I am using $hidden and $appends to hide pivot keyword from json array and pull the objects into main array. In the game model I added below script to do functionality as I said above
protected $hidden = ['pivot'];
protected $appends = ['user_id','highscore', 'level'];
public function getUserIdAttribute()
{
return $this->pivot->user_id;
}
public function getHighScoreAttribute()
{
return $this->pivot->highscore;
}
public function getLevelAttribute()
{
return $this->pivot->level;
}
Now the problem is that I want to fetch all games and I know it is so simple I just added into controller below script
$Games = Game::all();
return new GameResource($Games); /* GameResource is for API */
But the this one is return following error after adding above script into model.
ErrorException: Trying to get property user_id of non-object
Anyone can guide me please how to manage both of functionality because I need both of. I would appreciate if someone kindly guide.
After #emix Comment
#emix it is not duplicated because the reference is about core php and I am using laravel. Off course laravel is built with php but still there is complicated structure so I think this one is not same as you refered
The pivot is only available when you're fetching the models through the many-to-many relationship (BelongsToMany). The pivot represents the fields on the pivot table (eg. games_users) and thus fields that exist for that specific relationship.
When you're just pulling directly from the Game model (aka. games table), you have no relationship or pivot table to pull data from.
Related
i'm using laravel 7.30, I have a post model linked to user model with belongsTo relationship, I want to retrieve all posts with user property that contains only the name of the user for api purposes.
what i've tried so far.
public function index()
{
return Post::with('user:id,name')->get();
}
but the result of this code is a nested object 'user' which has 2 fields id and name on each post, I only want a single field with posts fields called user which has the name only and not a nested object for api purposes.
I've made it using database query builder, but i'm looking for a way using Eloquent
Thanks in advance
You can add this to your Post Model:
protected $appends = [
"author_name"
];
public function getAuthorNameAttribute()
{
return $this->user->name;
}
This will make sure the user's name is appended to the Post object every time it is being called.
Then from your controller, you can easily do this:
public function index()
{
return Post::get();
}
I'm trying to create a connection between a JSON field in my database and a table which stores music by ID. So, I have a table called "playlists" which has a field called "songs". In this "songs" field I have a array[] of song ID's e.g. [1,2]. I tried the following code to make a relationship between these two tables:
class Playlist extends Model
{
protected $table = 'playlists';
public function songs()
{
return $this->hasMany('App\Music', 'id');
}
}
I used the foreign_key id because of the songs table which has a id field.
The code I used to retrieve the playlist from the controller is as follows:
$playlist = Playlist::find($id)->songs;
print_r($playlist);
Which outputs:
[1,2]
I most probably did something wrong, not understanding the relationships correctly. Could someone explain how this works? I looked up the documentation but did not get any wiser.
Laravel has no native support for JSON relationships.
I created a package for this: https://github.com/staudenmeir/eloquent-json-relations
If you rename the songs column to song_ids, you can define a many-to-many relationship like this:
class Playlist extends Model
{
use \Staudenmeir\EloquentJsonRelations\HasJsonRelationships;
protected $casts = [
'song_ids' => 'json',
];
public function songs()
{
return $this->belongsToJson('App\Music', 'song_ids');
}
}
class Music extends Model
{
use \Staudenmeir\EloquentJsonRelations\HasJsonRelationships;
public function playlists()
{
return $this->hasManyJson('App\Playlist', 'song_ids');
}
}
Although this is a very old post but I will go ahead and drop my own opinion for my future self and fellow googlers.....
So, If I got this question correctly, you are trying to use a JSON field for a relationship query. This issue I have stumbled across a couple of times, at different occasions for different use-cases. With the most recent being for the purpose of saving a couple of Ids belonging to different tables, in a single JSON field on a given table (While I keep pondering on why the Laravel guy won't just add this functionality already! I Know Pivots, Data Normalization etc....But I'm pleading for the 1%). Until I came across this post on Laracast that worked like a charm.
Apologies for the long intro, let me get right into it....
On your Playlist model (in Laravel 8.0 and a few older versions I can't really keep track of) you can do something like so;
public function songs()
{
$related = $this->hasMany(Song::class);
$related->setQuery(
Song::whereIn('id', $this->song_ids)->getQuery()
);
return $related;
}
I have the really good solution for keeping data in column on json format. It help me on previous project online shop
https://scotch.io/tutorials/working-with-json-in-mysql
How to implement information and information_description tables in laravel Eloquent Model ? Some how it need to set language, because a title should be a one record.
