I'm trying to inner join a users table to itself using an eloquent model. I've looked everywhere but can't seem to find a solution to this without creating two queries which is what I am currently doing.
A users table has a many to many relationship itself through the pivot table friends
I tried and failed inner joining Users::class to itself. The best I can get at an inner join is by running two queries and seeing if there is an overlap. Thus one person has reached out to the other and vice versa.
friends | users
----------|------
send_id | id
receive_id| name
is_blocked|
sample data & expected result
users.id | name
---------|------
1 | foo
2 | bar
3 | baz
friends
send_id | receive_id | is_blocked
--------|------------|-----------
1 | 2 | 0
2 | 1 | 0
1 | 3 | 0
3 | 1 | 1
2 | 3 | 0
The user should have an eloquent relationship called friends. It should be what you expect comes out of requestedFriends or receivedFriends just joined.
foo->friends
returns `baz`
bar->friends
returns `foo`
baz->friends
returns empty collection
currently using
// User.php
public function requestedFriends()
{
$left = $this->belongsToMany(User::class, 'friends','send_id','receive_id')
->withPivot('is_blocked')
->wherePivot('is_blocked','=', 0)
->withTimestamps();
return $left;
}
public function receivedFriends()
{
$right = $this->belongsToMany(User::class, 'friends','receive_id','send_id')
->withPivot('is_blocked')
->wherePivot('is_blocked','=', 0)
->withTimestamps();
return $right;
}
public function friends()
{
$reqFriends = $this->requestedFriends()->get();
$recFriends = $this->receivedFriends()->get();
$req = explode(",",$recFriends->implode('id', ', '));
$intersect = $reqFriends->whereIn('id', $req);
return $intersect;
}
Research so far
Laravel Many to many self referencing table only works one way -> old question, but still relevant
https://github.com/laravel/framework/issues/441#issuecomment-14213883 -> yep, it works… but one way.
https://laravel.com/docs/5.8/collections#method-wherein
currently the only way I have found to do this in eloquent.
https://laravel.com/docs/5.7/queries#joins -> Ideally I would find a solution using an innerjoin onto itself, but no matter which way I put the id's I couldn't get a solution to work.
A solution would
A solution would inner join a self referencing table using eloquent in laravel 5.7 or 5.8, where a relationship only exists if send_id & receive_id are present on multiple rows in the friends table.
OR
Somehow let the community know that this can't be done.
Thanks in advance!
I have not checked this solution in every detail yet, but I have written a "ManyToMany" Class extending the "BelongsToMany" Class shipped with laravel, which appears to work.
The class basically just overrides the "get" method, duplicating the original query, "inverting" it and just performing a "union" on the original query.
<?php
namespace App\Database\Eloquent\Relations;
use Illuminate\Database\Eloquent\Relations\BelongsToMany;
class ManyToMany extends BelongsToMany
{
/**
* Execute the query as a "select" statement.
*
* #param array $columns
* #return \Illuminate\Database\Eloquent\Collection
*/
public function get($columns = ['*'])
{
// duplicated from "BelongsToMany"
$builder = $this->query->applyScopes();
$columns = $builder->getQuery()->columns ? [] : $columns;
// Adjustments for "Many to Many on self": do not get the resulting models here directly, but rather
// just set the columns to select and do some adjustments to also select the "inverse" records
$builder->addSelect(
$this->shouldSelect($columns)
);
// backup order directives
$orders = $builder->getQuery()->orders;
$builder->getQuery()->orders = [];
// clone the original query
$query2 = clone($this->query);
// determine the columns to select - same as in original query, but with inverted pivot key names
$query2->select(
$this->shouldSelectInverse( $columns )
);
// remove the inner join and build a new one, this time using the "foreign" pivot key
$query2->getQuery()->joins = array();
$baseTable = $this->related->getTable();
$key = $baseTable.'.'.$this->relatedKey;
$query2->join($this->table, $key, '=', $this->getQualifiedForeignPivotKeyName());
// go through all where conditions and "invert" the one relevant for the inner join
foreach( $query2->getQuery()->wheres as &$where ) {
if(
$where['type'] == 'Basic'
&& $where['column'] == $this->getQualifiedForeignPivotKeyName()
&& $where['operator'] == '='
&& $where['value'] == $this->parent->{$this->parentKey}
) {
$where['column'] = $this->getQualifiedRelatedPivotKeyName();
break;
}
}
// add the duplicated and modified and adjusted query to the original query with union
$builder->getQuery()->union($query2);
// reapply orderings so that they are used for the "union" rather than just the individual queries
foreach($orders as $ord)
$builder->getQuery()->orderBy($ord['column'], $ord['direction']);
// back to "normal" - get the models
$models = $builder->getModels();
$this->hydratePivotRelation($models);
// If we actually found models we will also eager load any relationships that
// have been specified as needing to be eager loaded. This will solve the
// n + 1 query problem for the developer and also increase performance.
