Get value of select, from a list of users - php

i have a table of users, where a user has a name, a surname, a right, and a "commit changes" button. This way, i want to assign rights to a person. Every column has the userID in it, and the whole thing is created from a database.
This is my dropdown to assign a right.
<form id="myForm" method="post" autocomplete="off">
<select name="rightsDropdownOptions" method="post">
<option value="admin">Admin</option>
<option value="masterEditor">MasterEditor</option>
<option value="modulEditor">ModulEditor</option>
<option value="teacher">Lehrer</option>
<option value="teacherAndEditor">Lehrer+Editor</option>
</select>
</form>
This is my php-code, which is executed by clicking the commitchangestorightsbutton
if ( isset($_POST['commitChangesOnRightsButton']) ){
$user = $_POST['commitChangesOnRightsButton'];
echo "<script>alert(".$user.");</script>";
$var = $_POST['rightsDropdownOptions'];
if($var == "1"){
echo "<script>alert(".$var.");</script>";
}
}
If i click the button now i get the following error:
Undefined index: rightsDropdownOptions in C:\xampp\htdocs\Iiigel\PHP\AdminGivePermission.php
I've been working on this for a while now, and i dont knwo how to solve this, id be glad if someone could help.

As highlighted by #Dharman you are making mistake in your code firstly you have to define post parameter "commitChangesOnRightsButton" into your code like this:
<form id="myForm" method="post" autocomplete="off" action"">
<select name="rightsDropdownOptions" method="post">
<option value="admin">Admin</option>
<option value="masterEditor">MasterEditor</option>
<option value="modulEditor">ModulEditor</option>
<option value="teacher">Lehrer</option>
<option value="teacherAndEditor">Lehrer+Editor</option>
</select>
<button type="submit" value="Assign" name="commitChangesOnRightsButton" />
</form>
Hope this will help!

Related

multiple select value foreach in php

Ok i have the problem! :)
I have a two same name select in my page ( if statement handling ) and i forgot add value options for one.... my bad :) Thanks for replys!
I have a multiple selection in my page:
<select multiple="multiple" name="diff[]">
<option value="1">Easy</option>
<option value="2">Medium</option>
<option value="3">Hard</option>
</select>
And i want to get the option-s value so:
foreach($_POST['diff'] as $key) {
echo $key;
}
I want to option values but i get this values -> Easy, Medium, Hard.
How i can acces the value="" attribute ?
Thanks dudes!
Your code should work, I guess the problem is how you post it.
Here is a little sample code, tested on my server. It gives the desierd ouput:
Edited Code:
<form class="form-inline" method="POST" action="">
<select multiple="multiple" name="diff[]">
<option value="1">Easy</option>
<option value="2">Medium</option>
<option value="3">Hard</option>
</select>
<button type="submit" class="button" name="mentes" id="mentes" title="Mentés az adatbázisba">Send</button>
</form>
<?php
if(!empty($_POST["diff"])) {
foreach($_POST['diff'] as $key) {
echo $key;
}
}
?>
When I select "easy" and press "Go" -> Output: 1
This works for all the other inputs as well.

