calculating difference between two dateTime with my owner class - php

Question

I want to calculate the days by write two the dates in html form we I did the code bellow I have this problem.
Fatal error: Uncaught ArgumentCountError: Too few arguments to
function Pos_Date::setDate(), 1 passed in
C:\xampp\htdocs\dateTimeZone\index.php on line 40 and exactly 3
expected in C:\xampp\htdocs\dateTimeZone\Date.php:116 Stack trace: #0
C:\xampp\htdocs\dateTimeZone\index.php(40): Pos_Date->setDate('2011,
5, 5') #1 {main} thrown in C:\xampp\htdocs\dateTimeZone\Date.php on
line 116
Note if I put for example 2019, 1 ,1 instead $date1 and 2020, 1
1 instead $date2 after in setDate, it works and echo 365 days left.
in my class on line 116 I have this code
public function setDate($year, $month, $day)
you can see the whole class and my code by this link.
https://drive.google.com/drive/folders/1D406OsQyUEI4MKjSjs3XRWl4aiDyIBAt?usp=sharing
<form action="index.php" method="post">
<input type="text" name="date1">
<input type="text" name="date2">
<input type="submit" name="submit">
</form>
here is php code
$date1 = $_POST['date1'];
$date2 = $_POST['date2'];
if(isset($_POST['date1']) && isset($_POST['date2']) && isset($_POST['submit'])){
try {
$now = new Pos_Date();
$newYear = new Pos_Date();
$now->setDate(2019, 1, 1);
$newYear->setDate($date2);
$diff = $now->dateDiff2($newYear);
$unit = abs($diff) > 1 ? 'days' : 'day';
if ($diff > 0) {
echo "$diff $unit left";
}
} catch (Exception $e) {
echo $e;
}
}

Answer 1

the setDate() method requires the date to be passed in the following format
public DateTime DateTime::setDate ( int $year , int $month , int $day )
So you have to format your date prior to sending it to the method, which can be done using
$date2->format('DD') // for day
$date2->format('Y') // for year
$date2->format('M') // for month
http://php.net/manual/en/datetime.setdate.php

Answer 2

I have make a function that returns difference of two dates in Years,months,days,hours,minutes and seconds. If dates difference in years than it gives only years respectively.
$diff = abs(strtotime($firstime) - strtotime($secondTime));
function timediff($diff) {
$years = floor($diff / (365 * 60 * 60 * 24));
if (empty($years)):
$months = floor(($diff - $years * 365 * 60 * 60 * 24) / (30 * 60 * 60 * 24));
if (empty($months)):
$days = floor(($diff - $years * 365 * 60 * 60 * 24 -
$months * 30 * 60 * 60 * 24) / (60 * 60 * 24));
if (empty($days)):
$hours = floor(($diff - $years * 365 * 60 * 60 * 24 - $months * 30 * 60 * 60 * 24 - $days * 60 * 60 * 24) / (60 * 60));
if (empty($hours)):
$minutes = floor(($diff - $years * 365 * 60 * 60 * 24 - $months * 30 * 60 * 60 * 24 - $days * 60 * 60 * 24 - $hours * 60 * 60) / 60);
if (empty($hours)):
$minutes = floor(($diff - $years * 365 * 60 * 60 * 24 - $months * 30 * 60 * 60 * 24 - $days * 60 * 60 * 24 - $hours * 60 * 60) / 60);
if (empty($minutes)):
$seconds = floor(($diff - $years * 365 * 60 * 60 * 24 - $months * 30 * 60 * 60 * 24 - $days * 60 * 60 * 24 - $hours * 60 * 60 - $minutes * 60));
endif;
endif;
endif;
endif;
endif;
endif;
I hope this will works better for you.
Thanks,
sandeep