i'm from codeIgniter , but for an internship I have to debug an ongoing website using cakePHP.
I'm familiar with mvc but currently stuck and unable to find any solution even after searching.
What I want is to be able to call a function in a controller (easy task with codeIgniter) ,but during the debug I noticed that the controller was called, but not the function:
<?php
App::uses('AppController', 'Controller');
class FournisseursController extends AppController { //debug stop here
public $helpers = array('Html', 'Form');
public function index() {
$this->set('Personnes', $this->Fournisseur->find('all'));
}
public function addFournisseur() {
//contain some code , but not usefull for this problem
}
}
}
?>
after the 2 first line , the associated view is displayed (it's a weird concept to always have a view displayed, but I guess cake php work this way).
and debug dont even start on the targeted function.
I call it from a view:
<form action="../../Fournisseurs/addFournisseur" method="post">
<input type="submit">
</form>
I know it's not really good to call a controller from view , but in that case I need the user to enter some data to send it in a database, I dont know any other way.
I already read the doc concerning controller and it didnt help.
One last thing , if I change the name of the function in the controller , the controller will not be called : an error message explain the the method dont exist (so for me the controller know I want to call the function, because the controller need it to run).
it's been a day since i'm stuck on this and i'm pretty sure it's a stupid mistake.
thanks for reading this even if you dont answer , and sorry if I made any english mistake, it's my first post and i'm not a native speaker.
I was only relying on Xdebug ,despite the breakpoint it was not stopping in the function ,so I thought it was not called (the function and the code inside it), but with the help of the debug($data) function the breakpoint worked and I was able to keep debuging in the function.
I dont know why Xdebug acted this way ,but I will not rely only on it now.
thanks to everyone who helped, I can keep going now!
You can also use Form helper like below, where you can define the contoller and action name:
<?php echo $this->Form->create('Fournisseur', array('url' => array('controller' => 'Fournisseurs', 'action' => 'addFournisseur'))); ?>
// Form elements
<?php echo $this->Form->end(); ?>
Related
I know that for some it might be stupid or funny question (but I am newbie) but I need to find know how to properly use DD() method in laravel projects.
For example - I have got tasks to debug some code and functionality in my project (PHP laravel). And it always takes me for ever to find the exact file or folder or code where the problem is.
My mentor says to use DD() method to find things faster (but for learning purposes he didn't explain me a lot about how to actually use it and said to find out my self), but said that I should start with Route (we use backpack as well for our project). So after finding Route (custom.php file) which controller connects to my required route what should I do next? How do I implement dd() method (or as my mentor says dd('call here') method) to fast find what I should be looking for to solve my problem and complete my task? Where should I write this dd() and how should I write it?
Thank you for the answer in advance!
for example I have a:
public function create(): View
{
return view('xxxxxx. \[
//
//
\]);
}
and if I put dd() anywhere in the code, I get error message in my URL :(
first of all ,in Laravel we use dd() before return in order to read any variable.
in controller we often use two kinds of variables : collection(which we get its members via foreach) or singular variable (we get it via its name)for example:$var = 1; dd($var).
notice:
if you are using ajax response you will not be able to see dd() results in page ,you can see the result via network tab in your browser (if u inspect your page).
dd stands for "Dump and Die."
Laravel's dd() function can be defined as a helper function, which is used to dump a variable's contents to the browser and prevent the further script execution.
Example:
dd($users,$variable1,$var2);
You can use dd() in blade
#foreach($users as $user)
#dd($user)
OR
{{dd($user)}}
#endforeach
#dd($var1)
You can read this article, the have more example and comparison
https://shouts.dev/articles/laravel-dd-vs-dump-vs-vardump-vs-printr-with-example
As Laravel is following model-view-controller or MVC design pattern. First go to the route and check which controller is called in the URL with the related URL.
Then go to the controller. **dd**() function is basically a dump and die. you also can do this by **print** or **echo** function too.
Lets assume that I have a controller name ProductController where I have method name index.From where I need to show a list of products in a table.
// in controller
public function index()
{
$products = Products::all();
// here you think ,I need to check whether I am getting the output or
not.
dd( $products );
//Or echo $products;
return view ('product.list',compact('products'));
}
let's suppose you are getting everything but in view when you loop through the products you declare the wrong variable name or mistakenly do some spelling mistakes. and want to see the result.
In view just do the dd() method by the following way:
{{ dd($products) }}
I'm posting this after my hair has been ripped out, ran out of rum, and tried everything I can find on google. I've been developing a site using codeigniter which makes use of templates. I've built the backend first and all is working properly there. So now i've started on getting the front end working which is where I'm hitting the issue.
I've created a controller called pages.php which is going to parse the uri string of the current page, use my library to get the page data from the database, then display it. My pages are all created through an editor on the back end and stored in the database.
