I have a blog and want to include the Users Name when shown to the public.
When creating the blog I make sure to include the user_id in the blogs table
In my Blog model I have the following:
public function users()
{
return $this->belongsTo(User::class);
}
In my Users model I have:
public function blogs()
{
return $this->hasMany(Blog::class);
}
In my Blog Controller I have:
public function index(User $user)
{
$users = User::get();
$blogs= DB::table('blogs')->where('user_id', '=', $users->id)->orderBy('id', 'DESC')->paginate(6);
return view('blogs.index',compact('blogs'));
}
Then in my view:
#foreach($blogs as $blog)
<h1>{{$blog->title}}</h1>
Source:{{$blog->users->first_name}} // This does not work
Source:{{$blog->first_name}} // This does not work either
#endforeach
I thought I could do something like this to show the names:
{{ $blogs->users->first_name }} {{ $blogs->users->last_name }}
But this isn't working either...
Try this:
#foreach($blogs as $blog)
<h1>{{$blog->title}}</h1>
{{$blog->user->first_name}}
#endforeach
And on your Blog Model
public function user()
{
return $this->belongsTo(User::class);
}
In your Blog controller the variable $blog needs to be $blogs. You also have extra characters (right parenthesis) in your Blade. It should be:
#foreach($blogs as $blog)
Source: {{ $blog->user->first_name }}
...
#endforeach
Blog Model
This function replaces the old "users" function, as only one user is returned (belongsTo is a singular relationship).
class Blog extends Model
{
public function user()
{
return $this->belongsTo('App\User');
}
}
User Model
public function blogs()
{
return $this->hasMany('App\Blog');
}
Controller Function
And, as such, you can cut down your controller code, including removing the redundant elements.
public function index(User $user)
{
$blogs = Blog::where('user_id', '=', $user->id)->orderBy('created_at','desc')->paginate(6);
return view('blogs.index', compact('blogs'));
}
The way you did is called Query Builder
$blogs= DB::table('blogs')->where('user_id', '=', $users->id)->orderBy('id', 'DESC')->paginate(6);
Query Builder does not support lazy loading, cause lazy loading is only supported for the Eloquent method
$blog->users->first_name
For Eloquent way you can try this instead:
$blogs = Blog::where('user_id', $user->id)->get()
foreach($blogs as $blog){
dd($blog->user); // you will get the user detail here
}
For lazy loading have a performance issue when come to load heavy data so to prevent lazy loading can use this
$blogs = Blog::with('user')->where('user_id', $user->id)->get()
For more information can look at Eloquent Relationship Documentation
For query builder, the only way to link your user is use join, which will be something like this
$blogs = DB::table('blogs')
->join('users', 'users.id', '=', 'blogs.user_id')
->get();
foreach($blogs as $blog){
dd($blog->first_name) // user first name
}
For more information can look at Query Builder Join
BlogController.php
public function index(){
$blogs = Blog::with('user')->get();
return view('blogs.index')->with('blogs',$blogs);
}
Blog.php
public function user()
{
return $this->belongsTo('App\User');
}
User.php
public function blogs()
{
return $this->hasMany('App\Blog');
}
Related
Hellow guys,
so I have 2 tables
is Listings
is Users
in Listings I have some columns, one is user_id, and is related to users tables.
I want to display the user name related to the user table.
in the index blade, I use some tags.
But when I use ->rightjoin("users", "users.id", "=", "listings.user_id") it's works but,
the join broke my tags make them default, same with others posts.
public function index(Request $request)
{
$listings = Listing::where('is_active', true)->with('tags')
//->rightjoin("users", "users.id", "=", "listings.user_id") //don't show tags of the posts
->orderBy('listings.created_at', 'desc')
->get();
//check if posts ar listing by last date or something
$tags = Tag::orderBy('name') // variable displayed in view
->get();
You could just use the with method to get the related user like this
public function index(Request $request) {
$listings = Listing::where('is_active', true)->with(['user', 'tags'])
->orderBy('listings.created_at', 'desc')
->get();
}
but make sure that you add to your Listing model the correct relation like this
Listing Model
public function user() {
return $this->belongsTo(User::class);
}
I recommend this code for controller:
public function index(Request $request) {
return $listings = Listing::query()
->where('is_active', true)->with(['user', 'tags'])
->orderBy('listings.created_at', 'desc')
->get();
}
In the models section, I suggest you put this code:
public function user() {
return $this->belongsTo(User::class);
}
I suggest you fill in the fields foreignKey, ownerkey in relation: as in the following example:
public function user()
{
return $this->belongsTo(User::class, 'user_id', 'id');
}
Here is the Controller code I have
public function index()
{
$ajobs = Job::all();
return view('jobs_all', ['jobs' => $ajobs]);
}
This shows all my Table Data. I have stored user id as another column named created_by
In the View, I get value by ID, how how can I get the Username from Users table.