How to return a URL and submit the form using onchange

Firstly, there may be a similar question answered amoungst the site but after carefully considering what solutions and problems I'm still stumped as to what to do.
I'm looking to return a URL and post my users to a page of the chosen URL from a select list.
Currently it works using the normal submit button using the following code;
<form id="formurl" name="formurl" method="post" action="" onSubmit="return getURL(this.url.value)">
<!-- begin postcode list -->
<select size="1" name="url" id="posctode_srch" onchange="this.form.submit()">
<option value="e1-office-space/">E1</option>
<option value="e7-office-space/">E7</option>
<option value="e10-office-space/">E10</option>
<option value="e11-office-space/">E11</option>
<option value="e14-office-space/">E14</option>
<option value="e15-office-space/">E15</option>
<option value="e16-office-space/">E16</option>
<option value="e17-office-space/">E17</option>
<option value="ec1-office-space/">EC1</option>
<option value="ec2-office-space/">EC2</option>
<option value="ec3-office-space/">EC3</option>
<option value="ec4-office-space/">EC4</option>
</select>
<input type="image" src="images/graphics/new/btn_go.png" class="go_btn" width="119" border="0" value="submit" onclick="_gaq.push(['_trackEvent', 'Contact', 'AreaSearchForm',,, false]);" alt="Area search submit" />
</form>
I'm looking to use post but I am testing it with get to see what result is created when choosing an option. when the form is set to get i'm seeing ?url=e7-office-space%2F so am I safe to assume it's working to some degree but there is something missing for the output to just take the value of the option and nothing more?
Being new to this kind of stuff i'm guessing it's a php / html problem as the functionality is there it's just a misused element somewhere so if anyone can help me see where i'm going wrong i'd really appreciate it.
Thanks
You have three things -
setting the url
setting the google stuff
submitting the form if not in the submit event
In the code below you can omit the image if you can rely on javascript only
DEMO
window.onload=function() {
document.getElementById("formurl").onsubmit=function() {
var val = this.url.value;
if (val=="") {
alert("Please select a value");
return false;
}
this.action="http://bing.com/search?q="+val;
_gaq.push(['_trackEvent', 'Contact', 'AreaSearchForm',,, false]);
}
document.getElementById("posctode_srch").onchange=function() {
var val = this.value;
if (val=="") return;
this.form.onsubmit(); // not 100% sure but this should not trigger twice
this.form.submit(); // since this is not triggering onsubmit
}
}
using
<form id="formurl" name="formurl" method="post" action="">
<!-- begin postcode list -->
<select size="1" name="url" id="posctode_srch">
<option value="">Please select</option>
<option value="e1-office-space/">E1</option>
<option value="e7-office-space/">E7</option>
<option value="e10-office-space/">E10</option>
<option value="e11-office-space/">E11</option>
<option value="e14-office-space/">E14</option>
<option value="e15-office-space/">E15</option>
<option value="e16-office-space/">E16</option>
<option value="e17-office-space/">E17</option>
<option value="ec1-office-space/">EC1</option>
<option value="ec2-office-space/">EC2</option>
<option value="ec3-office-space/">EC3</option>
<option value="ec4-office-space/">EC4</option>
</select>
<input type="image" src="images/graphics/new/btn_go.png"
class="go_btn" width="119" border="0" value="submit"
alt="Area search submit" />
</form>

Simple PHP select option programming

I have a simple problem in php select option.
The page has 5 select option & submit button. When I select a option then it should goes on specific web page. For Example: http://onlinetools.org/tricks/using_multiple_select.php
Then I select a option & press Send then It show Which option I select. But I need go specific webpage.
I have tried with this code but I have failed...
<form action="<?=$_SERVER['PHP_SELF']?>" method="post">
<select name="test[]" multiple="multiple">
<option value="http://google.com">one</option>
<option value="http://yahoo.com">two</option>
<option value="http://facebook.com">three</option>
<option value="http://who.is">four</option>
<option value="http://myspace.com">five</option>
</select>
<input type="submit" value="Send" />
</form>
<?php
$test=$_POST['test'];
echo "
<script type=\"text/javascript\">
window.location = \"$test\"
</script>
";
?>
Anybody Can help me?
This should be a simple select not a multiple one since you want to redirect to only one site. here is the code :
<?php
$test=$_POST['test'];
if(isset($test)){
header("Location: $test");
}
?>
<form action="<?=$_SERVER['PHP_SELF']?>" method="post">
<select name="test">
<option value="http://google.com">one</option>
<option value="http://yahoo.com">two</option>
<option value="http://facebook.com">three</option>
<option value="http://who.is">four</option>
<option value="http://myspace.com">five</option>
</select>
<input type="submit" value="Send" />
</form>
As you've declared:
<select name="test[]" multiple="multiple">
test is an array, thus you have to take the first object of the array or remove the unused []. By the way, you can do an HTTP redirection, which is faster and works more often than javascript ones.

