Can someone help me return a value? - php

I have created a loop which returns a random number between two values. Cool.
But now I want the script to return the following value too: The number of unique numbers between two similar numbers.
Example:
4
5
8
22
45
3
85
44
4
55
15
23
As you see there is a double which is the four and there are 7 numbers inbetween. So I would like the script to echo these numbers two so in this case it should echo 7 but if there are more doubles in the list it should echo all the numbers between certain doubles.
This is what I have:
for ($x = 0; $x <= 100; $x++) {
$min=0;
$max=50;
echo rand($min,$max);
echo "<br>";
}
Can someone help me or guide me? I'm learning :)
Thanks!

So You need to seperate script for three parts:
getting randoms and save them to array (name it 'result'),
analyze them,
print (echo) results
Simply - instead of printing every step of loop, save them to array(), exit loop, analyze every item with other, example:
take i element of list
check is i+j element is the same
if is it the same - save j-i to second array() (name it 'ranges')
And after this, print two arrays (named by me as 'result' and 'ranges')
UPDATE:
Here's solution, hope You enjoy:
$result = array(); #variable is set as array object
$ranges = array(); #same
# 1st part - collecting random numbers
for ($x = 0; $x < 20; $x++)
{
$min=0;
$max=50;
$result[] = rand($min,$max); #here's putting random number to array
}
$result_size = count($result); #variable which is containg size of $result array
# 2nd part - getting ranges between values
for ($i = 0; $i < $result_size; $i++)
{
for ($j = 0; $j < $result_size; $j++)
{
if($i == $j) continue; # we don't want to compare numbers with itself,so miss it and continue
else if($result[$i] == $result[$j])
{
$range = $i - $j; # get range beetwen numbers
if($range > 0 ) # this is for miss double results like 14 and -14 for same comparing
{
$ranges[$result[$i]] = $range;
}
}
}
}
#3rd part - priting results
echo("RANDOM NUMBERS:<br>");
foreach($result as $number)
{
echo ("$number ");
}
echo("<br><br>RANGES BETWEEN SAME VALUES:<br>");
foreach($ranges as $number => $range)
{
echo ("For numbers: $number range is: $range<br>");
}
Here's sample of echo ($x is set as 20):
RANDOM NUMBERS:
6 40 6 29 43 32 17 44 48 21 40 2 33 47 42 3 22 26 39 46
RANGES BETWEEN SAME VALUES:
For numbers: 6 range is: 2
For numbers: 40 range is: 9

Here is your fish:
Put the rand into an array $list = array(); and $list[] = rand($min,$max); then process the array with two for loops.
$min=0;
$max=50;
$list = array();
for ($x = 0; $x <= 100; ++$x) {
$list[] = rand($min,$max);
}
print "<pre>";print_r($list);print "</pre>";
$ranges = array();
$count = count($list);
for ($i = 0; $i < $count; ++$i) {
$a = $list[$i];
for ($j = $i+1; $j < $count; ++$j) {
$b = $list[$j];
if($a == $b) {
$ranges[] = $j-$i;
}
}
}
print "<pre>";print_r($ranges);print "</pre>";

