PHP: issue with switch statement (wrong return) - php

I have this method:
private function convertStatusStringToIntZeroOrOne(string $status)
{
$status = strtolower($status);
switch ($status) {
case "off":
case "0":
case 0:
$int_status = 0;
break;
case "on":
case "1":
case 1:
$int_status = 1;
break;
default:
$int_status = 1;
break;
}
return $int_status;
}
The $status parameter, when is the string "On" (with O letter capitalize), return 0 (zero).
Of course, I need return as 1.
Thank you

As you had numeric 0 and 1 in the options of the switch it was using a numeric comparison - "on" to a number is 0 and so it matched against 0.
As you have the parameter as type string a number would be converted to a string, so remove the numeric comparisons...
function convertStatusStringToIntZeroOrOne(string $status)
{
$status = strtolower($status);
switch ($status) {
case "off":
case "0":
$int_status = 0;
break;
case "on":
case "1":
$int_status = 1;
break;
default:
$int_status = 1;
break;
}
return $int_status;
}
echo convertStatusStringToIntZeroOrOne("On");
Although you could reduce the function to...
function convertStatusStringToIntZeroOrOne(string $status)
{
$status = strtolower($status);
return ($status == "off" || $status == 0)?0:1;
}

Related

PHP, switch case returned undefined variable

Hy,
I got switch case inside function when but when i call it, i got error Undefined Variable and i don't know why (i use PHP 8)
private function getIDFromBrand() {
switch ($this->brand) {
case "Niky":
$id = 1;
break;
case "Pumo":
$id = 4;
break;
case "Coke":
if ($this->typecoke== 0) {
$id = 2;
} else {
if ($this->typecoke== 1) {
$id = 3;
}
}
break;
case "Tomato":
$id = 5;
break;
case "Riles":
$id = 6;
break;
case "TEST":
$id = 7;
break;
}
return $id; // Error Undefined variable $id
}
When i declare $id at the top of my function, like
$id = null
or
$id = 0
The switch doesn't update it, so it will return null or 0, it will return the declared value.
Your switch statement has no default branch, so if $this->brand is, say, "Stack Overflow", it will not run any of the statements, and $id will never be set.
See the PHP manual for the switch statement:
A special case is the default case. This case matches anything that wasn't matched by the other cases.
Similarly, if $this->brand is "Coke", but $this->typecoke is, say, 42, it will not match either of the conditions in that branch.
switch ($this->brand) {
case "Niky":
$id = 1;
break;
case "Pumo":
$id = 4;
break;
case "Coke":
if ($this->typecoke== 0) {
$id = 2;
} elseif ($this->typecoke== 1) {
$id = 3;
} else {
$id = -1; // WAS PREVIOUSLY NOT SET
}
break;
case "Tomato":
$id = 5;
break;
case "Riles":
$id = 6;
break;
case "TEST":
$id = 7;
break;
default:
$id = -1; // WAS PREVIOUSLY NOT SET
break;
}

How to use switch in php

if (isset($_POST["submit"])){
$oride='';
$count = "25";
$origin = $_POST["origin"];
$destinataion = $_POST["destination"];
$oride = ($destination = $_POST["destination"] - $origin= $_POST["origin"]);
switch (true) {
case ($count<="0"):
echo "invalid";
break;
case ($count==="15"):
echo $count;
break;
case ($count==="16"):
$total = $count + "1";
echo $total;
break;
default:
echo "hello";
} }
The code will compute 1st then execute switch depending on what is the result of the computation. I tried if else but it will be too long because the case will go up to 130.
You must use the var $count in switch statement and the constant in case this way
switch ($count) {
case "0" :
echo "invalid";
break;
case "15":
echo $count;
break;
case "16":
$total = $count + "1";
echo $total;
break;
default:
echo "hello";
break;
}
You have to provide an expression to the switch statement, while the case statements are just "versions" of the result of that expression. The only thing you can NOT do directly is the "<= 0" expression, but you can work around it:
if (isset($_POST["submit"])){
$oride='';
$count = "25";
$origin = $_POST["origin"];
$destinataion = $_POST["destination"];
$oride = ($destination = $_POST["destination"] - $origin= $_POST["origin"]);
// --- normalize $count:
$count = $count <= 0 ? 0 : $count;
// use $count as expression:
switch ($count) {
case 0:
echo "invalid";
break;
case "15":
echo $count;
break;
case "16":
$total = $count + "1";
echo $total;
break;
default:
echo "hello";
} }

