I have this php script called title, where it is supposed to list movie details of those movies with the title matching the inputed substring. The expected output is supposed to be like in the link/picture below. I have trouble with concatenating the genres of each movies since one movie can have many genres. I have tried using the concat(), array_to_string() but still fails.
mkSQL() constructs "safe" SQL query strings by taking a query template
string and filling in printf-like slots in the template with values
supplied in subsequent arguments. The function takes a variable number
of arguments; the first is always a query template string, with the
following arguments corresponding exactly to the slots in the
template. E.g.
$id = 3012345;
$q1 = mkSQL("select * from R where id = %d",$id);
would create the query strings:
$q1: "select * from R where id = 12345"
Below are the codes, any helps and tips will be greatly appreciated, thanks!
This is the Genre Table Schema
CREATE TABLE Genre (
movie_id integer REFERENCES Movie(id),
genre GenreType,
primary key (movie_id,genre));
#!/usr/bin/php
<?php
// include the common PHP code file
require("a2.php");
$db = pg_connect("dbname=mydb");
// Check arguments
if (count($argv) < 2) exit("$usage\n");
// Get the return results
$val = $argv[1];
$q = "select m.title, m.year, m.content_rating, r.imdb_score, array_to_string(array(select g.genre FROM Genre g where g.movie_id = m.id),',')
-- concat(select g.genre FROM Genre g where g.movie_id = m.id
from Movie m JOIN Rating r ON r.movie_id = m.id
where m.title ilike %p
order by m.year, r.imdb_score desc, m.title asc";
$r = pg_query($db, mkSQL($q, $val));
// Iterate through the results and print
$i = 1;
while ($t = pg_fetch_array($r)) {
echo "$i. $t[0] ($t[1], $t[2], $t[3]) [$t[4]]\n";
$i++;
}
?>
The expected output is supposed to be in this format
Change your query like,
SELECT CONCAT(m.title, ' (', m.year, ', ', m.content_rating, ',', r.imdb_score, ') [', (SELECT array_to_string(array_agg(g.genre), ',') FROM Genre g WHERE g.movie_id = m.id), ']') movie_title
FROM Movie m JOIN Rating r ON r.movie_id = m.id
WHERE m.title ilike %p
ORDER BY m.year, r.imdb_score desc, m.title ASC
Here, I have concat all columns into one and given it an alias movie_title. You will get the movie name as per your specified format.
For achieving this, you can use the group_concat function in your mysql script.
This will concatenate your respective column via comma(,).
Related
I have two tables and the commonality is the tid. the $tid is the primary key for tourneys and if it is in team_tourney then the team selected it. The code below echos everything if a team selected it but drops only the variable $tid for every non selected item. How would you suggest I work around my delema.
tables
team_tourneys
tourneys
my sql is
$myChoice=#mysql_query("SELECT *
FROM tourneys
LEFT JOIN team_tourneys
ON tourneys.tid = team_tourneys.tid
WHERE tourney_state = '$region' AND tourney_start_date >= now()
GROUP BY tourneys.tid ORDER BY tourney_start_date ASC
");
if (!$myChoice)
{
die('<p>Error fetching Tourney details: ' .
mysql_error() . '</p>');
}
while ($choice = mysql_fetch_array($myChoice))
{
$tid = $choice['tid'];
$tourney_name = $choice['tourney_name'];
echo ''.$tourney_name.'</div>'
}
Since you are fetching into an associative array you only have one slot for any selected column name (or alias). In other words, you can not have:
array(
"tid" => 1,
"tid" => 2,
);
Your query is going to return all columns of all referenced tables in the order the tables are listed. Since the both tables contain tid and team_tourneys is the last table referenced, $choice["tid"] will contain team_tourneys.tid which of course can be NULL due to the LEFT JOIN.
Probably the easiest way to resolve this is to read the tourneys table last:
SELECT team_tourneys.*, tourneys.*
FROM tourneys
LEFT JOIN team_tourneys
ON tourneys.tid = team_tourneys.tid
WHERE tourney_state = '$region' AND tourney_start_date >= now()
GROUP BY tourneys.tid ORDER BY tourney_start_date ASC;
You should really enter each column name individually, however. It's bad practice to use *.
i'm in the process of joining two tables together under two different conditions. For primary example, lets say I have the following nested query:
$Query = $DB->prepare("SELECT ID, Name FROM modifications
WHERE TYPE =1 & WFAbility = '0'");
$Query->execute();
$Query->bind_result($Mod_ID,$Mod_Name);
and this query:
$Query= $DB->prepare("SELECT `ModID` from `wfabilities` WHERE `WFID`=?");
$Query->bind_param();
$Query->execute();
$Query->bind_result();
while ($Query->fetch()){ }
Basically, I want to select all the elements where type is equal to one and Ability is equal to 0, this is to be selected from the modifications table.
I further need to select all the IDs from wfabilities, but transform them into the names located in modifications where WFID is equal to the results from another query.
Here is my current semi-working code.
