I'm trying to send some Json formatted data via POST from a micropython controller to a PHP page and then into a mySQL database. The problem I am having is that the PHP code is not reading in the values from the Json data and therefore it is not being inserted into the database.
At the moment, it seems like the data is being successfully sent to the PHP page and in the right format. Here is the code below:
Python code sending the data to the php page:
data = '{"DeviceName": 1, "Humidity": %.2f, "Temperature": %.2f }'%(hum,temp)
headers = {'content-type': 'application/json'}
print(data)
res = urequests.post('http://192.168.1.187/insert.php', json=data, headers=headers)
print(res)
Here is the JSON string being sent:
{"DeviceName": 1, "Humidity": 36.88, "Temperature": 27.99 }
PHP code:
$server = "localhost";
$username = "admin";
$password = "passw";
$db = "test";
$dbCon = new mysqli($server, $username, $password, $db) or die("Unable to Connect");
$response = array();
$res=array();
$jsonRaw = file_get_contents('php://input');
$json = json_decode($jsonRaw);
if($json!=null){
$temperature = $json->Temperature;
$device = $json->DeviceName;
$sql = "insert into hostdata (HostID, DandT, Temp) values ('$device', now(), '$temperature')";
if(mysqli_query($dbCon, $sql)){
$svrResp["code"] = "1";
$svrResp["message"] = "Sucessfully Connected";
echo json_encode($response);
}else{
$svrResp["code"] = "2";
$svrResp["message"] = mysqli_error($dbCon);
echo json_encode($response);
}
}else{
echo "JSON data error";
}
mysqli_close($dbCon);
?>
This should insert the deviceName (is actually a number) and the temperature value into the sql statement and update the database. However, it is triggering the sql insert statement, just both the HostID and Temperature values are 0 when it is inserted. Am I missing something?
Any help would be appreciated!!
Related
Hi I'm trying to insert the json array into my MySQL database. I'm passing the data form my iphone there i have converted the data into json format and I'm passing the data to my server using the url its not inserting into my server.
This is my json data.
[{"name":"0","phone":"dsf","city":"sdfsdf","email":"dsf"},{"name":"13123123","phone":"sdfsdfdsfsd","city":"sdfsf","email":"13123123"}]
This is my Php code.
<?php
$json = file_get_contents('php://input');
$obj = json_decode($data,true);
//Database Connection
require_once 'db.php';
/* insert data into DB */
foreach($obj as $item) {
mysql_query("INSERT INTO `database name`.`table name` (name, phone, city, email)
VALUES ('".$item['name']."', '".$item['phone']."', '".$item['city']."', '".$item['email']."')");
}
//database connection close
mysql_close($con);
//}
?>
My database connection code.
<?php
//ENTER YOUR DATABASE CONNECTION INFO BELOW:
$hostname="localhost";
$database="dbname";
$username="username";
$password="password";
//DO NOT EDIT BELOW THIS LINE
$link = mysql_connect($hostname, $username, $password);
mysql_select_db($database) or die('Could not select database');
?>
Please tell where I'm doing wrong in the above code basically I'm not a php developer I'm mobile application developer so I'm using the php as a server side scripting please tell me how to resolve this problem.
$json = file_get_contents('php://input');
$obj = json_decode($json,true);
I think you are passing the wrong variable. You should pass $json in json_decode as shown above.
You are missing JSON source file. Create a JSON file then assign it to var data:
<?php
require_once('dbconnect.php');
// reading json file
$json = file_get_contents('userdata.json');
//converting json object to php associative array
$data = json_decode($json, true);
// preparing statement for insert query
$st = mysqli_prepare($connection, 'INSERT INTO users(firstname, lastname, gender, username) VALUES (?, ?, ?, ?)');
// bind variables to insert query params
mysqli_stmt_bind_param($st, 'ssss', $firstname, $lastname, $gender, $username);
// processing the array of objects
foreach ($data as $user) {
$firstname = $user['firstname'];
$lastname = $user['lastname'];
$gender = $user['firstname'];
$username = $user['username'];
// executing insert query
mysqli_stmt_execute($st);
}
There is no such variable as $data. Try
$obj = json_decode($json,true);
Rest looks fine. If the error still persists, enable error_reporting.