$information = App\Information::find(1);
$information->title
tables structure
You can review how to do this, and plenty more, by reading the documents by Laravel. They are a great help and this particular question has an example and everything. Having said that, I'll help with getting you started.
Define a relationship in either model, information or information_description, or both. For brevity, I'll use information only.
Pass the foreign_key and local_key in the hasMany() relationship since it differs from Laravel's default behavior.
So we have a model that now looks like:
class Information extends Model
{
/**
* Get the descriptions for the Information model.
* Note the 2nd and 3rd arguments in the method
* which define foreign_key and local_key.
*/
public function description()
{
return $this->hasMany('App\InformationDescription', 'information_id', 'information_id');
}
}
Now that you have the relationship defined, you can perform your query.
// Get the description for the information
$information = App\Information::find(1)->description;
// Iterate over the results
foreach ($information as $description) {
$description->title;
}
The table naming convention used is a little odd, but if I understand it correctly, this will work. Hope it helps.
I am trying to figure out a relationship but I can't seem to solve the issue.
So what my script does first is checking if there is a valid session where status = 0.
Then I want to check if there is a valid trial where status = 0 ->first() associated with that session. And if so, I want to grab all the relevant data related by trial_id.
I understand what logic is required. However, I am wondering if there is a method to do this with as little commands as possible using Eloquent relationships.
Specifically, once i have the $session object. How can I filter the trials, in order to get the appropriate stimuli_tracker data?
The important components to the relationships for the table is as follows:
Sessions
id (has one to many relationship to trials(sessions_id)
user_id (foreign key)
status
Trials
id (one to many relationship with stimuli_tracker)
sessions_id (foreign key)
status
Stimuli_Tracker
trials_id (foreign key)
stimulus
stimulus_type
Sessions Model
class Sessions extends Model
{
protected $table = 'sessions';
public function stimuliTracker()
{
return $this->hasManyThrough('App\StimuliTracker', 'App\Trials', 'sessions_id','trials_id');
}
}
Trials Model:
class Trials extends Model
{
public function stimuli()
{
return $this->hasMany(App\StimuliTracker);
}
}
EDIT
I have tried in artisan tinker to
$object = \App\Session::where(arg);
then I tried to
$object->stimulus
but didn't work. I tried a few other fields but I only received null. Maybe I'm not getting how to grab the content properly
$object->stimulus is an undefined attribute based on what you've shown in your code.
To access the stimulus information for your session, you have to use the name of the relationship, which in this case is:
$object->stimuliTracker
The thing is that this will return an Eloquent Collection because it is a hasManyThrough relationship (which is a hasMany of a hasMany).
I'm assuming that the 'stimulus' attribute belongs to the StimuliTracker class. If this is the case, then you will need to loop through your StimuliTracker Collection to extract it:
foreach ( $object->stimuliTracker as $record )
{
$stimulus = $record->stimulus;
// do something with $stimulus
}
EDIT (Added):
If you are just looking for an array of the values in the 'stimulus' attribute, you can get that with the lists() method:
$stimulus_values = $object->stimuliTracker->lists('stimulus');
I'm working on a project that has a many to many relationship between User and Club. This relationship works and I can get the respective objects with: $user->clubs. The pivot table I've named memberships. I can get the pivot data with $club->pivot. Foreign keys are defined for the memberships table in migrations.
However, I'd like the pivot table to be represented by a model so that I can easily update attributes of Membership such as role (Or even add a Role model to Membership!) or status.
I've looked at "Defining A Custom Pivot Model" in the docs, but what it says doesn't work for me, I get:
ErrorException
Argument 1 passed to Illuminate\Database\Eloquent\Model::__construct() must be of the type array, object given
I've also looked at this description of how to do it, but it's more or less the same as above.
Membership model:
class Membership extends Eloquent {
protected $table = 'memberships';
public function user()
{
return $this->belongsTo('User');
}
public function club()
{
return $this->belongsTo('Club');
}
}
Has anyone done this before?
This has been solved by a suggestion by a reddit user to extend Pivot in my Membership model. I also had to add ->withPivot('status', 'role')->withTimestamps() to the relationship declarations in the User and Club models.
You can do this by adding some manual code.
Your Membership model looks ok. You can get all clubs of a $user easily if you define method $user->clubs() where you get all the clubs manually.
clubs() {
$memberships=$this->memberships;
$clubs=new \Illuminate\Database\Eloquent\Collection();
foreach($memberships as $m) {
$clubs=$clubs->merge($m->clubs);
}
return $clubs;
}