How to echo array values which are incremented PHP - php

I have an array like this:
$aArray = array('one' => 0, 'two' => 0, 'three' =>0);
And a while loop like this:
$x = 50;
$y = 400;
$current = current($aArray);
while ($x<$y) {
$current++;
$x+=50;
if($x==$y) {
$current = next($aArray);
}
}
Now what I want is to show the array with the total times incrementation, but I don't know how. And is it able to show it without using a loop?

You can extract the keys of the array and then run according to index.
Consider the following modification:
$aArray = array('one' => 0, 'two' => 0, 'three' =>0);
$keys = array_keys($aArray);
$x = 50;
$y = 400;
$i = 0;
while ($x<$y) {
$aArray[$keys[$i]]++;
$x+=50;
if($x==$y) {
$i++;
}
}
print_r($aArray); // array('one' => 7, 'two' => 0, 'three' =>0);
If you don't want to loop you can just do:
$delta = $y - $x;
$cnt = intval($delta / 50);
if ($delta % 50 != 0)
$cnt++
Now $cnt will be 7 and you can set it in: $aArray["one"] = $cnt;

If you want the count the number of array incremented I have added a some line of coding
$x = 50;
$y = 400;
$aArray = array('one' => 0, 'two' => 0, 'three' =>0);
$countInc=0;
$current = current($aArray);
while ($x<$y) {
$current++;
$x+=50;
$countInc++;
if($x==$y) {
$current = next($aArray);
}
}
echo "Total Number of Increment from that Array: ". $countInc;

Related

Can not do the array equation in php

I am trying to create an array equation where the array value will be equated to the existing sequence, but I can not display it in array..how do I fix it?
$ht = array('day' => 1,'day' =>2,'day' =>3,'day' =>4);
for ($x = 1; $x <= 10; $x++) {
if($x == $ht['day']){
echo 'x';
}else{
echo $x;
}
}
Which I expect xxxx5678910 but I result 123x45678910
This is your array :
$ht = array('day' => 1,'day' =>2,'day' =>3,'day' =>4);
I you just do var_dump($ht); you will see that you have :
array (size=1)
'day' => int 4
So try this to get what you want :
$ht = array(1 => 1, 2 => 2, 3 => 3, 4 => 4);
for ($x = 1; $x <= 10; $x++) {
if(!empty($ht[$x])){
echo 'x';
}else{
echo $x;
}
}
Output is : xxxx5678910
You have multiple way to achieve it, that's just one among other :)
When u use same key, u overwrite your array key, so at the and u have only one record in your array, u can try something like this:
<?php
$ht = array('day1' => 1,'day2' =>2,'day3' =>3,'day4' =>4);
var_dump($ht);
for ($x = 1; $x <= 10; $x++) {
if (isset($ht['day' . $x])) {
if($ht['day' . $x] == $x){
echo 'x';
}
} else{
echo $x;
}
}
?>
Return :
xxxx5678910
You don't need to loop at all to get the expected output.
You can use range() to create an array with numbers 1 to 10 as in the loop.
Then array_diff finds the numbers not in the $ht array so that they can be echoed with implode.
$ht = array(1 => 1, 2 => 2, 3 => 3, 4 => 4);
$range = range(1,10);
$diff = array_diff($range, $ht); // [5,6,7,8,9,10]
echo str_repeat("x", count($ht)) . implode("", $diff);
https://3v4l.org/ZCU15
If the numbers are not always consecutive you can use array_intersect, array_fill and array_flip to create the new array with "x" instead of numbers in $ht array.
Then use array_replace to replace number values with "x" and output with implode.
$ht = array(1 => 1, 2 => 2, 3 => 3, 4 => 9);
$range = range(0,10);
unset($range[0]); // unset 0 since you want 1 as lowest
$x = array_intersect_key(array_fill(1,max($ht), "x"), array_flip($ht));
// $x = [1=>"x", 2=>"x", 3 => "x", 9=>"x"]
$new = array_replace($range, $x);
echo implode("", $new);
https://3v4l.org/gtSl9