PHP switch strange behavoiur with zero value and strings

Going immediately to the point:
in this code I expect the default case:
<?php
$a = 0;
switch ($a) {
case "one":
echo "one";
break;
case "two":
echo "two";
break;
default:
echo "default";
break;
}
?>
I get one instead.
here expect the zero case ("two"):
<?php
$a = 0;
switch ($a) {
case "one":
echo "one";
break;
case 0:
echo "two";
break;
default:
echo "default";
break;
}
?>
I get one instead.
That appens only with zero value because here I get correctly default:
<?php
$a = 1;
switch ($a) {
case "one":
echo "one";
break;
case "two":
echo "two";
break;
default:
echo "default";
break;
}
?>
but here I get correctly zero:
<?php
$a = 0;
switch ($a) {
case 1:
echo "one";
break;
case 0:
echo "zero";
break;
default:
echo "default";
break;
}
?>
Why?

Update PHP variable in switch statement (simple)

In PHP, I have a value outside of a switch called $chickens, equal to 1. After going through a switch statement, I want the value to change to b.
//original value of var
$chickens = 1;
switch ($chickens) {
case "0":
$chickens === "a";
break;
case "1":
$chickens === "b";
break;
case "2":
$chickens === "c";
break;
case "3":
$chickens === "b";
break;
}
//want this to be "b" defined in switch
echo $chickens;
For some reason the value does not update :(. Any Ideas
You're using the wrong operator. = is the assignment operator. === is a comparison operator:
//original value of var
$chickens = 1;
switch ($chickens) {
case "0":
$chickens = "a";
break;
case "1":
$chickens = "b";
break;
case "2":
$chickens = "c";
break;
case "3":
$chickens = "d";
break;
}
//want this to be "b" defined in switch
echo $chickens;

My PHP code is not working properly

I´m trying to do some program which would transfer hexa do binary. Problem is in changing of A,B,C,..,F to 10,11,12,...,15 so i can work with them as with numbers. I made this function:
function odstran_pismena($pole)
{
$dlzka = count($pole);
for ($i = 0; $i< $dlzka; $i++)
switch ($pole[$i])
{
case 0: break;
case 1: break;
case 2: break;
case 3: break;
case 4: break;
case 5: break;
case 6: break;
case 7: break;
case 8: break;
case 9: break;
case ("A" || "a"): $pole[$i] = 10;
break;
case ("B" || "b"): $pole[$i] = 11;
break;
case ("C" || "c"): $pole[$i] = 12;
break;
case ("D" || "d"): $pole[$i] = 13;
break;
case ("E" || "e"): $pole[$i] = 14;
break;
case ("F" || "f"): $pole[$i] = 15;
break;
default: $pole[$i] = "ERROR";
break;
}
return $pole;
}
First i made array from string, and now i want to change letters to numbers.
I´m testing it with this string: $test = "AbCdEf2345";
I was expecting result 10 11 12 13 14 15 2 3 4 5 but all i have is 10 10 10 10 10 10 2 3 4 5
Am I doing some mystake?(Of course I am, but where?)
("A" || "a") evaluates to boolean value 'true', so all a to f will get caught by the case ("A" || "a" ) and result in 10.
Without using the hexdec() and with minimal change to your code:
function odstran_pismena($pole)
{
$dlzka = count($pole);
for ($i = 0; $i< $dlzka; $i++)
switch ($pole[$i])
{
case 0: break;
case 1: break;
case 2: break;
case 3: break;
case 4: break;
case 5: break;
case 6: break;
case 7: break;
case 8: break;
case 9: break;
case "A":
case "a": $pole[$i] = 10;
break;
case "B":
case "b": $pole[$i] = 11;
break;
case "C":
case "c": $pole[$i] = 12;
break;
case "D":
case "d": $pole[$i] = 13;
break;
case "E":
case "e": $pole[$i] = 14;
break;
case "F":
case "f": $pole[$i] = 15;
break;
default: $pole[$i] = "ERROR";
break;
}
return $pole;
}
When you have specified case ("A" || "a"): $pole[$i] = 10; it evaluates to true. So all your chars matched against true returns true. for 'case' conditions avoid using expressions. Use the static values your comparing such as
case "A":
case "a":
$pole[$i] = 10;
break;
An easy way to help you with that would be to use a strtolower:
switch(strtolower($pole[$i])) {
case "a" :...
break;
case "b": ...
break;
}
or simply, as the first line of your function:
$pole = strtolower($pole);
This way you won't have to bother with upper/lower casing.
You should use hexdec() and replace you whole for loop with:
for ($i = 0; $i< $dlzka; $i++)
{
$pole[$i] = hexdec($pole[$i]);
}
Note that you will receive a 0 for non-valid values so you might have to check for that separately if it can happen, using for example is_numeric on the original value.

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