if (count($models) > 0) {
$models = $builder->eagerLoadRelations($models);
}
return $this->related->newCollection($models);
}
/**
* Get the select columns for the relation query.
*
* #param array $columns
* #return array
*/
protected function shouldSelectInverse(array $columns = ['*'])
{
if ($columns == ['*']) {
$columns = [$this->related->getTable().'.*'];
}
return array_merge($columns, $this->aliasedPivotColumnsInverse());
}
/**
* Get the pivot columns for the relation.
*
* "pivot_" is prefixed ot each column for easy removal later.
*
* #return array
*/
protected function aliasedPivotColumnsInverse()
{
$collection = collect( $this->pivotColumns )->map(function ($column) {
return $this->table.'.'.$column.' as pivot_'.$column;
});
$collection->prepend(
$this->table.'.'.$this->relatedPivotKey.' as pivot_'.$this->foreignPivotKey
);
$collection->prepend(
$this->table.'.'.$this->foreignPivotKey.' as pivot_'.$this->relatedPivotKey
);
return $collection->unique()->all();
}
}
I came across the same problem quite some time ago and have thus been following this problem closely and have made a lot of research. I have come across some of the solutions you have also found, and some more, and also have thought of other solutions that I summed here, mostly how to get both user_ids in the same column. I am afraid they will all not work well. I am also afraid that using any custom classes will stop you from using all of Laravel's handy relation features (especially eager loading). So I still thought what one could do, and, until one comes up with a hasMany-function on many columns, I think I have come up with a possible solution yesterday. I will show it first and then apply it to your project.
My project
Initial solution
In my project, one user partners with another one (= partnership) and then later will be assigned a commission. So I had the following tables:
USERS
id | name
---------|------
1 | foo
2 | bar
17 | baz
20 | Joe
48 | Jane
51 | Jim
PARTNERSHIPS
id | partner1 | partner2 | confirmed | other_columns
----|-----------|-----------|-----------|---------------
1 | 1 | 2 | 1 |
9 | 17 | 20 | 1 |
23 | 48 | 51 | 1 |
As each user should always have only one active partnership, the non-active being soft-deleted, I could have helped myself by just using the hasMany function twice:
//user.php
public function partnerships()
{
$r = $this->hasMany(Partnership::class, 'partner1');
if(! $r->count() ){
$r = $this->hasMany(Partnership::class, 'partner2');
}
return $r;
}
But if I had wanted to lookup all partnerships of a user, current and past, this of course, wouldn't have worked.
New solution
Yesterday, I came up with the solution, that is close to yours, of using a pivot table but with a little difference of using another table:
USERS
(same as above)
PARTNERSHIP_USER
user_id | partnership_id
--------|----------------
1 | 1
2 | 1
17 | 9
20 | 9
48 | 23
51 | 23
PARTNERSHIPS
id | confirmed | other_columns
----|-----------|---------------
1 | 1 |
9 | 1 |
23 | 1 |
// user.php
public function partnerships(){
return $this->belongsToMany(Partnership::class);
}
public function getPartners(){
return $this->partnerships()->with(['users' => function ($query){
$query->where('user_id', '<>', $this->id);
}])->get();
}
public function getCurrentPartner(){
return $this->partnerships()->latest()->with(['users' => function ($query){
$query->where('user_id', '<>', $this->id);
}])->get();
}
// partnership.php
public function users(){
return $this->belongsToMany(User::class);
}
Of course, this comes with the drawback that you always have to create and maintain two entrances in the pivot table but I think this occasional extra load for the database -- how often will this be altered anyway? -- is preferable to having two select queries on two columns every time (and from your example it seemed that you duplicated the entries in your friends table anyway).
