**How to select checkbox in database mysqli
what should i write in checkbox value
please kindly help
i also implode function which convert array to string
did not find values for checkbox values to print. .....
Also check the output on PICTURE...
**
OUTPUT PIC
<?php
while($fetch=mysqli_fetch_array($select))
{
?>
<tr>
<td><?php echo $fetch["tableno"]?></td>
<td><?php echo $fetch["customerid"]?></td>
<td><?php echo $fetch["item"]?></td>
<td><?php echo $fetch["money"]?></td>
<td><button>Delete</button></td>
<td><a href="update.php?tableno=<?php echo $fetch["tableno"]; ?>"/><button>Update</button></td>
<td><form method="POST">
<input type="checkbox" name="chk[]" value="???">
<input type="submit" name="sub1" value="Button for Checkbox">
</td> </form>
</tr>
<?php
}?>
</table>
<p style="font-size:30px">The Customer has TO Selected these Items from Menu List
and therefore submitted to<br> Kitchener to Make the Food and
then waiter will serve the Food to Customer.</p>
</body>
</html>
<?php
if(isset($_POST['sub1']))
{
$chk=implode(',', $_POST['chk']);
echo "<br>Customer has selected the following checkbox Item to be Prepared and Eat the Food:<br/>";
echo "<br/>".$chk."<br><br/><br/><br/><br/>";
}
?>
Try this:
In you form, method to insert multiple checkboxes
<form method="POST" action="test2.php">
<input type="checkbox" name="chk[]" value="InputText1">InputText1<br>
<input type="checkbox" name="chk[]" value="InputText2">InputText2<br>
<input type="submit" name="sub1">
</form>
if(isset($_POST['sub1'])) // check the submitted form and print the values
{
echo "You selected the following checkbox:<br/>";
foreach ($_POST['chk'] as $value) {
echo $value."<br>";
}
One method is the value of a checkbox can be concatenated with all data and after submitting, check for selected check boxes with for each loop and print all the selected rows. Like below
<input type="checkbox" name="chk[]" value="<?php echo "<td>".$fetch["tableno"]."</td><td>".$fetch["customerid"]."</td><td>".$fetch["item"]."</td><td>".$fetch["money"]."</td>"; ?>">
And after posting use this :
if(isset($_POST['sub1'])) // check the submitted form and print the values
{
echo "Below Customers have placed orders:<br/>";
echo "<table>";
foreach ($_POST['chk'] as $value) {
echo "<tr>".$value."</tr>";
}
echo "</table>";
}
Related
how to set checkbox value if form validation fails in codeigniter. I have multiple select checkbox whose values populated from other dropdown selection. I want if form validation fails it should give me selected values. In my case it disappers. Any help will be appreciated.
my code:
<tbody class="location_id">
<?
$checked='';
if(isset($data1['loc_id']))
{
if($data1['loc_id']!='')
{
$checked='checked';
}
}
if(isset($data1['loc_id'])){
?>
<tr><td><input type="checkbox" name="loc_id[]" value="<?php if(isset($data1['loc_id'])){ echo $data1['loc_id'];} ?>" <?php echo set_checkbox('loc_id[]', $data1['loc_id']); ?> <?php echo $checked;?>></td><td><?php if(isset($data1['loc_id'])){echo get_name('location_tbl','loc_id',$data1['loc_id'],'loc_name');}?></td></tr>
<?php
}
?>
</tbody>
hope you understand.
In my controller I have set
$this->form_validation->set_rules('loc_id', '', 'trim|xss_clean');
sorry for grammar.
<input type="checkbox" style= "position: initial;" name="hobby[]" value="Sport"<?php if(strpos($hobby, 'Sport') !== false) echo "checked='checked'"; ?> >Sport
model:-
$hobby =implode(",", $this->input->post('hobby'));
I'm working on a form that uploads an image to a server. The form contains checkboxes and select boxes formatted to a <table>. Each table row contains two columns. The First column iterates through a mysql query that displays a list of items (24 items to be exact) that is paired to a checkbox. The 2nd column iterates through a mysql query that displays list of clients.
What needs to be done are as follows:
When the form gets uploaded (via POST or GET) the checkboxes which only have check gets passed.
convert the subs_id (name parameter for the select box) to an array for easy processing for mysql insert.
Code Below. Thanks in advanced!
