show data from json - php

Question

I'm trying to show table from json but failed, what's wrong with this:
$nip=$_POST['nip'];
$sql = "select satker,shift_description,nip FROM jamkerja
inner join master_shift on master_shift.shiftno=jamkerja.shiftno
inner join tr_jamkerjahdr on jamkerja.id_jamkerja=tr_jamkerjahdr.id_jamkerja
inner join tr_jamkerjamember on tr_jamkerjamember.trno=tr_jamkerjahdr.trno
where nip='$nip' ";
$result = $con->query($sql);
$data = array();
while($row = mysqli_fetch_assoc($result)){
$data[] = $row;
}
print $data;
And this is the table:
$json = $data;
$json_decoded = json_decode($json);
foreach($json_decoded as $data12){
echo '<tr>';
echo '<td>'.$data12[satker].'</td>';
echo '<td>'.$data12[shift_description].'</td>';
echo '<td>'.$data12[nip].'</td>';
echo '</tr>';
}

Answer 1

You don't need the $json_decode.Just loop through your array $data.
remove the :
$json = $data;
$json_decoded = json_decode($json);
and modify the foreach loop, adding the table tag.Also add single qoutes to your array indexes:
echo '<table>';
foreach($data as $data12){
echo '<tr>';
echo '<td>'.$data12['satker'].'</td>';
echo '<td>'.$data12['shift_description'].'</td>';
echo '<td>'.$data12['nip'].'</td>';
echo '</tr>';
}
echo '</table>';

Answer 2

Not sure I fully understand your question.
But let me try to help you. I think your issue is around
$json = $data;
$json_decoded = json_decode($json);
json_decode() is not needed here, the $data that you are assigning to $json is a type array. With the code you shared, I don't see any need for Json, you should directly loop through your $data.
Hope that helps.