#foreach ($jobs as $ajob)
{{ $ajob->created_by }} //Here instead of UserID, how can i get Username by matching the UserID with UsersTable ?
#endforeach
Add next method to your "Job" model:
public function user(): BelongsTo
{
return $this->belongsTo(User::class, 'created_by');
}
now you can add ORM param "with" to your method "index":
public function index() {
$ajobs = Job::with('user')
->all();
return view('jobs_all', ['jobs' => $ajobs]); }
now we have access to user model fields, and you can show them this way:
#foreach($jobs as $ajob)
{{ $ajob->user->name }}
#endforeach
More info about laravel relations here: https://laravel.com/docs/8.x/eloquent-relationships#one-to-one
you can use laravel eloquent belongsTo relationship. in your Job model add the following method.
public function user()
{
return $this->belongsTo(User::class, 'created_by');
//assuming your user model name is User and both models are in the same namespace. if not, adjust according to your structure.
}
and then you can use this relationship to get the user name like
#foreach ($jobs as $ajob)
{{ $ajob->user->name }}
//name is the column name from the user table. change if necessary.
#endforeach
You can use relations but in fast way on your situation you can join your tables:
$user_id = DB::table('jobs')
->select('users.id')
->join('jobs', 'jobs.user_id', '=', 'users.id')
->get();
=> add on your job table as foreginId user
$table->timestamp('created_at')->useCurrent();
$table->foreignId('created_by')->constrained('users')->onUpdate('cascade')->onDelete('cascade');
**That Function add on job model**
public function getCreatedAttribute()
{
return ucfirst($this->user->name);
}
=>relationship add on job table
public function user()
{
return $this->belongsTo(User::class,'id','created_by');
}
=>created display your user name
#foreach ($jobs as $ajob)
{{ $ajob->created}}
#endforeach
=>listing controller
public function index() {
$jobs = Job::with(['user']);
return view('jobs_all', compact('jobs')); }
I'm trying write an website with Laravel (current version is 5.7) and I have 3 models as: Post, User and Fav. I'm using a simple form to add posts to "favs" table which has 3 columns as; id, user_id and post_id. And I want to list posts that user added favorites bu I can't use "hasMany" method properly.
I can use variables like; $post->user->name but I can't figure it out how to use relationship with "favs" table.
Post Model
public function user() {
return $this->belongsTo('App\User');
}
public function favs() {
return $this->hasMany('App\Fav');
}
Fav Model
public function users() {
return $this->hasMany('App\User');
}
public function posts() {
return $this->hasMany('App\Post', 'post_id', 'id');
}
User Model
public function posts() {
return $this->hasMany('App\Post');
}
public function favs() {
return $this->hasMany('App\Fav');
}
Controller
public function user($id){
$favs = Fav::orderBy('post_id', 'desc')->get();
$user = User::find($id);
$posts = Post::orderBy('id', 'desc')->where('user_id', $id)->where('status', '4')->paginate(10);
return view('front.user')->with('user', $user)->with('posts', $posts)->with('favs', $favs);
}
The Fav model only has one User and Post each, so you need to use belongsTo() instead of hasMany and change the method names to singular. You can also remove the additional parameters in post() since they're the default values.
public function user() {
return $this->belongsTo('App\User');
}
public function post() {
return $this->belongsTo('App\Post');
}
Loading all Posts that a user has favorited:
$user->favs()->with('post')->get();
The with() method is used to eager load the relationship.
Now you can loop through the Favs:
#foreach($favs as $fav)
{{ $fav->post->name }}
#endforeach
I think you can change these two lines of your code to
$posts = Post::orderBy('id', 'desc')->where('user_id', $id)->where('status', '4')->paginate(10);
return view('front.user')->with('user', $user)->with('posts', $posts)->with('favs', $favs);
to
$posts = Post::where('user_id', $id)->where('status', '4')->latest()->paginate(10);
return view('front.user', compact('user', 'posts', 'favs'));
And for retrieving favorite posts of an user,
if you will change the fav table to make it a pivot table only to handle a many to many relationships between Post and User, you can get it as $user->posts, for a separate model, I think you can consider something like $user->favs and in view
In Fav model
public function user() {
return $this->belongsTo('App\User');
}
public function post() {
return $this->belongsTo('App\Post');
}
and in view
#foreach ( $user->favs as $fav )
{{ $fav->post->id }}
#endforeach
If an User, per example, have many Favs you need to use a Iteration Block, like foreach.
