I have a table in which I have some products and from them I want to get just unique values. I have a database in which I have values like Kia Picanto, Toyota Corolla, Kia Sportage, BMW Series 6, BMW Series 7 etc. Now I want to show values like Kia, Toyota, BMW. I am trying to search over the internet but didn't find any possible solutions so that's why I ma posting my question here to get the solution.I am using
SQL:
$sql = $db_con->prepare("SELECT `post_title` FROM `panel_product` WHERE `product_type` LIKE '%vehicle%' ORDER BY `post_title`");
$sql->execute();
$menufectures = $sql->fetchAll();
if (count($menufectures) > 0) {
foreach ($menufectures as $key) {
$brand = explode(' ', $key['post_title']);
$brand = $brand[0];
echo $brand.'<br />';
}
}
But I am getting Kia, Kia, Toyota, BMW, BMW. Please let me know if you have any solution for this.
Thanks
You can store the ones you've displayed in an array that you can check while iterating:
// Initialize a new variable
$brands = [];
foreach ($menufectures as $key) {
$brand = explode(' ', $key['post_title']);
$brand = $brand[0];
if (!isset($brands[$brand])) {
// It doesn't exist in the array so echo it and add it to the array
$brands[$brand] = true;
echo $brand.'<br />';
}
}
Related
The below displays:
Marlena has 12 paintings (which is basically from the docs)
How do I access the data in collect(Paintings)
ex: title
$query = "MATCH (n:Artist)-[:PAINTED]->(Painting) RETURN n.first_name, collect(Painting) as paintings";
$result = $client->run($query);
foreach ($result->getRecords() as $record) {
echo sprintf('%s has %d paintings', $record->value('n.first_name'), count($record->value('paintings')));
echo '<br/>';
}
I would like to display:
Artist Name:
painting title
painting title
etc
I assume this data can be pull from either Painting or paintings. I am just unsure how to put together the query. It will display using print_r and the record so I know the data is coming through.
This should work for you:
$query = "MATCH (n:Artist)-[:PAINTED]->(Painting) RETURN n.first_name, collect(Painting) as paintings";
$result = $client->run($query);
foreach ($result->getRecords() as $record) {
echo sprintf('%s has %d paintings:<br/>', $record->value('n.first_name'), count($record->value('paintings')));
foreach ($record->value('n.paintings') as $painting) {
echo sprintf('- %s<br/>', $painting->value('title'));
}
echo '<br/>';
}
a) I suggest you alias your return values, it is easier to fetch them at the driver level
b) The paintings record value returns an array of Node objects, thus is iterable, no need to count for doing the for loop :
$query = "MATCH (n:Artist)-[:PAINTED]->(Painting) RETURN n.first_name as firstName, collect(Painting) as paintings";
$result = $client->run($query);
foreach($result->records() as $record) {
echo sprintf('%s painted %d paintings', $record->get('firstName'), count($record->get('paintings'))) . PHP_EOL;
foreach ($record->get('paintings') as $painting) {
echo sprintf('%s - %d views', $painting->value('title'), $painting->value('views')) . PHP_EOL;
}
}
I ended up getting it to work with the following:
foreach ($result->getRecords() as $record) {
$fname = $record->values()[0]->get('first_name');
$lname = $record->values()[0]->get('last_name');
echo '<strong>'.$fname.' '.$lname.' painted:</strong><br/>';
for ($x = 0; $x < count($record->values()[1]); $x++) {
print_r($record->values()[1][$x]->get('title'));
echo ' - ';
print_r($record->values()[1][$x]->get('views'));
echo ' views<br/>';
}
echo '<br/>';
}
Which provides the following output:
First Name Last Name painted:
Lumine - 86 views
Pooled Water - 69 views
Still Lake - 125 views
Final Notes
I actually tried code similar to what you suggested during my struggle to get this working. I'm a bit confused why it does not.
So I'm left wondering. Is what I come up with acceptable?
I've been wrestling with a really cool script someone gave me, trying to adapt it to my site. I'm getting closer, but I'm still getting two errors that have me puzzled.
First: Warning: Invalid argument supplied for foreach()...
This is the foreach statement:
foreach ($Topic as $Topics)
It follows a function:
function generate_menu_items($PopTax, $Topics, $Current_Topic)
I THINK the problem relates to the middle value in the function - $Topics. I don't understand how it's derived. My guess is it's supposed to be an array of all the possible topics (represented by $MyTopic in my database). But I'm not that familiar with functions, and I don't understand why he put the function and foreach BEFORE the database queries. (However, there is a more general DB query that establishes some of these values higher up the food chain.)
Here's the second problem: Fatal error: Call to undefined function render_menu()...
Can anyone tell me how and where I should define this function?