Adding numbers in a multidimensional array

Is there a faster way to add all the numbers in each segment of the multidimensional array rather than just doing it all manually? I was told before that a foreach loop could be used but I've hit a brick wall.
I'm trying to make it so it shows the total number of course enrollments in each campus and then the total number of students taking each course.
I feel like the answer is staring me in the face but I'm unsure.
<?
$campus = array();
$campus[1]['course1'] = 5; // <---- Number enrolled
$campus[1]['course2'] = 15;
$campus[1]['course3'] = 22;
$campus[1]['course4'] = 21;
$campus[1]['course5'] = 12;
$campus[1]['course6'] = 25;
$campus[1]['course7'] = 16;
$campus[1]['course8'] = 11;
$campus[1]['course9'] = 17;
$campus[1]['course10'] = 23;
$campus[2]['course1'] = 11;
$campus[2]['course2'] = 23;
$campus[2]['course3'] = 51;
$campus[2]['course4'] = 25;
$campus[2]['course5'] = 32;
$campus[2]['course6'] = 35;
$campus[2]['course7'] = 32;
$campus[2]['course8'] = 52;
$campus[2]['course9'] = 25;
$campus[2]['course10'] = 21;
$campus[3]['course1'] = 2;
$campus[3]['course2'] = 12;
$campus[3]['course3'] = 32;
$campus[3]['course4'] = 32;
$campus[3]['course5'] = 25;
$campus[3]['course6'] = 26;
$campus[3]['course7'] = 29;
$campus[3]['course8'] = 12;
$campus[3]['course9'] = 15;
$campus[3]['course10'] = 11;
echo "<pre>";
print_r($campus);
echo "<br/>";
foreach($campus as $key=>$value)
{
}
Use array_sum() to add the numbers in an array, and use array_map() to apply it to each element of the $campus array.
$total_by_campus = array_map('array_sum', $campus);
$courses = array();
foreach($campus as $key=>$value)
{
foreach($value as $course=>$num)
$courses[$course] += $num;
}
var_dump($courses);
Should do it.
You can use PHP's array_sum() function that will add up the values of the array you give it.
<?php
$sum = array_sum($campus[1]);
echo $sum;
$totcount = 0;
$count = array();
foreach($campus as $key=>$value)
{
foreach($value as $value1 => $value2)
{
$count[$value1]+=$value2;
$totcount++;
}
}
print_r($count);
echo "<br><br><br>". $totcount;
take a look:
$campus = array
(
'1' => array
(
'course1' => 5,
'course2' => 15,
'course3' => 22,
'course4' => 21,
'course5' => 12,
'course6' => 25,
'course7' => 16,
'course8' => 11,
'course9' => 17,
'course10' => 23,
),
'2' => array
(
'course1' => 11,
'course2' => 23,
'course3' => 51,
'course4' => 25,
'course5' => 32,
'course6' => 35,
'course7' => 32,
'course8' => 52,
'course9' => 25,
'course10' => 21,
),
'3' => array
(
'course1' => 2,
'course2' => 12,
'course3' => 32,
'course4' => 32,
'course5' => 25,
'course6' => 26,
'course7' => 29,
'course8' => 12,
'course9' => 15,
'course10' => 11,
),
);
foreach ($campus as $key0 => $value0)
{
// $key0 == (1, 2, 3)
// $value0 == array(course1 => 5, course2 => 15, course3 => 22, ...)
foreach ($value0 as $key1 => $value1)
{
// $key1 == (course1, course2, course3, ...)
// $value1 == (5, 15, 22, ...)
}
}
Sorry, but you post a question: "How to check an array's contents to see if they have any numbers?"
<?php
$cowboyfile = "COWBOY.TXT";
$data = array();
$data[] = "Colt Peacemaker, 12.20";
$data[] = "Holster, 2.00";
$data[] = "Levi Strauss Jeans, 1.35";
$data[] = "Saddle, 40.00";
$data[] = "Stetson, 10.00";
// Writing in the File
file_put_contents($cowboyfile, implode("\r\n", $data));
// Displaying all items above $10
$items = file($cowboyfile);
$item_filtred = array();
for ($i = 0; $i < count($items); $i++)
{
$item = $items[$i];
$item_price = substr($items[$i], strpos($item, ',') + 1);
if ($item_price >= 10)
{
$item_filtred[] = $item;
}
}
print_r($item_filtred);

How to get the uneven keys from an array?

