How to display images(.jpg) only? - php

Question

Array ( [0] => assets/image/man.jpg [1] => assets/image/violin.jpg [2] => assets/image/test.txt )
The data from data base is like above.It contain images and txt.how can i display only images.

Answer 1

$ar = ['assets/image/man.jpg','assets/image/violin.jpg','assets/image/test.txt'];
$allowed = ['jpg']; //your image extensions
$img_ar = [];
foreach($ar as $img){
$ext = pathinfo($img,PATHINFO_EXTENSION);
if(in_array($ext,$allowed)){
$img_ar[] = $img;
}
}
print_r($img_ar);

Answer 2

$array= Array ( [0] => assets/image/man.jpg [1] => assets/image/violin.jpg [2] => assets/image/test.txt )
$m_array = preg_grep('/^.jpg\s.*/', $array);
$m_array contains matched elements of array.
For more detail have look at this thread search a php array for partial string match

Answer 3

For this you can directly filter it when you are querying like
field like '%.jpg'
If you don't want to do that and manipulate the array you can use array_filter like,
$array= Array ('assets/image/man.jpg', 'assets/image/violin.jpg', 'assets/image/test.txt');
$output = array_filter($array, function($arr) {
if (strpos($arr, '.jpg') == true){
return $arr;
}
});
$output array contains only the entries which having the .jpg string.
Here am using strpos to check .jpg exists or not.
you maybe use substr($str, -4) == '.jpg' to check the last 4characters.

Answer 4

If you are using PHP 5+ (which I hope you are on 7.0+), use SplFileInfo() class
$spl = new SplFileInfo($fileName);
if ($spl->getExtension() == 'jpg') {
//image
}

Answer 5

Use foreach loop and get an extension of the file and display.
foreach($array_result as $result){
//$array_result is array data
//condition is checking the file that if it is an image or not
$allowed = array('gif','png' ,'jpg');
$filename = $result;
$ext = pathinfo($filename, PATHINFO_EXTENSION);
if(in_array($ext, $allowed) ) {
echo '<img src="'.$result.'" alt="" /> ';
}
}

Answer 6

This should do the trick:
$images = array();
$images_exts = array('.jpg','.png');
foreach($db_array as $key => $value)
{
foreach($images_exts as $ext)
{
if (strpos($value,$ext))
{
$images[] = $value;
}
}
}
Here is an example https://3v4l.org/8W3Be
And here is another way, whatever you like the most:
$images = array();
$images_exts = array('jpg','png');
foreach($input as $value)
{
if(in_array(#end(explode('.', $value)), $images_exts))
{
$images[] = $value;
}
}
Here is an example https://3v4l.org/b0njd

Answer 7

Why do you check it when you want write it on page?
You can:
1. split assets/image/man.jpg with '/'
2. get last one,
3. split last one with '.'
4. get extension and if it was 'jpg' write it to page.

Answer 8

<?php
$error = array();
$file_extArr = explode(".", $file_name);
$file_extEnd = end($file_extArr);
$file_ext = strtolower($file_extEnd);
$validateImage = array("png", "jpg", "jpeg", "gif");
if (!in_array($file_ext, $validateImage)) {
$error[] = "wrong format image";
}
if (!empty($error)) {
return;
}
?>

Answer 9

<?php
$data = Array (
'assets/image/man.jpg ',
'assets/image/violin.jpg ',
'assets/image/test.txt ',
);
$arrDara = array();
foreach ($data as $value) {
$fileName = explode('/', $value);
$arrDara[] = end($fileName);
}
print_r($arrDara);
?>
Just loop your array and explode every sting. the last index is what all you need.