Create json with php from all data from the database - php

Question

I want to create json which contains all orders from datebase. I tried to write this code but it returns only one order.
$query = mysql_query("SELECT * FROM orders WHERE id_user = '".$userdata['user_login']."' ORDER BY `nom` ASC ");
if ($query)
{
$i = 0;
while ($row = mysql_fetch_assoc($query))
{
$where=$row["where"];
$time_min=$row["time_min"];
$time_max=$row["time_max"];
$date1=$row["date1"];
$date2=$row["date2"];
$from=$row["from"];
$id=$row["id"];
$orders =[
'from' => $from,
'where' => $where,
'time_min' => $time_min,
'time_max' => $time_max,
'date1' => $date1,
'date2' => $date2,
'id' => $id];
$i++;
}
}
$data = [
'count' =>$i,
'orders' => $orders
];
header('Content-type: application/json');
echo json_encode( $data );
exit;
Now the response looks like this:
But I want like this:

Answer 1

Append to the $orders array:
$query = mysql_query("SELECT * FROM orders WHERE id_user = '".$userdata['user_login']."' ORDER BY `nom` ASC ");
if ($query)
{
$i = 0;
while ($row = mysql_fetch_assoc($query))
{
$where=$row["where"];
$time_min=$row["time_min"];
$time_max=$row["time_max"];
$date1=$row["date1"];
$date2=$row["date2"];
$from=$row["from"];
$id=$row["id"];
$orders[] =[ // <--- The difference
'from' => $from,
'where' => $where,
'time_min' => $time_min,
'time_max' => $time_max,
'date1' => $date1,
'date2' => $date2,
'id' => $id];
$i++;
}
}
$data = [
'count' =>$i,
'orders' => $orders
];
header('Content-type: application/json');
echo json_encode( $data );
exit;