$Get_ID = $DB->prepare("SELECT ID FROM warframes WHERE Name=?");
$Get_ID->bind_param('s',$_GET['Frame']);
$Get_ID->execute();
$Get_ID->bind_result($FrameID);
$Get_ID->fetch();
$Get_ID->close();
echo $FrameID;
$WF_Abilties = $DB->prepare("SELECT ModID FROM `wfabilities` WHERE WFID=?");
$WF_Abilties->bind_param('i',$FrameID);
$WF_Abilties->execute();
$WF_Abilties->bind_result($ModID);
$Mod_IDArr = array();
while ($WF_Abilties->fetch()){
$Mod_IDArr[] = $ModID;
}
print_r($Mod_IDArr);
$Ability_Name = array();
foreach ($Mod_IDArr AS $AbilityMods){
$WF_AbName = $DB->prepare("SELECT `Name` FROM `modifications` WHERE ID=?");
$WF_AbName->bind_param('i',$AbilityMods);
$WF_AbName->execute();
$WF_AbName->bind_result($Mod_Name);
$WF_AbName->fetch();
$Ability_Name[] = $Mod_Name;
}
print_r($Ability_Name);
See below:
SELECT ModID,
ID,
Name
FROM modifications M
LEFT JOIN wfabilities WF
ON WF.ModID = M.ID
WHERE TYPE =1 & WFAbility = '0'
To do this, you need to join your tables, I'm not quite sure what you are trying to do so you might have to give me more info, but here is my guess.
SELECT ID, Name, ModID
FROM modifications
JOIN wfabilities
ON WFID = ID
WHERE TYPE = '1'
AND WFAbility = '0'
In this version I am connecting the tables when WFID is equal if ID. You will have to tell me exactly what is supposed to be hooking to what in your requirements.
To learn more about joins and what they do, check this page out: MySQL Join
Edit:
After looking at your larger structure, I can see that you can do this:
SELECT modifications.Name FROM modifications
JOIN wfabilities on wfabilities.ModID = modifications.ID
JOIN warframes on warframes.ID = wfabilities.WFID
WHERE warframes.Name = 'the name you want'
This query will get you an array of the ability_names from the warframes name.
This is the query:
"SELECT A.ID, A.Name,B.ModID,C.Name
FROM modifications as A
LEFT JOIN wfabilities as B ON A.ID = B.WFID
LEFT JOIN warframes as C ON C.ID = B.WFID
WHERE A.TYPE =1 AND A.WFAbility = '0' AND C.Name = ?"
Solution:
$query = $this->db->query("
SELECT *, SUM(views.times) AS sum
FROM channel
RIGHT JOIN video
ON channel.channel_id = video.channel_id
LEFT JOIN user
ON channel.user_id = user.user_id
LEFT JOIN views
ON channel.channel_id = views.channel_id
GROUP BY channel.channel_name
ORDER BY sum DESC
");
I have a query that returns a list of items.
function getfrontpage(){
$this->db->select('*');
$this->db->from('channel');
$this->db->join('video', 'channel.channel_id = video.channel_id' , 'right');
$this->db->join('user', 'channel.user_id = user.user_id');
$this->db->group_by("channel.channel_name");
$query = $this->db->get();
return $query->result();
}
Now i'm trying to order these with the SUM from another table, how can i achieve this?
Here is a picture from that table:
I want the results to be sorted by the SUM of the total of "times" for each "channel_id"
thanks in advance
I would suggest to run this through $this->db->query() instead.
It's nice to fetch simple values through CodeIgniters AR functions. But at some situations it's simply easier to build query strings instead.
In your case:
$query = $this->db->query("
SELECT channel_id, SUM(times) AS sum
FROM channel
GROUP BY channel_id
ORDER BY sum DESC
");
You can also escape most values through db->query()!
$this->db->query("
SELECT name
FROM table_name
WHERE id = ?
", array(1));
Isn't it as simple as $this->db->order_by("channel_id", "desc");? this orders the results by channel_id in descending order.
Assuming the table displayed in your question is called times_table, and has a key of user_id, channel_id, you can use the following code to join the times_table into your query so the "times" column is available to sort by.
$this->db->join("times_table", "times.user_id=channel.user_id, times.channel_id=channel.channel_id", "left");
// You've already grouped by channel_name, so grouping by channel_id is probably not necessary.
$this->db->order_by("SUM(times_table.times) DESC");
N.B. I just guessed the name of your displayed table is times_table.
Sorry let me revise. I have a three tables:
events_year
• EventID
• YearID
• id
Date
• YearID
• Year
Event
• EventID
• EventName
• EventType
i want to dispay a record from the three tables like so:
EventName - Year: Marathon - 2008
i linked it to a table called "members" which contains a ID number field (members-id)
so i can limit the results to members id = $un(which is a username from a session)
I need to join the three tables and limit the results to the specific ID number record
Here is my portion of the code:
$query = "SELECT * FROM members JOIN events_year ON members.id = events_year.id ";
"SELECT * FROM Event JOIN events_year ON Event.EventID = events_year.EventID WHERE username = '$un'";
"SELECT * FROM Date JOIN events_year ON Date.YearID = events_year.YearID WHERE username = '$un'";
$results = mysql_query($query)
or die(mysql_error());
while ($row = mysql_fetch_array($results)) {
echo $row['Year'];
echo " - ";
echo $row['Event'];
echo "<br>";
}
the notices are almost self-explaining. There are no 'Year' and 'EventName' fields in the resultset. It's difficult (or: impossible) to tell why this happens as you haven't given your table-structure, but i guess this: 'Year' is a field of the date-table, 'EventName' is a field of the event-table - you're only selecting from members so this fields don't occur.
