I'd like to extract the numbers specifically with a PHP regex expression, I don't get the regex very much although I'm currently trying with the regex101 website. Thing is, I have this:
66
28006 MadridVer teléfono
(Literally that, it's seen with a lot of more spaces and 28006 MadridVer teléfono is presented in the next line actually). And I'd like to extract the number 28006 or at least split the findings of the expression in a way I have the 28006 separately in one of the groups. What would be my php regex expresion like? Maybe apart from capturing spaces I should capture a new line or something. But I am totally lost in this (yes, I'm an absolute regex novice yet).
I don't see a need for regex.
Remove the new line and explode on space.
Then use array_filter to remove empty values from the array and rearrange the array with array_values.
$str = "66
28006 MadridVer teléfono";
$str = str_replace("\n", " ", $str);
$arr = explode(" ", $str);
$arr = array_values(array_filter($arr));
var_dump($arr);
Returns:
array(4) {
[0]=>
string(2) "66"
[1]=>
string(5) "28006"
[2]=>
string(9) "MadridVer"
[3]=>
string(9) "teléfono"
}
Related
I'm trying to split a string that can either be comma, space or semi-colon delimitted. It could also contain a space or spaces after each delimitter. For example
chr1:22222-333333 or
chr1 22222 333333 or
chr1 22222 333333 or
chr1:22,222-33,333
Any one of these would produce an array with three values ["chr1","22222","33333"], I have tried some method, but it not all complete. especially the fourth case.
Thank you very much for help me.
$yourString = "chr1:22222-33333"; // for instance
$output = preg_split("/:| |;/", $yourString);
This acts as an equivalent of explode() but when you want multiple delimiters.
Explanation of the characters in the preg_split statement:
/ acts to enclose the regular expression, as to say ok, that's happening here
| acts as a OR statement, as if to tell this OR this OR that
So that in the end, /:| |;/ means select anything that is ":" or " " or ";"
If you want to practice or simply understand better the principles of RegEx, you can have a look to this nice collection of RegEx tutorials
you can use str_replace with explode
$str = array('chr1:22222-333333', 'chr1 22222 333333', 'chr1 22222 333333', 'chr1:22,222-33,333');
foreach($str as $val){
var_dump(explode(" ", str_replace(array(',',':','-'), array('',' ', ' '), $val)));
}
which pretty much removes all , then replaces : AND - with a space then explodes with spaces as a delimiter.
Demo
which produces
array(3) {
[0]=>
string(4) "chr1"
[1]=>
string(5) "22222"
[2]=>
string(6) "333333"
}
array(3) {
[0]=>
string(4) "chr1"
[1]=>
string(5) "22222"
[2]=>
string(6) "333333"
}
array(3) {
[0]=>
string(4) "chr1"
[1]=>
string(5) "22222"
[2]=>
string(6) "333333"
}
array(3) {
[0]=>
string(4) "chr1"
[1]=>
string(5) "22222"
[2]=>
string(5) "33333"
}
If you value conciseness and want to keep things neat, preg_split is the best way to go, in my opinion.
In the following examples, I assume you want your input separated by commas, spaces or colons:
$splitted = preg_split("/[,: ]/", $string);
If you want to treat tabs as whitespaces, you can replace the single space character with \s, which will match tabs as well:
$splitted = preg_split("/[,:\s]/", $string);
Note: The \s will match newlines too, if your input may eventually be a multline string.
Yet, if you don't trust your input (You don't, right?) and think that perhaps subsequent spaces and/or tabs should be ignored and treated as single spaces, you can go with this version:
$splitted = preg_split("/,|:|\s/", $string);
All the forms above work great provided the input you presented. If you want to play with these a little, this is a nice place to do so.
I'm using explode to parse a string of comma separated values into variables. No problem there. The issue I'm having is that one of the values is a date in the format: May 3, 2013. So the explode is picking up on the comma in the date. Do I have any options for getting around this? I don't have much control over the source (the original string) so I'm trying to come up with a way to work with what I've got.
$CONTENT = 'blue,red,purple,May 2, 2013,orange,green';
list($valueA, $valueB, $valueC, $valueD, $valueE, $valueF) = explode(',', $CONTENT);
Thank you!
You can use regex to split your string. This is based on the assumption, that there is not whitespace between two words if it is used as a seperator.
$CONTENT = 'blue,red,purple,May 2, 2013,orange,green';
$result = preg_split('/,(?! )/', $CONTENT);
your string will result correctly in
array(6) {
[0]=>
string(4) "blue"
[1]=>
string(3) "red"
[2]=>
string(6) "purple"
[3]=>
string(11) "May 2, 2013"
[4]=>
string(6) "orange"
[5]=>
string(5) "green"
}
so once you are using your list expression again, your variables should be set correctly
list($valueA, $valueB, $valueC, $valueD, $valueE, $valueF) = preg_split('/,(?! )/', $CONTENT);
Escape the comma by finding the value in the array and replacing the comma with a special symbol, then after the explode replace the special symbol with a comma.