Its simple you can insert json datatype as below. reference link: click here for more details
insert into sgv values('c-106', 'admin','owner',false,'[{"test":"test"},
{"test":"test"}]',0,'pasds');
$string=mysql_real_escape_string($json);
header("Access-Control-Allow-Origin: http://localhost/rohit/");
header("Content-Type: application/json; charset=UTF-8");
header("Access-Control-Allow-Methods: POST");
header("Access-Control-Max-Age: 3600");
header("Access-Control-Allow-Headers: Content-Type, Access-Control-Allow-Headers, Authorization, X-Requested-With");
//files needed to connect to database
include_once 'config/database.php';
include_once 'objects/main.php';
//get Database connection
$database = new Database();
$db = $database->getConnection();
//instantiate product object
$product = new Product($db);
//get posted data
$data = json_decode(file_get_contents("php://input"));
//set product property values
$product->b_nm = $data->Business_Name;
$product->b_pno = $data->Business_Phone;
$product->b_ads = $data->Business_Address;
$product->b_em = $data->Business_Email;
$product->b_typ = $data->Business_Type;
$product->b_ser = $data->Business_Service;
$name_exists = $product->nameExists();
if($name_exists){
echo json_encode(
array(
"success"=>"0",
"message" => "Duplicate Record Not Exists."
)
);
} else{
if($product->b_nm != null && $product->b_pno != null && $product->b_ads != null && $product->b_em != null && $product->b_typ != null && $product->b_ser != null){
if($product->create()){
//set response code
http_response_code(200);
//display message: Record Inserted
echo json_encode(array("success"=>"1","message"=>"Successfully Inserted"));
}
}
else{
//set response code
http_response_code(400);
//display message: unable to insert record
echo json_encode(array("success"=>"0","message"=>"Blank Record Not Exists."));
}
}
I want to do an HTTP GET request from the Python script to my server. The data I want to send is stored in a variable data.
I am using requests package of python to send it to my PHP page and I am getting the following error
import requests
data=850
r=requests.get("http://xxxxx.org/retrieve.php", params= str(data))
my retrieve.php file is
<?php
if (isset($_GET['data'])){
$data = $_GET['data'];
echo $data;
}
else{
echo "Data not received";
}
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "databasename";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$f=0;
$data= intval(data);
$sql="select max(ID) from moisture";
$res1 = mysqli_query($conn,$sql);
$row = mysqli_fetch_row($res1);
$ref = $row[0] + 1;
$sql1 = "INSERT INTO moisture VALUES ('$ref' , '$data')";
if (mysqli_query($conn, $sql1))
{
$f=1;
}
else {
$f=0;
}
mysqli_close($conn);
?>
I converted the data to string and then send it. On php script, I am getting the intval of the string but it is storing value '0' instead of '850'
My code is working for any static value that I am assigning to it. But it is not sending the data if I am receiving it from the sensor.
import serial
import requests
ser=serial.Serial('COM12',9600)
while True:
data=ser.readline()
r=requests.get("http://xxxxx.org/retrieve.php", params= data)
I've been trying to get my python code to transfer SQL query data from client running python to web server running PHP, then input that data into a MySQL database.
The below is the python test code simulating a single row:
#!/usr/bin/python
import requests
import json
url = 'http://192.168.240.182/insert_from_json.php'
payload = {"device":"gabriel","data_type":"data","zone":1,"sample":5,"count":0,"time_stamp":"00:00"}
headers = {'content-type': 'application/json'}
response = requests.post(url, data=dict(payload=json.dumps(payload)), headers=headers)
print response
The below is the PHP script on the server side:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "practice";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connection made...";
$payload_dump = $_POST['payload']
//$payload = '{"device":"gabriel","data_type":"data","zone":1,"sample":4,"count":0,"time_stamp":"00:00"}';
$payload_array = json_decode($payload_dump,true);
//get the data_payload details
$device = $payload_array['device'];
$type = $payload_array['data_type'];
$zone = $payload_array['zone'];
$sample = $payload_array['sample'];
$count = $payload_array['count'];
$time = $payload_array['time_stamp'];
$sql = "INSERT INTO data(device, data_type, zone, sample, count, time_stamp) VALUES('$device', '$type', '$zone', '$sample', '$count', '$time')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
If I comment out $payload_dump and instead use $payload and run the script the row is added correctly. But when I call the python script on the client I get a "response 200" but the record was not added. Something either my JSON string in python isn't formatted correctly or I am not passing the value correctly.