So here's the pages controller
class Pages extends CI_Controller {
public function __construct()
{
parent::__construct();
$this->load->library("pages");
}
public function display_page()
{
$page_slug = $this->uri->segment(1);
$data["joes"] = "Here's joes first variable";
$this->pages->get_page($page_slug);
}
}
and here's the error message i get when i hit my url like this demo.mydomain.com/joes-test
and here is how my routes are set up. $route['(:any)'] = 'pages/display_page';
My Pages.php library works perfect on the back end but it's a large file. I've only posted the get_page function below. If you need to see everything let me know. But i dont believe the issue has anything to do with the library itself.
public function get_page($slug){
$objPages = new pages();
$objPages->get_object('slug="'.$slug.'"');
return $objPages;
}
[EDIT] If i place the following inside my homepage controller it works. But the calling function needs to be inside the library.
$this->load->library('pages');
$the_page = $this->pages->get_page("joes-test");
I want to call $this->get_object("joes-test") but this doesn't work. get_object() is an inherited function inside the library.
Now oddly enough. The code i put above will NOT work if i do the exact same thing inside the pages controller
any help leading to a solution would be awesome. I'm under a time crunch and pay to get some assistance. Thanks in advance.
No you can't use the same name with controller and library. please choose another name. for example Mypages for you controller name.
change your routes
$route['(:any)'] = 'mypages/display_page';
then call your controller.
http://demo.mydomain.com/joes-test
I think there nothing wrong with library uri, because as codeigniter official website say: This class is initialized automatically by the system so there is no need to do it manually.
I don't know about lib pages, but how about use
$this->load->view(<file-html>);
and if you want to passing data in variable, you can add variable like this
$this->load->view(<file-html>, $data);
Hope this help, Cheers
while working yesterday with codeIgniter I found some strange(I don't know what to call),maybe I don't know whether it is normal or not as am a rookie using this framework.Below is my controller class.
class Posts extends CI_Controller
{
public function __construct() {
parent::__construct();
$this->load->model( 'post' );
}
public function index() {
// echo "<pre>";
// print_r($data['posts']);
// echo "</pre>";
$data['posts']=$this->post->get_posts();
$this->load->view( 'post_index', $data );
}
public function post( $postID ) {
$data['post']=$this->post->get_post_by_ID( $postID );
$this->load->view( 'post', $data, FALSE );
}
I found that strange in function "post" the reason is simple if I change the function name then I will get the error-page not found.
Why is that?? Is it necessary to have function name and view name to be same.As I told am a beginner to this framework.So please co-operate and provide your precious feedback.
Function name and view name do not need to be the same. Your view can be anything you want it to be so long as you call the filename (and sometimes path) correctly :)
The biggest problem I see here is you are trying to access some object called posts, which I do not see defined. I have a good hunch you're looking for the "input" object provided by code igniter.
That being said, replace:
$this->post->get_posts();
With:
$this->input->post(NULL,true);//return all post objects with cross site scripting scrub
And replace:
$this->post->get_post_by_ID($postID);
With:
$this->post->post('postID',true);//same as above, except again, with XSS scrub enabled.
If this is not your answer and you need me to re-evaluate, please let me know in a comment and I'll redo the answer.
With regards to your page not found issue, it's because Codeigniter automatically assumes the paths depending on what you name your functions. It uses the following convention by default (routes.php allows you to override this in config/routes.php)
site.com/index.php/controller_name/method_name/param_1/param_2/param_n
Or if you have mod_rewrite taking out the front controller
site.com/controller_name/method_name/param_1/param_2/param_n
Since the view is loaded from the controller function itself, if you change the name of that function, then the URL will no longer be able to "find" it, hence the error.
thanks to help me.
In CodeIgniter, I have a Controller named "Idee" in which there is this function :
public function index(){
$this->load->model("idee");
echo "Doesn t go ahead";
$data['idees'] = $this->idee->getAll();
var_dump($data);
$this->load->view("view_home", $data);
}
But when I try the URL, the page is blank, and even the echo is not reached.
It is weir because I already did this on others page, and it's working.
Could you help me please ? Thanls a lot !
You need to name your model something different from your controller. It is failing because you are trying to redeclare the same class (Idee). Usually in CodeIgniter you would call your model something like Idee_m (the file and class).
how do I make available some data for a layout/layout.phtml script without having to create a view script from a controller?
I've tried the following in indexAction function, but it does not work. When I do not create the view script I get an error. I could created empty one, but I don't like this solution much. Any better ideas?
$this->layout->content = "foo"
$this->_helper->viewRenderer->setNoRender(true);
Thanks in advance
You don't actually render some data you make the data available and then choose which script to render. Don't confuse the terminology.
What you have done there is stopped any script from being rendered by using the :
$this->_helper->viewRenderer->setNoRender(true);
When you do
$this->layout->content = "foo";
You are setting the property content, which you then neeed to make use in your layout script.
So then in your layout.phtml script (which I hope you have already configured to render by efault) you then just do this
echo $this->content
Notice that I don't actually use $this->layout because when you are inside the layout, $this equal $this->layout. The same goes for $this->view->foo is $this->foo inside your view.
I hope this helps.
Any questions just ask.