Applied to your project
In your example the tables could be structured like this:
USERS
id | name
---------|------
1 | foo
2 | bar
3 | baz
FRIENDSHIP_USER
user_id | friendship_id
---------|------
1 | 1
2 | 1
3 | 2
1 | 2
FRIENDSHIPS
id |send_id* | receive_id* | is_blocked | [all the other nice stuff
--------|---------|-------------|------------|- you want to save]
1 | 1 | 2 | 0 |
2 | 3 | 1 | 0 |
[*send_id and receive_id are optional except
you really want to save who did what]
Edit: My $user->partners() looks like this:
// user.php
// PARTNERSHIPS
public function partnerships(){
// 'failed' is a custom fields in the pivot table, like the 'is_blocked' in your example
return $this->belongsToMany(Partnership::class)
->withPivot('failed');
}
// PARTNERS
public function partners(){
// this query goes forth to partnerships and then back to users.
// The subquery excludes the id of the querying user when going back
// (when I ask for "partners", I want only the second person to be returned)
return $this->partnerships()
->with(['users' => function ($query){
$query->where('user_id', '<>', $this->id);
}]);
}
Related
I need to get rows from one table using an id which is two joins away.
I know I can use join('table_name') but I am trying to use the model names rather than raw table names.
I'm trying to select shipping_shipment.* by joining order_item_join_shipping_shipment then joining order_item, and filtering where order_item.order_id = x
I tried this in the ShippingShipment class, but I can't figure it out.
return $this->hasManyThrough(OrderItem::class, ShippingShipment::class, 'shipment_id', 'order_item_id', 'id', 'id');
There are many items in an order, and many shipments. I need to get the shipments.
There can be more than one shipment per order - items come from various places.
There can be more than one shipment per item - if something is returned and needs shipping again.
The table I want to get rows from, shipping_shipment, is joined to order_item by a join table order_item_join_shipping_shipment. That join table has the order_item_id. I need then to join order_item table so that I can search for order_item.order_id
Table order_item model OrderItem
+-----+---------------+
| id | order_id |
+-----+---------------+
| 6 | 13464 |
| 8 | 13464 |
| 9 | 13464 |
+-----+---------------+
Table order_item_join_shipping_shipment model OrderItemJoinShippingShipment
+-----+---------------+-------------+
| id | order_item_id | shipment_id |
+-----+---------------+-------------+
| 1 | 6 | 12 |
| 1 | 9 | 12 | two items in one shipment
| | | |
| 2 | 8 | 13 |
| 3 | 8 | 14 | one item was returned so shipped again
+-----+---------------+-------------+
Table shipping_shipment don't need describing except to say it has an id column.
If I was to do it with MySQL it would look like this
SELECT ss.*, oiss.order_item_id FROM
order_item_join_shipping_shipment AS oiss
INNER JOIN shipping_shipment AS ss ON (oiss.shipment_id = ss.id)
INNER JOIN order_item AS oi ON (oiss.order_item_id = oi.id)
WHERE oi.order_id = 13464
I noticed you are not using the default table names, so your Models must have the table names explicit, e.g.:
class OrderItem extends Model
{
/**
* The table associated with the model.
*
* #var string
*/
protected $table = 'order_item';
}
In the same Model file of the above example, you need to indicate how the relationship works, i.e.:
public function shippingShipments()
{
return $this->belongsToMany(ShippingShipment::class, 'order_item_join_shipping_shipment', 'order_item_id', 'shipment_id');
}
Here you can check in Laravel documentation the whole explanation.