I don't understand why there are three sql-statements but only one is assigned to a variable - the other two are just standing there and do nothing. Please explain this and put more information into your question about what you're trying to achive, what your table-structure looks like and whats your expected result.
I think what you really wanted to do is some kind of joined query, so please take a look at the documentation to see how this works.
finally, i think your query should look like this:
SELECT
*
FROM
members
INNER JOIN
events_year ON members.id = events_year.id
INNER JOIN
Event ON Event.EventID = events_year.EventID
INNER JOIN
´Date´ ON ´Date´.YearID = events_year.YearID
WHERE
members.username = '$un'
Does the field 'Year' exist in the query output ? I suspect not.
the string $query is only using the first line of text:
"SELECT * FROM members JOIN events_year ON members.id = events_year.id ";
and not the others.
The query itself is not returning any fields that are called Year or EventName.
Do a var_dump($row) to find out what is being returned.
I have three tables which are currently structured in the following way
Table: Images
image_id
image_title
...
Table: Keywords
keyword_id
keyword
Table: Image_Keyword
image_id
keyword_id
With this structure, I'm able to search if any images match any keywords using joins and or statements - however I would like to be able to retrieve images that have multiple keywords matches e.g. "keyword = ('red' or 'dress') and 'night'" - which would return all images that had either 'red' or 'dress' in them, alongside night.
Ideally I want to allow the user to be able to specify the AND and OR commands in the search box, which is why I have so far opted out of making separate joins for each new keyword - however I'm not sure how to proceed with the structuring of the query.
Currently I have the following, without the 'and' implementation:
SELECT i.* FROM images i
JOIN image_keyword ik ON i.id = ik.image_id
JOIN keywords k ON k.id = ik.keyword_id
WHERE k.keyword IN ('night','red')
Any help on how to go about creating the 'and' portion of this query would be greatly appreciated! Thanks kindly,
Dan
// UPDATE
So it looks as if I am going to have to do it by creating joins for each 'AND' request that I need to sort out - however I have an extension on the requirements now...
I have two other tables which follow the following structure
Table ImageData
id
image_id
caption_id
...
Table Caption
id
data (text)
In this instance, I would want to search for the keywords ('red','dress' and 'night'), using the same 'AND' and 'OR' capability as before, but also return the image if the text matches (using the same rules) in the caption data field. I would assume I potentially use an OR after the 'keyword' search, and then use a fulltext search on the caption, however I don't know if there is a cleaner way of combining the two, maybe even as two separate queries and then choosing the distinct results - which might allow for instances where the AND is successful in the keywords, and the OR is successful in the caption.
Any thoughts would be fantastic
Thanks again
I think what you will end up is this -
One INNER JOIN for all your ORs.
One INNER JOIN each for all your ands.
For example -
SELECT i.* FROM images i
INNER JOIN image_keyword ik ON i.id = ik.image_id
INNER JOIN keywords kOR ON kOR.id = ik.keyword_id AND (kOR.keyword IN ('dress', 'red'))
INNER JOIN keywords kAND1 ON kAND1.id = ik.keyword_id AND kAND1.keyword = 'night'
PHP script would look something like.
$orKeywords = arrya('dress', 'red', 'white');
$andKeywords = array('night', 'day');
$orJoin = '';
$andJoin = '';
if(count($orKeywords) > 0)
{
$orCondition = "'".implode("', '", $orKeywords)."'";
$orJoin = " INNER JOIN keywords kOR ON kOR.id = ik.keyword_id AND kOR.keyword IN ($orCondition) ";
}
if(count($andKeywords) > 0)
{
$cnt = 1;
foreach($andKeywords as $keyword)
{
$andJoin .= " INNER JOIN keywords kAND{$cnt} ON kAND{$cnt}.id = ik.keyword_id AND kAND{$cnt}.keyword = '$keyword' ";$cnt++;
}
}
$sql = "SELECT i.* FROM images i
INNER JOIN image_keyword ik ON i.id = ik.image_id
$orJoin
$andJoin";
You get the idea..
I would just generate the WHERE part of the query in PHP script, like this:
<?php
$entered_keywords = array('night','red');
$logic = 'OR'; // or 'AND'
$sql_where = implode(' '.$logic.' ', "k.keyword='$entered_keywords'"); //don't forget the escaping here!
$sql = 'SELECT i.* FROM images i
JOIN image_keyword ik ON i.id = ik.image_id
JOIN keywords k ON k.id = ik.keyword_id
WHERE '.$sql_where;
?>