Echo two multidimensional array with different table - php

Question

So I have this kind of project to have post divided into several provinces. I have two multidimensional array with table1 and table2, I have been trying to echo it with foreach function and etc but still error. This is my array :
array(2) {
[0]=>
array(1) {
[1]=>
array(2) {
["table1"]=>
array(12) {
[0]=>
string(1) "1"
["id_province"]=>
string(1) "1"
[1]=>
string(13) "Province A"
["nm_province"]=>
string(13) "Province A"
}
["table2"]=>
array(2) {
[0]=>
array(58) {
[0]=>
string(2) "43"
["id_news"]=>
string(2) "43"
[1]=>
string(1) "1"
["id_province"]=>
string(1) "1"
[2]=>
string(23) "News A"
["nm_news"]=>
string(23) "News A"
}
[1]=>
array(58) {
[0]=>
string(3) "123"
["id_news"]=>
string(3) "123"
[1]=>
string(1) "1"
["id_province"]=>
string(1) "1"
[2]=>
string(21) "News B"
["nm_news"]=>
string(21) "News B"
}
}
}
}
[1]=>
array(1) {
[2]=>
array(2) {
["table1"]=>
array(12) {
[0]=>
string(1) "2"
["id_province"]=>
string(1) "2"
[1]=>
string(23) "Province B"
["nm_province"]=>
string(23) "Province B"
}
["table2"]=>
array(2) {
[0]=>
array(58) {
[0]=>
string(2) "44"
["id_news"]=>
string(2) "44"
[2]=>
string(1) "2"
["id_province"]=>
string(1) "2"
[5]=>
string(24) "News A Province B"
["nm_news"]=>
string(24) "News A Province B"
}
[1]=>
array(58) {
[0]=>
string(3) "127"
["id_news"]=>
string(3) "127"
[2]=>
string(1) "2"
["id_province"]=>
string(1) "2"
[5]=>
string(13) "News B Province B"
["nm_news"]=>
string(13) "News B Province B"
}
}
}
}
}
I don't have any idea how to retrieve more than 2 table in my array with. So I repeat again I want to echo this 2 table the 1st province had 2 news and 2nd province also had 2 news, What I want to do is echo this 2 news sorting with province.
Ps. This is my code to show arrays output
<?php
$a=mysql_query("select * from province");
while($m1=mysql_fetch_array($a)){
$result[]=$m1;
}
$output=[];
$i=0;
foreach($result as $r){
$b=$r['id_province'];
$c=mysql_query("select * from news where id_province=".$b);
$output[$i][$b]['table1']=$r;
$dummy=[];
while($response = mysql_fetch_array($c)){
$dummy[] = $response;
}
$output[$i][$b]['table2']=$dummy;
$i++;
}
Thanks For helping guys.

Answer 1

update below code it will work for you..
foreach($result as $r){
$b=$r['id_province'];
$c=mysql_query("select * from news where id_province=".$b);
$output[$i]['table1']=$r;
$dummy=[];
while($response = mysql_fetch_array($c)){
$dummy[] = $response;
}
$output[$i]['table2']=$dummy;
$i++;
}
Here i have removed extra [$b] from $output array.
Now copy below code to print array.
foreach($output as $out){
$table1= $out['table1'];
$table2= $out['table2'];
echo $table1['nm_provinsi'].'<br>';
echo 'Data from table 2';
foreach($table2 as $tab2){
echo "\t".$tab2['nm_berita'].'<br>';
}
}

Answer 2

I'd say you'd need to clean up your array first to make sure you are trying to reference the right object, you seem to have everything duplicated with an index and a key in the array.
[0]=>"123",
["id_news"]=>"123",
[1]=>"1",
["id_province"]=>"1",
[2]=>"News B",
["nm_news"]=>"News B",
Edit
I've broken down your array so you can see what I mean clearly
array(
'table1' => array(
'0' => 1,
'id_province' => 1,
'1' => 'Province A',
'nm_province' => 'Province A'
),
'table2' => array(
array(
'0' => '43',
'id_news' => '43',
'1' => '1',
'id_province' => '1',
'2' => 'News A',
'nm_news' => 'News A'
),
array(
'0' => '123',
'id_news' => '123',
'1' => 1,
'id_province' => '1',
'2' => 'New B',
'nm_news' => 'News B')
)
),
array(
'table1' => array(
'0' => "2",
'id_province' => "2",
'1' => "Province B",
'nm_province' => 'Province B'
),
'table2' => array(
array(
'0'=>'44',
'id_news' => '44',
'2' => '2',
'id_province' => '2',
'5' => 'News A Province B',
'nm_news' => 'News A Province B'
),
array(
'0'=>'127',
'id_news' => '127',
'2'=>'2',
'id_province' => '2',
'5' => 'News B Province B',
'nm_news' => 'News B Province B'
)
)
)

Answer 3

Try
$c=mysql_query("select * from news where id_province='$b'");