I have to create a function that copy the array(that i pass to the function) with only uneven keys. Example:
$a = array(
'0' => '0',
'one => 'one',
'1' => '1',
'two' => 'two'
)
I have to get:
$result = array(
'one => 'one',
'two' => 'two'
)
I have created the follow function, it works, but maybe I need to optimize it(maybe exists a function that does this job). Advice?
private clean($values){
$vv = array();
$keys = array_keys($values);
for($i=1; $i < count($values); $i+=2) $vv[$keys[$i]] = $values[$keys[$i]];
return $vv;
}
Thanks
$even = range(0, count($array), 2);
source
UPDATE:
for ($i = 0, $c = count($array); $i <= $c; $i = $i + 2) {
$even = array_push($even, $array[$i]);
}
Try
$outputArray = array();
$keyToAdd = false;
foreach( $inputArray as $key => $value ) {
if( $keyToAdd ) {
$outputArray[$key] = $value;
}
$keyToAdd = !$keyToAdd;
}

How to convert a Roman numeral to integer in PHP?

Using PHP, I'd like to convert a string containing a Roman number into its integer representation. I need this because I need to make calculations on them.
Wikipedia on Roman numerals
It would suffice to only recognize the basic Roman numeral characters, like:
$roman_values=array(
'I' => 1,
'V' => 5,
'X' => 10,
'L' => 50,
'C' => 100,
'D' => 500,
'M' => 1000,
);
That means the highest possible number is 3999 (MMMCMXCIX). I will use N to represent zero, other than that only positive integers are supported.
I cannot use the PEAR library for Roman numbers.
I found this great question on SO on how to test whether the string contains a valid Roman numeral:
How do you match only valid roman numerals with a regular expression?
What would be the best way of coding this?
How about this:
$romans = array(
'M' => 1000,
'CM' => 900,
'D' => 500,
'CD' => 400,
'C' => 100,
'XC' => 90,
'L' => 50,
'XL' => 40,
'X' => 10,
'IX' => 9,
'V' => 5,
'IV' => 4,
'I' => 1,
);
$roman = 'MMMCMXCIX';
$result = 0;
foreach ($romans as $key => $value) {
while (strpos($roman, $key) === 0) {
$result += $value;
$roman = substr($roman, strlen($key));
}
}
echo $result;
which should output 3999 for the supplied $roman. It seems to work for my limited testing:
MCMXC = 1990
MM = 2000
MMXI = 2011
MCMLXXV = 1975
You might want to do some validation first as well :-)
I am not sure whether you've got ZF or not, but in case you (or any of you who's reading this) do here is my snippet:
$number = new Zend_Measure_Number('MCMLXXV', Zend_Measure_Number::ROMAN);
$number->convertTo (Zend_Measure_Number::DECIMAL);
echo $number->getValue();
Zend_Measure_Number on framework.zend.com
This is the one I came up with, I added the validity check as well.
class RomanNumber {
//array of roman values
public static $roman_values=array(
'I' => 1, 'V' => 5,
'X' => 10, 'L' => 50,
'C' => 100, 'D' => 500,
'M' => 1000,
);
//values that should evaluate as 0
public static $roman_zero=array('N', 'nulla');
//Regex - checking for valid Roman numerals
public static $roman_regex='/^M{0,3}(CM|CD|D?C{0,3})(XC|XL|L?X{0,3})(IX|IV|V?I{0,3})$/';
//Roman numeral validation function - is the string a valid Roman Number?
