enter image description herei have tried many php functions like strpos(), preg_match() but none of them works. i have a string
i want to extract only the four digit number which is 1234.
<?php
$texxt="abcd1245 784563 1234 98756 kfg7456178";
$results=array();
preg_match('/[0-9]{4}/', $texxt, $results);
print_r($results);
?>
but the above code return 1245 instead of 1234.if i remove the abcd1245 then the out put is 7845.the actual string is very large it containg more than 200 numbers like above. i want only the exact 4 digit number. is there any way to solve this?
You need to place boundaries on both sides of your pattern.
\b\d{4}\b
An alternative would be to use \s instead of \b for whitespace - because boundaries will match other non-alphanumeric characters. Depends on exactly what you're looking for.
See it here
As you said you have more than 200 numbers then use below code:
<?php
$texxt="abcd1245 784563 1234 3421 98756 kfg7456178";
$results=array();
preg_match_all('/\b\d{4}\b/', $texxt, $results);
print_r($results);
?>
preg_match check for only one occurrence, where as preg_match_all check all occurrences.
For regex explanation please refer doc.
Related
$my_string = '88888805';
echo preg_replace("/(^.|.$)(*SKIP)(*F)|(.)/","*",$,my_string);
This shows the first and last number like thus 8******5
But how can i show this number like this 888888**. (The last 2 number is hidden)
Thank you!
From this: 8******5
To: 888888**
I'm not sure if you have worked on this Regex pattern to do something unique. However, I will provide you with a general one that should fit your question without using your current pattern.
$my_string = '88888805';
echo preg_replace("/([0-9]+)[0-9]{2}$/","$1**",$,my_string);
Explanation:
The ([0-9]+) will match all digits, this could be replaced with \d+, it's between brackets to be captured as we are going to use it in the results.
[0-9]{2} is going to match the last 2 digits, again, it can be replaced with \d{2}, it's outside the brackets because we don't want to include them in the result. the $ after that is to indicate the end of the test, it's optional anyways.
Results:
Input: 88888805
Output: 888888**
echo preg_replace("/(.{2}$)(*SKIP)(*F)|(.)/","*",$my_string);
If it for a uni assignment, you'd probably want to do this. Basically says, don't match if its the last two characters, otherwise match.
i'm trying to get the string between two words in a entire string:
Ex.:
My string:
...'Total a Facturar 123,061 221,063 26,860161,16080,580310,760 358,297 Recepcionado'...
I'm using
/(?<=Total a Facturar )(.*?) Recepcionado/
I need the highlighted characters (26,860161,16080,580310,760)
and i get 221,061 221,063 26,860161,16080,580310,760 358,297 Recepcionado with my pattern.
The numbers of the string are always different, i need the numbers that are together without a space.
Thanks
EDIT:
Here is the entire string: eval.in/802292
I hope this will be helpful
Regex demo or Regex demo 2
Regex: (?:\d+(?:\,\d+){2,})
For above question you can also use it like this (?:\d+(?:\,\d+){4})
1. (?:\d+) this will match digits one or more.
2. (?:\,\d+){2,} Adding this in expression will match patterns like , and digits {2,} for 2 or more than 2 times.
PHP code: Try this code snippet here
<?php
ini_set('display_errors', 1);
$string = "Total a Facturar 123,061 221,063 26,860161,16080,580310,760 358,297 Recepcionado";
preg_match("#(?:\d+(?:\,\d+){2,})#", $string, $matches);
print_r($matches);
I'm trying to check if a string has a certain number of occurrence of a character.
Example:
$string = '123~456~789~000';
I want to verify if this string has exactly 3 instances of the character ~.
Is that possible using regular expressions?
Yes
/^[^~]*~[^~]*~[^~]*~[^~]*$/
Explanation:
^ ... $ means the whole string in many regex dialects
[^~]* a string of zero or more non-tilde characters
~ a tilde character
The string can have as many non-tilde characters as necessary, appearing anywhere in the string, but must have exactly three tildes, no more and no less.