Related

PHP: for loop $i value turns zero if the number is greater

I want to turn the $i variable value to start counting from 1 if the given value is greater than 10:
here is what i am trying to achieve
<?php
$givenValue = 15; //number of x value
for ($i = 1; $i < $givenValue; $i++) {
if ($givenValue > 10){
$i = 1;
}
echo $i."<br>";
}
?>
This is how i want my result to look like
output: 1
output: 2
output: 3
output: 4
output: 5
output: 6
output: 7
output: 8
output: 9
output: 10
output: 1
output: 2
output: 3
output: 4
output: 5
in for loop body
Any help is welcome
You can use modulo calculation to get the result you want.
I also changed your if from $givenvalue to $i as $givenvalue will "always" be 10+.
$givenValue = 15; //number of x value
for ($i = 1; $i <= $givenValue; $i++) {
if ($i > 10){
Echo $i%10 . "\n";
}else{
echo $i . "\n";
}
}
https://3v4l.org/5afc5
Another option, if that is possible for you, is to start at zero and only use modulo calculation and add one to it to get the same result.
This also means I need to stop the loop at <$givenvalue as your original code shows.
$givenValue = 15; //number of x value
for ($i = 0; $i < $givenValue; $i++) {
Echo $i%10+1 . "\n";
}
https://3v4l.org/r0sgA
A method that uses less looping is to add 10 to the loop on each iteration and create the values using range().
Then add them to the array with array_merge, and output with implode.
$givenValue = 47; //number of x value
$breakpoint = 10;
$arr=[];
For($i = $breakpoint; $i< $givenValue;){
// Add new values from 1-$breakpoint in array
$arr = array_merge($arr, range(1,$breakpoint));
$i +=$breakpoint;
}
// Loop will exit before all values been collected
// Add the rest of the values
$arr = array_merge($arr, range(1,$givenValue-($i-10)));
// Echo the values in array
Echo implode("\n", $arr);
https://3v4l.org/jGsO4
Your code can be written like this:
<?php
$givenValue = 15; //number of x value
for ($i = 1; $i <= $givenValue; $i++)
{
if ($i > 10)
{
$i = 1;
$givenValue-=10;
}
echo "output: $i\n";
}
?>
http://sandbox.onlinephpfunctions.com/code/ed34d8dcd12a9a5a866b73338ad1209f55298519
You are resenting the counter, I would expect the behaviour you have. To do what you want add another counter to the mix
$j=1;
$givenValue = 15; //number of x value
for ($i = 1; $i <= $givenValue; $i++) {
if ($j > 10){
$j = 1;
}
echo $j."\n";
++$j;
}
You also had several missing ;
Output:
1
2
3
4
5
6
7
8
9
10
1
2
3
4
5
If you want to end on 5 you have to do 16 as the $givenValue or change it to <= less than or equal
See it here live
See what I have now, the $i variable counts to the $givenValue then the $j variable counts along side it, but with a range of 1-10 ( resets to 1 after 10 )

Print all combination of sub range within a given array

I want to print all combination of sub range in an given array. I have an array of y number of elements in it from which I want to print all combination of contiguous sub range.
Constraint is : each sub range should have at least 2 elements and each element in sub range should be contiguous. It should share same border of each element.
For example, We have an array of 7 elements [11,12,13,14,11,12,13]
So, the total number of sub range combination will [7 * (7-1) /2] = 21
So, the Output will be something like this:
11,12
12,13
13,14
14,11
11,12
12,13
11,12,13
12,13,14
13,14,11
...
11,12,13,14 and so on (total 21 combination as per above array)
we should not print any combination which is not contiguous. example: [11,12,14] is not valid combination as it skips the element "13" in between.
I am able to print the combination with 2 elements but i am having difficulty in printing more then 2 elements combination.
Below is what I have tried so far.
$data=array("11","12","13","14","11","12","13");
$totalCount=count($data);
for($i=0;$i<$totalCount;$i++){
if(($i+1) < ($totalCount)){
echo "[".$data[$i].",".$data[$i+1]."]<br>";
}
}
You can do that:
$arr = [11,12,13,14,11,12,13];
function genComb($arr, $from = 1, $to = -1) {
$arraySize = count($arr);
if ($to == -1) $to = $arraySize;
$sizeLimit = $to + 1;
for ($i = $from; $i < $sizeLimit; $i++) { // size loop
$indexLimit = $arraySize - $i + 1;
for ($j = 0; $j < $indexLimit; $j++) { // position loop
yield array_slice($arr, $j, $i);
}
}
}
$count = 0;
foreach (genComb($arr, 2) as $item) {
echo implode(',', $item), PHP_EOL;
$count++;
}
echo "total: $count\n";
Casimir et Hippolyte was faster, but you can gain huge performance by processing each contiguous section independently:
function getCombos(&$data) {
$combos = array();
$count = count($data);
$i = 0;
while ($i < $count) {
$start = $i++;
while ($i < $count && $data[$i - 1] + 1 == $data[$i]) // look for contiguous items
$i++;
if ($i - $start > 1) // only add if there are at least 2
addCombos($data, $start, $i, $combos); // see other answer
}
return $combos;
}