php filter by dropdown without submit button

ive got the code below set up. but how do i filter the result without submit button and filtering the result based on dropdown value (id for user)?
form method="post" name="report_filter" action="<?= $_SERVER['PHP_SELF'];?>" >
select name="name" onchange="report_filter.submit();">
<option value="--">Filter by:</option>
<option value="1">Andi</option>
<option value="2">Katy</option>
<option value="3">Max</option>
<select>
PHP //
<? if(isset($_POST['submit'])):
$mem->StaffTodayFilterSummary($_GET('value'));
else :
$mem->StaffToday();
endif;
?>
</form>
You need to change name="report_filter" to id="report_filter".
Then change your onchange event to say onchange="document.getElementById('report_filter').submit()"
Here's the full code:
<form method="post" id="report_filter" action="<?= $_SERVER['PHP_SELF'];?>" >
<select name="name" onchange="document.getElementById('report_filter').submit();">
<option value="--">Filter by:</option>
<option value="1">Andi</option>
<option value="2">Katy</option>
<option value="3">Max</option>
<select>
<?
if(isset($_POST['name'])):
$mem->StaffTodayFilterSummary($_POST['name']);
else :
$mem->StaffToday();
endif;
?>
</form>
I changed isset() to check POST['name'] and set the filter summary to pass in $_POST['name'] as well. I don't know where $_GET('value') was trying to get anything from but unless it's in the URL I don't see how it would work.

HTML form submit to PHP script

I am making an HTML form. I want the results to appear in the PHP script.
<form action="chk_kw.php" method="post"> <br />
<select> name="website_string"
<option value="" selected="selected"></option>
<option VALUE="abc"> ABC</option>
<option VALUE="def"> def</option>
<option VALUE="hij"> hij/option>
</select>
<input type="submit" name="website_string" >
</form>
The problem is I cannot get the value passed to the PHP. if I use value:
<INPUT TYPE="submit" name="website_string" value="selected" >
It always passes the text in the quotes. In this case "selected". How do I pass one of the strings from the option?
Try this:
<form method="post" action="check.php">
<select name="website_string">
<option value="" selected="selected"></option>
<option VALUE="abc"> ABC</option>
<option VALUE="def"> def</option>
<option VALUE="hij"> hij</option>
</select>
<input TYPE="submit" name="submit" />
</form>
Both your select control and your submit button had the same name attribute, so the last one used was the submit button when you clicked it. All other syntax errors aside.
check.php
<?php
echo $_POST['website_string'];
?>
Obligatory disclaimer about using raw $_POST data. Sanitize anything you'll actually be using in application logic.
<form method="POST" action="chk_kw.php">
<select name="website_string">
<option selected="selected"></option>
<option value="abc">abc</option>
<option value="def">def</option>
<option value="hij">hij</option>
</select>
<input type="submit">
</form>
As your form gets more complex, you
can a quick check at top of your php
script using print_r($_POST);,
it'll show what's being submitted an the respective element name.
To get the submitted value of the element in question do:
$website_string = $_POST['website_string'];
It appears that in PHP you are obtaining the value of the submit button, not the select input. If you are using GET you will want to use $_GET['website_string'] or POST would be $_POST['website_string'].
You will probably want the following HTML:
<select name="website_string">
<option value="" selected="selected"></option>
<option value="abc">ABC</option>
<option value="def">def</option>
<option value="hij">hij</option>
</select>
<input type="submit" />
With some PHP that looks like this:
<?php
$website_string = $_POST['website_string']; // or $_GET['website_string'];
?>
Assuming you've fixed the syntax errors (you've closed the select box before the name attribute), you're using the same name for the select box as the submit button. Give the select box a different name.
For your actual form, if you were to just post the results to your same page, it should probably work out all right. Try something like:
<form action=<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?> method="POST>
Here is what I find works
Set a form name
Use a default select option, for example...
<option value="-1" selected>Please Select</option>
So that if the form is submitted, use of JavaScript to halt the submission process can be implemented and verified at the server too.
Try to use HTML5 attributes now they are supported.
This input
<input type="submit">
should be
<input name="Submit" type="submit" value="Submit">
whenever I use a form that fails, it is a failure due to the difference in calling the button name submit and name as Submit.
You should also set your enctype attribute for your form as forms fail on my web host if it's not set.

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