<form method="post" enctype="multipart/form-data" action="upload2.php">
Name: <input type="text" name="item_desc" value="">
Show Date: <input type="text" name="upload_date" class="date" size="10"> to <input type="text" name="expiry_date" class="date" size="10">
Item: <input type="file" name="item"> Display Length: <input type="number" value="8" name="show_time" size="3" style="width:50px"> secs
<table class="data-list" width="100%">
<tr>
<td>Widget</td>
<td>Client</td>
</tr>
<?php foreach($instance as $item):?>
<tr>
<td><input type="checkbox" id="checkAll"/> <?php echo $item['name']; ?></td>
<td><select id="selectBox" name="subs_id[]">
<option selected="selected" value="none">Select Client</option>
<?php foreach($subs as $client): ?>
<option value="<?php echo $item['id'] . '-' . $client['id']; ?>" client="<?php echo $client['client_name']; ?>" ><?php echo $client['client_name']; ?></option>
<?php endforeach ?>
</select>
</td>
</tr>
<?php endforeach; ?>
</table>
<br>
<input type="submit" value="upload">
</form>
<input type="checkbox" id="checkAll" name='client[]' value ="1" /> <?php echo $item['name']; ?>
name and value is missing
1 .Change your checkbox code to
<input type="checkbox" id="checkAll" name="checkId[]" value="<?php echo $item['name']; ?>"/> <?php echo $item['name']; ?>
Here, I am taking name as array checkId[] and value of checkbox value="<?php echo $item['name']; ?>"
This should work for you.
Your select box is fine. There is no need to change it. you can find value of select box by checking index.
I figured it out. What I did was detect when there was a change on the select box and assign the value of the select box to the check box's value.
$(".selectBox").change(function() {
$(this).parent().siblings().children('input').attr('value',$(this).val());
});
then, on the upload2.php, I used the code below to get the value of only the boxes with check
if(!empty($_POST['checkId'])) {
$filename = $this->unique_filename($this->extract_ext( $_FILES["item"]["name"]));
$folder = dirname(__FILE__) . '/items';
move_uploaded_file($_FILES['item']['tmp_name'],"{$folder}/{$filename}");
foreach($_POST['checkId'] as $check) {
//save to db
$split = explode("-",$check);
$subs_id = $this->use_table('clients')->where('client_name like "' . $split[2] . '%"')->where('site_id=' . $split[1])->fetch();
//$subs_id = $this->query('select * from clients where client_name like "Trinoma%" and site_id=1');
//print_r($subs_id[0][id]);
$data = array(
'item_name'=> 'widgets/' . strtolower(get_class($this)) . '/items/' . $filename,
'show_time'=> $_POST['show_time'],
'instance_id'=> $split[0],
'item_desc'=>$_POST['item_desc'],
'subs_id'=> $subs_id[0][id]
);
$this->use_table(TBL_NAME)->insert($data)->execute();
$mid = $this->last_insert_id();
$this->use_table(TBL_SCHED)->insert(array(
'multirotator_id'=>$mid,
'show_from'=>'00:00',
'show_to'=>'23:59',
'upload_date'=>$_POST['upload_date'],
'expiry_date'=>$_POST['expiry_date']
))->execute();
} //end of foreach
} //end of if(!empty($_POST['checkId']))
and voila! working code for me.
I have a form with 640 cards each with a checkbox so the user can mark the ones he owns.
I'm wondering how to write the update SQL statement to take each of the 640 card ids and insert/update into the db.
Each row is created by this code:
echo "<td>"?>
<form name="some form" action="editform.php" method="post">
<input type="checkbox" name="<?php
echo $row['stickerID'] ?>" value=" <?php echo $row['stickerStatus'] ?> ">
<?php "</td>";
echo "</tr>";
}
I know I need some kind of for each loop in php. But how do I get the 640 individual checkboxes from the post?
suggest you name them like so
<input type="checkbox" name="stickerid[<?php
echo $row['stickerID'] ?>]" value=" <?php echo $row['stickerStatus'] ?> ">
then you can loop through the $_POST['stickerid'] array
foreach($_POST['stickerid'] as $k=>$v ){
//code
//$k=id
//$v=status
}
I have this code to show my table:
<form action="<?php echo $_SERVER['PHP_SELF'] ?>" method="POST">
<table cellspacing='0'>
<?php
if(isset($_GET["ordem"])){
if($_GET["ordem"] == 'descendente'){
echo "<thead><tr><th><a title='Ordenar por título' href='visualizarVoucher.php'>Utilizador</a></th>";
echo "<th>Email</th>";
echo "<th>Voucher</th>";
echo "<th>Categoria</th>";
echo "<th>Preço</th>";
echo "<th>Confirmação</th>";
echo "<th>Enviar mail</th>";
echo "</tr></thead>";
}
elseif($_GET["ordem"] == 'ascendente'){
echo "<thead><tr><th><a title='Ordenar por título' href='visualizarVoucher.php?ordem=descendente'>Utilizador</a></th>";
echo "<th>Email</th>";
echo "<th>Voucher</th>";
echo "<th>Categoria</th>";
echo "<th>Preço</th>";
echo "<th>Confirmação </th>";
echo "<th>Enviar mail</th>";
echo ("</tr></thead>");
}
}
else{
echo "<thead><tr><th><a title='Ordenar por título' href='visualizarVoucher.php?ordem=ascendente'>Utilizador</a></th>";
echo "<th>Email</th>";
echo "<th>Voucher</th>";
echo "<th>Categoria</th>";
echo "<th>Preço</th>";
echo "<th>Confirmação</th>";
echo "<th>Enviar mail</th>";
echo("</tr></thead>");
}
while($stmt->fetch()){
echo("<tbody>");
echo("<tr><td>$nomeUser</td>");
echo("<td>$email</td>");
echo("<td>$nomeVoucher</td>");
echo("<td>$categoria</td>");
echo("<td>$preco</td>");
echo("<td>$confirmacao</td>");
$content = file_get_contents($file,$filePDF);
echo("<td><INPUT TYPE='checkbox' NAME='mail[]' multiple='yes'></td>");
echo("</tr>");
echo("</tbody>");
}$stmt->close(); ?>
I have a checkbox in my table and I would like to know how can I get the values of each rows from the table when i selected the checkbox. I want to send email when the user selected multiple checkbox.
