Data comparison in laravel - php

I'm beginner in laravel and I'm trying to run comparison queries given in the database.
I saved a field date that is implemented by a form together with other fields including the name.
I tried to query the name and it works all regularly with this code below.
I would like to retrieve all the rows that have the name variable as the field name that I pass (and here it seems to work) and then only those with the field date that have the specified month at the number that I pass as variable $month.
what would be the right form to do this?
thanks
Piero
public function filterparamenter(){
$name = request('name');
$month = request('$month');
$query = subagente::all();
$query = $query->where('subagente', $subagente);
$query = $query->whereMonth('data', $month)->get();
Method Illuminate\Database\Eloquent\Collection::whereMonth does not exist.

Using ::all() returns a Collection, which has a ->where() method, but ->whereMonth() is only available on Eloquent's Builder class. Change your code as follows:
$query = subagente::query();
$query = $query->where('subagente', $subagente);
$query = $query->whereMonth('data', $month)->get();
Or, more compact:
$results = subagente::where("subagente", $subagente)
->whereMonth("data", $month)
-get();
Using ::query() or ::where() to start your query will generate a Builder instance, which you can chain addition clauses (->where(), ->whereMonth(), etc) on before calling ->get() to return a Collection of subagente records.
Side note, should "data" be "date"?

Related

Yii2 How to get all values from column (DB)

I've been sitting for hours trying to find how to get values from table's iab_categories column category_name. I've found only the way to echo all table names:
$connection = Yii::app()->db;//get connection
$dbSchema = $connection->schema;
//or $connection->getSchema();
$tableNames = $dbSchema->getTableNames();//returns array of tbl schema's
var_export($tableNames);
Can anyone help me?
You can use query builder to do that:
$categories = (new \yii\db\Query())
->select(['category_name'])
->from('iab_categories')
->column();
The select() method sets what columns should be included in result.
The from() method sets what table should be queried.
And the column() method executes the query and return first column from result set as array.
EDIT: now, I've realized that even though you've mentioned Yii 2 in title the code you've included in question looks more like Yii 1.x.
So there is query builder version for Yii 1.x:
$categories = Yii::app()->db->createCommand()
->select('category_name')
->from('iab_categories')
->queryColumn();

How to insert SQL column name to Raw Query from PHP/Laravel

I have this code in Laravel:
DB::table('items')
->whereRaw("? = 1", ['active'])
->get();
In my database table, I have a column named active and the query I want to run is:
SELECT *
FROM items
WHERE active=1
My code fails because the query passes my 'active' parameter as a String instead of a column name in SQL syntax (which is the expected behavior).
So, instead of the above, I get something like this:
SELECT *
FROM items
WHERE "active"=1
Any idea how to solve this?
PS: I tried the MySQL function TRIM but with no success (perhaps I did not do it correctly).
It is not the cleanest way;
$day = 'Monday'; // dynamically Tuesday, Wednesday....
$method = 'where' . $day;
return DB::table('items')->$method('1')->get();

retrieve single row in LARAVELusing eloquent

i am using laravel 5.1 and want to retrieve a single row in the database then manipulate it after.
my current code is
$profiles = Profile::where('user_id', $this->user->user_id)
->where('profile_code', $this->user->profile_code)
->get();
foreach($profiles as $profile ){
$data['address'] = $profile->address;
}
why cant i do it like this?
$profiles = Profile::where('user_id', $this->user->user_id)
->where('profile_code', $this->user->profile_code)
->get();
$data['address'] = $profiles->address;
am i using a wrong function or something?
thanks in advance.
Try this:
$data['address'] = $profiles[0]->address;
When you are using get(), it returns an array of Std class object.
In addition to retrieving all of the records for a given table, you may also retrieve single records using first. Instead of returning a collection of models, these methods return a single model instance:
// Retrieve the first model matching the query constraints...
$flight = App\Flight::where('active', 1)->first();
laravel 5.8
Retrieving A Single Row / Column From Profile
If you just need to retrieve a single row from the database table, you may use the first() method. This method will return a single stdClass object:
$Profile = DB::table('Profiles')->where('user_id', $this->user->user_id)
->where('profile_code', $this->user->profile_code)->first();
If you don't even need an entire row, you may extract a single value from a record using the value() method. This method will return the value of the column directly:
$address = DB::table('Profiles')->where('user_id', $this->user->user_id)
->where('profile_code', $this->user->profile_code)->value('address');

Cannot retrieve single column from database. Laravel

I'm trying to retrieve single column from my table grades.
For that I have used following code in my controller:
public function verify($id,$sid)
{
$grade=Grade::all('annual')->whereLoose('id',$id);
return $grade;
}
Where, annual is column name. But it is returning empty set of array [].
all() takes a list of columns to load from the database. In your case, you're fetching only one column called annual, therefore filtering on id later on does not return results. Replace your code with the following and it should work:
$grade = Grade::all('id', 'annual')->whereLoose('id', $id);
Keep in mind that it will return a collection of objects, not a single object.
NOTE: you're always loading all Grade objects from the database which is not efficient and not necessary. You can simply fetch object with given id with the following code:
$grade = Grade::find($id); // fetch all columns
$grade = Grade::find($id, ['id', 'annual']); // fetch only selected columns
The code you are using is loading all rows from the grades table and filtering them in code. It is better to let your query do the filter work.
For the columns part, you can add the columns you need to the first() function of the query, like so:
public function verify($id,$sid)
{
$grade = Grade::where('id', $id)->first(['annual']);
return $grade->annual;
}

Why do Laravel relationships prevent calls to query builder methods?

I want to find all patients that belong to a user where id = 1
This works:
$data = Patient::where('user_id', '=', 1)
->with('method', 'images')->get()->toJson();
This doesn't work:
$data = User::find(1)->patients->with('method', 'images')->get()->toJson();
It says:
Call to undefined method Illuminate\Database\Eloquent\Collection::with()
Why is it wrong? Could it be corrected?
The reason your code doesn't work is all Eloquent relationship declaration returns different result depending on whether you are trying to access the relationship as property or as method (with () or without ()).
// Return you chainable queries
$query = User::find(1)->patients()->...
// Return you collection of patients
$patientsCollection = User::find(1)->patients;
Try
User::find(1)->patients()->with('method', 'images')->get()->toJson();
Try this
$patient = New Patient;
$data = $patient->where('user_id','=',1)->with('method','images')->get()->toJson();

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