I have Users table which has under_reference column that represents by whom this user was referred.
I want to order user by having highest under_reference count. How to order by counting under reference
$data['user'] = User::orderBy('id','DESC')->get();
$data['user'] = User::select(DB::raw('count(*) as total'))
->groupBy('under_reference')
->orderBy('under_reference','DESC')
->get();
Here is the query that can help you. You can get the total users referred by a person and orderBy reference.
Use Group By for this situation, and sort from it. Here's an example.
$query = [
'name',
'email',
// store count of under_reference as total
DB::raw('count(under_reference) as total')
];
$sorted = User::groupBy('name', 'email')
->select($query)
->orderBy('total', 'desc') // remember total before, sort it by desc or asc
->get();
You can refer from laravel documentation here on raw expressions
The name and email is just an examaple, as you didn't show us what your table's column looks like. But you should get a pretty rough idea
i created another column totalref with Integer . i coded logic to update this column also with referral bonus and then orderby totalref. and it worked like magic
Try this:
$user_info = DB::table('users')
->select('under_reference',DB::raw('count(under_reference) as ur'))
->groupBy('under_reference')
->orderBy('ur','DESC')
->get();
You can try in this way also worked.
$data['user'] = DB::select('SELECT *` FROM `user` ORDER BY
CAST(`under_reference` AS decimal) DESC');
You can cast the DB column varchar to decimal in query.
Related
I have a table (A) that has a One to Many relation with another table (B).
I want to query Table A and eager load Table B with the Table A results - but I also want to sort Table A by a value in Table B.
I have tried using OrderBy in the query and also trying SortBy on the resultant collection but cannot get the Table A data to be sorted by the value found in Table B.
Example of what I have tried:
$query = ModelA::with("ModelB"])->get()->sortByDesc('ModelB.sortValue');
Keep in mind, I am only interested in the LATEST record from Table B. So I need to query Table A and sort by a value in the LATEST records of Table B.
How can I achieve this?
EDIT:
The below (as suggested by #ljubadr) works pretty close, but the issue is that there are many record in Table B which means that it doesn't reliably sort as it doesn't seem to sortby the latest records in Table B. Can I have the join return ONLY the latest record for each ID?
$query = ModelA::select('TableA.*')
->join('TableB', 'TableA.id', '=', 'TableB.col_id')
->groupBy('TableA.id')->orderBy('TableB.sortCol', 'desc')
->with(['x'])
->get();
EDIT 2:
#Neku80 answer has gotten me closest but it seems to not sort the column with the greatest accuracy.. I'm sorting a Decimal column and for the most part it is in order but in some places the items are out of order..
$latestTableB = ModelB::select(['TableA_id', 'sortByColumnName'], DB::raw('MAX(created_at) as created_at'))
->groupBy('TableA_id');
$query = ModelA::select('TableA.*')
->joinSub($latestTableB, 'latest_TableB', function ($join) {
$join->on('TableA.id', '=', 'latest_TableB.TableA_id');
})
->orderBy('latest_TableB.sortByColumnName')
->get();
For example, the ordering is like:
0.0437
0.0389
0.0247 <-- -1
0.025 <-- +1
0.0127
When I delete all rows except for the 'latest' rows, then it orders correctly, so it still must be ordering with old data...
I have found a solution:
ModelA::select('TableA.*', 'TableB.sortByCol as sortByCol')
->leftJoin('TableB', function ($query) {
$query->on('TableB.TableA_id', '=', 'TableA.id')
->whereRaw('TableB.id IN (select MAX(a2.id) from TableB as a2 join TableA as u2 on u2.id = a2.TableA_id group by u2.id)');
})
->orderBy('TableB.sortByCol')
->get();
Another alternative to order is like this:
$users = User::orderBy(
Company::select('name')
->whereColumn('companies.user_id', 'users.id'),
'asc'
)->get();
Here we are ordering in asc order by company name field.
In this article it is explained in detail.
You can simply execute a left join query:
ModelA::query()->leftJoin('model_b_table', 'model_a_table.primary_key', '=', 'model_b_table.foreign_key')->orderBy('model_a_table.target_column')->get();
This should work if you only need TableB's ID and created_at columns:
$latestTableB = ModelB::select('TableA_id', DB::raw('MAX(created_at) as created_at'))
->groupBy('TableA_id');
$query = ModelA::select('TableA.*')
->joinSub($latestTableB, 'latest_TableB', function ($join) {
$join->on('TableA.id', '=', 'latest_TableB.TableA_id');
})
->orderBy('latest_TableB.created_at')
->get();
I have a column move_out that stores date in this format - m/Y e.g 02/2020. I want to order the records in that table by the move_out column in descending order but my solution don't seem to be working. It does not arrange the records appropriately. This is what I am doing.
$data = User::orderBy('move_out', 'DESC')->get();
How do I solve this?
The datatype for the move_out column is string.
try STR_TO_DATE
$data = User::orderBy(DB::raw("STR_TO_DATE(CONCAT('01-', move_out),'%d-%m/%Y')"), 'DESC')->get();
Try to use DATE_FORMAT:
$items = DB::table("users")
->orderBy(DB::raw("DATE_FORMAT(move_out,'%M/%Y')"), 'DESC')
->get();
This query is for getting other data with the highest value of date with the group by/unique. Here I used unique in place of group by.
