Get the last string of URL's - php

Question

I am getting data from a page like this:
<?php $speaker = $page->uri();
$speakerEvents = page('program')->grandchildren()->filter(function($child) use($speaker) {
$speakers = $child->speaker()->toStructure();
return $speakers->findBy('selectspeaker', $speaker);
});
echo $speakerEvents;
?>
It's output is:
"page/page/pageIWant
page/page/pageIWant"
The Result I want is
pageIWant
pageIWant
I tried to get the last name with
echo basename($speakerEvents);
But I only get one of the last pageIWant
How do I get the last pages without removing the first URL?

Answer 1

Use the explode method to get array of URL
<?php
$link = $_SERVER['PHP_SELF'];
$link_array = explode('/',$link);
echo $page = end($link_array);
?>
If your output is
page/page/pageIWant
page/page/pageIWant
<?php
$text = "page/page/pageIWant";
$text_arr = explode('/',$text);
echo $page = end($text_arr);
// this will print: pageIWant
?>

Answer 2

Your string has a line break as path separator. You need to split lines by either \r\n (CR-LF), \n, or \r which can be done with preg_split. If you can ensure one of the formats, you can also use the simple explode function.
foreach (preg_split('~(?:\r?\n|\r)~u', $speakerEvents) as $path)
echo basename($path) , PHP_EOL;
As AbraCadaver noted, you can add the flag PREG_SPLIT_NO_EMPTY to preg_split if you do not want empty lines to be handled.
If the double qoutes you show in the question are part of the string, you need further more to trim the string:
foreach (preg_split('~(?:\r?\n|\r)~u', trim($speakerEvents, '"')) as $path)
echo basename($path) , PHP_EOL;

Answer 3

You can explode the string e.g.
$array = explode('/', 'page/page/pageIWant');
Then you can retrieve it using the index like so:
$array[(count($array) - 1)];