Simple PHP program requires less time to execute

i had applied for a job recently and the requirement was to complete a test and then interview
2 questions were given for test which was very simple and i did it successfully but still i was told that i have failed the test because the script took more than 18 seconds to complete execution. here is the program i dont understand what else i could do to make it fast. although i have failed the test but still wants to know else i could do?
Program language is PHP and i had to do it using command line input
here is the question:
K Difference
Given N numbers , [N<=10^5] we need to count the total pairs of numbers that have a difference of K. [K>0 and K<1e9]
Input Format:
1st line contains N & K (integers).
2nd line contains N numbers of the set. All the N numbers are assured to be distinct.
Output Format:
One integer saying the no of pairs of numbers that have a diff K.
Sample Input #00:
5 2
1 5 3 4 2
Sample Output #00:3
Sample Input #01:
10 1
363374326 364147530 61825163 1073065718 1281246024 1399469912 428047635 491595254 879792181 1069262793
Sample Output #01:
0
Note: Java/C# code should be in a class named "Solution"
Read input from STDIN and write output to STDOUT.
and this is the solution
$fr = fopen("php://stdin", "r");
$fw = fopen("php://stdout", "w");
fscanf($fr, "%d", $total_nums);
fscanf($fr, "%d", $diff);
$ary_nums = array();
for ($i = 0; $i < $total_nums; $i++) {
fscanf($fr, "%d", $ary_nums[$i]);
}
$count = 0;
sort($ary_nums);
for ($i = $total_nums - 1; $i > 0; $i--) {
for ($j = $i - 1; $j >= 0; $j--) {
if ($ary_nums[$i] - $ary_nums[$j] == $diff) {
$count++;
$j = 0;
}
}
}
fprintf($fw, "%d", $count);
Your algorithm's runtime is O(N^2) that is approximately 10^5 * 10^5 = 10^10. With some basic observation it can be reduced to O(NlgN) which is approximately 10^5*16 = 1.6*10^6 only.
Algorithm:
Sort the array ary_nums.
for every i'th integer of the array, make a binary search to find if ary_nums[i]-K, is present in the array or not. If present increase result, skip i'th integer otherwise.
sort($ary_nums);
for ($i = $total_nums - 1; $i > 0; $i--) {
$hi = $i-1;
$low = 0;
while($hi>=$low){
$mid = ($hi+$low)/2;
if($ary_nums[$mid]==$ary_nums[$i]-$diff){
$count++;
break;
}
if($ary_nums[$mid]<$ary_nums[$i]-$diff){
$low = $mid+1;
}
else{
$hi = $mid-1;
}
}
}
}
I got the same question for my technical interview. I wonder if we are interviewing for the same company. :)
Anyway, here is my answer I came up with (after the interview):
// Insert code to get the input here
$count = 0;
sort ($arr);
for ($i = 0, $max = $N - 1; $i < $max; $i++)
{
$lower_limit = $i + 1;
$upper_limit = $max;
while ($lower_limit <= $upper_limit)
{
$midpoint = ceil (($lower_limit + $upper_limit) / 2);
$diff = $arr[$midpoint] - $arr[$i];
if ($diff == $K)
{
// Found it. Increment the count and break the inner loop.
$count++;
$lower_limit = $upper_limit + 1;
}
elseif ($diff < $K)
{
// Search to the right of midpoint
$lower_limit = $midpoint + 1;
}
else
{
// Search to the left of midpoint
$upper_limit = $midpoint - 1;
}
}
}
#Fallen: Your code failed for the following inputs:
Enter the numbers N and K: 10 3
Enter numbers for the set: 1 2 3 4 5 6 7 8 9 10
Result: 6
I think it has to do with your calculation of $mid (not accounting for odd number)

Modulus inside loop

I have an array that I am looping through and breaking up into chunks of 50. However occasionally the number of items inside that array are more than what fits inside that chunk of 50 ex.:
$array = array(); // has 220 rows
for ($i = 0; $i < count($array); $i++) {
$j[] = $i;
if ($i % 50 == 1) {
print_r($j); // do something here with the 50 rows
$j = null;
}
}
The problem here is that this will not print anything after 201. I know there is some algebraic math involved in solving this but I am drawing a blank. Its times like these where I really wish I had paid attention in math class back in high school.
I think array_chunk fits up your requirement and no maths required.
$result_array = array_chunk($array, 50, true);
Add additional condition
if ($i % 50 == 1 || count($array)-1 == $i)
You just have to redeclare the array is my guess:
$array = array(); // has 220 rows
for ($i = 0; $i < count($array); $i++) {
$j[] = $i;
if ($i % 50 == 1) {
print_r($j); // do something here with the 50 rows
$j = array() ;
}
}
Once you perform $j = null there is no way you can do $j[] = $i
$array = array(); // has 220 rows
for ($i = 0; $i < count($array); $i++) {
$j[] = $i;
if ($i % 50 == 1) {
doSomething($j); // do something here with the 50 rows
$j = array(); // reset the array
}
}
doSomething($j); // with the last 20 entries
After your loop is finished, you will have the remaining 201 through 220 entries in $j, so just do your stuff again.
array_chunk
might be useful. Basically splits the array into chunks returning a multi dimensional array

How do I distribute values of an array in three columns?