static function IsRomanNumber($roman) {
return preg_match(self::$roman_regex, $roman) > 0;
}
//Conversion: Roman Numeral to Integer
static function Roman2Int ($roman) {
//checking for zero values
if (in_array($roman, self::$roman_zero)) {
return 0;
}
//validating string
if (!self::IsRomanNumber($roman)) {
return false;
}
$values=self::$roman_values;
$result = 0;
//iterating through characters LTR
for ($i = 0, $length = strlen($roman); $i < $length; $i++) {
//getting value of current char
$value = $values[$roman[$i]];
//getting value of next char - null if there is no next char
$nextvalue = !isset($roman[$i + 1]) ? null : $values[$roman[$i + 1]];
//adding/subtracting value from result based on $nextvalue
$result += (!is_null($nextvalue) && $nextvalue > $value) ? -$value : $value;
}
return $result;
}
}
Quick idea - go through the Roman number from right to left, if value of $current (more to the left) is smaller than $previous, then subtract it from the result, if larger, then add it.
$romanValues=array(
'I' => 1,
'V' => 5,
'X' => 10,
'L' => 50,
'C' => 100,
'D' => 500,
'M' => 1000,
);
$roman = 'MMMCMXCIX';
// RTL
$arabic = 0;
$prev = null;
for ( $n = strlen($roman) - 1; $n >= 0; --$n ) {
$curr = $roman[$n];
if ( is_null($prev) ) {
$arabic += $romanValues[$roman[$n]];
} else {
$arabic += $romanValues[$prev] > $romanValues[$curr] ? -$romanValues[$curr] : +$romanValues[$curr];
}
$prev = $curr;
}
echo $arabic, "\n";
// LTR
$arabic = 0;
$romanLength = strlen($roman);
for ( $n = 0; $n < $romanLength; ++$n ) {
if ( $n === $romanLength - 1 ) {
$arabic += $romanValues[$roman[$n]];
} else {
$arabic += $romanValues[$roman[$n]] < $romanValues[$roman[$n+1]] ? -$romanValues[$roman[$n]] : +$romanValues[$roman[$n]];
}
}
echo $arabic, "\n";
Some validation of roman number should also be added, though you said that you already have found how to do it.
Copyrights is for this blog (btw!)
http://scriptsense.blogspot.com/2010/03/php-function-number-to-roman-and-roman.html
<?php
function roman2number($roman){
$conv = array(
array("letter" => 'I', "number" => 1),
array("letter" => 'V', "number" => 5),
array("letter" => 'X', "number" => 10),
array("letter" => 'L', "number" => 50),
array("letter" => 'C', "number" => 100),
array("letter" => 'D', "number" => 500),
array("letter" => 'M', "number" => 1000),
array("letter" => 0, "number" => 0)
);
$arabic = 0;
$state = 0;
$sidx = 0;
$len = strlen($roman);
while ($len >= 0) {
$i = 0;
$sidx = $len;
while ($conv[$i]['number'] > 0) {
if (strtoupper(#$roman[$sidx]) == $conv[$i]['letter']) {
if ($state > $conv[$i]['number']) {
$arabic -= $conv[$i]['number'];
} else {
$arabic += $conv[$i]['number'];
$state = $conv[$i]['number'];
}
}
$i++;
}
$len--;
}
return($arabic);
}
function number2roman($num,$isUpper=true) {
$n = intval($num);
$res = '';
/*** roman_numerals array ***/
$roman_numerals = array(
'M' => 1000,
'CM' => 900,
'D' => 500,
'CD' => 400,
'C' => 100,
'XC' => 90,
'L' => 50,
'XL' => 40,
'X' => 10,
'IX' => 9,
'V' => 5,
'IV' => 4,
'I' => 1
);
foreach ($roman_numerals as $roman => $number)
{
/*** divide to get matches ***/