Example:
foreach($user->favs as $fav) {
dd($fav) // do something
}
Ps.: Be careful not to confuse hasMany and belongsToMany.
In my routes/web.php I have a route like this...
Route::get('/tags/{tag}', 'TagsController#show');
Then, inside TagsController because I have a post_tag pivot table that has been defined as a many-to-many relationship.
Tag.php...
public function posts(){
return $this->belongsToMany(Post::class);
}
public function getRouteKeyName(){
return 'name';
}
Post.php...
public function tags(){
return $this->belongsToMany(Tag::class);
}
I get the posts for a certain tag like this...
public function show(Tag $tag){
$posts = $tag->posts;
return view('posts.index', compact('posts','tag'));
}
Then, to sort the posts into newest first I can do this in index.blade.php...
#foreach ($posts->sortByDesc('created_at') as $post)
#include('posts.post')
#endforeach
This works fine, but I'm doing the re-ordering at collection level when I'd prefer to do it at query level.
From Eloquent: Relationships I can see that I can do something like this, which also works...
$user = App\User::find(1);
foreach ($user->roles as $role) {
//
}
But, something like this does not seem to work...
public function show($tag){
$posts = \App\Tag::find($tag);
return view('posts.index', compact('posts'));
}
My question is, how can I filter/order the data at a query level when using pivot tables?
To order your collection you must change
public function tags(){
return $this->belongsToMany(Tag::class);
}
to
public function tags(){
return $this->belongsToMany(Tag::class)->orderBy('created_at');
}
Extending #leli. 1337 answer
To order content without changing the relation created.
First, keep the original relation
class User
{
public function tags
{
return $this->belongsToMany(Tag::class);
}
}
Second, during query building do the following
//say you are doing query building
$users = User::with([
'tags' => function($query) {
$query->orderBy('tags.created_at','desc');
}
])->get();
With this, you can order the content of tags data and in query level also if needed you can add more where clauses to the tags table query builder.
I'm trying to make a RBAC in my own forum software.
For so far, the permissions work, but the problem is, when I want to add colors to usernames (what MyBB also has) something doesn't work and I don't understand it propperly.
So I have an ForumController with this code inside:
<?php
class ForumController extends \BaseController {
public function index()
{
$forums = Forums::orderBy('disp_order', 'asc')->get();
$categories = Categorie::orderBy('disp_order', 'asc')->get();
return View::make('index')->with('forums', $forums)->with('categories', $categories);
}
public function forum($name)
{
$forums = Forums::where('name', '=', str_replace('Forum-', '',str_replace('-', ' ', $name)))->first();
$categories = Categorie::orderBy('disp_order', 'asc')->get();
return View::make('forum')->with('forums', $forums)->with('categories', $categories);
}
public function categorie($name)
{
$categories = Categorie::where('name', '=', str_replace('Categorie-', '',str_replace('-', ' ', $name)))->first();
$threads = Thread::orderBy('date_posted', 'asc')->get();
return View::make('categorie')->with('categories', $categories)->with('threads', $threads);
}
public function thread($title)
{
$thread = Thread::where('title', '=', str_replace('Thread-', '',str_replace('-', ' ', $title)))->first();
$comments = Comment::orderBy('posted_at', 'asc')->get();
return View::make('thread')->with('threads', $thread)->with('comments', $comments);
}
}
Good, everything of that works.
But now I need to get the roles for users inside of the function thread.
I also have these models:
There is only an extend to Eloquent and the protected $table inside of these files.
The scheme of my role table looks like this:
I did hear somethig about belongsTo and hasMany, but I really don't understand it...
I want to be able to get the right color on the right user.
So the scheme of the user table:
I hope someone can help me out, because I'm looking for the answer a long time.
I'm using Laravel4
Kindest regards,
Robin
You're right, you need to add some relationships:
// In Comment.php, assuming that your comments table has a user_id field.
public function user()
{
return $this->belongsTo(User::class);
}
// In User.php
public function role()
{
return $this->belongsTo(Role::class);
}
Then adjust your controller to eager load these relationships.
$comments = Comment::orderBy('posted_at')->with('user.role')->get();
Now you can show the color next to a comment in your blade template like:
#foreach ($comments as $comment)
<p>Color: {{ $comment->user->role->colour }}</p>
#endfoeach