I have this query in my php and it seems to be fetching the wrong data set from my db.
$querystring = "
SELECT a.*,
b.itemcolour,
b.itemcolourname
FROM itemorders AS a
INNER JOIN catalogueitemscolour AS b
ON a.colourid = b.colourid
WHERE a.colourid IN(SELECT colourid
FROM itemorders
WHERE orderid = 61)
";
Here is a picture of my results
Can I know why it's not selecting the specific orderID of 61?
You can try below -
SELECT a.*, b.itemColour,b.itemColourName FROM itemorders
AS a INNER JOIN CatalogueItemsColour AS b ON a.colourID = b.colourID WHERE
a.orderID = 61
Because you are not putting condition on orderID, rather putting it on colorID. What you actually want is this condition: WHERE a.orderID = 61.
Related
I have a first SQL query getting a table with id_member as parameter
$stmt = $mysqli -> prepare("SELECT a.id_alerte,
a.nom_alerte,
ar.id_roster,
r.nom_roster,
FROM alerte a,
alerte_par_roster ar,
roster_par_membre rm
INNER JOIN roster r
ON r.id_roster = rm.id_roster
WHERE rm.id_roster = ar.id_roster
AND ar.id_alerte = a.id_alerte
AND rm.id_membre = ?");
$stmt->bind_param('i', $id_membre);
I need to insert a second query counting the number of lines in another table.
The second query is:
"SELECT COUNT(DISTINCT id_roster)
FROM disponibilites_par_member_alertes
WHERE id_member = ?
AND id_alerte = ?"
As you can notice id_member is the identical in both queries but id_alerte (used as a parameter of the second query is a result of a first query).
I hope I am clear.
Any idea will be very welcome
I don't fully understand what your queries are intended to do. It would help to have clear information on the table structure and what each of the fields represents. I've tried to make a guess based on the table names but can't be certain it's correct.
The first thing I did was just to transform your WHERE condition such that each of the tables are joined explicitly. This is just for readability.
SELECT
a.id_alerte,
a.nom_alerte,
ar.id_roster,
r.nom_roster
FROM alerte a
INNER JOIN alerte_par_roster ar
ON ar.id_alerte = a.id_alerte
INNER JOIN roster_par_membre rm
ON rm.id_roster = ar.id_roster
INNER JOIN roster r
ON r.id_roster = rm.id_roster
WHERE
rm.id_membre = ?
Now we combine with the other query:
SELECT
a.id_alerte,
a.nom_alerte,
ar.id_roster,
r.nom_roster,
rc.id_roster_count
FROM alerte a
INNER JOIN alerte_par_roster ar
ON ar.id_alerte = a.id_alerte
INNER JOIN roster_par_membre rm
ON rm.id_roster = ar.id_roster
INNER JOIN roster r
ON r.id_roster = rm.id_roster
LEFT JOIN (
SELECT id_membre, id_alerte, COUNT(DISTINCT id_roster) AS id_roster_count
FROM disponibilites_par_member_alertes
GROUP BY id_membre, id_alerte
) AS rc
ON rc.id_membre = rm.id_membre
AND rc.id_alerte = ar.id_alerte
WHERE
rm.id_membre = ?
With my own generated data I get results like this:
If this is not enough to solve the problem you will need to provide more details about the tables and the design.
I have this statement:
SELECT personen.*, klassen.naam as klas FROM `personen`
JOIN `klassen` ON `klassen`.id = `personen`.Id
WHERE `rol` = "Docent" ORDER BY id
I know that it basically puts the column klassen.naam into personen by checking if the foreign key K_Id is the same as the id of Klassen:
In the table above I have 4 results, these are all the people who have a K_Id assigned, however there are 2 more people who have a K_Id of null:
My problem is that when K_Id is null it doesn't return anything at all, which makes sense, I just don't know how to fix it.
My question is: How can i write the statement so that it still shows all the other rows where the K_Id value is null?