The only thing I can think of is to use a regular expression to look for something matching the pattern of a date, replace the comma with something else, then after you explode the string, replace that special character with a comma again.
It's messy, but if you genuinely have no control over the string coming in, there's probably not a lot you can do.
I have for example such string - "7-th Road" or "7th number some other words" or "Some word 8-th word".
I need to get the first occurrence of number and all other next symbols to first occurrence of space.
So for examples above i need such values "7-th", "7th", "8-th".
And then from these matches like "7-th" i need extract only numbers in other operations.
Thanks in advance!
Regex should be /(\d+)([^\d]+)\s/ and the numbers would resolve to $1 and the ending characters to $2
Sample Code:
$string = '7-th Road';
preg_match_all('/(\d+)([^\d]+)\s/', $string, $result, PREG_PATTERN_ORDER);
var_dump($result[1]);
array(1) {
[0]=> string(1) "7"
}
var_dump($result[2]);
array(1) {
[0]=> string(1) "-th"
}
Are you asking for something like this?
#(\d+)-?(?:st|nd|rd|th)#
Example
If you would like to get just nums from the text use it:
preg_match_all('/(\d+)[th|\-th]*?/','7-th", "7th", "8-th', $matches);
But if you would like to remove 'th' or other just do replacement:
preg_replace('/(\d+)[th|\-th]*?/','$1', 'some string')
Not sure about the last one...
I need to use a regex pattern , but what is the right php "decode" . my pattern is "similar" to BBcode i.e. ['something'] the 'something' could be "any length" but realistically I doubt not more than 10 chars/numbers. What is the correct php syntax to "unscrambe" i.e.
if ($row->xyz =['something'] ):
do this
else:
do that
endif;
Thanks in advance
A basic regexp to match BBCode style tags would look something like this:
preg_match('/\[[\/]?[A-Za-z0-9]+\]/', $row->xyz)
That will match anything that starts with a "[", ends with a "]", and has one or more alphanumeric characters in the middle (with an optional "/" for an end-tag.) Note it has flaws - for example, if you have a nested "[...]" in a larger "[...]", it will only grab the inner one. (i.e. [foo[bar]] will return only "[bar]".)
Example:
<?php
$regexp = '/\[[\/]?[A-Za-z0-9]+\]/';
$testString = '[i]An italic string with some [b]bold[/b] text.[/i]';
preg_match_all($regexp, $testString, $result);
print_r($result);
?>
Result:
array(1) {
[0]=> array(4) {
[0]=> string(3) "[i]"
[1]=> string(3) "[b]"
[2]=> string(4) "[/b]"
[3]=> string(4) "[/i]"
}
}
Of course, I'm not sure this is what you actually mean you want to do, but it is what you say you want to do. Are you sure you want to find BBCodes, rather than find strings that are wrapped in them?
I'm trying to use PHP's split() (preg_split() is also an option if your answer works with it) to split up a string on 2 or more \r\n's. My current effort is:
split("(\r\n){2,}",$nb);
The problem with this is it matches every time there is 2 or 3 \r\n's, then goes on and finds the next one. This is ineffective with 4 or more \r\n's.
I need all instances of two or more \r\n's to be treated the same as two \r\n's. For example, I'd need
Hello\r\n\r\nMy\r\n\r\n\r\n\r\n\r\n\r\nName is\r\nShadow
to become
array('Hello','My','Name is\r\nShadow');
preg_split() should do it with
$pattern = "/(\\r\\n){2,}/";
What about the following suggestion:
$nb = implode("\r\n", array_filter(explode("\r\n", $nb)));
It works for me:
$nb = "Hello\r\n\r\nMy\r\n\r\n\r\n\r\n\r\n\r\nName is\r\nShadow";
$parts = split("(\r\n){2,}",$nb);
var_dump($parts);
var_dump($parts === array('Hello','My',"Name is\r\nShadow"));
Prints:
array(3) {
[0]=>
string(5) "Hello"
[1]=>
string(2) "My"
[2]=>
string(15) "Name is
Shadow"
}
bool(true)
Note the double quotes in the second test to get the characters represented by \r\n.
Adding the PREG_SPLIT_NO_EMPTY flag to preg_replace() with Tomalak's pattern of "/(\\r\\n){2,}/" accomplished this for me.
\R is shorthand for matching newline sequences across different operating systems. You can prevent empty elements being created at the start and end of your output array by using the PREG_SPLIT_NO_EMPTY flag or you could call trim() on the string before splitting.
Code: (Demo)
$string = "\r\n\r\nHello\r\n\r\nMy\r\n\r\n\r\n\r\n\r\n\r\nName is\r\nShadow\r\n\r\n\r\n\r\n";
var_export(preg_split('~\R{2,}~', $string, 0, PREG_SPLIT_NO_EMPTY));
echo "\n---\n";
var_export(preg_split('~\R{2,}~', trim($string)));
Output from either technique:
array (
0 => 'Hello',
1 => 'My',
2 => 'Name is
Shadow',
)