i want to update each columns acording by id, when i click on an image, without refresh all the page. my codes just update last ids column when i click each on images.
index.php:
$rzp=mysqli_query($conn,"SELECT * FROM `tbl_users_posts` WHERE uid=1");
while($rw=mysqli_fetch_assoc($rzp)){$id=$rw['id'];
echo $id;?><img id="up" src="pc3/up.png" alt=""><br>
<?php }?>
<script>
$(document).ready(function() {
var id = <?php echo $id;?>;
$(document).on("click","#up",function() {
$.ajax({
method: "POST",
url: "y2.php",
data: {id: id},
async :false
}).done(function(msg2) {
alert(msg2);
});
});
});
</script>
y2.php:
$id=$_POST['id'];
mysqli_query($conn,"UPDATE `tbl_users_posts` SET lik=lik+1 WHERE id='$id'");
thanks
There are a couple things immediately wrong here:
You are re-using id values in your HTML, which is invalid.
Your var id = ... JavaScript code always has the last value from your data, and you're explicitly using that every time instead of any value from your HTML element.
Let's simplify. First, echo your HTML elements to include (1) a class to use for triggering the click handler and (2) the ID that the click handler needs:
<?php
while($rw=mysqli_fetch_assoc($rzp)){
$id=$rw['id'];
echo $id;
?>
<img class="up" src="pc3/up.png" alt="" data-id="<?php echo $id; ?>"><br>
<?php } ?>
(Note: There's probably a much cleaner way to do that. I'm attempting to maintain the coding style you currently have, but you should definitely look into cleaner approaches of writing code overall.)
Now you have a bunch of images with (1) a class called "up" and (2) a data- attribute with the ID you need upon clicking. Your click handler can now use that information:
$(document).on("click", ".up", function() { // use the class as the selector
var id = $(this).data('id'); // get the data-id value from this specific element
$.ajax({
method: "POST",
url: "y2.php",
data: {id: id}
}).done(function(msg2) {
alert(msg2);
});
});
(Note: I also removed async: false because one should never use async: false. If there's some reason you think you need to use it, that's a different problem entirely and one that should be addressed as well.)
Related
Thanks for reading. I have tried the answers in other similar questions but none have worked so far. I'm trying to UPDATE values inside a Table that is inside a form, so in the first part of the file is the isset "saveImport" which is the name of the a tag that I'm using to send the id thru the URL:
if (isset($_POST['saveImport'])) {
$id = $_POST['id'];
}
a tag:
<a name="saveImport" href="./?id=<?= $row['id']; ?>" class="saveImport btn btn-success col-xs">Save</a>
I do get the ID value in the URL but since is been updated in the same file I'm assuming it refreshes the page before the variable gets post thru AJAX:
<script type="text/javascript">
$(document).ready(function() {
$('.saveImport').click(function() {
var imp_id = id.id;
var imp_href = $(id).attr('href');
alert(imp_href);
$.ajax({
url: "./",
data: {id : imp_id},
type: "POST",
success: function(data){
alert(id);//send this ID to the PHP variable without
//refreshing the file
}
});
});
});
I'm getting the class .saveImport because it's inside a Table which is displaying values from a Database so it's inside a while loop and if I use an ID it will cause conflict as the ID will repeat itself.
I already created the PHP function to UPDATE the Values which executes if the ISSET is true, so my real problem will be to execute the ISSET and inside grab the ID that was posted with AJAX so I can use the ID in the UPDATE function. Right now, if I click on the a tag, it sends the ID thru URL, the page refreshes but the value of the ID is not getting in the $id = $_POST['id];
I appreciate your time.
This should work.
Change the ajax url to your php file name (mine was t.php).
Replace 99 with your data from php. (id is used. href is not used)
<?php
if (isset($_POST['saveImport'])) {
print_r( $_POST );
exit;
}
?>
<a name="saveImport" id='99' href="./?id=99" class="saveImport btn btn-success col-xs"'>Save</a>
<script type="text/javascript">
$('.saveImport').click(function(event) {
var imp_id = this.id;
$.ajax({
url: "t.php",
data: {id : imp_id, saveImport: 1},
type: "POST",
success: function(data){
alert( data );//send this ID to the PHP variable without
//refreshing the file
}
});
event.preventDefault();
});
</script>
.preventDefault() will prevent the link from loading the target page... And then, ajax will proceed.