My question is how to get min(date) and max(date) with group by/unique.
The group by/unique is for Dataset table's date field.
I have searched for this but not getting exact solution that how to get max and min date with group by/unique in laravel eloquent.
In table structure, there are multiple entries for one code so here I used group by/unique to get one record for the code.
There can be multiple dates as 02-01-2003,01-03-2007,01-01-2019, 01-07-2018... etc. with same/ different code. If I group by with code then get onmy one record per code. So here I want to select the max date [01-01-2019] and min date [02-01-2003].
Thanks in advance.
Controller:
$datasets = Dataset::where('user_id', $user_id)
->orderBy('date','desc')
->get(['code', 'access','user_id','date'])
->unique('code');
Finally I got solution but this can not be the exact solution but as I am beginner and not getting the exact solution I do this functionality as below:
I created two different queries to get min and max values.
$min_datasets = Dataset::where('user_id', $user_id)
->orderBy('date','asc')
->get(['code', 'access','user_id','date'])
->unique('code');
$max_$datasets = Dataset::where('user_id', $user_id)
->orderBy('date','desc')
->get(['code', 'access','user_id','date'])
->unique('code');
Try to select max and min date like this:
$datasets = Dataset::select('code', 'access','user_id', DB::raw('MAX(date) as max_date'), DB::raw('MIN(date) as min_date'))
->where('user_id', $user_id)
->orderBy('date','desc')
->get()
->unique('code');
$data = DB::table('table_name')->where('user_id',$user_id)
->select('code','access','user_id','date')
->whereBetween('date', [02-01-2003, 01-01-2019])
->groupBy('unique_column')
->get()
I'm trying to fetch following things from the database:
user name
user avatar_name
user avatar_filetype
complete conversation_messages
with the following query:
static public function getConversation($id)
{
$conversation = DB::table('conversation_messages')
->where('belongsTo', $id)
->join('users', 'conversation_messages.sender', '=', 'users.id')
->join('user_avatars', 'conversation_messages.sender', '=', 'user_avatars.id')
->select('users.name', 'conversation_messages.*', 'user_avatars.name', 'user_avatars.filetype')
->get();
return $conversation;
}
It works fine so far, but the avatar's column name is 'name' like the column name from the 'users' table.
So if I'm using this query the to get the output via $conversation->name, the avatar.name overwrites the users.name
Is there a way to rename the query output like the mysql "as" feature at laravel 5.1?
For example:
$conversation->avatarName
$conversation->userName
Meh okay.. i've found a simple solution here
->select('users.name as userName', 'conversation_messages.*', 'user_avatars.name as avatarName', 'user_avatars.filetype')
As you can mention I've added the requested "as-Feature" next to the table.columnName
Take a look at this example of trying to join three tables staffs, customers and bookings(pivot table).
$bookings = \DB::table('bookings')
->join('staffs', 'staffs.id' , '=', 'bookings.staff_id')
->join('customers', 'customers.id' , '=', 'bookings.customer_id')
->select('bookings.id', 'bookings.start_time', 'bookings.end_time', 'bookings.service', 'staffs.name as Staff-Name', 'customers.name as Customer-Name')
->orderBy('customers.name', 'desc')
->get();
return view('booking.index')
->with('bookings', $bookings);
I had the following problem, simplified example:
$result = Donation::join('user', 'user.id', '=', 'donation.user_id')->where('user.email', 'hello#papabello.com')->first();
$result is a collection of Donation models. BUT CAREFUL:
both tables, have a 'created_at' column. Now which created_at is displayed when doing $result->created_at ? i don't know. It seems that eloquent is doing an implicit select * when doing a join, returning models Donation but with additional attributes. created_at seems random. So what I really wanted, is a return of all Donation models of the user with email hello#papabello.com
solution is this:
$result = Donation::select('donation.*')->join('user', 'user.id', '=', 'donation.user_id')->where('user.email', 'hello#papabello.com')->first();
Yeah, simply rename the column on either table and it should work.
Also what you can do is, rename the user.name column to anything, also rename sender column of conversation_messages to id and perform a natural join.
I have a query like this:
$users = DB::table('users')->join('user_roles','users.role_id','=','user_roles.id')->get();
and a table that has a column id (users.id) and another table that has columns id and user_id (user_roles.id & user_roles.user_id),
but the problem is.. what is being returned on $user->id is the user_roles.id instead of the users.id column.. how do i fix this so that what i get is not the role id but the user id instead..
thanks!
Found it!
using ->select('users.*', 'user_roles.role_name') i was able to remove user_roles.id from the returned values and thus eliminating the conflict.
Here is the final query:
$users = DB::table('users')->join('user_roles','users.role_id','=','user_roles.id')->select('users.*', 'user_roles.role_name')->get();
The better way to do this is using 'as':
$users = DB::table('users')->join('user_roles','users.role_id','=','user_roles.id')->get(array('users.*', '**user_roles.id as user_roles_id**', 'user_roles.*'));