Let me briefly explain what this script is all about. First imagine these URL's:
MySite/topics/animal
MySite/topics/animal-homes
MySite/topics/animal-ecology
MySite/topics/mammal-ecology
MySite/topics/bird-ecology
Two key values are associated with each URL - $PopTax (popular name) and $MyTopic. For the first three URL's, $PopTax = Animal, while the other two are Mammal and Bird. $MyTopic = Ecology for the last three rows. For the first two, $MyTopics = Introduction and Homes.
The ID's for both values (Tax_ID and Topic_ID) are simply the first three letters of the name (e.g. Mam = Mammal, Eco = Ecology). Also, Life is the Parent of Animal, which is the Parent of Vertebrate, which is the Parent of Mammal.
Now I'm just trying to pull it all together to create a little index in the sidebar. So if you visit MySite/topics/animal-ecology, you'd see a list of ALL the animal topics in the sidebar...
Animals
Animal Classification
Animal Homes
Animal Ecology
As you can see there are some case and plural differences (animal vs Animals), though I don't think that really relates to the problems I'm having right no.
But I'm not sure if my code just needs to be tweaked or if there's something grotesquely wrong with it. Something doesn't look right to me. Thanks for any tips.
$Tax_ID = 'Mam'; // Mam represents Mammal
$Current_Topic = 'Homes';
function generate_menu_items($PopTax, $Topics, $Current_Topic)
{
$menu_items = array();
foreach ($Topic as $Topics)
{
$url = "/topics/$PopTax[PopTax]-$Topic[MyTopic]";
$title = "$PopTax[PopTax] $Topic[MyTopic]";
$text = $Topic['MyTopic'];
if ($Topic === 'People') {
$url = "$PopTax[PopTax]-and-$Topic[MyTopic]";
$title = "$PopTax[PopTax] and $Topic[MyTopic]";
$text = "$PopTax[PopTax] & $Topic[MyTopic]";
}
if ($Topic === 'Movement' && $PopTax['Parent'] == 'Ver' && $PopTax['PopTax'] != 'Human') {
$url = "$PopTax[PopTax]-locomotion";
$title = "$PopTax[PopTax] Locomotion";
$text = "Locomotion";
}
$menu_items[] = array(
'url' => strtolower($url),
'title' => ucwords($title),
'text' => ucfirst($text),
'active' => ($Topic['MyTopic'] === $Current_Topic)
);
}
return $menu_items;
}
function generate_menu_html($menu_items)
{
$list_items = array();
foreach ($menu_items as $item)
{
if ($item['active']) {
$list_items[] = "<li><span class=\"active\">$item[text]</b></span></li>";
} else {
$list_items[] = "<li>$item[text]</li>";
}
}
return '<ol>' . implode("\n", $list_items) . '</ol>';
}
$stm = $pdo->prepare("SELECT T.Topic_ID, T.MyTopic
FROM gz_topics T
JOIN gz_topics_poptax TP ON TP.Topic_ID = T.Topic_ID
WHERE TP.Tax_ID = :Tax_ID");
$stm->execute(array('Tax_ID' => $Tax_ID));
// Fetch all rows (topics) as an associative array
$Topics = $stm->fetchAll(PDO::FETCH_ASSOC);
// Get the DB row for the taxon we're dealing with
$stm = $pdo->prepare("SELECT Tax.ID, Tax.PopTax, Tax.Parent
FROM gz_poptax Tax
WHERE Tax.ID = :Tax_ID");
$stm->execute(array('Tax_ID' => $Tax_ID));
// Fetch a single row, as the query should only return one row anyway
$PopTax = $stm->fetch(PDO::FETCH_ASSOC);
// Call our custom functions to generate the menu items, and render them as a HTML list
$menu_items = generate_menu_items($PopTax, $Topics, $Current_Topic);
$menu_html = render_menu($menu_items);
// Output the list to screen
echo $menu_html;
You want foreach ($Topics as $Topic). You are looping over each $Topic in $Topics is another way to think of it.
Using this sample multidimensional array (of a palette which contains colours, which in turn contains their respective shades), let’s say I would like to display the colours in an imploded list (comma-separated) and, if applicable, its respective shades in brackets, also in an imploded (comma-separated) list.
I can easily implode the inner array (shades), but cannot figure out how to do that with the outer array (colours) given it contains the array of shades which must be run through for each colour.
I’ve seen there are several solutions for imploding a multidimensional array, but these seem to be without requiring running through a possible inner array for each. Perhaps there is another method by which to separate the entries with a comma?
And while I’m on the subject, is there a way of replacing the last comma of an imploded string with ‘and’?
Thanks in advance.
