I have a BuildingImage model with a OneToOne relation to BuildingType:
BuildImage Model:
/**
* Get the source type of the Building Image.
*/
public function type()
{
return $this->hasOne('App\BuildingType');
}
BuildingType Model:
/**
* Get the Building Image that owns the building type.
*/
public function buildingImage()
{
return $this->belongsTo('App\BuildingImage');
}
My tables:
building_images table -> source is the building type id
building_types table
When I try to do this in my controller just to test:
(an ImageRequest has one or more Builings and a Building has one BuildingType)
$imageRequest = ImageRequest::findOrFail($id);
$buildings = $imageRequest->buildingImages;
foreach ($buildings as $building) {
dd($building->type);
}
I get this error:
SQLSTATE[42S22]: Column not found: 1054 Unknown column
'building_types.building_image_id' in 'where clause' (SQL: select *
from building_types where building_types.building_image_id = 45
and building_types.building_image_id is not null limit 1)
What am I doing wrong here?
That's because by default laravel will look for a primary key named {model}_id, and given that you are using a different column name (source), you need to specify when defining the relationship:
As the documentation states:
Eloquent determines the foreign key of the relationship based on the model name. In this case, the Phone model is automatically assumed to have a user_id foreign key. If you wish to override this convention, you may pass a second argument to the hasOne method:
return $this->hasOne('App\Phone', 'foreign_key');
Additionally, Eloquent assumes that the foreign key should have a value matching the id (or the custom $primaryKey) column of the parent. In other words, Eloquent will look for the value of the user's id column in the user_id column of the Phone record. If you would like the relationship to use a value other than id, you may pass a third argument to the hasOne method specifying your custom key:
return $this->hasOne('App\Phone', 'foreign_key', 'local_key');
Now that that is clear. Let's talk about the relationship itself.
You are defining that a BuildImage has one BuildingType. But with that logic, the foreign key should be stored in the building_types table, and not the other way around (source column appears in the building_images table). And -I'm just assuming that- many BuildImage can belongs to an specific BuildingType. So, if this assumption is correct:
a BuildImage belongs to a specific BuildingType.
a BuildinType can be specify in many BuildImages
So, you should define your relationship like this:
BuildImage.php
public function type()
{
return $this->belongsTo('App\BuildingType', 'source');
}
BuildingType.php
public function images()
{
return $this->hasMany(BuildingImage::class, 'source');
}
Your BuildImage model should be
/**
* Get the source type of the Building Image.
*/
public function type() {
return $this->hasOne('App\BuildingType',"id","source");
}
And BuildingType Model should be
/**
* Get the Building Image that owns the building type.
*/
public function buildingImage()
{
return $this->belongsTo('App\BuildingImage',"source","id");
}
This should work.
For more info have a look
https://laravel.com/docs/5.7/eloquent-relationships#one-to-one
Have you tried to indicate the index ID like this?
public function buildingImage()
{
return $this->belongsTo('App\BuildingImage', 'image_request_id');
}
Eloquent determines the foreign key of the relationship based on the
model name. In this case, the Phone model is automatically assumed to
have a user_id foreign key. If you wish to override this convention,
you may pass the second argument to the hasOne method:
return $this->hasOne('App\Phone', 'foreign_key');
https://laravel.com/docs/5.7/eloquent-relationships#one-to-one
Related
I have a Work model where one of its attributes is the requestor, I am trying to obtain the requestor´s data (I can already obtain the primary key).
In this way I call the view:
$obras = Obra::all();
return view("obra.index", compact("obras"));
The view:
#forelse ($obras as $i)
<li>{{ $i->requestor_id->email }}</li>
#empty
The relationship in the work model:
public function requestor_id(){
return $this->hasOne(User::class);
}
Tables:
Users(applicants) have: id, name, email, password etc.
Work have: id, user_id, start_date etc.
The problem seems to be that I had the relations wrong, I had to use hasOne in the requester model (in the end I used hasMany because someone can create more than one work) and in the work model use belongsTo.
IMPORTANT note: the name of the function in the model cannot be the same as the name of a field in your table. Also in my case the column names do not follow the laravel/eloquent nomenclature so another parameter is added to belongsTo with the field name.