As single character is technically a substring, and the task is to count the number of its occurences, I suppose the most efficient approach lies in using a special PHP function - substr_count:
$string = '123~456~789~000';
if (substr_count($string, '~') === 3) {
// string is valid
}
Obviously, this approach won't work if you need to count the number of pattern matches (for example, while you can count the number of '0' in your string with substr_count, you better use preg_match_all to count digits).
Yet for this specific question it should be faster overall, as substr_count is optimized for one specific goal - count substrings - when preg_match_all is more on the universal side. )
I believe this should work for a variable number of characters:
^(?:[^~]*~[^~]*){3}$
The advantage here is that you just replace 3 with however many you want to check.
To make it more efficient, it can be written as
^[^~]*(?:~[^~]*){3}$
This is what you are looking for:
EDIT based on comment below:
<?php
$string = '123~456~789~000';
$total = preg_match_all('/~/', $string);
echo $total; // Shows 3
$st1='dsdsdsd 97537 sdsdd dsddd';
$st2='fdsf 23e sdsd 434 432443454';
$st3='fdf97537 ds344dsddd';
I want to check whether a 5 digit number is available in a string.
st1-- has 5 digit number
st2--- not
st3-- has 5 digit number
A simple regex will do the job.
preg_match('/\d{5}/', $input)
See also http://www.php.net/preg_match
Try this regular expression with preg_match() or preg_match_all()
preg_match("/\b[^\d]*\d{5}[^\d]*\b/", $str);
Let's assume that each element to be checked if this is five digits number is separated by space in string. Therefore you may use explode function to convert string into array of substrings. next you can use is_numeric function to check if that is digit along with check if that sub string is five length long. Also you may use regular expression for that.
Here RegEx is far more better. As I see the #Matt's answer meets these requirements, my comments will be unnecessary.
Currently I am developing a web application to fetch Twitter stream and trying to create a natural language processing by my own.
Since my data is from Twitter (limited by 140 characters) there are many words shortened, or on this case, omitted space.
For example:
"Hi, my name is Bob. I m 19yo and 170cm tall"
Should be tokenized to:
- hi
- my
- name
- bob
- i
- 19
- yo
- 170
- cm
- tall
Notice that 19 and yo in 19yo have no space between them. I use it mostly for extracting numbers with their units.
Simply, what I need is a way to 'explode' each tokens that has number in it by chunk of numbers or letters without delimiter.
'123abc' will be ['123', 'abc']
'abc123' will be ['abc', '123']
'abc123xyz' will be ['abc', '123', 'xyz']
and so on.
What is the best way to achieve it in PHP?
I found something close to it, but it's C# and spesifically for day/month splitting. How do I split a string in C# based on letters and numbers
You can use preg_split
$string = "Hi, my name is Bob. I m 19yo and 170cm tall";
$parts = preg_split("/(,?\s+)|((?<=[a-z])(?=\d))|((?<=\d)(?=[a-z]))/i", $string);
var_dump ($parts);
When matching against the digit-letter boundary, the regular expression match must be zero-width. The characters themselves must not be included in the match. For this the zero-width lookarounds are useful.
http://codepad.org/i4Y6r6VS
how about this:
you extract numbers from string by using regexps, store them in an array, replace numbers in string with some kind of special character, which will 'hold' their position. and after parsing the string created only by your special chars and normal chars, you will feed your numbers from array to theirs reserved places.
just an idea, but imho might work for you.
EDIT:
try to run this short code, hopefully you will see my point in the output. (this code doesnt work on codepad, dont know why)
<?php
$str = "Hi, my name is Bob. I m 19yo and 170cm tall";
preg_match_all("#\d+#", $str, $matches);
$str = preg_replace("!\d+!", "#SPEC#", $str);
print_r($matches[0]);
print $str;