post values from jquery are (id_workers: 1124,1545,4268)
$rows= array($_POST['id_workers']);
foreach($rows as $row) {
echo $row;// has to echo 112415454268
but its show 1124,1545,4268
}
// sample code workers perfectly
$rows= array(1124,1545,4268);
foreach($rows as $row) {
echo $row;// result 112415454268
}
unable to figure out the issue.
You are getting 1124,1545,4268 because $_POST['id_workers'] having string value comma separated like "1124,1545,4268".
When you try to use array("1124,1545,4268") it will use only 1 index like:
Array ( [0] => 1124,1545,4268 )
So, you need to use explode() here to convert string into an array like:
$rows= explode(",",$_POST['id_workers']);
foreach($rows as $row) {
echo $row; // 112415454268
}
If comma is an issue only, you can also use str_replace() to remove comma from a string like:
$rows = $_POST['id_workers'];
echo str_replace(",", "", $rows); // 112415454268
Related
Here's my Query
$rows = $mydb->get_results("SELECT title, description
FROM site_info
WHERE site_id='$id';");
I get something like:
Title1 Desc1
Title2 Desc2
etc.
I want to put that data in array so I do:
$data = array();
foreach ($rows as $obj) {
$data['title'] = $obj->title;
$data['description'] = $obj->description;
}
When I do:
print_r($data);
I only get title and description of first item... Please help :/ I checked and my query returns all what i want to be in array not only the first row.
You are over-writing array indexes each time in iteration.You need to create new indexes each time when you are assigning the values to array.
So either do:-
$data = array();
foreach ($rows as $key=>$obj) { // either use coming rows index
$data[$key]['title'] = $obj->title;
$data[$key]['description'] = $obj->description;
}
Or
$data = array();
$i=0; //create your own counter for indexing
foreach ($rows as $key=>$obj) {
$data[$i]['title'] = $obj->title;
$data[$i]['description'] = $obj->description;
$i++;// increase the counter each time after assignment to create new index
}
For display again use foreach()
foreach ($data as $dat) {
echo $dat['title'];
echo $dat['description'];
}
If the eventual goal is simply to display these values, then you shouldn't bother with re-storing the data as a new multi-dimensional array.
$rows = $mydb->get_results("SELECT title, description FROM site_info WHERE site_id='$id';");
If $id is user-supplied data or from an otherwise untrusted source, you should implement some form of sanitizing/checking as a matter of security. At a minimum, if the $id is expected to be an integer, cast it as an integer (an integer doesn't need to be quote-wrapped).
$rows = $mydb->get_results("SELECT title, description FROM site_info WHERE site_id = " . (int)$id);
When you want to display the object-type data, just loop through $rows and using -> syntax to echo the values.
echo "<ul>";
foreach ($rows as $obj) {
echo '<li>' , $obj->title , ' & ' , $obj->description , '</li>';
}
}
echo "</ul>";
If you have a compelling reason to keep a redundant / restructured copy of the resultset, then you can more simply command php to generate indexes for you.
foreach ($rows as $obj) {
$data[] = ['title' => $obj->title, 'id' => $obj->id];
}
The [] is just like calling array_push(). PHP will automatically assign numeric keys while pushing the associative array as a new subarray of $data.
Im getting the array from a function then using it on a foreach, it prints all rows, how can i print specific row when im using [0] after array it displays only first letters of both rows.
PHP FUNCTION:
public function selectedOffer($model_id){
$qq = mysqli_query($this->connection,"SELECT offerId FROM offers WHERE model_id='$model_id' ORDER BY id ASC");
$results = array();
while ($result = mysqli_fetch_array($qq)) {
$results[] = $result;
}
return $results;
}
FOREACH PHP
foreach ($mUser->selectedOffer($modelid) as $key) {
echo $key['offerId'][0];
}
also when i remove the [0] it prints both rows.
My question is how to print the first or second or which row i want?
To get specific/ first row,s column
$data = $mUser->selectedOffer($modelid);
echo $data[0]["offerId"];
And all rows column
foreach ($data as $key) {
echo $key['offerId'];
}
Use implode and array_column to echo a complete array column in one line of code:
echo implode("", array_column($yourarray, "offerId"));
The first argument of the implode is what should join the items in the array.
Your and the accepted answer has nothing that is why it's "", but it can be replaced with say: "<br>\n" if you want new line between each item of the array.
I am trying to save the rows (results) from an SQL query to a csv file.
I am using array push in order to put the results in a list. Later I put the data from this list to my csv file.