$('.saveImport').click(function(event) {
event.preventDefault();
I have been going crazy for the last 2 weeks trying to get this to work. I am calling a MySQL Db, and displaying the data in a table. Along the way I am creating href links that DELETE and EDIT the records. The delete pulls an alert and stays on the same page. The EDIT link will POST data then redirect to editDocument.php
Here is my PHP:
<?php
foreach ($query as $row){
$id = $row['document_id'];
echo ('<tr>');
echo ('<td>' . $row [clientName] . '</td>');
echo ('<td>' . $row [documentNum] . '</td>');
echo "<td><a href='**** I NEED CODE HERE ****'>Edit</a>";
echo " / ";
echo "<a href='#' onclick='deleteDocument( {$id} );'>Delete</a></td>";
// this calls Javascript function deleteDocument(id) stays on same page
echo ('</tr>');
} //end foreach
?>
I tried (without success) the AJAX method:
<script>
function editDocument(id){
var edit_id = id;
$.ajax({
type: 'POST',
url: 'editDocument.php',
data: 'edit_id='edit_id,
success: function(response){
$('#result').html(response);
}
});
}
</script>
I have been using <? print_r($_POST); ?> on editDocument.php to see if the id has POSTed.
I realize that jQuery/AJAX is what I need to use. I am not sure if I need to use onclick, .bind, .submit, etc.
Here are the parameters for the code I need:
POSTs the $id value: $_POST[id] = $id
Redirects to editDocument.php (where I will use $_POST[id]).
Does not affect other <a> OR any other tags on the page.
I want AJAX to "virtually" create any <form> if needed. I do not
want to put them in my PHP code.
I do not want to use a button.
I do not want to use $_GET.
I don't know what I am missing. I have been searching stackoverflow.com and other sites. I have been trying sample code. I think that I "can't see the forest through the trees." Maybe a different set of eyes. Please help.
Thank you in advance.
UPDATE:
According to Dany Caissy, I don't need to use AJAX. I just need to $_POST[id] = $id; and redirect to editDocument.php. I will then use a query on editDocument.php to create a sticky form.
AJAX is used when you need to communicate with the database without reloading the page because of a certain user action on your site.
In your case, you want to redirect your page, after you modify the database using AJAX, it makes little sense.
What you should do is put your data in a form, your form's action should lead to your EditDocument, and this page will handle your POST/GET parameters and do whatever database interaction that you need to get done.
In short : If ever you think you need to redirect the user after an AJAX call, you don't need AJAX.
You have a SyntaxError: Unexpected identifier in your $.ajax(); request here
<script>
function editDocument(id){
var edit_id = id;
$.ajax({
type: 'POST',
url: 'editDocument.php',
data: 'edit_id='edit_id,
success: function(response){
$('#result').html(response);
}
});
}
</script>
it should be like this
<script>
function editDocument(id){
var edit_id = id;
$.ajax({
type: 'POST',
url: 'editDocument.php',
data: {edit_id: edit_id},
success: function(response){
$('#result').html(response);
}
});
}
</script>
note the 'edit_id='edit_id, i changed, well for a start if you wanted it to be a string it would be like this 'edit_id = ' + edit_id but its common to use a object like this {edit_id: edit_id} or {'edit_id': edit_id}
and you could also use a form for the edit button like this
<form action="editDocument.php" method="POST">
<input type="hidden" name="edit_id" value="272727-example" />
<!-- for each data you need use a <input type="hidden" /> -->
<input type="submit" value="Edit" />
</form>
or in Javascript you could do this
document.location = 'editDocument.php?edit_id=' + edit_id;
That will automatically redirect the user
Given your comment, I think you might be looking for something like this:
Edit
$(document).ready(function() {
$('.editLink').click(function(e) {
e.preventDefault();
var $link = $(this);
$('<form/>', { action: 'editdocument.php', method: 'POST' })
.append('<input/>', {type:hidden, value: $link.data('id') })
.appendTo('body')
.submit();
});
});
Now, I don't necessarily agree with this approach. If your user has permission to edit the item with the given id, it shouldn't matter whether they access it directly (like via a bookmark) or by clicking the link on the list. Your desired approach also prevents the user from opening links in new tabs, which I personally find extremely annoying.
