}
This function expects two arrays with equal length and merges their values.
If you don't need your values in alternating order you can use array_merge. array_merge will append the second array to the first and will not do what you ask.
Try this elegant solution
function array_alternate($array1, $array2)
{
$result = Array();
array_map(function($item1, $item2) use (&$result)
{
$result[] = $item1;
$result[] = $item2;
}, $array1, $array2);
return $result;
}
This solution works AND it doesn't matter if both arrays are different sizes/lengths:
function array_merge_alternating($array1, $array2)
{
$mergedArray = array();
while( count($array1) > 0 || count($array2) > 0 )
{
if ( count($array1) > 0 )
$mergedArray[] = array_shift($array1);
if ( count($array2) > 0 )
$mergedArray[] = array_shift($array2);
}
return $mergedArray;
}
Try this function:
function arrayMergeX()
{
$arrays = func_get_args();
$arrayCount = count($arrays);
if ( $arrayCount < 0 )
throw new ErrorException('No arguments passed!');
$resArr = array();
$maxLength = count($arrays[0]);
for ( $i=0; $i<$maxLength; $i+=($arrayCount-1) )
{
for ($j=0; $j<$arrayCount; $j++)
{
$resArr[] = $arrays[$j][$i];
}
}
return $resArr;
}
var_dump( arrayMergeX(array(1,3,5,7), array(2,4,6,8)) );
var_dump( arrayMergeX(array('You', 'very'), array('are', 'intelligent.')) );
var_dump( arrayMergeX() );
It works with variable numbers of arrays!
Live on codepad.org: http://codepad.org/c6ZuldEO
if arrays contains numeric values only, you can use merge and sort the array.
<?php
$a = array(1,3,5,7);
$b = array(2,4,6,8);
$merged_array = array_merge($a,$b);
sort($merged,SORT_ASC);
?>
else use this solution.
<?php
function my_merge($array1,$array2)
{
$newarray = array();
foreach($array1 as $key => $val)
{
$newarray[] = $val;
if(count($array2) > 0)
$newarray[] = array_shift($array2)
}
return $newarray;
}
?>
hope this help
Expects both arrays to have the same length:
$result = array();
foreach ($array1 as $i => $elem) {
array_push($result, $elem, $array2[$i]);
}
echo join(' ', $result);
I have an array like the following:
array('category_name:', 'c1', 'types:', 't1')
I want the alternate values of an array to be the values of an array:
array('category_name:' => 'c1', 'types:' => 't1')
You could try: (untested)
$data = Array("category_name:","c1","types:","t1"); //your data goes here
for($i=0, $output = Array(), $max=sizeof($data); $i<$max; $i+=2) {
$key = $data[$i];
$value = $data[$i+1];
$output[$key] = $value;
}
Alternatively: (untested)
$output = Array();
foreach($data as $key => $value):
if($key % 2 > 0) { //every second item
$index = $data[$key-1];
$output[$index] = $value;
}
endforeach;
function fold($a) {
return $a
? array(array_shift($a) => array_shift($a))
+ fold($a)
: array();
}
print_r(fold(range('a','p' )));
~)
upd: a real-life version
function fold2($a) {
$r = array();
for($n = 1; $n < count($a); $n += 2)
$r[$a[$n - 1]] = $a[$n];
return $r;
}
Here is another yet complex solution:
$keys = array_intersect_key($arr, array_flip(range(0, count($arr)-1, 2)));
$values = array_intersect_key($arr, array_flip(range(1, count($arr)-1, 2)));
$arr = array_combine($keys, $values);
$array = your array;
$newArray['category_name:'] = $array[1];
$newArray['types:'] = $array[3];