$matches = intval($n / $number);
/*** assign the roman char * $matches ***/
$res .= str_repeat($roman, $matches);
/*** substract from the number ***/
$n = $n % $number;
}
/*** return the res ***/
if($isUpper) return $res;
else return strtolower($res);
}
/* TEST */
echo $s=number2roman(1965,true);
echo "\n and bacK:\n";
echo roman2number($s);
?>
I'm late to the party, but here's mine. Assumes valid Numerals in the string, but doesn't test for a valid Roman number, whatever that is...there doesn't seem to be a consensus. This function will work for Roman numbers like VC (95), or MIM (1999), or MMMMMM (6000).
function roman2dec( $roman ) {
$numbers = array(
'I' => 1,
'V' => 5,
'X' => 10,
'L' => 50,
'C' => 100,
'D' => 500,
'M' => 1000,
);
$roman = strtoupper( $roman );
$length = strlen( $roman );
$counter = 0;
$dec = 0;
while ( $counter < $length ) {
if ( ( $counter + 1 < $length ) && ( $numbers[$roman[$counter]] < $numbers[$roman[$counter + 1]] ) ) {
$dec += $numbers[$roman[$counter + 1]] - $numbers[$roman[$counter]];
$counter += 2;
} else {
$dec += $numbers[$roman[$counter]];
$counter++;
}
}
return $dec;
}
Whew! Those are quite a few answers, and made of them are code-heavy! How about we define an algorithm for this first, before I give an answer?
The Basics
Don't store multi-digit Roman numerals, like 'CM' => 900, or anything like that in an array. If you know that M - C (1000 - 100) equals 900, then ultimately, you should only be storing the values of 1000 and 100. You wouldn't have multi-digit Roman numerals like CMI for 901, would you? Any answer that does this will be inefficient from one that understands the Roman syntax.
The Algorithm
Example: LIX (59)
Do a for loop on the numbers, starting at the end of the string of Roman numerals. In our example: We start on "X".
Greater-Than-Equal-To Case — If the value we are looking at is the same or greater than the last value, simply add it to a cumulative result. In our example: $result += $numeral_values["X"].
Less-Than Case — If the value we are subtracting is less than the previous number, we subtract it from our cumulative result. In our example IX, I is 1 and X is 10, so, since 1 is less than 10, we subtract it: giving us 9.
The Demo
Full Working Demo Online
The Code
function RomanNumeralValues() {
return [
'I'=>1,
'V'=>5,
'X'=>10,
'L'=>50,
'C'=>100,
'D'=>500,
'M'=>1000,
];
}
function ConvertRomanNumeralToArabic($input_roman){
$input_length = strlen($input_roman);
if($input_length === 0) {
return $result;
}
$roman_numerals = RomanNumeralValues();
$current_pointer = 1;
$result = 0;
for($i = $input_length - 1; $i > -1; $i--){
$letter = $input_roman[$i];
$letter_value = $roman_numerals[$letter];
if($letter_value === $current_pointer) {
$result += $letter_value;
} elseif ($letter_value < $current_pointer) {
$result -= $letter_value;
} else {
$result += $letter_value;
$current_pointer = $letter_value;
}
}
return $result;
}
print ConvertRomanNumeralToArabic("LIX");
function romanToInt($s) {
$array = ["I"=>1,"V"=>5,"X"=>10,"L"=>50,"C"=>100,"D"=>500,"M"=>1000];
$sum = 0;
for ($i = 0; $i < strlen($s); $i++){