Edit - Another idea:
Maybe when the user clicks an edit link, it pops up an edit form with the details of the item to be edited (details retrieved as JSON via ajax if necessary). Not a new page, just something like a jQuery modal over the top of the list page. When the user hits submit, post all of the edited data via ajax, and update the sql database. I think that would be a little more user-friendly method that meets your requirements.
I was facing the same issue with you. I also wanted to redirect to a new page after ajax post.
So what is did was just changed the success: callback to this
success: function(resp) {
document.location.href = newURL; //redirect to the url you want
}
I'm aware that it defies the whole purpose of ajax. But i had to get the value from a couple of select boxes, and instead of a traditional submit button i had a custom anchore link with custom styling in it. So in a hurry i found this to be a viable solution.
I have the following loop, which creates a list from a database:
for ($i=0;$i<count($tutor_subj);$i++){
$query_tutors = "SELECT level, subject FROM level, subject WHERE level.id = '$tutor_lvl[$i]' AND subject.id = '$tutor_subj[$i]'";
$result_t = mysqli_query($db_conx, $query_tutors);
while($m = mysqli_fetch_array($result_t)){
echo $m['level']." ".$m['subject']." ".$tutor_top[$i]."<div style='float:right; padding-right:5px;'><a href='#'><img src='images/remove_btn.png' onclick='removeSubj'></a></div></br>";
}
}
?>
As you can see I'm adding a 'remove' button in the html after each entry, and I want to use this button to allow the users to delete that particular row of data from the database if they choose.
My question is how can I link the row from this while loop to the button being generated at the end of each line (so that the appropriate entry is deleted in the DB)?
PS - I havent written the javascript/jquery function removeSubj yet because I'm stuck, hence am not including that
Add an unique identifier to onclick='removeSubj' so that when it is called, you can determine what you would want to delete. You could use something like onclick='removeSubj("unique_identifier")'. Replace that unique_identifier with something that is always unique for every row in your database (for example an id-field).
You can then use this value in your javascript function, and finally in your server-side script, to delete the correct row.
Let me give you and example to buttress #sumurai8s' point because i had the same issue before i read his answer.
assuming this is the item you intend to loop (i.e you have dynamically generated this from your php/database loop)
<div class="media-body media-right">
<span onclick="delete(<?php echo $fromDb['id']; ?>);" class="icon icon-trash-o icon-3x text-blood pull-lg-right"></span>
</div>
This is what your java script should be
//delete
function delete(I) {
// delete methodology
var id_to_be_deleted = I;
var formData = new FormData();
formData.append("id_to_be_deleted", id_to_be_deleted);
$.ajax({
type: "POST",
url: "/delete.php",
contentType: false,
processData: false,
//contentType: "application/json; charset=utf-8",
dataType: "json",
data : formData,
success: function()
{
alert('successs');
}
});
}
And delete.php should be
<?php
if ($_POST['id_to_be_deleted']) {
$delete = $_POST['id_to_be_deleted'];
//do db delete query here i.e DELETE FROM table_name WHERE id='$id_to_be_deleted'
...
}
if you don't do it this way you might be experiencing your DELETE ACTION being fired twice.
Don't thank me, thank #sumurai8 for waking me up from my slumber ;)
Happy coding.
Hi everyone I have been working on this particular problem for ages by now,plz help.
I have looked at jQuery: Refresh div after another jquery action?
and it does exactly what I want but only once! I have a table generated from db and when I click on delete it deletes the row and refreshes the div but after which none of my jquery functions will work.
$('#docs td.delete').click(function() {
$("#docs tr.itemDetail").hide();
var i = $(this).parent().attr('id');
$.ajax({
url: "<?php echo site_url('kt_docs/deleteDoc'); ?>",
type: 'POST',
data: 'id=' + i,
success: function(data) {
$("#docs tr.itemDetail").hide();
$("#f1").html(data); // wont work twice
//$("#docs").load(location.href+" #docs>*"); //works once as well
}
});
});
in my body I have
<fieldset class='step' id='f1'>
<?php $this->load->view('profile/docs_table'); ?>
</fieldset>
profile/docs reads data from db. <table id='docs'>....</table>
and my controller:
function deleteDoc() {
$id = $_POST['id'];
$this->load->model('documents_model');
$del = $this->documents_model->deleteDocument($id);
return $this->load->view('docs_table');
}
Thanks in advance!