My code :
while ($row = $query->fetch_assoc())
{
echo sprintf( $row['campaign']);
array_push($list, $row['campaign']);
}
The results are there because sprintf works. The problem is with the syntax of array_push. I even tried :
array_push($list, array(''.$row['campaign']);
I am getting an error:
fputcsv() expects parameter 2 to be array
The full code is here :
$list = array
(
array('old_campaign_name', 'new_campaign_name')
);
// table 1
$sql = ('select distinct(campaign) as campaign from '.$table1.'');
// Run the query
$query = $Db->query($sql);
// Check for SQL errors
if ($Db->error)
{
return ($Db->error);
}
// Put data in the list
while ($row = $query->fetch_assoc())
{
echo sprintf( $row['campaign']);
array_push($list,$row['campaign'],'');
}
$fp = fopen($location, 'w');
foreach ($list as $fields)
{
fputcsv($fp, $fields);
}
fclose($fp);
As the error says, fputcsv expects each row that you put to be an array, so it can write it out with commas separating the elements. $list should be a 2-dimensional array, so you need to push an array onto it when you're building it.
while ($row = $query->fetch_assoc() {
$list[] = array($row['campaign']);
}
BTW, $list[] = x is equivalent to array_push($list, x).
When you initially create the $list array, it is an array containing one array. But when you add more values to it from your query results, you are pushing strings onto the end of it, not arrays. In effect, you will be making something like
$list = array (
array('old_campaign_name', 'new_campaign_name'),
'first campaign',
'second campaign',
'etc.',
...
);
Because of this, when you loop over $list, the first value should work with fputcsv, because it is an array, but any subsequent values will be strings instead of arrays and will cause the error you are seeing.
You should be able to fill the $list like this:
while ($row = $query->fetch_assoc()) {
$list[] = $row;
}
$list[] = $row will not overwrite the values previously in $list. From the PHP documentation for array_push:
Note: If you use array_push() to add one element to the array it's better to use $array[] = because in that way there is no overhead of calling a function.
It works like this :
while ($row = $query->fetch_assoc())
{
// array_push($list,$row['campaign'],'');
array_push($list,array($row['campaign'], ''));
}
I am fetching values from mysql table. I am then placing the values inside an array and using th php built function json_enconde to convert these values into a json format. I am getting results back but not in the desired format. In the php code you will notice I am using array and fetching values with a foreach loop to place all values inside. As a result I am getting back several json objects. How can I get back just one json object with the corresponding values?
header("Content-type: application/json");
$query = $db_con->prepare("SELECT id, name FROM table");
$query->execute();
$data = $course_query->fetchAll();
$json_data = array();
foreach ($data as $row) {
$json_data[] = array(
$row["id"] => $row["name"]
);
} // foreach ($data as $row) {
echo json_encode($json_data);
Results:
{
1: "Item1"
},
{
2: "Item2"
},
{
3: "Item3"
}
Desired Results:
{
"1":"Item1",
"2":"Item2",
"3":"Item3"
}
change this array( $row["id"] => $row["name"]);
to $json_data[$row["id"] ] = $row["name"] inside the for loop
foreach ($data as $row) {
$json_data[$row["id"] ] = $row["name"];
}
try this
foreach ($data as $row) {
$id=$row["id"];
$json_data[$id] =$row["name"];
}
The problem was that while defining the value in json_data in your foreach loop you are creating an array for every single value, so you are not getting the desired result.
You will need to change your PHP code to create a normal single dimensional array, right now you are creating a multidimensional array. Your PHP should be like this:
header("Content-type: application/json");
$query = $db_con->prepare("SELECT id, name FROM table");
$query->execute();
$data = $course_query->fetchAll();
$json_data = array();
foreach ($data as $row) {
$json_data[$row["id"]] = $row["name"];
} // foreach ($data as $row) {
echo json_encode($json_data);
Notice the change in the foreach loop, we are no longer appending a new array onto the $json_data array(which would create a multidimensional array). This will give you a single dimensional array with the proper key:value pairs. Then when you run the json_encode you will get your desired JSON format.
Using select query am select some data from database.
i fetched data using while loop.
while($row=mysql_fetch_array($query1))
{
}
now i want to print only index of $row.
i tried to print using following statements but it prints index and value(Key==>Value)
foreach ($row as $key => $value) {
echo $key ;
}
and i tried array_keys() also bt it is also not helpful to me.
echo implode(array_keys($row));
please help to get out this.
i need to print only index.
You are fetching the results row as both associative array and a numeric array (the default), see the manual on mysql_fetch_array.
If you need just the numeric array, use:
while($row=mysql_fetch_array($query1, MYSQL_NUM))
By the way, you should switch to PDO or mysqli as the mysql_* functions are deprecated.
You should pass separator(glue text) in Implode function.
For comma separated array keys, you can use below code.
echo implode(",",array_keys($row));
The $row variable in your while loop gets overwritten on each iteration, so the foreach won't work as you expect it to.
Store each $row in an array, like so:
$arr = array();
while($row=mysql_fetch_array($query1)) {
$arr[] = $row;
}
Now, to print the array keys, you can use a simple implode():
echo implode(', ', array_keys($arr));
$query1 from while($row=mysql_fetch_array($query1)) should be the result from
$query1 = mysql_result("SELECT * FROM table");
//then
while($row=mysql_fetch_array($query1))
To get only the keys use mysql_fetch_row
$query = "SELECT fields FROM table";
$result = mysql_query($query);
while ($row = mysql_fetch_row($result)) {
print_r(array_keys($row));
}