I'm trying to see what my server's request IP is. For example.
<?php
$contents = file_get_contents("https://example.com");
?>
I want to know what IP my server is using to connect to example.com. I cannot use tools like IPLookUp because that just gets the IP of the response and if I have cloudflare on my domain, then it will keep showing cloudflares proxy IP's.
If I use $_SERVER['SERVER_ADDR'] it just shows me the local IP 127.0.0.7
Use gethostbyname
gethostbyname ( string $hostname )
Related
echo $_SERVER['SERVER_ADDR'] always yields 192.168.1.142, which is the IP address of my server within my home network. I can access the website using my external IP since I've set up the port forward on my router, but $_SERVER['SERVER_ADDR'] will only return the internal IP, no matter what I try.
How can I make $_SERVER['SERVER_ADDR'] return my external IP?
You can use file_get_contents function for this. You just need to find a host which can return your ip address
$externalContent = file_get_contents('http://checkip.dyndns.com/');
preg_match('/Current IP Address: ([\[\]:.[0-9a-fA-F]+)</', $externalContent, $myIp);
echo $myexternalIp = $myIp[1];
Add a second IP to your server (ifconfig eth0:1 192.168.1.143) and use that in your router's port forwarding rules. That way, external accesses will be coming in through that address instead and you can tell the difference between the two.
Hi I need to know the IP address of my website to give to my payment gateway. I know I can find an IP address by going to any of the websites which come up on google, but my understanding is that they give the domain's IP address which may be different from the IP address of the server the site is hosted on.
So how to I find out what the IP address of my server is?
Thanks :)
Run this from the command line to get your server's outgoing IP:
wget -q -O - checkip.dyndns.org|sed -e 's/.*Current IP Address: //' -e 's/<.*$//'
The server's IP address can be found with the $_SERVER variable:
<?php
echo $_SERVER['SERVER_ADDR'];
you can also do a quick PHP output of
<?php
phpinfo();
?>
it will contain all the values you need for your host details (just don't leave this file public after you use it).
What do you mean by the domain IP? The IP returned from a DNS lookup when querying your domain? This is most likely equal to the IP of your (shared) server, otherwise your website would be unreachable.
An exception to that is when the IP your DNS record represents belongs to a proxy server, which forwards the request to the real server.
You could always get the public IP address of the server by visiting www.whatismyip.com from the server.
I'm quite a novice at PHP.
I would like the IP address that I (myself, only. I modified my hosts file for the HotSpot shield webpage) have been given when using HotSpot shield to show up on my webpage, but unfortunately, it's echoed as 127.0.0.1. The main objective is that when I connect, the IP address that I've been set is echoed on the page. This is what code I've used:
<?php $rmt = $_SERVER["REMOTE_ADDR"]; echo "$rmt \n" ?>
The only problem is is that $rmt is 127.0.0.1. Do any of you know how to get it to display the public IP address to be displayed?
This can happen with local proxy servers; you could check out the other headers that are sent with your request by var_dump($_SERVER); and search for stuff like X-Forwarded-For or X-Real-IP
$_SERVER['REMOTE_ADDR'] is referring to the IP adress from which you connected. If you're running the server on your local machine and connecting from your local machine, it uses your local ip (127.0.0.1 is always "localhost").
In order to show a different ip you need to run it on another server (a public web hotel server preferably), or connect to your server from another machine.
I had just the same issue.
As it turns out, I was getting the proxy IP address instead of my own IP.
So I ran:
var_dump($_SERVER)
//you could also use print_r($_SERVER);
And then looked for something like this:
["HTTP_X_REAL_IP"]
Then captured it into a var like this:
$ip = getenv('HTTP_X_REAL_IP')
I am trying to write a small script that prints ip of the client. I am trying to run it on my localhost, but I am not able to get the IP address. Instead I get something like ::1.
Here's the code:
<?php echo $_SERVER['REMOTE_ADDR'];?>
Why this is not working as expected?
::1
Is the loopback adress (127.0.0.1 in IPv4) in IPv6.
This is the expected behaviour. If you use Firefox, you can navigate to about:config, search for disableIPv6 and set it to true. You'll then see 127.0.0.1.
So yes, it's working.
It is working correctly. That is your IP addresses... the IPv6 version of it. If you had connected over IPv4 it would have shown as 127.0.0.1.
These are loopback addresses. They allow you to connect to your own computer without using an actual network interface. See http://en.wikipedia.org/wiki/Loopback#Virtual_network_interface
Ok simple enough
<?PHP
echo $_SERVER[REMOTE_ADDR];
?>
Ok maybe not, I my IP is currently 72.184.212.85 however the code above which I am using on an IP blocking system for a script shows my IP as my home server IP of 127.0.0.1
So when I go to my script my IP is shown as 127.0.0.1 but when I go to other websites it is shown as 72.184.212.85
How can I get the first value to show on my test server?
$_SERVER['REMOTE_ADDR'] will always show the IP address from which the request came. If you access your own script on your own computer within your own network, your external IP address never comes into play. The request would have to leave your local network and then come back in for the external address to show up, but if it's all local, that'll never happen.
You'll have to make your server publicly accessible and then access it from the public address. I'm guessing you're currently using localhost to access your server?
run your server say port 8080 and then forward the port in your router so it's public to the internet. Then visit your webpage/phpscript from http://72.184.212.85:8080 instead of http://localhost:8080.
Here is a ridiculous solution that I wouldn't recommend:
Register your home IP with a domain name, then see where the request came from via URL:
$url = $_SERVER["SERVER_NAME"];
or
$url = $_SERVER["HTTP_HOST"];
and then do a dns lookup of that result, which should return the IP it's registered to, ie your external IP.
$ext_ip = gethostbyaddr($url);
The only reason this wouldn't work (so sorry if I'm wrong), is if SERVER_NAME uses the same method as "REMOTE_HOST", which is a reverse DNS lookup, which won't resolve, as your internal IP won't be registered to that domain name. An easy way to check is to do either:
phpinfo();
and see what the environmental variables are.