You need to apply the same concept in ShippingShipment Model, so your Model will be something like this:
<?php
namespace App\Models;
use Illuminate\Database\Eloquent\Model;
class User extends Model
{
/**
* The table associated with the model.
*
* #var string
*/
protected $table = 'order_item';
/**
* The roles that belong to the user.
*/
public function orderItens()
{
return $this->belongsToMany(OrderItem::class, 'order_item_join_shipping_shipment', 'shipment_id', 'order_item_id');
}
}
This way you can get shipments by order item and vice-versa:
//Shipments of Order item 13464
$shipments = OrderItem::find(13464)->shippingShipments()->get();
//Order items of Shipment 1
$orders = ShippingShipment::find(1)->orderItems()->get();
Source: Laravel Documentation
As far as I can tell you are using a pivot table between ShippingShipment and OrderItem. If I understand you correctly you want to get OrderItems that are connected to ShippingShipment, if that is the case this is what you can do:
Make belongs to many relationships in both models, such as:
ShippingShipment:
public function orderItems(){
return $this->belongsToMany(OrderItem::class, 'table_name', 'column_id');
}
OrderItem:
public function shippingShipment(){
return $this->belongsToMany(ShippingShipment::class, 'table_name', 'column_id');
}
And then you can get the desired result by typing this query:
ShippingShipment::find(1)->with('orderItems')->get();
OrderItem::find(13464)->with('shippingShipments')->get();
Note: you can use orderItems:id,order or shippingShipment:id,some_other_field for more optimized query
Consider a table of nested locations which has columns for the location_id, its name and a parent_id. This parent field lets you know that you're in a nested location.
Example setup:
Locations
-----------------------------------
location_id | name | parent_id
-----------------------------------
1 | Isle A | NULL
2 | Column 23 | 1
3 | Shelf 2 | 2
4 | Box C | 3
Let's say we have an item sitting in location_id=4.
We now want to easily show the item's full location in a comma separated format. We expect to see:
Isle A, Column 23, Shelf 2, Box C
In order to achieve that, I have the following Laravel Model with a full_name() function which takes care of formatting and recursive calls:
<?php
namespace App;
use Illuminate\Database\Eloquent\Model;
class Location extends Model
{
protected $table = 'locations';
protected $primaryKey = 'location_id';
protected $with = [
'location'
];
public function location()
{
return $this->hasMany('App\Location', 'parent_id', 'location_id');
}
public function full_name()
{
return ($this->location ? $this->location->full_name() . ', ' : '') . $this->name;
}
}
Nothing fancy soo far, works correctly and outputs what I need it to.
Now imagine down the line, some other piece of code allows for a mistake and the following happens:
Locations
-----------------------------------
location_id | name | parent_id
-----------------------------------
1 | Isle A | NULL
2 | Column 23 | 3
3 | Shelf 2 | 2
4 | Box C | 3
Notice that location #2's parent_id changed to 3. This creates an infinite loop of joins between 2 and 3. Laravel will not detect this recurrence (after all we're telling it to keep joining) and the execution will eventually die. This is my problem.
A possible solution I thought about would be to keep an ongoing list of "visited" location_id's, and if we stumble upon a repeat, we terminate the execution. If this was a "normal" function, I recon something like this would work:
public function location($recurrence_guard = [])
{
if(in_array($this->location_id, $recurrence_guard)) {
return collect([]); // or null?
}
array_push($recurrence_guard, $this->location_id);
return $this->hasOne('\App\Location(<somehow pass $recurrence_guard_in_here>)', 'location_id', 'parent_id');
}
Clearly this is nonsense and that's not how Laravel's relationships work. I'm looking for ideas on how to pass extra parameters into the relationships or for any better ideas on how to design this.
Thanks!
I have an interesting eloquent challenge and my knowledge is not quite there to work it through, hoping you smart folks can give me some guidance. I have read this: Getting just the latest value on a joined table with Eloquent and it is very close to what I want, but I have an extra level of tables in there.
