I have a URL that looks like:
example.com/profile.php?id=1
I want to dynamically generate the URL by taking username from the form input in the database's id field. Like :
example.com/profile.php?id=username
This link give errors.If I use below link than it works
example.com/profile.php?id="username"
But , I am facing problem in anchor tag.My Code :
<a href="contributor-profile.php?id=<?PHP echo "$data['id']";?>">
<h4 class="contributor-name">
<?PHP echo $data ['name'];?>
</h4>
</a>
I have also used urlencode fuction but it is not working.
<a href="profile.php?id=<?PHP echo urlencode($data['id']);?>">
<h4>
<?PHP echo $data ['name'];?>
</h4>
</a>
Related
I am trying to link to a specific part in my php page. I have tried all the other answers on here but none of them have helped my special problem. This is how I am trying to go to the link
<a href="<?php echo $userLoggedIn; ?>#posts_tab">
So when the user clicks the dropdown they see a list of things. One of those things being the word Profile and when the user clicks on their profile they go to their own personal profile. When they are there they have a list of items at the top that look like this:
So what I want to do is when they click the profile they are automatically on the Profile Posts tab. Like a default option. For some reason it's not working for me and I can't figure out why. Any help please ?
header.php:
<a href="<?php echo $userLoggedIn; ?>#posts_tab">
</a>
profile.php:
<a style="color: #000;" id="posts_tab" href="javascript:void(0)" onclick="openCity(event, 'Posts');">
<div class="w3-third tablink w3-bottombar w3-hover-light-grey w3-padding">
<center>Profile Posts</center>
</div>
</a>
I believe this is what you want, you need to let your profile page know that you want to load that part of profile.php, you can do it different ways I have used php and GET as example, I've sent a parameter on the URL and received it on profile.php
header.php
<a href="<?php echo $userLoggedIn; ?>?tab=posts_tab">
profile.php
<?php
$tab = $_GET["tab"];
if ($tab == "posts_tab"){
?><script>openCity(event, 'Posts');</script><?php
}
?>
<a style="color: #000;" id="posts_tab" href="javascript:void(0)" onclick="openCity(event, 'Posts');">
<div class="w3-third tablink w3-bottombar w3-hover-light-grey w3-padding">
<center>Profile Posts</center>
</div>
</a>
<ul>
<li> Telephone number : <?php echo $row[3]?> </li>
<li> Website : <a href = "<?php echo $row[4]?>" ></a> </li>
</ul>
$row[4] represents the column in database that has the link to website.
I'm trying this code to get href but it's not working for some reason. Any hints what am I doing wrong here?
If I echo it without making it an href then it's working fine. So my database connection is perfectly working.
Thanks in advance.
Well, you filled only the href attribute of the link. The text to be displayed must be put between the link tags:
<?php echo $row[4]; ?>
I'm working on a simple project which has a requirement to show a particular block of html by passing an div id to that url.
I have tried so many solutions, but none of them worked for me.
Here is my code.
<div class="row">
<a onclick="redirect_tooltip();">
<i class="fa fa-question-circle" aria-hidden="true"></i>
</a>
</div>
Whenever I click the icon it calls a Javascript function, through that function I tried to pass a url with another page division id
function redirect_tooltip()
{
var source_type = $("#_src_type").val();
if(source_type == "source")
{
window.location.replace(base_url+'/help/tooltip#rtmp_4');
//I have already difined the base url
}
}
My html code:
<div id="rtmp_4">
<h4>Some Title</h4>
<h5> <?php echo trim($tooltip_rtmp_server[1]);?></h5>
<p> <?php echo trim($tooltip_rtmp_server[3]);?> </p>
<h5> <?php echo trim($tooltip_rtmp_stream_name[1]);?></h5>
<p> <?php echo trim($tooltip_rtmp_stream_name[3]);?> </p>
</div>
I need to display only the rtmp block whenever the url executes. Please give me a suggestions like where I am doing the mistake.
When I browse "localhost/ProjectName/users" then I get a user account image like
But When I browse "localhost/ProjectName/users/add" then I get a user account image like
But I wanna see correct image all actions.
My code is below.
<a href="#" class="dropdown-toggle" data-toggle="dropdown">
<img src="img/penguen.jpg" class="user-image">
<?php $this->User = ClassRegistry::init('User');?>
<span class="hidden-xs">
<?php if (AuthComponent::user('id')): ?>
<?= AuthComponent::user('username') ?>
<?php endif; ?>
</span>
</a>
<img src="img/penguen.jpg" class="user-image">
was your mistake.
Leverage the helper to generate "valid" links for you, problem solved:
$this->Html->image('penguen.jpg', ['class' => 'user-image']);
Never use manual a or img tags with manually built URLs, that can only go wrong.
I have 2 tables:
TABLE users (id, name, image, user_group_id)
TABLE user_groups (id, name, menu)
column menu value contains something like this:
<img src="../images/employees/'.$row_UserDetails['Image'].'" alt="">
Now at img src its creating a problem.
'.$row_UserDetails['Image'].'
This doesn't display the value.
Why is that and how do we fix this?
I want to display results from recordset UserGroup like this:
Now the value coming from php mysql is: <img src="../images/employees/'.$row_UserDetails['Image'].'" alt="">
you see .$row_UserDetails['Image'].
This value must be abc.jpg which comes from Recordest UserDetails:
On this php page if i want to display user name, i use php echo like this: <?php echo $row_UserDetails['Name'];?>
When using echo in php you will need to escape the quotes as they cause problems.
<header id=\"header-navbar\" class=\"content-mini content-mini-full\"> <ul class=\"nav-header pull-right\"> <li> <div class=\"btn-group\"> <button class=\"btn btn-default btn-image dropdown-toggle\" data-toggle=\"dropdown\" type=\"button\"> <img src=\"../images/employees/\"" .$row_UserDetails['Image']. "\" alt=\"\"> <span class=\"caret\"></span> </button> <ul class=\"dropdown-menu dropdown-menu-right\"> <li> <a tabindex=\"-1\" href=\"my-profile.php\"> <i class=\"si si-user pull-right\"></i> My Profile </a> </li> <li> <a tabindex=\"-1\" href=\"../logout.php\"> <i class=\"si si-logout pull-right\"></i>Log out </a> </li> </ul> </div> </li> </ul>
</header>
You say you echo $row_UserDetails['Image'], but I don't see an echo statement anywhere. Also, if that PHP code is really in your database like that, I believe you are on the wrong track.
Much better would be to use some sort of placeholder, and replace that by your desired database value when rendering that menu.
Something like this:
// assume something like "... <img src="../images/employees/%{image}"> ..."
// in the menu column, where '%{image}' serves as a placeholder
echo str_replace('%{image}', $row['image'], $row['menu']);
You need to echo your tag or echo your data inside the src attribute to use the value return by $row_UserDetails['Image'].
If you have done so, this may be the problem.
You have a issue with cocatenation. Your code should be like this
<?php echo "<img src='../images/employees/".$row_UserDetails['Image']."' alt='test'/>"; ?>
This article mat help you : https://teamtreehouse.com/community/why-do-we-use-concatenation-when-outputting-this-img-tag-with-php
Best regards !