$sql = "SELECT DISTINCT colour_id, colour_nm, colour_url
FROM palettecolours
INNER JOIN colour ON colourid = colour_id
WHERE paletteid = '$palette_id'";
while ($row = mysqli_fetch_array($result))
{
$colour = '' . $row['colour_url'] . '';
$colours[$row['colour_id']] = array('colour' => $colour, 'shades' => array());
}
$sql = "SELECT colourid, shade_name, shade_url
FROM palettecolours
INNER JOIN shade ON shadeid = shade_id
WHERE paletteid = '$palette_id'";
while ($row = mysqli_fetch_array($result))
{
$shade = '' . $row['shade_url'] . '';
$colours[$row['colourid']]['shades'][] = array('shade' => $shade);
}
<?php foreach ($colours as $colour): ?>
<?php echo $colour['colour']; ?>
<?php if(!empty($colour['shades'])) { ?>(<?php echo implode(", ", $colour['shades']); ?>)<?php } ?>
<?php endforeach; ?>
CURRENT DISPLAY:-
Red (Magenta, Burgundy, Crimson) Blue Green Yellow (Egyptian Cotton, Magnolia) White (Soft Moon)
DESIRED OUTCOME:-
Red (Magenta, Burgundy, Crimson), Blue, Green, Yellow (Egyptian Cotton, Magnolia), White (Soft Moon)
How about recursive functions? Something like
function array_implode_recursive($glue, $data, $before = '(', $after = ')') {
//Loop through every child and check whether it is an array or not and implode it if so
foreach($data as &$element) {
if (is_array($element)) {
$element = $before . array_implode_recursive($glue, $element) . $after;
}
}
//It's really safe to erase this variable as sometimes PHP has fun with them
unset($element);
return implode($glue, $data);
}
Use it like this
$mydata = implode_recursive(', ', $data);
$mydata = implode_recursive(', ', $data, '[', ']');
Hope it helped
Since you know what your array looks like and it appears to have keys you could try something similar to what I've done here.
So I have a tv show website and I created custom lists where you can add whatever tv shows you want.
There is one table called lists (with user_id, list_title) and another table called show_lists which contains (list_id, show_id).
So my PHP is there:
<?php
$findlistsq = $conn->prepare('SELECT * FROM show_lists, shows, lists
WHERE lists.user_id = :user_id AND
lists.list_id = show_lists.list_id AND
shows.id = show_lists.show_id');
$findlistsq->execute(array(':user_id' => 2));
$listscount = $findlistsq->rowCount();
echo $listscount;
$list = array();
while ($listarray = $findlistsq->fetch()) {
$list[$listarray['list_title']][$listarray['name']] = $listarray;
}
?>
<?php
foreach ($list as $key => $show) {
echo $key; //echo title of list
foreach ($show as $key => $value) {
echo $value['name']; //echo tv shows
;
}
}
?>
Basically, I create an array to join a list to its tv shows, display the title of the list and whatever it contains and so on. My question is: I want to display the list only if there is more than 3 shows (at least 3 different $value).
Can anybody tell me how I could do that ? Thanks!!
Edit: Also, there is slight chance that I might have overcomplicated this. Let me know if I did.
Your explanation of your data is not great, but you could try doing this in the SELECT statement, this will be faster than messing with arrays.
$findlistsq = $conn->prepare('SELECT *
FROM show_lists, shows, lists
WHERE
lists.user_id = :user_id AND
lists.list_id = show_lists.list_id AND
shows.id = show_lists.show_id AND
COUNT(DISTINCT shows.id) > 3');
This will count the DISTINCT (unique) show ids and only return you a data set if there are more than 3 DISTINCT show ids.
You will want to look into is_array() and count()
$list = array('show1','show2','show3');
if(is_array($list)){
if(count($list) > 3){
//more than 3 shows found, execute code!
}
}
I need to be able to display the course_desc on line 30, beside the course_name.
<?php
$result = $db->query("select distinct c.dbid, c.course_name, c.course_image, m.module_id, m.module_name, m.module_name_id, m.module_image, m.hasFiles, m.files from courses c join modules_to_courses mc on (c.dbid = mc.courses_id) join modules m on (mc.modules_id = m.module_id)");
$course_name = $db->query("SELECT distinct course_name, course_desc FROM courses");
while ($temp = $course_name->fetch_assoc()) {
$courses[] = $temp['course_name'];
}
$final = array();
// Retrieve results
while ($row = $result->fetch_assoc()) {
// Add to final array via counter if valid course is found
if (in_array($row['course_name'], $courses)) {
$final[$row['course_name']][] = $row;
}
}
// Display if final array is not empty
if (!empty($final)) {
// Loop through each potential course name
foreach ($courses as $name) {
// Output if the course has values within the final array
if (array_key_exists($name, $final)) {
echo '<div>'."\n";
echo ' '. $name . "\n";
echo '<!-- list of modules -->'."\n";
// Loop through internal values
foreach ($final[$name] as $value) {
$module_name = $value['module_name'];
echo ' '. $module_name ."\n";
}
echo ' </div>'."\n";
}
}
}
?>
You already having your course description in $final so you can access it using,
$final[$name]['course_desc']
I have created a paste based on your with changes. Also note that it's need to change your $final array.
distinct course_name, course_desc means you are trying to fetch the values regarding to distinct course_name and distinct course_desc together. You may wanna use group by instead. If I understood correctly, your statement will not bring you distinct course names and their related course desc. (if that is what you want)