PHP - Update SQL Statement mysqli database+Variables - php

Question

<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
$name = $_REQUEST['teamname'];
$email = $_REQUEST['email'];
$password = (md5($_REQUEST['password']));
$query = "UPDATE users SET email = ?,password = ? WHERE name = ?";
$statemnt = $conn->prepare($query);
$statemnt->bind_param('sss',$email,$password,$name);
$statemnt->execute(); echo $name,$email,$password; var_dump();
$statemnt->close(); $conn->close(); } ?>
managed to get the SELECT Statement figured out before this one and still having issues with the UPDATE - a form above this php snippet and is suppose to fill out $email $password and $name
<form method="post" action="">Team Name:<br>
<input type="text" name="teamname" value="<?php echo $name;?>">
<br>Email:<br><input type="text" name="email" value="<?php echo $email;?>">
<br>Password:<br><input type="text" name="password" value="">
<br><br><input type="Submit" value="Update the Record" name="Submit">
</form>
EDITED TO THE FOLLOWING (there is code above this part and below dont expect u want to see the rest of my html code - the bottom is what i am have trouble with):SELECT STATEMENT and var_dump is working but when i enter a password into the form it doesnt trigger the Submit and ultimately the UPDATE Statement - i have worked on it today again to no avail. pls any help would be appreciated not sure what im doing wrong - also var_dump at the bottom is outputing all of the values now
<?php
if (isset($_POST['submit'])) {
$sql = $conn->prepare("UPDATE users SET email=? , password=? WHERE team=?");
$postedemail=$_POST['teamemail'];
$postedpassword= $_POST['teampassword'];
$sql->bind_param("ssi",$postedemail,$postedpassword,$_POST["mySelect"]);
if($sql->execute()) {
$success_message = "Edited Successfully";
} else {
$error_message = "Problem in Editing Record";
}
var_dump($postedpassword);
var_dump($postedemail);
}
$stmt = $conn->prepare("SELECT team, name, email, password FROM users WHERE team = ?");
$stmt->bind_param("i", $_POST["mySelect"]);
$stmt->execute();
$result = $stmt->get_result();
if($result->num_rows === 0) exit('No rows');
while($rows = $result->fetch_assoc()) {
$name = $rows['name'];
$email = $rows['email'];
$password = $rows['password'];
}
var_dump($password);
var_dump($name);
var_dump($email);
var_dump($_POST['mySelect']);
$stmt->close();
?>
<?php if(!empty($success_message)) { ?>
<div class="success message"><?php echo $success_message; ?></div>
<?php } if(!empty($error_message)) { ?>
<div class="error message"><?php echo $error_message; ?></div>
<?php } ?>
<form name="frmUser" method="post" action="">
<label>NAME:</label>
<input type="text" name="teamname" class="txtField" value="<?php echo $name?>">
<label>EMAIL:</label>
<input type="text" name="teamemail" class="txtField" value="<?php echo $email?>">
<label>PASSWORD</label>
<input type="text" name="teampassword" class="txtField" value="">
<input type="submit" name="submit" value="Submit" class="demo-form-submit">
</form>
thanks

Answer 1

You have this at the begining of your script : $selectedOption = $_POST["mySelect"];
Nowhere in your code (especially in your <form></form>) I see any input named "mySelect"
Add this field in your form and the problem should be solved.
var_dump(); helps a lot debugging.