I have two tables like this:
Users have many Assessments. Each Assessment hasOne body_fat_testing (and 4 other hasOnes that I need to use as well).
Each body_fat_testing table has several columns I'm interested (see below) in.
I'd like to get the "best" result from each "grandchild", per user.
So out of all the assessments, the best lean_mass, body_fat_percentage, etc
I have this so far:
$users = User::with(
[
'trainer',
'firstAssessment.body_fat_testing',
'firstAssessment.circumference_measurement',
'firstAssessment.exercise_testing',
'firstAssessment.overhead_squat_movement_screen',
'firstAssessment.push_ups_movement_screen',
'lastAssessment.body_fat_testing',
'lastAssessment.circumference_measurement',
'lastAssessment.exercise_testing',
'lastAssessment.overhead_squat_movement_screen',
'lastAssessment.push_ups_movement_screen',
]
)->find($request->input('user_ids'));
...
(in User.php)
public function lastAssessment()
{
return $this->hasOne('App\Assessment')->latest('assessment_date');
}
public function firstAssessment()
{
return $this->hasOne('App\Assessment')->orderBy('assessment_date');
}
There are about 30 total values I want the "best" of. Any ideas on how to accomplish this without looping through each and every value individually?
assessment table:
+----+---------+-----+--------+---------------+
| id | user_id | age | weight | assessed_date |
+----+---------+-----+--------+---------------+
| 1 | 7 | 24 | 204 | 2019-10-29 |
+----+---------+-----+--------+---------------+
body_fat_testing table:
+----+---------------+-----------+---------------------+
| id | assessment_id | lean_mass | body_fat_percentage |
+----+---------------+-----------+---------------------+
| 1 | 1 | 130.97 | 21.10 |
+----+---------------+-----------+---------------------+
Try this approach (it assumes you have models for your three tables and the relationships between them exist):
First, you'll relate your User model to your BodyFatTesting model, with this:
public function bodyFatTestings() {
return $this->hasManyThrough("App\BodyFatTesting", "App\Assessment");
}
Then, you'll create a secondary method bestBodyFatPercentage like this:
public function bestBodyFatTesting() {
return $this->bodyFatTestings()->max('body_fat_testing.body_fat_percentage');
}
To use it, just get a model in whichever way you prefer and call bestBodyFatTesting().
From there I think you can adapt it to your other "has ones".
You can also do it this way:
public function bestLeanMass()
{
return $this->hasOneThrough('App\BodyFatTesting', 'App\Assessment')
->selectRaw('user_id, max(lean_mass) as aggregate')
->groupBy('user_id');
}
Not sure which way I like better. The former is a bit easier to understand but creates more methods. This one is harder to understand but fewer methods.
I am trying to learn laravel and currently using eloquent to interact with the database. I am stuck on how I could use eloquent to get a kind of a join in eloquent.
I have a many to many relation between two tables :users and projects , I use sharedProject table to be the intermediate table .
The tables are as such
Users:
| iduser | name | password |
----------------------------------------
| 1 | somename | hashPassword |
| 2 | somename2 | hashPassword |
| 3 | somename3 | hashPassword |
| 4 | somename4 | hashPassword |
----------------------------------------
Projects:
| pid | projectname
-------------------
| 1 | somename
| 2 | somename
SharedProjects:
| pid | iduser | sharedProjectid |
----------------------------------
| 1 | 1 | 1 |
| 1 | 2 | 2 |
Now I want to get all the users who are not sharing a given project, for example in the above case for project with id 1 , I should get user 3 and user 4.