Thanks
It's possible that the code above is a snippet of a larger page, but if not:
You aren't actually wrapping your input elements in an HTML form tag. Doing so will cause the user agent (presumably a browser) to treat each input tag as something to be submitted to your backend form.
You should wrap the tables in a table element; tbody is a child of a table.
Regardless of the above:
It looks like your PHP code above will render the entire tbody each time the statement fetches a new row, which is a bit weird. I'd assume you only want to render a row containing mail options?
To the best of my knowledge, there is no multiple attribute allowed in a checkbox element. You may be thinking of the select element.
You are not setting a value attribute on your checkbox input tag. If the user actually submits a form, you'll either get a set of empty mail[] variables, or nothing at all, I'm not actually sure which.
Consider the code below: Note that the checkboxes have the same name attribute, but different values.
<form method="post">
<table>
<tbody>
<tr>
<td>
<input type="checkbox" name="mail[]" value="val1" id="mail-val1" />
<label for="mail-val1">Value 1</label>
</td>
</tr>
<tr>
<td>
<input type="checkbox" name="mail[]" value="val2" id="mail-val2" />
<label for="mail-val2">Value 2</label>
</td>
</tr>
<tr>
<td>
<input type="checkbox" name="mail[]" value="val3" id="mail-val3" />
<label for="mail-val3">Value 3</label>
</td>
</tr>
</tbody>
</table>
<input type="submit" />
</form>
Given this form, if the user selects all three of the checkboxes and submits, your server will receive a POST request with the payload:
mail[]=val1&mail[]=val2&mail[]=val3
Depending on how PHP parses that response (it's been about a decade since I've dealt with PHP), you'll probably have an array variable accessible to your application:
# mail == ["val1", "val2", "val3" ]
Hope this helps.
I have a form with rows which are populated from a table. Each row has a "checkbox" which the user can check or not.
When the form is submitted I want to be able to read which checkbox have been selected and insert the result in to a data table.
My code so far
FORM:
<form method="post" name="form1" action="<?php echo $editFormAction; ?>">
<table
<?php do { ?>
<tr>
<td>input type="text" name="InspectRoomNo" value="<?php print $row_InspectItems['AuditItemNo']; ?>"></td>
<td>php echo $row_InspectItems['AuditItem']; ?>td>
<td>input name="check[]" type="checkbox" ></td>
</tr>
<?php } while ($row_InspectItems = mysql_fetch_assoc($InspectItems)); ?>
<input type="submit" value="Insert record">
</table>
The insert: fetchs $Items from table
while($row = mysql_fetch_assoc($Items))
{
$array[] = $row['AuditItem'];
}
foreach($array as $id) {
$AuditItemID = mysql_real_escape_string($id);
if(isset($_POST['check'])){
$Checked = mysql_real_escape_string($_POST['check'][$row]);
}
}
The problem I am having is the returned values for all the checkbox is true, even if a checkbox was not selected.
Can anyone help me sort this issue.
Many thanks.
Do it like this:
if(!empty($_POST['check'])) {
foreach($_POST['check'] as $check) {
echo $check;
}
}
You should put the item id inside the checkbox name:
<td><input name="check[<?= $row_InspectItems['AuditItem']; ?>]" type="checkbox" /></td>
Then, you can simply iterate over it:
foreach ($_POST['check'] as $id => $value) {
// do stuff with your database
}
I'm assuming than whomever runs this script is trusted, because it would be easy to forge the list of ids; make sure the current user has permissions to update those records.
What is happening, is that only selected checkboxes get sent to the server, so you will see that your $_POST['check'] array (this is an array!) is smaller than the number of items you have displayed on the screen.
You should add your ID's so that you know what checkboxes got checked and adapt your php processing code to handle an array instead of a single value.
You are also overwriting your InspectRoomNo every row, so you should use an array there as well.
The form side would look something like:
<td><input type="text" name="InspectRoomNo[<?php echo row_InspectItems['AuditItemNo']; ?>]" value="<?php print row_InspectItems['AuditItemNo']; ?>"></td>
<td><?php echo $row_InspectItems['AuditItem']; ?></td>
<td><input name="check[<?php echo row_InspectItems['AuditItemNo']; ?>]" type="checkbox" ></td>