$curr = $s[$i];
$next = $s[$i+1];
if ($array[$curr] < $array[$next]) {
$sum += $array[$next] - $array[$curr];
$i++;
} else {
$sum += $array[$curr];
}
}
return $sum;
}
Define your own schema! (optional)
function rom2arab($rom,$letters=array()){
if(empty($letters)){
$letters=array('M'=>1000,
'D'=>500,
'C'=>100,
'L'=>50,
'X'=>10,
'V'=>5,
'I'=>1);
}else{
arsort($letters);
}
$arab=0;
foreach($letters as $L=>$V){
while(strpos($rom,$L)!==false){
$l=$rom[0];
$rom=substr($rom,1);
$m=$l==$L?1:-1;
$arab += $letters[$l]*$m;
}
}
return $arab;
}
Inspired by andyb's answer
I just wrote this in about 10 mins, it's not perfect, but seems to work for the few test cases I've given it. I'm not enforcing what values are allowed to be subtracted from what, this is just a basic loop that compares the current letter value with the next one in the sequence (if it exists) and then either adds the value or adds the subtracted amount to the total:
$roman = strtolower($_GET['roman']);
$values = array(
'i' => 1,
'v' => 5,
'x' => 10,
'l' => 50,
'c' => 100,
'd' => 500,
'm' => 1000,
);
$total = 0;
for($i=0; $i<strlen($roman); $i++)
{
$v = $values[substr($roman, $i, 1)];
$v2 = ($i < strlen($roman))?$values[substr($roman, $i+1, 1)]:0;
if($v2 && $v < $v2)
{
$total += ($v2 - $v);
$i++;
}
else
$total += $v;
}
echo $total;
Just stumbled across this beauty and have to post it all over:
function roman($N)
{
$c = 'IVXLCDM';
for ($a = 5, $b = $s = ''; $N; $b++, $a ^= 7)
{
for (
$o = $N % $a, $N = $N / $a ^ 0;
$o--;
$s = $c[$o > 2 ? $b + $N - ($N &= -2) + $o = 1 : $b] . $s
);
}
return $s;
}
function Romannumeraltonumber($input_roman){
$di=array('I'=>1,
'V'=>5,
'X'=>10,
'L'=>50,
'C'=>100,
'D'=>500,
'M'=>1000);
$result=0;
if($input_roman=='') return $result;
//LTR
for($i=0;$i<strlen($input_roman);$i++){
$result=(($i+1)<strlen($input_roman) and
$di[$input_roman[$i]]<$di[$input_roman[$i+1]])?($result-$di[$input_roman[$i]])
:($result+$di[$input_roman[$i]]);
}
return $result;
}
function rom_to_arabic($number) {
$symbols = array(
'M' => 1000,
'D' => 500,
'C' => 100,
'L' => 50,
'X' => 10,
'V' => 5,
'I' => 1);
$a = str_split($number);
$i = 0;
$temp = 0;
$value = 0;
$q = count($a);
while($i < $q) {
$thys = $symbols[$a[$i]];
if(isset($a[$i +1])) {
$next = $symbols[$a[$i +1]];
} else {
$next = 0;
}
if($thys < $next) {
$value -= $thys;
} else {
$value += $thys;
}
$temp = $thys;
$i++;
}
return $value;
}
function parseRomanNumerals($input)
{
$roman_val = '';
$roman_length = strlen($input);
$result_roman = 0;
for ($x = 0; $x <= $roman_length; $x++) {
$roman_val_prev = $roman_val;
$roman_numeral = substr($input, $roman_length-$x,1);
switch ($roman_numeral) {
case "M":
$roman_val = 1000;
break;
case "D":
$roman_val = 500;
break;
case "C":
$roman_val = 100;
break;
case "L":
$roman_val = 50;
break;
case "X":
$roman_val = 10;
break;
case "V":
$roman_val = 5;
break;
case "I":
$roman_val = 1;
break;
default:
$roman_val = 0;
}
if ($roman_val_prev<$roman_val) {
$result_roman = $result_roman - $roman_val;
}
else {
$result_roman = $result_roman + $roman_val;
}
}
return abs($result_roman);
}