1) What is the syntax/procedure on the python code that would allow me to see what has actually been received by the PHP code. (i.e. convert the "$payload_dump" variable contents to a string and send back to the python script?
2) How do I resolve the above code?
Your first problem is using json headers which you shouldn't use since you aren't sending a raw json:
your data look like
{payload = {'key1': 'value1',
'key2': 'value2' }
}
and a raw json data should be in the form:
{'key1': 'value1',
'key2': 'value2'}
So you need to remove the headers from the request
response = requests.post(url, data=dict(payload=json.dumps(payload)))
Second you need to fix that missing semicolon
$payload_dump = $_POST['payload']
to
$payload_dump = $_POST['payload'];
Better solution
You can send the json data directly using requests
response = requests.post(url, json=payload)
then grab it in php with
$payload_array = json_decode(file_get_contents('php://input'), true);
Hi I'm trying to insert the json array into my MySQL database. I'm passing the data form my iphone there i have converted the data into json format and I'm passing the data to my server using the url its not inserting into my server.
This is my json data.
[{"name":"0","phone":"dsf","city":"sdfsdf","email":"dsf"},{"name":"13123123","phone":"sdfsdfdsfsd","city":"sdfsf","email":"13123123"}]
This is my Php code.
<?php
$json = file_get_contents('php://input');
$obj = json_decode($data,true);
//Database Connection
require_once 'db.php';
/* insert data into DB */
foreach($obj as $item) {
mysql_query("INSERT INTO `database name`.`table name` (name, phone, city, email)
VALUES ('".$item['name']."', '".$item['phone']."', '".$item['city']."', '".$item['email']."')");
}
//database connection close
mysql_close($con);
//}
?>
My database connection code.
<?php
//ENTER YOUR DATABASE CONNECTION INFO BELOW:
$hostname="localhost";
$database="dbname";
$username="username";
$password="password";
//DO NOT EDIT BELOW THIS LINE
$link = mysql_connect($hostname, $username, $password);
mysql_select_db($database) or die('Could not select database');
?>
Please tell where I'm doing wrong in the above code basically I'm not a php developer I'm mobile application developer so I'm using the php as a server side scripting please tell me how to resolve this problem.
$json = file_get_contents('php://input');
$obj = json_decode($json,true);
I think you are passing the wrong variable. You should pass $json in json_decode as shown above.
You are missing JSON source file. Create a JSON file then assign it to var data:
<?php
require_once('dbconnect.php');
// reading json file
$json = file_get_contents('userdata.json');
//converting json object to php associative array
$data = json_decode($json, true);
// preparing statement for insert query
$st = mysqli_prepare($connection, 'INSERT INTO users(firstname, lastname, gender, username) VALUES (?, ?, ?, ?)');
// bind variables to insert query params
mysqli_stmt_bind_param($st, 'ssss', $firstname, $lastname, $gender, $username);
// processing the array of objects
foreach ($data as $user) {
$firstname = $user['firstname'];
$lastname = $user['lastname'];
$gender = $user['firstname'];
$username = $user['username'];
// executing insert query
mysqli_stmt_execute($st);
}
There is no such variable as $data. Try
$obj = json_decode($json,true);
Rest looks fine. If the error still persists, enable error_reporting.