SELECT personen.*, klassen.naam as klas
FROM `personen`
JOIN `klassen`
ON `klassen`.id = `personen`.Id
WHERE `rol` = "Docent"
ORDER BY id
You should use left join if you want all of your data from personen Table where personen.id is not present in klassen table it look like this
SELECT personen.*, klassen.naam as klas
FROM `personen`
LEFT JOIN `klassen`
ON `klassen`.id = `personen`.Id
WHERE `rol` = "Docent"
ORDER BY id
You would use a left join for this purpose. Assuming rol is in the personen table:
SELECT p.*, k.naam as klas
FROM `personen` p LEFT JOIN
`klassen` i
ON i.id = p.Id
WHERE p.`rol` = 'Docent'
ORDER BY p.id;
If rol is in the klassen table, then:
SELECT p.*, k.naam as klas
FROM `personen` p LEFT JOIN
`klassen` i
ON i.id = p.Id AND i.`rol` = 'Docent'
ORDER BY p.id;
Note that I also introduced table aliases in the query. These make queries easier to write and to read.
Also, this will return all rows in the personen table (subject to the where), including non-matches. If you just specifically wanted NULL values, then you would use:
SELECT p.*, k.naam as klas
FROM `personen` p JOIN
`klassen` i
ON i.id = p.Id or p.id is null
WHERE p.`rol` = 'Docent'
ORDER BY p.id;
I'm guessing you really want the left join version.
I am having problem when querying data from 3 tables (FABRICATION, FABRICATION_QC, AND WEIGHT) and using their values in the PHP. My query is like this:
select fabrication.*,master_drawing.weight,
(select fabrication_qc.marking_qc from fabrication_qc where fabrication_qc.head_mark=fabrication.head_mark) MARKING_QC,
(select fabrication_qc.marking_qc_date from fabrication_qc where fabrication_qc.head_mark=fabrication.head_mark) MARKING_QC_DATE,
(select fabrication_qc.marking_qc_sign from fabrication_qc where fabrication_qc.head_mark=fabrication.head_mark) MARKING_QC_SIGN
from fabrication,fabrication_qc,master_drawing
where fabrication.head_mark = master_drawing.head_mark";
and when I do this in the PHP to get that data into a table,
while (($row = oci_fetch_array($fabParse, OCI_BOTH)) != false)
{
echo '<tr>';
echo '<td>'.$row['PROJECT_NAME'].'</td>';
echo '<td>'.$row['HEAD_MARK'].'</td>';
echo '<td>'.$row['ID'].'</td>';
var_dump($row['MARKING_QC']);
PROJECT_NAME, HEAD_MARK, and ID work fine. Only the dumped MARKING_QC shows NULL in the output.
Can anyone tell me what I'm doing wrong here?
I am assuming this is the query you really want:
select f.*, md.weight,
(select fqc.marking_qc from fabrication_qc fqc where fqc.head_mark = f.head_mark) as MARKING_QC,
(select fqc.marking_qc_date from fabrication_qc fqc where fqc.head_mark = f.head_mark) as MARKING_QC_DATE,
(select fqc.marking_qc_sign from fabrication_qc fqc where fqc.head_mark = f.head_mark) as MARKING_QC_SIGN
from fabrication f join
master_drawing md
on f.head_mark = md.head_mark;
This removes the reference fabrication_qc in the outer from clause. That simply causes an unnecessary cartesian product. I also introduced table aliases to make the query more readable. And, put in proper explicit join syntax rather than the implicit joins.
You can further simplify this to:
select f.*, md.weight,
fqc.marking_qc, fqc.marking_qc_date, fqc.marking_qc_sign
from fabrication f join
master_drawing md
on f.head_mark = md.head_mark left outer join
fabrication_qc fqc
on fqc.head_mark = f.head_mark
I would write the query like this:
select
f.project_name,
f.head_mark,
f.id,
m.weight,
qc.marking_qc,
qc.marking_qc_date,
qc.marking_qc_sign
from fabrication as f
join master_drawing as m
on f.head_mark = m.head_mark
left outer join fabrication_qc as qc
on f.head_mark = qc.head_mark
-- where (no criteria given)
;
Try running the query from a query execution tool outside of your code, to confirm the results.