Are you removing any expressions matching $('#docs td.delete') anywhere? If so, consider using $.live(), which will attach your function to ALL matching elements regardless of current or in the future; e.g.
$('#docs td.delete').live('click', function() {
// Do stuff.
});
http://api.jquery.com/live/
Try using bind() instead of click(). The click() method won't work on dynamically added elements to the DOM, which is probably why it only works the first time and not after you re-populate it with your updated content.
You should just have to replace
$('#docs td.delete').click(function() {
with
$('#docs td.delete').bind('click', function() {
Are you replacing the html elements that have the events on them with the data your getting through ajax? If you end up replacing the td.delete elements, then the new ones won't automatically get the binding.
This is a very simple form that I have found on the web (as I am a jQuery beginner).
<!-- this is my jquery -->
<script>
$(document).ready(function(){
$("form#submit_wall").submit(function() {
var message_wall = $('#message_wall').attr('value');
var id = $('#id').attr('value');
$.ajax({
type: "POST",
url: "index.php?leht=pildid",
data:"message_wall="+ message_wall + "&id="+ id,
cache: false,
success: function(){
$("ul#wall").prepend(""+message_wall+"", ""+id+"");
$("ul#wall li:first").fadeIn();
alert("Thank you for your comment!");
}
});
return false;
});
});
</script>
<!-- this is my HTML+PHP -->
some PHP ...
while($row_pilt = mysql_fetch_assoc($select_pilt)){
print
<form id="submit_wall">
<label for="message_wall">Share your message on the Wall</label>
<input type="text" id="message_wall" />
<input type="hidden" id="id" value="'.(int)$row_pilt['id'].'">
<button type="submit">Post to wall</button>
</form>
and down below is my PHP script that
writes to mySQL.
It is a pretty straight forward script. However, it is getting little complicated when I submit it. Since I have more than one form on my page (per WHILE PHP LOOP), thus when I submit - only the FIRST form gets submitted. Furthermore, any other subsequent forms that I submit - data is being copied from the first form.
Is there any jQuery functions that clear the data? - or is there a better solution.
Thanks,
Nick
It's because you're giving each form the same id, and thus it is submitting the first element it finds with that id, i.e. the first form. What you should do is assign a unique id to each form, and then give each form an AJAX submit function that submits the form-specific data. You can use jQuery's $.each() function to loop through all the forms and $(this).attr('id') within the submit function to retrieve the form-specific id.
UPDATE: As revealed by the comment on this answer, you actually don't need the each() function because jQuery applies it to every form element anyway.
Here would be an example script:
$(document).ready(function(){
$("form").submit(function() {
var message_wall = $(this).children('input[type="text"]').attr('value');
var id = $(this).children('input[type="hidden"]').attr('value');
$.ajax({
type: "POST",
url: "index.php?leht=pildid",
data:"message_wall="+ message_wall + "&id="+ id,
cache: false,
success: function(){
$("ul#wall").prepend(""+message_wall+"", ""+id+"");
$("ul#wall li:first").fadeIn();
alert("Thank you for your comment!");
}
});
return false;
});
});
Because we can't see all of your forms, I'm not entirely sure, but given your question I'm going to assume that the other forms all share the same id (form#submit_wall), which is invalid an id must be unique within the document.
Given that you're going to change the id of the other forms (I'd suggest using a class name of, probably, 'submit_wall', but the specifics are up to you), the jQuery needs to be changed, too. From:
$("form#submit_wall").submit(function() {
To:
$("form.submit_wall").submit(function() { // using the class-name instead of the id.
Now, of course, you run into the same problems of duplicate ids.
So I'd suggest, again, changing the id to a class and changing:
var message_wall = $('#message_wall').attr('value');
var id = $('#id').attr('value');
to:
var message_wall = $(this).find('.#message_wall').attr('value');
var id = $(this).find('.id').attr('value');
Given the mess that you've posted, above, I find it hard to believe that this is all you need. It would definitely be worth posting the full page (or a demo at JS Fiddle or JS Bin) that fully reproduces your code.