Check and return duplicates array php

I would like to check if my array has any duplicates and return the duplicated values in an array.
I want this to be as efficient as possible.
Example:
$array = array( 1, 2, 2, 4, 5 );
function return_dup($array); // should return 2
$array2 = array( 1, 2, 1, 2, 5 );
function return_dup($array2); // should return an array with 1,2
Also the initial array is always 5 positions long
this will be ~100 times faster than array_diff
$dups = array();
foreach(array_count_values($arr) as $val => $c)
if($c > 1) $dups[] = $val;
You can get the difference of the original array and a copy without duplicates using array_unique and array_diff_assoc:
array_diff_assoc($arr, array_unique($arr))
function array_dup($ar){
return array_unique(array_diff_assoc($ar,array_unique($ar)));
}
Should do the trick.
You can do like this:
function showDups($array)
{
$array_temp = array();
foreach($array as $val)
{
if (!in_array($val, $array_temp))
{
$array_temp[] = $val;
}
else
{
echo 'duplicate = ' . $val . '<br />';
}
}
}
$array = array(1,2,2,4,5);
showDups($array);
Output:
duplicate = 2
function returndup($array)
{
$results = array();
$duplicates = array();
foreach ($array as $item) {
if (in_array($item, $results)) {
$duplicates[] = $item;
}
$results[] = $item;
}
return $duplicates;
}
in addition to gumbo's answer:
function returndup($arr)
{
return array_diff_key($arr, array_unique($arr));
}
I did some tests and indeed #user187291's variant is the fastest. But, it turns out that #Gumbo's and #faebser's alternative are almost as fast, #faebser's being just slightly faster than #Gumbo's and sometimes even fastest of all.
Here's the code I used
$array = array(1, "hello", 1, "world", "hello");
$times = 1000000;
$start = microtime(true);
for ($i = 0; $i < $times; $i++) {
$dups = array();
foreach(array_count_values($array) as $val => $c)
if( $c > 1) $dups[] = $val;
}
$end = microtime(true);
echo 'variant 1 (user187291): ' . ($end - $start);
echo '<br><br><br>';
$start = microtime(true);
for ($i = 0; $i < $times; $i++)
$dups = array_unique(array_diff_assoc($array, array_unique($array)));
$end = microtime(true);
echo 'variant 2 (JAL): ' . ($end - $start);
echo '<br><br><br>';
$start = microtime(true);
for ($i = 0; $i < $times; $i++)
$dups = array_diff_assoc($array, array_unique($array));
$end = microtime(true);
echo 'variant 3 (Gumbo): ' . ($end - $start);
echo '<br><br><br>';
$start = microtime(true);
for ($i = 0; $i < $times; $i++)
$dups = array_diff_key($array, array_unique($array));
$end = microtime(true);
echo 'variant 4 (faebser): ' . ($end - $start);
echo '<br><br><br>';
I have found another way to return duplicates in an array
function printRepeating($arr, $size)
{
$i;
$j;
for($i = 0; $i < $size; $i++)
for($j = $i + 1; $j < $size; $j++)
if($arr[$i] == $arr[$j])
echo $arr[$i], " ";
}
printRepeating($array, sizeof($array,0);
If you need a solution that will work with an array of arrays (or any array values other than integers or strings) try this:
function return_dup( $arr ) {
$dups = array();
$temp = $arr;
foreach ( $arr as $key => $item ) {
unset( $temp[$key] );
if ( in_array( $item, $temp ) ) {
$dups[] = $item;
}
}
return $dups;
}
$arr = array(
array(
0 => 'A',
1 => 'B',
),
array(
0 => 'A',
1 => 'B',
),
array(
0 => 'C',
1 => 'D',
),
array(
0 => 'C',
1 => 'D',
),
array(
0 => 'E',
1 => 'F',
),
array(
0 => 'F',
1 => 'E',
),
array(
0 => 'Y',
1 => 'Z',
),
);
var_export( return_dup( $arr ) );
/*
array (
0 => array (
0 => 'A',
1 => 'B',
),
1 => array (
0 => 'C',
1 => 'D',
),
)
*/
As per your problem if you have duplicate values then you have to return those values. I write a function for this problem. If your array has duplicate values this function returns these values within the array otherwise it returns null values. Here is an example:
function containsDuplicate($array_values) {
$duplicates_values = [];
for($i = 0; $i < count($array_values); $i++){
for ($j=$i+1; $j <count($array_values) ; $j++) {
if ($array_values[$i] == $array_values[$j]) {
$duplicates_values[] = $array_values[$i];
}
}
}
if(count($duplicates_values) > 0){
return $duplicates_values;
}
}
$duplicate_array = array();
for($i=0;$i<count($array);$i++){
for($j=0;$j<count($array);$j++){
if($i != $j && $array[$i] == $array[$j]){
if(!in_array($array[$j], $duplicate_array)){
$duplicate_array[] = $array[$j];
}
}
}
}

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