php stmt similar products display - php

Question

I am creating PHP stmt similar products display script this script working but not showing similar products I want to display similar products title
Here is my code
<?php
$id=$row['id'];
if($stmt = $con->prepare("SELECT title
FROM products order by rand() limit 3
")){
$stmt->execute();
}
$result = $stmt->get_result();
if($result->num_rows > 0){
while($row = $result->fetch_array(MYSQLI_ASSOC)){
//results
}}
?>
view.php
<?php
if(isset($_GET['id'])) {
include("config.php");
$id = $_GET['id'];
$sql = "select * from products where id = '$id'";
$result = $con->query($sql);
if($result->num_rows > 0){
while($row = $result->fetch_assoc()){
//results
}}}
?>

Answer 1

Ensure that Database credentials were okay.
Try the code below and let me know
1) Query using rand() method( This is what you want)
<?php
$dbhost = 'localhost:3306';
$dbuser = 'root';
$dbpass = 'your password goes here';
$dbname = 'your database goes here';
$conn = mysqli_connect($dbhost, $dbuser, $dbpass,$dbname);
if(! $conn ) {
die('Could not connect: ' . mysqli_error());
}
echo 'Connected successfully<br>';
$sql = 'SELECT title FROM products order by rand() limit 3';
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
echo "Title: " . $row["title"]. "<br>";
}
} else {
echo "0 results";
}
mysqli_close($conn);
?>
2.) Query Using where Clause in this case an id(1) to show product title where id of 1 matches it in the database
<?php
$dbhost = 'localhost:3306';
$dbuser = 'root';
$dbpass = 'your password goes here';
$dbname = 'your database goes here';
$conn = mysqli_connect($dbhost, $dbuser, $dbpass,$dbname);
if(! $conn ) {
die('Could not connect: ' . mysqli_error());
}
echo 'Connected successfully<br>';
$sql = "SELECT id,title FROM products where id='1'";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
echo "Title: " . $row["title"]. "<br>";
}
} else {
echo "0 results";
}
mysqli_close($conn);
?>
Updated Section
First create table below and insert into it
create table products(id int(11) primary key auto_increment,title varchar(30),description varchar(30),image varchar(30),cat_id int(11));
You will insert at least one record
insert into products (id,title,description,image,cat_id) values(1,'product title','product details','product.png',100);
For testing query the products table to get details where id is 1
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$dbname = 'anglejs';
$conn = mysqli_connect($dbhost, $dbuser, $dbpass,$dbname);
if(! $conn ) {
die('Could not connect: ' . mysqli_error());
}
echo 'Connected successfully<br>';
$sql = "SELECT id,title,description,image,cat_id FROM products where id='1'";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
echo "Id: " . $row["id"]. "<br>";
echo "Title: " . $row["title"]. "<br>";
echo "description: " . $row["description"]. "<br>";
}
} else {
echo "0 results";
}
mysqli_close($conn);
?>
Now since the Id is coming from url
For testing purpose:
You can save the code as view.php like you did
Open your browser and Enter something like
http://localhost/-----yourfolder diretory goes here-----/view.php?id=1
You can see Id of 1 coming from the Url as appended to view.php files. since we have inserted record which has id of 1, the code below will display the
records only for rows where id is = 1 and so on....
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$dbname = 'anglejs';
$conn = mysqli_connect($dbhost, $dbuser, $dbpass,$dbname);
if(! $conn ) {
die('Could not connect: ' . mysqli_error());
}
echo 'Connected successfully<br>';
$id = $_GET['id'];
//check if id is empty
if($id==''){
echo "Id is empty";
exit;
}
$sql = "SELECT id,title,description,image,cat_id FROM products where id='$id'";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
echo "Id: " . $row["id"]. "<br>";
echo "Title: " . $row["title"]. "<br>";
echo "description: " . $row["description"]. "<br>";
}
} else {
echo "0 results";
}
mysqli_close($conn);
?>