I need this output..
1 3 5
2 4 6
I want to use array function like array(1,2,3,4,5,6). If I edit this array like array(1,2,3), it means the output need to show like
1 2 3
The concept is maximum 3 column only. If we give array(1,2,3,4,5), it means the output should be
1 3 5
2 4
Suppose we will give array(1,2,3,4,5,6,7,8,9), then it means output is
1 4 7
2 5 8
3 6 9
that is, maximum 3 column only. Depends upon the the given input, the rows will be created with 3 columns.
Is this possible with PHP? I am doing small Research & Development in array functions. I think this is possible. Will you help me?
For more info:
* input: array(1,2,3,4,5,6,7,8,9,10,11,12,13,14)
* output:
1 6 11
2 7 12
3 8 13
4 9 14
5 10
You can do a loop that will automatically insert a new line on each three elements:
$values = array(1,1,1,1,1);
foreach($values as $i => $value) {
printf('%-4d', $value);
if($i % 3 === 2) echo "\n";
}
EDIT: Since you added more information, here's what you want:
$values = array(1,2,3,4,5);
for($line = 0; $line < 2; $line++) {
if($line !== 0) echo "\n";
for($i = $line; $i < count($values); $i+=2) {
printf('%-4d', $values[$i]);
}
}
And if you want to bundle all that in a function:
function print_values_table($array, $lines = 3, $format = "%-4d") {
$values = array_values($array);
$count = count($values);
for($line = 0; $line < $lines; $line++) {
if($line !== 0) echo "\n";
for($i = $line; $i < $count; $i += $lines) {
printf($format, $values[$i]);
}
}
}
EDIT 2: Here is a modified version which will limit the numbers of columns to 3.
function print_values_table($array, $maxCols = 3, $format = "%-4d") {
$values = array_values($array);
$count = count($values);
$lines = ceil($count / $maxCols);
for($line = 0; $line < $lines; $line++) {
if($line !== 0) echo "\n";
for($i = $line; $i < $count; $i += $lines) {
printf($format, $values[$i]);
}
}
}
So, the following:
$values = range(1,25);
print_array_table($values);
Will output this:
1 10 19
2 11 20
3 12 21
4 13 22
5 14 23
6 15 24
7 16 25
8 17
9 18
One solution is to cut the array into chunks, representing the columns, and then print the values in row order:
$cols = array_chunk($arr, ceil(count($arr)/3));
for ($i=0, $n=count($cols[0]); $i<$n; $i++) {
echo $cols[0][$i];
if (isset($cols[1][$i])) echo $cols[1][$i];
if (isset($cols[2][$i])) echo $cols[2][$i];
}
If you don’t want to split your array, you can also do it directly:
for ($c=0, $n=count($arr), $m=ceil($n/3); $c<$m; $c++) {
echo $arr[$c];
for ($r=$m; $r<$n; $r+=$m) {
echo $arr[$c+$r];
}
}
$a = array(1,2,3,4,5);
"{$a[0]} {$a[1]} {$a[2]}\n{$a[3]} {$a[4]}";
or
$a = array(1,2,3,4,5);
"{$a[0]} {$a[1]} {$a[2]}".PHP_EOL."{$a[3]} {$a[4]}";
or
$a = array(1,2,3,4,5);
$second_row_start = 3; // change to vary length of rows
foreach( $a as $index => $value) {
if($index == $second_row_start) echo PHP_EOL;
echo "$value ";
}
or, perhaps if you want a longer array split into columns of 3?
$a = array(1,2,3,4,5,6,7,8,9,10,11,12,13);
$row_length = 3; // change to vary length of rows
foreach( $a as $index => $value) {
if($index%$row_length == 0) echo PHP_EOL;
echo "$value ";
}
which gives
1 2 3
4 5 6
7 8 9
10 11 12
13
one solution is :
your array has N elements, and you want 3 columns, so you can get the value of each cell with $myarray[ column_index + (N/3) + line_index ] (with one or two loops for columns and lines, at least for lines)
I hope this will help you
Bye
Here's something I whipped up. I'm pretty sure this could be more easily accomplished if you were using HTML lists, I've assumed you can't use them.
$arr = array(1,2,3,4,5,6,7,8,9,10,11,12,13,14, 15, 16);
$max = count($arr);
$cols = 3;
$block = ceil($max / $cols);
for ($i = 0; $i < $block ; $i++) {
echo $arr[$i] . ' ';
for ($j = 1; $j < $cols; $j++) {
$nexKey = $i + $block * $j;
if (!isset($arr[$nexKey])) break;
echo $arr[$nexKey] . ' ';
}
echo '<br>';
}
NOTE : You can easily refactor the code inside the loop that uses $nexkey variable by making it into a loop itself so that it works for any number of columns. I've hardcoded it.
Uses loops now.

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