Work model:
public function solicitante(){
return $this->belongsTo(User::class, "requestor_id");
}
Requestor model:
public function obra(){
return $this->hasMany(Obra::class, "requestor_id");
}
And how to obtain requester data: $obra->solicitante->email
I think it's because of the name of the relation. You can try to renaming it to requestor. Laravel has some internal behavior runing on underscore. It might return only the id.
public function requestor()
{
return $this->hasOne(User::class);
}
import use App\Models\Obra; in the Controller.
use App\Models\Obra;
$obras = Obra::all();
return view("obra.index", compact("obras"));
Returned function must be same table name exm:
public function obra(){
return $this->hasMany(Obra::class, "requestor_id");
}
table name must be obra
SQL scheme:
bulletins
id increment
deals
id increment
seller_id
buyer_id
deals_items - items = bulletins
id increment
title
desc
bulletin_id
deal_id
How can I get deal row by bulletin id? In raw SQL it looks like:
select `deals`.* from `deals` inner join `deals_items` on `deals_items`.`deal_id` = `deals`.`id` where `deals_items`.`bulletin_id` = 10572
I tried:
public function deals()
{
return $this->hasManyThrough(DealItem::class,Deal::class, 'bulletin_id','dealid','id');
}
But it seems a wrong way. Can't find right way in laravel doc about relation.
#HCK shows right way.
but when I doing $bulletin->deals() in blade template I got empty collection of deals.
When just $bulletin->deal - all is fine, we have collection of deals.
I using protected $with = ['deals'] in my bulletin model, but what is different call method or property? Why with method empty result?
#Amarnasan was close, but the order of the foreign keys was wrong. Try this:
Deal.php
public function bulletins()
{
return $this
->belongsToMany(Bulletin::class, 'deals_items', 'deal_id', 'bulletin_id')
->withPivot('title','desc');
}
Bulletin.php
public function deals()
{
return $this
->belongsToMany(Deal::class, 'deals_items', 'bulletin_id', 'deal_id')
->withPivot('title','desc');
}
From the docs:
As mentioned previously, to determine the table name of the
relationship's joining table, Eloquent will join the two related model
names in alphabetical order. However, you are free to override this
convention. You may do so by passing a second argument to the
belongsToMany method:
return $this->belongsToMany('App\Role', 'role_user');
In addition to customizing the name of the joining table, you may also
customize the column names of the keys on the table by passing
additional arguments to the belongsToMany method. The third argument
is the foreign key name of the model on which you are defining the
relationship, while the fourth argument is the foreign key name of the
model that you are joining to:
return $this->belongsToMany('App\Role', 'role_user', 'user_id', 'role_id');
Update
When you access the relationship as a method: $bulletin->deals() you are accessing the relationship itself. This will return an instance of \Illuminate\Database\Eloquent\Relations\BelongsToMany (in your case). Here the query is not executed yet, so you could keep adding constrains to your query, for example:
$bulletin
->deals()
->where('seller_id', 45) // <---
->skip(5) // <---
-> ... (And so on)
When you access it as a dynamic property, you are already executing the query, so this will return a Collection instance. Is the same as calling the relationship as a method and then attach the ->get() at the end, so this two are equivalent:
$bulletin->deals()->get()
// equals to:
$bulletin->deals
Check this other answer, it answers your question.
DealClass:
public function bulletins()
return $this->belongsToMany('App\Bulletin', 'deals_items ', 'bulletin_id', 'deal_id')->withPivot('title','desc');
}
BulletinClass:
public function deals()
return $this->belongsToMany('App\Deal', 'deals_items ', 'deal_id', 'bulletin_id')->withPivot('title','desc');
}
deals model -
public function bulletins()
return $this->belongsToMany(Bulletin::class, 'deals_items ', 'bulletin_id', 'deal_id');
}
bulletin model:-
public function deals()
{
return $this
->belongsToMany(Deal::class, 'deals_items', 'deal_id', 'bulletin_id',);
}
My User model have these fields :
user_id
username
name
family
supervisor
And in that model I defined an accesssor that same name as supervisor attribute like this (because I want to return supervisor user as an User object and not a simple id):
public function getSupervisorAttribute($value)
{
return is_null($value) ? null : User::select('user_id', 'name', 'family')->find($value);
}
In the other hand there is a OneToMany relationship like this:
public function child()
{
return $this->hasMany(self::class, 'supervisor', 'user_id');
}
Now each time I call child() relation it return Illegal offset type error. seems that supervisor field does not recognized in second argument of hasMany method.
There is any way to solve this problem Without having to change accessor name.
I think the problem comes when you try to retrieve the relationship child, why? Because you have an accessor on your supervisor which is a foreign key inside of child relationship, so what happens is when you ask for that relationship, Laravel will try to use your supervisor property, since it has an accessor, it will trigger and instead of getting a desired property (which i guess is an integer), you will either get NULL or a User. I hope this clarifies it for you.
