How to display random image from random directory - php

Question

Im trying to select random image from random directory. I make function to get random directory and another function to get random image from that directory. Okay, but its not working, its getting random directory and random image from another directory
<?php
function showRandomDir()
{
$files = glob('images/portfolio/*/', GLOB_ONLYDIR);
shuffle($files);
$files = array_slice($files, 0, 1);
foreach($files as $file)
{
return $file;
}
}
function rotate2()
{
$list = scandir(showRandomDir());
$fileRotateList = array();
$img = '';
foreach($list as $fileRotate)
{
if (is_file(showRandomDir() . htmlspecialchars($fileRotate)))
{
$ext = strtolower(pathinfo($fileRotate, PATHINFO_EXTENSION));
if ($ext == 'gif' || $ext == 'jpeg' || $ext == 'jpg' || $ext == 'png')
{
$fileRotateList[] = $fileRotate;
}
}
}
if (count($fileRotateList) > 0)
{
$imageNumber = time() % count($fileRotateList);
$img = showRandomDir() . urlencode($fileRotateList[$imageNumber]);
}
return $img;
}

Answer 1

At the beginning of your rotate2() function, you call showRandomDir() to get the contents of a random directory:
$list = scandir(showRandomDir());
But then at the end, you call showRandomDir() again, so you get a different random directory.
(Well, a new one, that's probably different, but could randomly be the same.)
$img = showRandomDir() . urlencode($fileRotateList[$imageNumber]);
You need to save the first call into a variable instead, and reuse that variable instead of calling showRandomDir() a second time.
$dir = showRandomDir();
$list = scandir($dir);
// ... the rest of the code in between
$img = $dir . urlencode($fileRotateList[$imageNumber]);