php mysql query
I have multiple linked tables - I also have a table that only creates and entry if certian conditions exist so I would like to add that into my query to avoid having to go through thousands of query searches looking for this special case
here is my current query
$query = "SELECT a.UUID FROM contract a
INNER JOIN geoPoint b ON a.customer_UUID = b.customerUUID
WHERE b.garcom_UUID = '$garbCom'
AND b.city_UUID = '$city'";
I then go through each item that was returned (in the thousands)
while ($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
$sentdata = getothertable($row['UUID']); //checks if the item is in the table
$sent = $sentdata ['senttoGarcom'];
if($sent == 0) //if it wasn't found add it to my list
{
array_push($Contracts,$row['UUID']);
}
}
instead of all that I would like to just make it one query - pseduo code something like this
$query = "SELECT a.UUID FROM contract a
INNER JOIN geoPoint b ON a.customer_UUID = b.customerUUID
INNER JOIN contract_sales c ON a.UUID = c.contractUUID
WHERE b.garcom_UUID = '$garbCom'
AND b.city_UUID = '$city' AND c.DOESNOTEXIST";
this way I dont have to return thousands I will only be returned the few that are not yet in the contract_sales table and I can go about my business...
Appreciate any help!
just check for NULL rows of c with a outer join
$query = "SELECT a.UUID FROM contract a
INNER JOIN geoPoint b ON a.customer_UUID = b.customerUUID
LEFT OUTER JOIN contract_sales c ON a.UUID = c.contractUUID
WHERE b.garcom_UUID = '$garbCom'
AND b.city_UUID = '$city' AND c.contractUUID IS NULL ";
I think this is a left outer join problem
Have a look at this example. You specifically need to have a check for a null in a column in the table which you want to find the missing row rof
mysql left outer join
Sounds like a NOT EXISTS correlated subquery is what you need:
$query = "SELECT a.UUID FROM contract a
INNER JOIN geoPoint b ON a.customer_UUID = b.customerUUID
WHERE b.garcom_UUID = '$garbCom'
AND b.city_UUID = '$city'
AND NOT EXISTS (SELECT 1
FROM contract_sales c
WHERE c.contractUUID = a.UUID)";
I want to select from 2 different tables.
In the first table I want to select all, but I will display only what I want.
In the second table I want to select only the profile picture but even if a user does not have a profile picture his data from the user table should be selected.
I am using inner joins. Below is my code:
SELECT * FROM
tish_user INNER JOIN tish_images
ON tish_user.user_id = tish_images.user_id
WHERE tish_images.prof_image = 1
To select from two different tables, you should specify values from each table that you want, not using catch-all *. Using a LEFT JOIN instead of an INNER JOIN lets you connect the tables you are querying from on a single point. You can query any kind of relationship between the tables at that point.
This query will give you all the userids in tish_user returning the matching tish_images.prof_image record if prof_image is 1, NULL otherwise.
SELECT
tish_user.user_id,
tish_images.prof_image
FROM
tish_user
LEFT JOIN tish_images
ON tish_user.user_id = tish_images.user_id
AND tish_images.prof_image = 1
Try this way
SELECT * FROM
tish_user, tish_images
WHERE tish_user.user_id = tish_images.user_id
AND
tish_images.prof_image = 1;
I think this might help you.
Cheers bro
Use LEFT JOIN instead of INNER JOIN.
SELECT * FROM
tish_user LEFT JOIN tish_images
ON tish_user.user_id = tish_images.user_id
WHERE tish_images.prof_image = 1
Explanation
LEFT JOIN selects all rows in the left table, even if there are no entries in the right table (in which case the columns for the right table will be NULL)
Also check RIGHT JOIN, it does the same thing with the right side :)
Try this:
SELECT *
FROM
tish_user U
LEFT JOIN tish_images I
ON U.user_id = I.user_id
AND = I.prof_image = 1
Try this:
Suppose you want to display the userID, firstname and lastname from the tish_user table and the prof_image from the tish_images table.
SELECT tish_user.userd_id, tish_user.firstname, tish_user.lastname, tish_images.prof_image
FROM tish_user tish_user LEFT JOIN tish_image tish_image ON tish_user.user_id=tish_images.user_id WHERE tish_image.prof_image=1
I think this will do.