Its simple you can insert json datatype as below. reference link: click here for more details
insert into sgv values('c-106', 'admin','owner',false,'[{"test":"test"},
{"test":"test"}]',0,'pasds');
$string=mysql_real_escape_string($json);
header("Access-Control-Allow-Origin: http://localhost/rohit/");
header("Content-Type: application/json; charset=UTF-8");
header("Access-Control-Allow-Methods: POST");
header("Access-Control-Max-Age: 3600");
header("Access-Control-Allow-Headers: Content-Type, Access-Control-Allow-Headers, Authorization, X-Requested-With");
//files needed to connect to database
include_once 'config/database.php';
include_once 'objects/main.php';
//get Database connection
$database = new Database();
$db = $database->getConnection();
//instantiate product object
$product = new Product($db);
//get posted data
$data = json_decode(file_get_contents("php://input"));
//set product property values
$product->b_nm = $data->Business_Name;
$product->b_pno = $data->Business_Phone;
$product->b_ads = $data->Business_Address;
$product->b_em = $data->Business_Email;
$product->b_typ = $data->Business_Type;
$product->b_ser = $data->Business_Service;
$name_exists = $product->nameExists();
if($name_exists){
echo json_encode(
array(
"success"=>"0",
"message" => "Duplicate Record Not Exists."
)
);
} else{
if($product->b_nm != null && $product->b_pno != null && $product->b_ads != null && $product->b_em != null && $product->b_typ != null && $product->b_ser != null){
if($product->create()){
//set response code
http_response_code(200);
//display message: Record Inserted
echo json_encode(array("success"=>"1","message"=>"Successfully Inserted"));
}
}
else{
//set response code
http_response_code(400);
//display message: unable to insert record
echo json_encode(array("success"=>"0","message"=>"Blank Record Not Exists."));
}
}
i have the following problem... i am building an android app and i regeuest text formated in utf8 (greek chars) from editTexts by using the POST method. The POST method gets the greek chras from the editTexts as '???' and insert them in mysal again as '???'
How will the POST recognize my greek chars???
<?php
// PHP variable to store the host address
$db_host = "localhost";
// PHP variable to store the username
$db_uid = "lolen";
// PHP variable to store the password
$db_pass = "lolen";
// PHP variable to store the Database name
$db_name = "lolen";
// PHP variable to store the result of the PHP function 'mysql_connect()' which establishes the PHP & MySQL connection
$db_con = mysql_connect($db_host,$db_uid,$db_pass) or die('could not connect');
mysql_query("SET character_set_results=utf8", $db_con);
mb_language('uni');
mb_internal_encoding('UTF-8');
mysql_select_db($db_name, $db_con);
mysql_query("set names 'utf8'",$db_con);
// array for JSON response
$response = array();
// check for required fields
if (isset($_POST['k_p']) )
{
$Kwdikos_Proiontos=$_POST['k_p'];
$Proion=$_POST['p'];
$Kwdikos_Tupou=$_POST['k_t'];
//$Tupos=$_POST['t'];
$sql=mysql_query("SELECT * FROM tupoi WHERE Kwdikos_Tupou LIKE '". $_POST["k_t"]."'", $db_con);
while($row = mysql_fetch_array($sql))
{
$output[]=$row['Tupos'];
$re= json_encode($output[0]);
$dd= json_decode($re, true);
}
$result =mysql_query("INSERT INTO proionta(Kwdikos_Proiontos, Proion, Kwdikos_Tupou, Tupos) VALUES('$Kwdikos_Proiontos', '$Proion', '$Kwdikos_Tupou', '$dd')");
//check if row inserted or not
if ($result) {
// successfully inserted into database
$response["success"] = 1;
$response["message"] = "Product successfully created.";
// echoing JSON response
echo json_encode($response);
}
else {
// failed to insert row
$response["success"] = 0;
$response["message"] = "Oops! An error occurred.";
// echoing JSON response
echo json_encode($response);
}
}
else
{
// required field is missing
$response["success"] = 0;
$response["message"] = "Required field(s) is missing";
// echoing JSON response
echo json_encode($response);
}
?>
ps. my db is already in utf8 cause i display and add other data in greek, by using SELECT , INSERT, in the db.
Finally i found a solution to my problem, i used GET method instead of POST, and now it works correctly! Thnx for the sql injection tips, i will read more about this issue!