Here are my relationships in User model
/**
* User can have many projects
*
* #var array
*/
public function projects(){
return $this->hasMany('App\Project','pid','iduser'); // hasmany(model,foreignkey,localkey)
}
/**
* The user can have many shared projects
*/
public function sharedProjects()
{
return $this->belongsToMany('App\SharedProject', 'sharedProjects', 'iduser', 'pid');// belongsToMany('intermediate tablename','id1','id2')
}
and in the Project model:
/**
* The project can be shared by many users
*/
public function sharedProjects()
{
return $this->belongsToMany('App\SharedProject', 'sharedProjects', 'pid', 'iduser');// belongsToMany('intermediate tablename','id1','id2')
}
/**
* a project belongs to a single user
*
* #var array
*/
public function user()
{
return $this->belongsTo('App\User');
}
I would prefer a eloquent way to do this , but would also except it, if can't be done in eloquent and I have to see a alternate approach I would appreciate a plain mysql query as well.
Thanks
Once you define your Eloquent models and your many-to-many relationships, you can use them to get the data you're looking for.
Assuming a User model that has a projects relationship defined, you can use the whereDoesntHave() method to query for a list of users that are not related to a specific project.
$projectId = 1;
$users = User::whereDoesntHave('projects', function ($q) use ($projectId) {
return $q->where('projects.id', $id);
})->get();
You can read about defining many-to-many relationships in Eloquent here.
You can read about querying relationship existence here.
As you may notice, not all methods are documented (like whereDoesntHave()), so you may have to go source code diving. You can dig into the Eloquent codebase here.
I resort to use plain mysql queries, this seems to work for me:
$nonSharedUsers = DB::select( DB::raw("SELECT iduser FROM users WHERE NOT EXISTS (SELECT * FROM sharedProjects WHERE sharedProjects.iduser= users.iduser and sharedProjects.pid=:projectId)"), array(
'projectId' => $pid,
));
can anybody help me on the following query.
I have a table that holds a postcode column and a rating column, ie.
ID | POSTCODE | RATING
1 | sk101dd | E
2 | sk101de | A
3 | sk101df | E
4 | sk101dg | E
5 | sk101dh | D
etc
This is set up as a model called PostcodeList
I have a relational table, linked via the RATING column that holds a customer id and cost, ie.
ID | CUSTOMER_ID | RATING | COST
1 | 1234 | E | 0.05
2 | 9999 | E | 0.02
This is set up as a model called RatingCost. I linked this to PostcodeList model using the following code:
public function costing()
{
return $this->hasMany('PostcodeList','RATING','RATING');
}
I need to return the COST from the RatingCost model using CUSTOMER_ID as the filter without resorting to multiple sql statements. I think I've nearly got it, using the code below, but it's not quite right:
$p = PostcodeList::where('postcode',$somepostcode)->first();
$cost = $p->costing()->where('customer_id',$somecustomerid)->first()->cost;
The error I'm getting at the moment is "Trying to get property of non-object".
Any help greatly appreciated. I don't want to resort to DBRAW or another form of join as I really like the relational setup Laravel provides.
thanks
I know you're trying to stay away from joins, but this Laravel query would produce the desired results:
DB::table('PostcodeList')
->join('RatingCost', function($join)
{
$join->on('RATING', '=', 'RatingCost.RATING')
->->where('customer_id',$somecustomerid)
})
You have this
$postcode_get = PostcodeList::where('postcode',$somepostcode)->get();
foreach($postcode_get as $p){
...
$cost = $p->costing()->where('customer_id',$somecustomerid)
// ...
}
You have defined the method costing in your RatingCost model but calling it from PostcodeList model, in this case you need to declare the relation inside your PostcodeList model like this:
public function costing()
{
// change the field name 'RATING' in any table, maybe
// prefix with table name or something else, keep different
return $this->belongsToMany('RatingCost','RATING', 'RATING');
}
So, you can use this (inside loop):
$cost = $p->costing();
Because, inside your loop each $p represents a PostcodeList model and $postcode_get is a collection of PostcodeList models.
I don't think what I'm trying to do is actually possible without using joins. So the solution was to scrap the belongsTo and hasMany options for a standard join (similar to dev_feed's response):
$pr = PostcodeList::join('RatingCost', function($join)
{
$join->on('PostcodeList.content_rate', '=', 'RatingCost.code');
})
->where('postcode', '=', $somepostcode)
->where('RatingCost.customer_id','=',$somecustomerid)
->first();