One workaround for this is to add appends attribute to your Model and then put mutators and accessors on that attribute.
If a User has children then it's one to many(he/she can have many children or none)
Anyway,
Lets assume you have a table named Children make sure you change the table name in the model(laravel assumes it's childrens in the DB).
If public function child() {} is in the User model then,
/*
* children since he/she can have many children
* hasMany means this model has many of the other model by self::class
* it's as if you're saying this model has many of this model so change it
*/
public function children()
{
/* you're building a relationship between User('user_id' as local primary key)
* and Children('parent_id' as foreign key)
* means children table has foreign key parent_id(unsignedInt)
* it returns an array of all the children objects of this User row
*/
return $this->hasMany('Children', 'parent_id', 'user_id');
}
On the other hand the Children Model:
<?php
namespace App;
use Illuminate\Database\Eloquent\Model;
class Children extends Model
{
/**
* The table associated with the model.
*
* #var string
*/
protected $table = 'children';
public function parent()
{
// belongsTo means 'parent_id' in this model(Children) relates to 'user_id' on 'User' model
// it returns the User object which is the parent of this child row
return $this->belongsTo('User', 'user_id', 'parent_id');
}
}
This solution is for creating another table however it seems you want it with the same table(it's not very clear edit your post).
// this function makes no sense, it takes an integer and finds the parameter to was given
$userWithIdOne = $user->getSupervisorAttribute(1);
Give us the migrations of the table, show us the relationships.
I'm trying to retrieve data from many to many relationship.I have two tables :
companies: [cid,name,origin]
vehicle_types: [id, type]
their pivot table: companies_vehicle_types: companies_id,vehicle_types_id
Relationship defined:
In Companies:
public function vehicle_types(){
return $this->belongsToMany('App\vehicle_types');
}
In vehicle_types
public function companies(){
return $this->belongsToMany('App\companies')->withTimestamps();
}
I want to retrieve companies where vehicle_types = specific type. How can i do that?
I tried doing following in my controller:
$vehicle_types=vehicle_types::all()->whereLoose('type','Bike');
foreach ($vehicle_types->companies as $vehicle_types) {
$company[]=$vehicle_types->pivot->name;
}
return $company;
But it doesn't seem to be working. It throws error of Undefined property: Illuminate\Database\Eloquent\Collection::$companies
Override the second, third and fouth argument in the relation if you are not following laravel's convention. See the documentation Many to Many Relation
Second argument determines the table name of the relationship's
joining table. The third argument is the foreign key name of the
model on which you are defining the relationship, while the fourth
argument is the foreign key name of the model that you are joining to:
public function vehicle_types(){
return $this->belongsToMany('App\vehicle_types', 'companies_vehicle_types', 'companies_id', 'vehicle_types_id');
}
Also, One $vehicle_type can have many companies, so:
$vehicle_types=vehicle_types::all()->whereLoose('type','Bike');
foreach ($vehicle_types as $vehicle_type) {
foreach($vehicle_type->companies as $company)
{
$company[]=$company->pivot->name;
}
endforeach
}
Again, I don't see name field in pivot table for this line to work: $company[]=$company->pivot->name;
I have 3 tables : hotels, hotels_data, hotels_types
Table hotels have id, type, stars, etc... type field is set as foreign key referencing type_id in hotels_types. I'm managing to get the correct data from hotels_data but have an empty result on getting hotels_types title and I don't understand why.
The code is the following :
class Hotel extends Eloquent {
public function getList() {
$data = Hotel::select('id','stars')->with('HotelData', 'HotelType')->paginate(10);
return View::make('hotels.index')->with('hotels', $data);
}
public function HotelData()
{
return $this->hasOne('HotelsData')->select('id','hotel_id','title');
}
public function HotelType()
{
return $this->hasOne('HotelType','type_id', 'type')->select('id','type_id','title');
}
}
You're using the wrong relationship for HotelType()
Your Hotel model should use the inverse of hasOne, which is belongsTo, because it contains the foreign key to HotelType (when a table contains a foreign key, it always belongs to the table being pointed to).
The following should work:
public function hotelType() {
return $this->belongsTo('HotelType','type', 'type_id')->select('id','type_id','title');
}
I've obtained the desired result with the following:
Hotel::select('hotels.*','hotels_types.title as type')
->join('hotels_types', 'hotels.type', '=', 'hotels_types.type_id')
->with('HotelData');